Outrunning the Glider

For discussion of other cellular automata.
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Hdjensofjfnen
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Outrunning the Glider

Post by Hdjensofjfnen » February 6th, 2019, 8:45 pm

Post any diagonal spaceships (EDIT: preferably in non-B0 rules) that can outrun the glider (c/4) below!
For starters:
2c/7d, one transition from Life: (EDIT: Shown with glider)

Code: Select all

x = 11, y = 11, rule = B3/S234w
9bo$10bo$8b3o4$bo2bo$o3bo$4bo$3bo$3o!
c/3d, a lot of transitions from Life:

Code: Select all

x = 3, y = 3, rule = B2e3-j4a/S2-k3-ry4q5i
obo$2bo$3o!
Last edited by Hdjensofjfnen on February 6th, 2019, 8:48 pm, edited 1 time in total.

Code: Select all

x = 5, y = 9, rule = B3-jqr/S01c2-in3
3bo$4bo$o2bo$2o2$2o$o2bo$4bo$3bo!

Code: Select all

x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!

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muzik
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Re: Outrunning the Glider

Post by muzik » February 6th, 2019, 8:47 pm

This rule also has a c/3d: viewtopic.php?f=11&t=3194&p=54127#p54076

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PkmnQ
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Re: Outrunning the Glider

Post by PkmnQ » February 7th, 2019, 1:00 am

Here's an alternating rule that has a c/2 that I call "Slider":

Code: Select all

@RULE B26S2B358S3

@TABLE
n_states:3
neighborhood:Moore
symmetries:permute

#B26S2
0,1,1,0,0,0,0,0,0,2
0,1,1,1,1,1,1,0,0,2
1,0,0,0,0,0,0,0,0,0
1,1,0,0,0,0,0,0,0,0
1,1,1,0,0,0,0,0,0,2
1,1,1,1,0,0,0,0,0,0
1,1,1,1,1,0,0,0,0,0
1,1,1,1,1,1,0,0,0,0
1,1,1,1,1,1,1,0,0,0
1,1,1,1,1,1,1,1,0,0
1,1,1,1,1,1,1,1,1,0

#B358S3
0,2,2,2,0,0,0,0,0,1
0,2,2,2,2,2,0,0,0,1
0,2,2,2,2,2,2,2,2,1
2,0,0,0,0,0,0,0,0,0
2,2,0,0,0,0,0,0,0,0
2,2,2,0,0,0,0,0,0,0
2,2,2,2,0,0,0,0,0,1
2,2,2,2,2,0,0,0,0,0
2,2,2,2,2,2,0,0,0,0
2,2,2,2,2,2,2,0,0,0
2,2,2,2,2,2,2,2,0,0
2,2,2,2,2,2,2,2,2,0
And here's the ship itself:

Code: Select all

x = 3, y = 3, rule = B26S2B358S3
A.A$A$.2A!

wildmyron
Posts: 1544
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Location: Western Australia

Re: Outrunning the Glider

Post by wildmyron » February 7th, 2019, 5:12 am

There was some discussion about the fastest possible diagonal spaceship speeds in 2-state rules on the Moore nighbourhood, both with and without B0, some time ago but I can't remember which thread it was in. For non-totalistic rules, the limit is c:

Code: Select all

x = 1, y = 1, rule = MAPQAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
o!
For isotropic rules with B0, the limit is 3c/4. Here's a small one which moves at that speed

Code: Select all

x = 3, y = 2, rule = B02akn3n4ak5ak6a/S01e2k4r5a6e7e
2bo$2o!
There's a nice collection of low period diagonal ships in rules with B0 here, many of which are faster than c/4.

In isotropic rules without B0, the limit is c/2:

Code: Select all

x = 3, y = 4, rule = B2ac/S1
2bo2$b2o$o!
There are example c/2 ships with many different periods in the 5S diagonal collection. You'll also find example ships for all speeds k/P c for P/4 < k <= P/2, where P < 20 as well as many more for P > 20.

