## Outrunning the Glider

For discussion of other cellular automata.

### Outrunning the Glider

Post any diagonal spaceships (EDIT: preferably in non-B0 rules) that can outrun the glider (c/4) below!
For starters:
2c/7d, one transition from Life: (EDIT: Shown with glider)
`x = 11, y = 11, rule = B3/S234w9bo\$10bo\$8b3o4\$bo2bo\$o3bo\$4bo\$3bo\$3o!`

c/3d, a lot of transitions from Life:
`x = 3, y = 3, rule = B2e3-j4a/S2-k3-ry4q5iobo\$2bo\$3o!`
Last edited by Hdjensofjfnen on February 6th, 2019, 8:48 pm, edited 1 time in total.
Life is hard. Deal with it.
My favorite oscillator of all time:
`x = 7, y = 5, rule = B3/S2-i3-y4i4b3o\$6bo\$o3b3o\$2o\$bo!`

Hdjensofjfnen

Posts: 1093
Joined: March 15th, 2016, 6:41 pm
Location: r cis θ

### Re: Outrunning the Glider

This rule also has a c/3d: viewtopic.php?f=11&t=3194&p=54127#p54076
Bored of using the Moore neighbourhood for everything? Introducing the Range-2 von Neumann isotropic non-totalistic rulespace!
muzik

Posts: 3301
Joined: January 28th, 2016, 2:47 pm
Location: Scotland

### Re: Outrunning the Glider

Here's an alternating rule that has a c/2 that I call "Slider":
`@RULE B26S2B358S3@TABLEn_states:3neighborhood:Mooresymmetries:permute#B26S20,1,1,0,0,0,0,0,0,20,1,1,1,1,1,1,0,0,21,0,0,0,0,0,0,0,0,01,1,0,0,0,0,0,0,0,01,1,1,0,0,0,0,0,0,21,1,1,1,0,0,0,0,0,01,1,1,1,1,0,0,0,0,01,1,1,1,1,1,0,0,0,01,1,1,1,1,1,1,0,0,01,1,1,1,1,1,1,1,0,01,1,1,1,1,1,1,1,1,0#B358S30,2,2,2,0,0,0,0,0,10,2,2,2,2,2,0,0,0,10,2,2,2,2,2,2,2,2,12,0,0,0,0,0,0,0,0,02,2,0,0,0,0,0,0,0,02,2,2,0,0,0,0,0,0,02,2,2,2,0,0,0,0,0,12,2,2,2,2,0,0,0,0,02,2,2,2,2,2,0,0,0,02,2,2,2,2,2,2,0,0,02,2,2,2,2,2,2,2,0,02,2,2,2,2,2,2,2,2,0`

And here's the ship itself:
`x = 3, y = 3, rule = B26S2B358S3A.A\$A\$.2A!`
`x = 3, y = 3, rule = B26/S2|B358/S32o\$2bo\$obo!`
PkmnQ

Posts: 449
Joined: September 24th, 2018, 6:35 am
Location: Server antipode

### Re: Outrunning the Glider

There was some discussion about the fastest possible diagonal spaceship speeds in 2-state rules on the Moore nighbourhood, both with and without B0, some time ago but I can't remember which thread it was in. For non-totalistic rules, the limit is c:
`x = 1, y = 1, rule = MAPQAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAo!`

For isotropic rules with B0, the limit is 3c/4. Here's a small one which moves at that speed
`x = 3, y = 2, rule = B02akn3n4ak5ak6a/S01e2k4r5a6e7e2bo\$2o!`

There's a nice collection of low period diagonal ships in rules with B0 here, many of which are faster than c/4.

In isotropic rules without B0, the limit is c/2:
`x = 3, y = 4, rule = B2ac/S12bo2\$b2o\$o!`

There are example c/2 ships with many different periods in the 5S diagonal collection. You'll also find example ships for all speeds k/P c for P/4 < k <= P/2, where P < 20 as well as many more for P > 20.

In my collections of small spaceships I have over a hundred such ships which have a minimum population of 3 cells, and there would be far more if I hadn't filtered low period ships out of most of those searches.

