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Counterfeit Gliders

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Re: Counterfeit Gliders

Postby Bullet51 » April 9th, 2017, 8:24 pm

x = 3, y = 3, rule = B2e35678_S2678
o$obo$2o!
Still drifting.
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Re: Counterfeit Gliders

Postby 83bismuth38 » April 15th, 2017, 7:21 pm

lol, glider and r-pentomino are became one:
x = 3, y = 3, rule = B3-i45-a8/S3-ai4-a5-e
obo$2o$bo!
x = 8, y = 10, rule = B3/S23
3b2o$3b2o$2b3o$4bobo$2obobobo$3bo2bo$2bobo2bo$2bo4bo$2bo4bo$2bo!

No football of any dui mauris said that.
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Re: Counterfeit Gliders

Postby Saka » April 16th, 2017, 8:12 am

83bismuth38 wrote:lol, glider and r-pentomino are became one:
x = 3, y = 3, rule = B3-i45-a8/S3-ai4-a5-e
obo$2o$bo!

Saka wrote:Sorry, but we're focusing on spaceships

Saka wrote:
x = 3, y = 3, rule = B3-nqr4acew5y6/S1e2-a34wz
3o$o$bo!
Proud owner and founder of Sakagolue
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!

(Check gen 2)
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Re: Counterfeit Gliders

Postby toroidalet » August 12th, 2017, 11:04 am

double counterfeit gliders:
x = 8, y = 3, rule = B34i/S1c2-ck3
bo5bo$o4b2o$3o3b2o!

counterfeit toad in the same rule:
x = 4, y = 4, rule = B34i/S1c2-ck3
bo$o2bo$o2bo$2bo!

(I really want someone to apgsearch this rule to see how it handles this)
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Re: Counterfeit Gliders

Postby A for awesome » August 12th, 2017, 11:55 am

toroidalet wrote:(I really want someone to apgsearch this rule to see how it handles this)

It should catch the toad and miss both gliders. Please no one search until I've fixed this.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Counterfeit Gliders

Postby toroidalet » August 12th, 2017, 12:56 pm

A for awesome wrote:It should catch the toad and miss both gliders. Please no one search until I've fixed this.

I tried apgsearching without uploading to Catagolue in V0.54+0.3i and it didn't give any fatal errors, giving an xq4_153 and an xq4_163. V0.54+0.2i also gave an xq4_153 and xq4_163. I think it's safe to run (and really fast).
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Re: Counterfeit Gliders

Postby Saka » August 16th, 2017, 4:37 am

bump
x = 3, y = 3, rule = B2-an3ijny4aejkwyz5-acjr6cik7e8/S01c2eik3nqy4aijqryz5aijy6ci78
bo$o$3o!
Proud owner and founder of Sakagolue
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!

(Check gen 2)
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Re: Counterfeit Gliders

Postby Goldtiger997 » August 17th, 2017, 9:18 am

I've been using wildmyron's recently published script to find more counterfeit gliders. So far I've found 30, and most of them have not already been posted on this thread. (I've also been using getallrules.py to optimise the rules, which is something I've noticed that the 5s project hasn't done.)

Here is what is probably the highlight of the current collection, a 3c/266d:

x = 3, y = 3, rule = B2ekn3aikn4eiqry5q6ac7e/S1c2ek3-jky4kw5acy6c7e
3o$o$bo!


And here is the current full collection:
counterfeit gliders.zip
(7.5 KiB) Downloaded 114 times
.
Things to work on:
  • Work on the snowflakes orthogonoid
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Re: Counterfeit Gliders

Postby Saka » August 17th, 2017, 9:34 am

Goldtiger997 wrote:I've been using wildmyron's recently published script to find more counterfeit gliders.


Same! I didnt get to looking for any today, I focused on making cool apgcodes, but the system keeps changing them
Proud owner and founder of Sakagolue
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!

(Check gen 2)
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Re: Counterfeit Gliders

Postby drc » August 17th, 2017, 10:30 am

Goldtiger997 wrote:which is something I've noticed that the 5s project hasn't done.

I was going to say that all gliders in the 5s project should have their rulestring shortened as much as possible, but I decided to leave them in whatever rule is most interesting/whatever rule they were found in.
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Current rule interest: B2ce3-ir4a5y/S2-c3-y
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Re: Counterfeit Gliders

Postby Saka » August 18th, 2017, 3:56 am

c/6d
x = 3, y = 3, rule = B2cek3ikr4-aeqtw5-eijk6-ck8/S02ace3ar4knw5n6e7e
obo$2o$bo!

2c/6o
x = 3, y = 3, rule = B2eik3-cjnq4eijqwy5-ijn6cei8/S01c2-c3ijnqr4inqtwyz5ajnq6-k78
bo$2bo$3o!

x = 3, y = 3, rule = B2ce3er4cejyz5jq6ain7/S01c2-ek3-eqy4-cekr5ekny6cek7c8
2bo$2o$b2o!

c/12d
x = 3, y = 3, rule = B2-an3-knq4-cqrty5-kry6-e78/S01c2-k3-aci4-kqw5ijkry6ikn78
bo$o$3o!
Proud owner and founder of Sakagolue
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!