In my collections of small spaceships I have over a hundred such ships which have a minimum population of 3 cells, and there would be far more if I hadn't filtered low period ships out of most of those searches.

Now, if you restrict the rulespace to isotropic rules in which the CGoL glider works, then I suspect the speed limit is c/3, but that's just a guess on my part. Here's a 2c/7 ship racing a glider.

Code: Select all

x = 9, y = 7, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6e
7b2o$6b2o$6bo2$2bo$obo$b2o!
If you'd like to find more ships like this, then logic life search is your friend.

Code: Select all

./lls -r pB2-ace3aijn4-r5-n678/S02ae3jnr4-k5678 -b 7 -p 7 -x 2 -y 2 -i -s 'D2\'
is the command I used to find the 2c/7 above.

==========

Here are a few of the ships from the 5S collection:

c/2, period 4

Code: Select all

x = 3, y = 3, rule = B2-ei3aq4ik5ceq/S02aei3acjn4aijny5ejkn6ein7e
o$b2o$bo!
2c/5, period 2

Code: Select all

x = 3, y = 3, rule = B2aci3a4ny5a/S03i4ajw5a7c
2bo2$obo!
c/2, period 6

Code: Select all

x = 3, y = 3, rule = B2ac3a/S02-ik3a
o$b2o$bo!
c/3, period 6

Code: Select all

x = 3, y = 3, rule = B2cik3a4qt5kny6n/S01e2k3ejkn4ktw5ek6n
2bo2$obo!
3c/7, period 7

Code: Select all

x = 3, y = 3, rule = B2-en3ak4iw5acr/S02ek3aiy5ck
2bo2$obo!
c/2, period 8

Code: Select all

x = 3, y = 4, rule = B2acn3y4e/S12-ei3c4ey
2bo2$b2o$o!
3c/8, period 8

Code: Select all

x = 3, y = 3, rule = B2-ek3ae4r5a/S01e3j4e5ack
2bo2$obo!
The 5S project (Smallest Spaceships Supporting Specific Speeds) is now maintained by AforAmpere. The latest collection is hosted on GitHub and contains well over 1,000,000 spaceships.

Semi-active here - recovering from a severe case of LWTDS.

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77topaz
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Re: Outrunning the Glider

Post by 77topaz » February 7th, 2019, 5:33 am

wildmyron wrote:Now, if you restrict the rulespace to isotropic rules in which the CGoL glider works, then I suspect the speed limit is c/3, but that's just a guess on my part. Here's a 2c/7 ship racing a glider.

Code: Select all

x = 9, y = 7, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6e
7b2o$6b2o$6bo2$2bo$obo$b2o!
Surprisingly, this rule also has a third tiny diagonal spaceship - but this one has a speed of c/19:

Code: Select all

x = 3, y = 3, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6e
obo$2bo$3o!
EDIT: And there's a small 3c/17 diagonal too! :o

Code: Select all

x = 5, y = 5, rule = B3-r4k5jy6e7c/S02-ci3ajnqr4arw5ak6e
o$3bo$2b2o$b2obo$3b2o!

cvojan
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Re: Outrunning the Glider

Post by cvojan » February 7th, 2019, 9:04 pm

Wow... that's a lot of spaceships

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Βεν Γ. Κυθισ
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Re: Outrunning the Glider

Post by Βεν Γ. Κυθισ » February 26th, 2019, 4:07 am

I have these two hexagonal generations spaceships:

Code: Select all

x = 134, y = 132, rule = 0/2/256H
5.2A$4.AB2C$5.BD2E$2A4.DF2G$A2C4.FH2I$.C2E4.HJ2K$2.E2G4.JL2M$3.G2I4.L
N2O$4.I2K4.NP2Q$5.K2M4.PR2S$6.M2O4.RT2U$7.O2Q4.TV2W$8.Q2S4.VX2pA$9.S
2U4.XpB2pC$10.U2W4.pBpD2pE$11.W2pA4.pDpF2pG$12.pA2pC4.pFpH2pI$13.pC2pE
4.pHpJ2pK$14.pE2pG4.pJpL2pM$15.pG2pI4.pLpN2pO$16.pI2pK4.pNpP2pQ$17.pK
2pM4.pPpR2pS$18.pM2pO4.pRpT2pU$19.pO2pQ4.pTpV2pW$20.pQ2pS4.pVpX2qA$
21.pS2pU4.pXqB2qC$22.pU2pW4.qBqD2qE$23.pW2qA4.qDqF2qG$24.qA2qC4.qFqH
2qI$25.qC2qE4.qHqJ2qK$26.qE2qG4.qJqL2qM$27.qG2qI4.qLqN2qO$28.qI2qK4.qN
qP2qQ$29.qK2qM4.qPqR2qS$30.qM2qO4.qRqT2qU$31.qO2qQ4.qTqV2qW$32.qQ2qS
4.qVqX2rA$33.qS2qU4.qXrB2rC$34.qU2qW4.rBrD2rE$35.qW2rA4.rDrF2rG$36.rA
2rC4.rFrH2rI$37.rC2rE4.rHrJ2rK$38.rE2rG4.rJrL2rM$39.rG2rI4.rLrN2rO$
40.rI2rK4.rNrP2rQ$41.rK2rM4.rPrR2rS$42.rM2rO4.rRrT2rU$43.rO2rQ4.rTrV
2rW$44.rQ2rS4.rVrX2sA$45.rS2rU4.rXsB2sC$46.rU2rW4.sBsD2sE$47.rW2sA4.sD
sF2sG$48.sA2sC4.sFsH2sI$49.sC2sE4.sHsJ2sK$50.sE2sG4.sJsL2sM$51.sG2sI
4.sLsN2sO$52.sI2sK4.sNsP2sQ$53.sK2sM4.sPsR2sS$54.sM2sO4.sRsT2sU$55.sO
2sQ4.sTsV2sW$56.sQ2sS4.sVsX2tA$57.sS2sU4.sXtB2tC$58.sU2sW4.tBtD2tE$
59.sW2tA4.tDtF2tG$60.tA2tC4.tFtH2tI$61.tC2tE4.tHtJ2tK$62.tE2tG4.tJtL
2tM$63.tG2tI4.tLtN2tO$64.tI2tK4.tNtP2tQ$65.tK2tM4.tPtR2tS$66.tM2tO4.tR
tT2tU$67.tO2tQ4.tTtV2tW$68.tQ2tS4.tVtX2uA$69.tS2tU4.tXuB2uC$70.tU2tW
4.uBuD2uE$71.tW2uA4.uDuF2uG$72.uA2uC4.uFuH2uI$73.uC2uE4.uHuJ2uK$74.uE
2uG4.uJuL2uM$75.uG2uI4.uLuN2uO$76.uI2uK4.uNuP2uQ$77.uK2uM4.uPuR2uS$
78.uM2uO4.uRuT2uU$79.uO2uQ4.uTuV2uW$80.uQ2uS4.uVuX2vA$81.uS2uU4.uXvB
2vC$82.uU2uW4.vBvD2vE$83.uW2vA4.vDvF2vG$84.vA2vC4.vFvH2vI$85.vC2vE4.vH
vJ2vK$86.vE2vG4.vJvL2vM$87.vG2vI4.vLvN2vO$88.vI2vK4.vNvP2vQ$89.vK2vM
4.vPvR2vS$90.vM2vO4.vRvT2vU$91.vO2vQ4.vTvV2vW$92.vQ2vS4.vVvX2wA$93.vS
2vU4.vXwB2wC$94.vU2vW4.wBwD2wE$95.vW2wA4.wDwF2wG$96.wA2wC4.wFwH2wI$
97.wC2wE4.wHwJ2wK$98.wE2wG4.wJwL2wM$99.wG2wI4.wLwN2wO$100.wIwKwJ4.wNwP
2wQ$101.wK2wL4.wPwR2wS$102.wL2wN4.wRwT2wU$103.wN2wP4.wTwV2wW$104.wP2wR
4.wVwX2xA$105.wR2wT4.wXxB2xC$106.wT2wV4.xBxD2xE$107.wV2wX4.xDxF2xG$
108.wX2xB4.xFxH2xI$109.xB2xD4.xHxJ2xK$110.xD2xF4.xJxL2xM$111.xF2xH4.xL
xN2xO$112.xH2xJ4.xNxP2xQ$113.xJ2xL4.xPxR2xS$114.xL2xN4.xRxT2xU$115.xN
2xP4.xTxV2xW$116.xP2xR4.xVxX2yA$117.xR2xT4.xXyB2yC$118.xT2xV4.yByD2yE
$119.xV2xX4.yDyF2yG$120.xX2yB4.yFyH2yI$121.yB2yD4.yHyJ2yK$122.yD2yF4.
yJyL2yM$123.yF2yH4.yLyN2yO$124.yH2yJ4.yN$125.yJ2yL$126.yL2yN$127.yN!
I AM INACTIVE AND LIKELY WILL BE FOR THE FORSEEABLE FUTURE, DON'T ATTEMPT TO TALK TO ME AS I LIKELY WON'T RESPOND.