Now, if you restrict the rulespace to isotropic rules in which the CGoL glider works, then I suspect the speed limit is c/3, but that's just a guess on my part. Here's a 2c/7 ship racing a glider.
`x = 9, y = 7, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6e7b2o\$6b2o\$6bo2\$2bo\$obo\$b2o!`

If you'd like to find more ships like this, then logic life search is your friend.
`./lls -r pB2-ace3aijn4-r5-n678/S02ae3jnr4-k5678 -b 7 -p 7 -x 2 -y 2 -i -s 'D2\'`

is the command I used to find the 2c/7 above.

==========

Here are a few of the ships from the 5S collection:

c/2, period 4
`x = 3, y = 3, rule = B2-ei3aq4ik5ceq/S02aei3acjn4aijny5ejkn6ein7eo\$b2o\$bo!`

2c/5, period 2
`x = 3, y = 3, rule = B2aci3a4ny5a/S03i4ajw5a7c2bo2\$obo!`

c/2, period 6
`x = 3, y = 3, rule = B2ac3a/S02-ik3ao\$b2o\$bo!`

c/3, period 6
`x = 3, y = 3, rule = B2cik3a4qt5kny6n/S01e2k3ejkn4ktw5ek6n2bo2\$obo!`

3c/7, period 7
`x = 3, y = 3, rule = B2-en3ak4iw5acr/S02ek3aiy5ck2bo2\$obo!`

c/2, period 8
`x = 3, y = 4, rule = B2acn3y4e/S12-ei3c4ey2bo2\$b2o\$o!`

3c/8, period 8
`x = 3, y = 3, rule = B2-ek3ae4r5a/S01e3j4e5ack2bo2\$obo!`
The latest version of the 5S Project contains over 57,000 spaceships. Tabulated pages up to period 160 are available on the LifeWiki.
wildmyron

Posts: 1119
Joined: August 9th, 2013, 12:45 am

### Re: Outrunning the Glider

wildmyron wrote:Now, if you restrict the rulespace to isotropic rules in which the CGoL glider works, then I suspect the speed limit is c/3, but that's just a guess on my part. Here's a 2c/7 ship racing a glider.
`x = 9, y = 7, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6e7b2o\$6b2o\$6bo2\$2bo\$obo\$b2o!`

Surprisingly, this rule also has a third tiny diagonal spaceship - but this one has a speed of c/19:
`x = 3, y = 3, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6eobo\$2bo\$3o!`

EDIT: And there's a small 3c/17 diagonal too!
`x = 5, y = 5, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6eo\$3bo\$2b2o\$b2obo\$3b2o!`

77topaz

Posts: 1345
Joined: January 12th, 2018, 9:19 pm

### Re: Outrunning the Glider

Wow... that's a lot of spaceships
'sup.