(Check gen 2)
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Re: Counterfeit Gliders

Postby muzik » August 20th, 2017, 5:24 pm

x = 6, y = 7, rule = 23/3/4
3.C$3.ACA$2.B3A$BCA.A$ACA$B2A$.A!
waiting for apgsearch to support one-dimensional rules
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Re: Counterfeit Gliders

Postby toroidalet » August 20th, 2017, 7:08 pm

muzik wrote:
ship

I don't think that counts.
A variation of my original counterfeit LWSS rule:
x = 5, y = 4, rule = B2i34a/S23-ijn4a
bo2bo$o$o3bo$4o!
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Re: Counterfeit Gliders

Postby Rhombic » August 21st, 2017, 5:12 pm

x = 3, y = 3, rule = B2ce3aj4an/S1c2ace3aj4ak
obo$b2o$bo!

x = 3, y = 3, rule = B2ce3ijnq/S1c2e
bo$2bo$3o!
Last edited by Rhombic on August 24th, 2017, 1:19 pm, edited 3 times in total.
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Re: Counterfeit Gliders

Postby Hdjensofjfnen » August 21st, 2017, 5:13 pm

muzik wrote:
x = 6, y = 7, rule = 23/3/4
3.C$3.ACA$2.B3A$BCA.A$ACA$B2A$.A!


Counterfeit crab thingamajig?
Life is hard. Deal with it.
This is my new favorite spaceship:
x = 8, y = 4, rule = B3-ek/S023
bobo$2obo3bo$bobo$3bo!
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Re: Counterfeit Gliders

Postby A for awesome » August 23rd, 2017, 9:48 pm

A 3ITVN counterfeit glider:
x = 3, y = 3, rule = 000200-10102-1010-222-11-1
.A$A$3B!

Sadly, the rule is explosive.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Counterfeit Gliders

Postby Rhombic » August 24th, 2017, 1:19 pm

Counterfeit block on table:
x = 4, y = 5, rule = B2k3ai4iwz/S01e2aen3aer
o2bo$4o2$2b2o$2b2o!
x = 4, y = 5, rule = B2e3-kqry4knr/S1c2ae3ajnr
o2bo$4o2$2b2o$2b2o!
x = 4, y = 5, rule = B3-cknr4ijn6ik/S1c2-c3a4aqz5i6c
o2bo$4o2$2b2o$2b2o!
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Re: Counterfeit Gliders

Postby Rhombic » October 13th, 2017, 9:36 am

B2c3aijn4r5q/S2ace3nr (1,1)c/8
B2ck3aceijkn4jk5cj7c/S2ae3inr4akqrz5jn (1,1)c/32
B2k3aijn/S2ae3jnr4ak (2,0)c/8
B2ck3aijnr5c/S02e3jnr (1,1)c/8

a few more that preserve both distinct generations of the glider
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Re: Counterfeit Gliders

Postby A for awesome » November 21st, 2017, 7:07 pm

One in CGoL:
x = 53, y = 49, rule = B3/S23
13$16bobo$16bo2bo$19b2o$17bo3bo$18bob3o$24b2o$18b5o3bo$23bo3b
o$20b2o5bo$18b4o2bo2bo$18bo5bobo3bo$30b4o$25b3o3b3o$25b3o3bo3b
o$24bob2o5b3o$31bo4bobo$24bo2bo4b8o$27b2o10b2o$26bobo5b2o4b2o$
31bo2bo4b2o$29bobobo3bo$30bo7b5o$42b2o$40b2o2bo$40bob3o$45bo$
44b3o$42bo2b3o$46bo$42b4o$45bo$42b2o$40b4o$40bo!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Counterfeit Gliders

Postby LaundryPizza03 » December 15th, 2017, 1:00 am

From the "crystallographic defect rule":
x = 3, y = 3, rule = B2c3aijn4k/S2-k34cnqrt
o$b2o$2o!
x = 4, y = 3, rule = B3-q4z5y/S234k5j
2b2o$b2o$2o!

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Re: Counterfeit Gliders

Postby LaundryPizza03 » December 15th, 2017, 12:05 pm

Request a Rule to Be "Tamed":
drc wrote:Found a small c/6 diagonal in a related (stable!) rule:
x = 3, y = 3, rule = B2e3-ajqr4a/S23
b2o$obo$2bo!

[Edited for phase]
x = 4, y = 3, rule = B3-q4z5y/S234k5j
2b2o$b2o$2o!

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Re: Counterfeit Gliders

Postby Majestas32 » December 29th, 2017, 12:46 am

c/10 diagonal
x = 3, y = 3, rule = B3-r4aiw5cny/S123c4w6c
3o$o$bo!
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Re: Counterfeit Gliders

Postby LaundryPizza03 » January 3rd, 2018, 11:39 pm

From a rule apgsearched by danny, a 4c/18 diagonal:
x = 3, y = 3, rule = B2-ac3i4ce/S123ik4e
bo$2bo$3o!
x = 4, y = 3, rule = B3-q4z5y/S234k5j
2b2o$b2o$2o!

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Re: Counterfeit Gliders

Postby danny » January 3rd, 2018, 11:51 pm

LaundryPizza03 wrote:From a rule apgsearched by danny, a 4c/18 diagonal:
x = 3, y = 3, rule = B2-ac3i4ce/S123ik4e
bo$2bo$3o!

This glider was known here. I think it may have been posted here too
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Re: Counterfeit Gliders

Postby BlinkerSpawn » January 4th, 2018, 8:27 pm

danny wrote:
LaundryPizza03 wrote:From a rule apgsearched by danny, a 4c/18 diagonal:
x = 3, y = 3, rule = B2-ac3i4ce/S123ik4e
bo$2bo$3o!

This glider was known here. I think it may have been posted here too

I haven't seen it here, and it's just being cross-posted here for recordkeeping purposes.
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