AlephAlpha
Posts: 66
Joined: October 6th, 2017, 1:50 am

Re: Outrunning the Glider

Post by AlephAlpha » February 26th, 2019, 4:20 am

A glider that outruns the glider (2c/7):

Code: Select all

x = 3, y = 3, rule = B2ce3aijkn4w5i7e/S1c2cei3aj4ainq5ry6c
bo$2bo$3o!

Hunting
Posts: 4395
Joined: September 11th, 2017, 2:54 am

Re: Outrunning the Glider

Post by Hunting » February 26th, 2019, 5:27 am

Hello, AlephAlpha!

I will probably try to search some fast diagonal ship in RSS(Really Small Spaceship) project, or #76 at GitHub [s]Also known as "Manual LLS"[/s].

AlephAlpha
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Joined: October 6th, 2017, 1:50 am

Re: Outrunning the Glider

Post by AlephAlpha » February 26th, 2019, 8:57 am

Restricting to the rules that the original glider works:

4c/15:

Code: Select all

x = 13, y = 13, rule = B2in3-eqy4ijkqw5cikq6aik/S02-ck3-aeky4inqtwy5nqry6an7e8
11bo$12bo$10b3o8$b2o$obo$3o!
3c/11:

Code: Select all

x = 13, y = 13, rule = B2ik3aijn4iqw5cky6c7c/S02-ci3-ciqy4ir5acq6k7c
11bo$12bo$10b3o8$2bo$b2o$3o!
2c/7:

Code: Select all

x = 13, y = 13, rule = B3-ckqy4k/S02ae3ijknr4iw5any6n7
11bo$12bo$10b3o8$b2o$obo$3o!
3c/10:

Code: Select all

x = 13, y = 13, rule = B3-ekqy4aqy5i6e7c8/S02ae3ajnr4cqrw5cknq6cn
11bo$12bo$10b3o8$obo$2bo$3o!
4c/13:

Code: Select all

x = 13, y = 13, rule = B2kn3-ekqy4jt5c/S02ae3-ckqy4jqw5aik7e
11bo$12bo$10b3o8$b2o$3o$3o!
c/3:

Code: Select all

x = 13, y = 13, rule = B3aijnr4k7c/S2ae3jnr4i5a7c
11bo$12bo$10b3o8$b2o$obo$3o!
Last edited by AlephAlpha on February 26th, 2019, 10:06 am, edited 1 time in total.