cvojan

Posts: 130
Joined: October 7th, 2018, 7:07 pm

### Re: Outrunning the Glider

I have these two hexagonal generations spaceships:
`x = 134, y = 132, rule = 0/2/256H5.2A\$4.AB2C\$5.BD2E\$2A4.DF2G\$A2C4.FH2I\$.C2E4.HJ2K\$2.E2G4.JL2M\$3.G2I4.LN2O\$4.I2K4.NP2Q\$5.K2M4.PR2S\$6.M2O4.RT2U\$7.O2Q4.TV2W\$8.Q2S4.VX2pA\$9.S2U4.XpB2pC\$10.U2W4.pBpD2pE\$11.W2pA4.pDpF2pG\$12.pA2pC4.pFpH2pI\$13.pC2pE4.pHpJ2pK\$14.pE2pG4.pJpL2pM\$15.pG2pI4.pLpN2pO\$16.pI2pK4.pNpP2pQ\$17.pK2pM4.pPpR2pS\$18.pM2pO4.pRpT2pU\$19.pO2pQ4.pTpV2pW\$20.pQ2pS4.pVpX2qA\$21.pS2pU4.pXqB2qC\$22.pU2pW4.qBqD2qE\$23.pW2qA4.qDqF2qG\$24.qA2qC4.qFqH2qI\$25.qC2qE4.qHqJ2qK\$26.qE2qG4.qJqL2qM\$27.qG2qI4.qLqN2qO\$28.qI2qK4.qNqP2qQ\$29.qK2qM4.qPqR2qS\$30.qM2qO4.qRqT2qU\$31.qO2qQ4.qTqV2qW\$32.qQ2qS4.qVqX2rA\$33.qS2qU4.qXrB2rC\$34.qU2qW4.rBrD2rE\$35.qW2rA4.rDrF2rG\$36.rA2rC4.rFrH2rI\$37.rC2rE4.rHrJ2rK\$38.rE2rG4.rJrL2rM\$39.rG2rI4.rLrN2rO\$40.rI2rK4.rNrP2rQ\$41.rK2rM4.rPrR2rS\$42.rM2rO4.rRrT2rU\$43.rO2rQ4.rTrV2rW\$44.rQ2rS4.rVrX2sA\$45.rS2rU4.rXsB2sC\$46.rU2rW4.sBsD2sE\$47.rW2sA4.sDsF2sG\$48.sA2sC4.sFsH2sI\$49.sC2sE4.sHsJ2sK\$50.sE2sG4.sJsL2sM\$51.sG2sI4.sLsN2sO\$52.sI2sK4.sNsP2sQ\$53.sK2sM4.sPsR2sS\$54.sM2sO4.sRsT2sU\$55.sO2sQ4.sTsV2sW\$56.sQ2sS4.sVsX2tA\$57.sS2sU4.sXtB2tC\$58.sU2sW4.tBtD2tE\$59.sW2tA4.tDtF2tG\$60.tA2tC4.tFtH2tI\$61.tC2tE4.tHtJ2tK\$62.tE2tG4.tJtL2tM\$63.tG2tI4.tLtN2tO\$64.tI2tK4.tNtP2tQ\$65.tK2tM4.tPtR2tS\$66.tM2tO4.tRtT2tU\$67.tO2tQ4.tTtV2tW\$68.tQ2tS4.tVtX2uA\$69.tS2tU4.tXuB2uC\$70.tU2tW4.uBuD2uE\$71.tW2uA4.uDuF2uG\$72.uA2uC4.uFuH2uI\$73.uC2uE4.uHuJ2uK\$74.uE2uG4.uJuL2uM\$75.uG2uI4.uLuN2uO\$76.uI2uK4.uNuP2uQ\$77.uK2uM4.uPuR2uS\$78.uM2uO4.uRuT2uU\$79.uO2uQ4.uTuV2uW\$80.uQ2uS4.uVuX2vA\$81.uS2uU4.uXvB2vC\$82.uU2uW4.vBvD2vE\$83.uW2vA4.vDvF2vG\$84.vA2vC4.vFvH2vI\$85.vC2vE4.vHvJ2vK\$86.vE2vG4.vJvL2vM\$87.vG2vI4.vLvN2vO\$88.vI2vK4.vNvP2vQ\$89.vK2vM4.vPvR2vS\$90.vM2vO4.vRvT2vU\$91.vO2vQ4.vTvV2vW\$92.vQ2vS4.vVvX2wA\$93.vS2vU4.vXwB2wC\$94.vU2vW4.wBwD2wE\$95.vW2wA4.wDwF2wG\$96.wA2wC4.wFwH2wI\$97.wC2wE4.wHwJ2wK\$98.wE2wG4.wJwL2wM\$99.wG2wI4.wLwN2wO\$100.wIwKwJ4.wNwP2wQ\$101.wK2wL4.wPwR2wS\$102.wL2wN4.wRwT2wU\$103.wN2wP4.wTwV2wW\$104.wP2wR4.wVwX2xA\$105.wR2wT4.wXxB2xC\$106.wT2wV4.xBxD2xE\$107.wV2wX4.xDxF2xG\$108.wX2xB4.xFxH2xI\$109.xB2xD4.xHxJ2xK\$110.xD2xF4.xJxL2xM\$111.xF2xH4.xLxN2xO\$112.xH2xJ4.xNxP2xQ\$113.xJ2xL4.xPxR2xS\$114.xL2xN4.xRxT2xU\$115.xN2xP4.xTxV2xW\$116.xP2xR4.xVxX2yA\$117.xR2xT4.xXyB2yC\$118.xT2xV4.yByD2yE\$119.xV2xX4.yDyF2yG\$120.xX2yB4.yFyH2yI\$121.yB2yD4.yHyJ2yK\$122.yD2yF4.yJyL2yM\$123.yF2yH4.yLyN2yO\$124.yH2yJ4.yN\$125.yJ2yL\$126.yL2yN\$127.yN!`
Sorry, some of my rules before April 20 2019 have Unicode characters that are not compatible with Golly; you will have to remove them when pasting them in your text editor.

Βεν Γ. Κυθισ

Posts: 207
Joined: December 27th, 2018, 5:42 am

### Re: Outrunning the Glider

A glider that outruns the glider (2c/7):

`x = 3, y = 3, rule = B2ce3aijkn4w5i7e/S1c2cei3aj4ainq5ry6cbo\$2bo\$3o!`
AlephAlpha

Posts: 30
Joined: October 6th, 2017, 1:50 am

### Re: Outrunning the Glider

Hello, AlephAlpha!

I will probably try to search some fast diagonal ship in RSS(Really Small Spaceship) project, or #76 at GitHub [s]Also known as "Manual LLS"[/s].
This post was brought to you by the Element of Magic.

Plz correct my grammar mistakes. I'm still studying English.

Working on:

Nothing.

Favorite gun ever:
`#C Favorite Gun. Found by me.x = 4, y = 6, rule = B2e3i4at/S1c23cijn4ao2bo\$4o3\$4o\$o2bo!`
Hunting

Posts: 1058
Joined: September 11th, 2017, 2:54 am
Location: Ponyville, Equestria

### Re: Outrunning the Glider

Restricting to the rules that the original glider works:

4c/15:
`x = 13, y = 13, rule = B2in3-eqy4ijkqw5cikq6aik/S02-ck3-aeky4inqtwy5nqry6an7e811bo\$12bo\$10b3o8\$b2o\$obo\$3o!`

3c/11:
`x = 13, y = 13, rule = B2ik3aijn4iqw5cky6c7c/S02-ci3-ciqy4ir5acq6k7c11bo\$12bo\$10b3o8\$2bo\$b2o\$3o!`

2c/7:
`x = 13, y = 13, rule = B3-ckqy4k/S02ae3ijknr4iw5any6n711bo\$12bo\$10b3o8\$b2o\$obo\$3o!`

3c/10:
`x = 13, y = 13, rule = B3-ekqy4aqy5i6e7c8/S02ae3ajnr4cqrw5cknq6cn11bo\$12bo\$10b3o8\$obo\$2bo\$3o!`

4c/13:

`x = 13, y = 13, rule = B2kn3-ekqy4jt5c/S02ae3-ckqy4jqw5aik7e11bo\$12bo\$10b3o8\$b2o\$3o\$3o!`

c/3:
`x = 13, y = 13, rule = B3aijnr4k7c/S2ae3jnr4i5a7c11bo\$12bo\$10b3o8\$b2o\$obo\$3o!`
Last edited by AlephAlpha on February 26th, 2019, 10:06 am, edited 1 time in total.
AlephAlpha

Posts: 30
Joined: October 6th, 2017, 1:50 am

### Re: Outrunning the Glider

AlephAlpha wrote:2c/7:
`x = 13, y = 13, rule = B3-ckqy4k/S02ae3ijknr4iw5any6n711bo\$12bo\$10b3o8\$2bo\$b2o\$3o!`

Hey, I think you posted the wrong pattern. The "2c/7d" is an oscillator.
This post was brought to you by the Element of Magic.

Plz correct my grammar mistakes. I'm still studying English.

Working on:

Nothing.