Hunting
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Joined: September 11th, 2017, 2:54 am

Re: Outrunning the Glider

Post by Hunting » February 26th, 2019, 9:38 am

AlephAlpha wrote: 2c/7:

Code: Select all

x = 13, y = 13, rule = B3-ckqy4k/S02ae3ijknr4iw5any6n7
11bo$12bo$10b3o8$2bo$b2o$3o!
Hey, I think you posted the wrong pattern. The "2c/7d" is an oscillator.

wildmyron
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Location: Western Australia

Re: Outrunning the Glider

Post by wildmyron » February 26th, 2019, 9:46 am

AlephAlpha wrote:Restricting to the rules that the original glider works:
Nice work. There's a 2c/7 in a glider compatible rule in my post above ^. Here are some other speeds:

5c/16d

Code: Select all

x = 13, y = 13, rule = B2k3aijn4qt5acjk6-ae7c/S23ajnqr4acijrt5-cenr6-a7e
12bo$10bobo$11b2o8$2bo$2bo$3o!
5c/17d

Code: Select all

x = 13, y = 13, rule = B2i3aijnr4eknqy5aceq6-k78/S02ae3-ceq4inrtwy5-enqy6-kn7e
12bo$10bobo$11b2o8$2bo$b2o$3o!
5c/18d

Code: Select all

x = 13, y = 13, rule = B2kn3-cekr4eijnqt5-ckn6ci7c/S2-k3-eky4nrwyz5aei6cen78
12bo$10bobo$11b2o8$2bo$b2o$3o!
5c/19d

Code: Select all

x = 13, y = 13, rule = B2i3-kq4ckntyz5cejk6ck7c/S02aen3jnry4cinqwz5-ey6an78
12bo$10bobo$11b2o8$b2o$obo$3o!
6c/19d

Code: Select all

x = 13, y = 13, rule = B2k3-cery4ikyz5ikqry6cek7c8/S02aek3-ci4ceinwz5iknr8
12bo$10bobo$11b2o8$b2o$3o$3o!
Last edited by wildmyron on February 26th, 2019, 10:41 am, edited 2 times in total.
The 5S project (Smallest Spaceships Supporting Specific Speeds) is now maintained by AforAmpere. The latest collection is hosted on GitHub and contains well over 1,000,000 spaceships.

Semi-active here - recovering from a severe case of LWTDS.

AlephAlpha
Posts: 66
Joined: October 6th, 2017, 1:50 am

Re: Outrunning the Glider

Post by AlephAlpha » February 26th, 2019, 10:07 am

Hunting wrote:
AlephAlpha wrote: 2c/7:

Code: Select all

x = 13, y = 13, rule = B3-ckqy4k/S02ae3ijknr4iw5any6n7
11bo$12bo$10b3o8$2bo$b2o$3o!
Hey, I think you posted the wrong pattern. The "2c/7d" is an oscillator.
Sorry. Edited.

wildmyron
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Location: Western Australia

Re: Outrunning the Glider

Post by wildmyron » February 26th, 2019, 10:42 am

Some more:

c/3d, p18

Code: Select all

x = 13, y = 13, rule = B2n3-kqr4-eijry5aciky6-ai7e8/S2-c3-eky4ejryz5aceir6kn7c8
12bo$10bobo$11b2o8$obo$b2o$3o!
3c/10, p20

Code: Select all

x = 13, y = 13, rule = B3aijn4-aeirt5eqry6ace7e8/S2aek3-cky4eirwyz5-ckry6cn7c
12bo$10bobo$11b2o8$2bo$b2o$3o!
2c/7d, p21

Code: Select all

x = 13, y = 13, rule = B2in3-eqy4cejwz5-jnr6-en7c8/S02-cn3-aey4cirtyz5aijky6-k8
12bo$10bobo$11b2o8$b2o$obo$3o!
3c/11d, p22

Code: Select all

x = 13, y = 13, rule = B2ikn3-q4aejtyz5acer67e/S02-ik3-aeiy4ejnqtz5aejqy6-k8
12bo$10bobo$11b2o8$obo$2bo$3o!
7c/22d