Favorite gun ever:
`#C Favorite Gun. Found by me.x = 4, y = 6, rule = B2e3i4at/S1c23cijn4ao2bo\$4o3\$4o\$o2bo!`
Hunting

Posts: 1058
Joined: September 11th, 2017, 2:54 am
Location: Ponyville, Equestria

### Re: Outrunning the Glider

AlephAlpha wrote:Restricting to the rules that the original glider works:

Nice work. There's a 2c/7 in a glider compatible rule in my post above ^. Here are some other speeds:

5c/16d
`x = 13, y = 13, rule = B2k3aijn4qt5acjk6-ae7c/S23ajnqr4acijrt5-cenr6-a7e12bo\$10bobo\$11b2o8\$2bo\$2bo\$3o!`

5c/17d
`x = 13, y = 13, rule = B2i3aijnr4eknqy5aceq6-k78/S02ae3-ceq4inrtwy5-enqy6-kn7e12bo\$10bobo\$11b2o8\$2bo\$b2o\$3o!`

5c/18d
`x = 13, y = 13, rule = B2kn3-cekr4eijnqt5-ckn6ci7c/S2-k3-eky4nrwyz5aei6cen7812bo\$10bobo\$11b2o8\$2bo\$b2o\$3o!`

5c/19d
`x = 13, y = 13, rule = B2i3-kq4ckntyz5cejk6ck7c/S02aen3jnry4cinqwz5-ey6an7812bo\$10bobo\$11b2o8\$b2o\$obo\$3o!`

6c/19d
`x = 13, y = 13, rule = B2k3-cery4ikyz5ikqry6cek7c8/S02aek3-ci4ceinwz5iknr812bo\$10bobo\$11b2o8\$b2o\$3o\$3o!`
Last edited by wildmyron on February 26th, 2019, 10:41 am, edited 2 times in total.
The latest version of the 5S Project contains over 57,000 spaceships. Tabulated pages up to period 160 are available on the LifeWiki.
wildmyron

Posts: 1119
Joined: August 9th, 2013, 12:45 am

### Re: Outrunning the Glider

Hunting wrote:
AlephAlpha wrote:2c/7:
`x = 13, y = 13, rule = B3-ckqy4k/S02ae3ijknr4iw5any6n711bo\$12bo\$10b3o8\$2bo\$b2o\$3o!`

Hey, I think you posted the wrong pattern. The "2c/7d" is an oscillator.

Sorry. Edited.
AlephAlpha

Posts: 30
Joined: October 6th, 2017, 1:50 am

### Re: Outrunning the Glider

Some more:

c/3d, p18
`x = 13, y = 13, rule = B2n3-kqr4-eijry5aciky6-ai7e8/S2-c3-eky4ejryz5aceir6kn7c812bo\$10bobo\$11b2o8\$obo\$b2o\$3o!`

3c/10, p20
`x = 13, y = 13, rule = B3aijn4-aeirt5eqry6ace7e8/S2aek3-cky4eirwyz5-ckry6cn7c12bo\$10bobo\$11b2o8\$2bo\$b2o\$3o!`

2c/7d, p21
`x = 13, y = 13, rule = B2in3-eqy4cejwz5-jnr6-en7c8/S02-cn3-aey4cirtyz5aijky6-k812bo\$10bobo\$11b2o8\$b2o\$obo\$3o!`

3c/11d, p22
`x = 13, y = 13, rule = B2ikn3-q4aejtyz5acer67e/S02-ik3-aeiy4ejnqtz5aejqy6-k812bo\$10bobo\$11b2o8\$obo\$2bo\$3o!`

7c/22d
`x = 13, y = 13, rule = B2kn3-e4ceknqy5-ekny6-ac7c/S02-c3cjnr4einyz5-eikn6eik7812bo\$10bobo\$11b2o8\$b2o\$obo\$3o!`

6c/23d
`x = 13, y = 13, rule = B3-qr4-aqryz5cry6-cn8/S02-n3-ai4ceijntz5-cejn6-en7e812bo\$10bobo\$11b2o8\$obo\$2bo\$3o!`

7c/23d
`x = 13, y = 13, rule = B2i3-ceqr4-krwy5ciqr6-i7c8/S2-c3-ekqy4iqrtw5aikq6kn7c812bo\$10bobo\$11b2o8\$b2o\$3o\$3o!`

These were all found with LLS. The shapes are mostly a function of the boundary conditions set up by the search. You can improve the search behaviour by using the make_lls_grid.py script. I used it for the 7c/22 and 7c/23 ships. As a bonus this reduces the search space and therefore improves the search speed considerably. Here's the command I used to find the 7c/23:
`./make_lls_grid.py -p 23 -x 7 -y 7 -f 3 3 5 5 | ./lls -r pB2-ace3aijn4-r5-n678/S02ae3jnr4-k5678 -i -s 'D2\'`

This took about 15 seconds to run, most of which was in preprocessing.
The latest version of the 5S Project contains over 57,000 spaceships. Tabulated pages up to period 160 are available on the LifeWiki.
wildmyron

Posts: 1119
Joined: August 9th, 2013, 12:45 am

### Re: Outrunning the Glider

Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?
Life is hard. Deal with it.
My favorite oscillator of all time:
`x = 7, y = 5, rule = B3/S2-i3-y4i4b3o\$6bo\$o3b3o\$2o\$bo!`

Hdjensofjfnen

Posts: 1093
Joined: March 15th, 2016, 6:41 pm
Location: r cis θ

### Re: Outrunning the Glider

Hdjensofjfnen wrote:Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?

It kind of already is known. In a non-B2a or B1e rule, the max diagonal speed is C/3. Therefore, there is no faster one in a rule with the glider.
Things to work on:
- Find a (7,1)c/8 ship in a Non-totalistic rule (someone please search the rules)
- Find a C/10 in JustFriends
- Find a C/10 in Day and Night
AforAmpere

Posts: 1003
Joined: July 1st, 2016, 3:58 pm

### Re: Outrunning the Glider

AforAmpere wrote:
Hdjensofjfnen wrote:Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?

It kind of already is known. In a non-B2a or B1e rule, the max diagonal speed is C/3. Therefore, there is no faster one in a rule with the glider.

Oh. In that case, time to find every single possible speed between c/3 and c/4 with the CGOL glider.
Life is hard. Deal with it.
My favorite oscillator of all time:
`x = 7, y = 5, rule = B3/S2-i3-y4i4b3o\$6bo\$o3b3o\$2o\$bo!`

Hdjensofjfnen

Posts: 1093
Joined: March 15th, 2016, 6:41 pm
Location: r cis θ

### Re: Outrunning the Glider

Hdjensofjfnen wrote:
AforAmpere wrote:
Hdjensofjfnen wrote:Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?

It kind of already is known. In a non-B2a or B1e rule, the max diagonal speed is C/3. Therefore, there is no faster one in a rule with the glider.

Oh. In that case, time to find every single possible speed between c/3 and c/4 with the CGOL glider.

That's also impossible (at least for small ships) because there are infinite rational numbers between any two different rational numbers.
My rules:
They can be found here

Also, the tree game
Bill Watterson once wrote: "How do soldiers killing each other solve the world's problems?"

Moosey

Posts: 1546
Joined: January 27th, 2019, 5:54 pm
Location: A house, or perhaps the OCA board.

### Re: Outrunning the Glider

Moosey wrote:That's also impossible (at least for small ships) because there are infinite rational numbers between any two different rational numbers.

However, there are a finite number of rules with the glider, and if there aren't fast diagonal adjustable ships with the glider, there may only be finitely many speeds.
Things to work on:
- Find a (7,1)c/8 ship in a Non-totalistic rule (someone please search the rules)
- Find a C/10 in JustFriends
- Find a C/10 in Day and Night
AforAmpere

Posts: 1003
Joined: July 1st, 2016, 3:58 pm

### Re: Outrunning the Glider

AforAmpere wrote:
Moosey wrote:That's also impossible (at least for small ships) because there are infinite rational numbers between any two different rational numbers.

However, there are a finite number of rules with the glider, and if there aren't fast diagonal adjustable ships with the glider, there may only be finitely many speeds.

If you limit the bounding box, the max period is less than or equal to 2^(number of cells in the bounding box).
`x = 81, y = 96, rule = LifeHistory58.2A\$58.2A3\$59.2A17.2A\$59.2A17.2A3\$79.2A\$79.2A2\$57.A\$56.A\$56.3A4\$27.A\$27.A.A\$27.2A21\$3.2A\$3.2A2.2A\$7.2A18\$7.2A\$7.2A2.2A\$11.2A11\$2A\$2A2.2A\$4.2A18\$4.2A\$4.2A2.2A\$8.2A!`
Gamedziner

Posts: 724
Joined: May 30th, 2016, 8:47 pm
Location: Milky Way Galaxy: Planet Earth

### Re: Outrunning the Glider

This is Entity Valkyrie 2.

c/3:

`x = 5, y = 5, rule = B2e3-cjnr/S2aei3b2o\$obo\$3o\$4bo\$3bo!`
Last edited by Entity Valkyrie 2 on February 27th, 2019, 12:27 am, edited 1 time in total.
Take Very Tinily.
The ENEERG-y of the EVAD is watching.

`x = 47, y = 23, rule = B3/S23obo41bo\$b2o41bobo\$bo42b2o8\$10bobo21bo\$11b2o21bobo\$11bo22b2o7\$22b2o\$20bo\$21bo3bo\$21b4o!#C [[ THEME 6 THUMBSIZE 2 Y 10 ZOOM 32 GPS 20 AUTOSTART LOOP 40 ]]`

Entity Valkyrie 2

Posts: 17
Joined: February 26th, 2019, 7:13 pm

### Re: Outrunning the Glider

Entity Valkyrie 2 wrote:This is Entity Valkyrie 2.

c/3:

`x = 5, y = 5, rule = B2e3-cnr/S2aei3b2o\$obo\$3o\$4bo\$3bo!`

No, it becomes ash instantly,
Sorry, some of my rules before April 20 2019 have Unicode characters that are not compatible with Golly; you will have to remove them when pasting them in your text editor.

Βεν Γ. Κυθισ

Posts: 207
Joined: December 27th, 2018, 5:42 am

### Re: Outrunning the Glider

Βεν Γ. Κυθισ wrote:
Entity Valkyrie 2 wrote:This is Entity Valkyrie 2.

c/3:

`x = 5, y = 5, rule = B2e3-cnr/S2aei3b2o\$obo\$3o\$4bo\$3bo!`

No, it becomes ash instantly,

I forgot the "j" in B2e3-cjnr/S2aei3! Fixed.

`x = 5, y = 5, rule = B2e3-cjnr/S2aei3b2o\$obo\$3o\$4bo\$3bo!`
Take Very Tinily.
The ENEERG-y of the EVAD is watching.

`x = 47, y = 23, rule = B3/S23obo41bo\$b2o41bobo\$bo42b2o8\$10bobo21bo\$11b2o21bobo\$11bo22b2o7\$22b2o\$20bo\$21bo3bo\$21b4o!#C [[ THEME 6 THUMBSIZE 2 Y 10 ZOOM 32 GPS 20 AUTOSTART LOOP 40 ]]`

Entity Valkyrie 2

Posts: 17
Joined: February 26th, 2019, 7:13 pm

### Re: Outrunning the Glider

AlephAlpha wrote:3c/11:
`x = 13, y = 13, rule = B2ik3aijn4iqw5cky6c7c/S02-ci3-ciqy4ir5acq6k7c11bo\$12bo\$10b3o8\$2bo\$b2o\$3o!`

This rule also has a small 2c/8 orthogonal:
`x = 2, y = 6, rule = B2ik3aijn4iqw5cky6c7c/S02-ci3-ciqy4ir5acq6k7c2o\$2o2\$bo2\$bo!`

Unfortunately, it is explosive.

77topaz

Posts: 1345
Joined: January 12th, 2018, 9:19 pm

### Re: Outrunning the Glider

`x = 4, y = 5, rule = B3ai4a/S2e34aeiwz5iqr6abo\$3o\$2bo\$2b2o\$3bo!`

rule that's golfed to have a small explosive seed, modified a bit giving this c/3d with population going 8-9-10
c(>^w^<c)~*
This is Fluffy the cat.
Fluffy wants to discover new things that everyone likes.
Fluffy likes to watch spaceship guns in Golly.
Fluffy knows Natsuki best girl.

Redstoneboi

Posts: 335
Joined: May 14th, 2018, 3:57 am