Code: Select all

x = 13, y = 13, rule = B2kn3-e4ceknqy5-ekny6-ac7c/S02-c3cjnr4einyz5-eikn6eik78
12bo$10bobo$11b2o8$b2o$obo$3o!
6c/23d

Code: Select all

x = 13, y = 13, rule = B3-qr4-aqryz5cry6-cn8/S02-n3-ai4ceijntz5-cejn6-en7e8
12bo$10bobo$11b2o8$obo$2bo$3o!
7c/23d

Code: Select all

x = 13, y = 13, rule = B2i3-ceqr4-krwy5ciqr6-i7c8/S2-c3-ekqy4iqrtw5aikq6kn7c8
12bo$10bobo$11b2o8$b2o$3o$3o!
These were all found with LLS. The shapes are mostly a function of the boundary conditions set up by the search. You can improve the search behaviour by using the make_lls_grid.py script. I used it for the 7c/22 and 7c/23 ships. As a bonus this reduces the search space and therefore improves the search speed considerably. Here's the command I used to find the 7c/23:

Code: Select all

./make_lls_grid.py -p 23 -x 7 -y 7 -f 3 3 5 5 | ./lls -r pB2-ace3aijn4-r5-n678/S0
2ae3jnr4-k5678 -i -s 'D2\'
This took about 15 seconds to run, most of which was in preprocessing.
The 5S project (Smallest Spaceships Supporting Specific Speeds) is now maintained by AforAmpere. The latest collection is hosted on GitHub and contains well over 1,000,000 spaceships.

Semi-active here - recovering from a severe case of LWTDS.

User avatar
Hdjensofjfnen
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Re: Outrunning the Glider

Post by Hdjensofjfnen » February 26th, 2019, 5:25 pm

Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?

Code: Select all

x = 5, y = 9, rule = B3-jqr/S01c2-in3
3bo$4bo$o2bo$2o2$2o$o2bo$4bo$3bo!

Code: Select all

x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!

AforAmpere
Posts: 1334
Joined: July 1st, 2016, 3:58 pm

Re: Outrunning the Glider

Post by AforAmpere » February 26th, 2019, 5:39 pm

Hdjensofjfnen wrote:Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?


It kind of already is known. In a non-B2a or B1e rule, the max diagonal speed is C/3. Therefore, there is no faster one in a rule with the glider.
I manage the 5S project, which collects all known spaceship speeds in Isotropic Non-totalistic rules. I also wrote EPE, a tool for searching in the INT rulespace.

Things to work on:
- Find (7,1)c/8 and 9c/10 ships in non-B0 INT.
- EPE improvements.

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Hdjensofjfnen
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Re: Outrunning the Glider

Post by Hdjensofjfnen » February 26th, 2019, 7:57 pm

AforAmpere wrote:
Hdjensofjfnen wrote:Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?


It kind of already is known. In a non-B2a or B1e rule, the max diagonal speed is C/3. Therefore, there is no faster one in a rule with the glider.
Oh. In that case, time to find every single possible speed between c/3 and c/4 with the CGOL glider.

Code: Select all

x = 5, y = 9, rule = B3-jqr/S01c2-in3
3bo$4bo$o2bo$2o2$2o$o2bo$4bo$3bo!

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x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!

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Moosey
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Re: Outrunning the Glider

Post by Moosey » February 26th, 2019, 8:02 pm

Hdjensofjfnen wrote:
AforAmpere wrote:
Hdjensofjfnen wrote:Can we either prove or disprove wildmyron's conjecture that rules with CGOL gliders have a maximum diagonal speed of c/3?


It kind of already is known. In a non-B2a or B1e rule, the max diagonal speed is C/3. Therefore, there is no faster one in a rule with the glider.
Oh. In that case, time to find every single possible speed between c/3 and c/4 with the CGOL glider.
That's also impossible (at least for small ships) because there are infinite rational numbers between any two different rational numbers.
not active here but active on discord

AforAmpere
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Re: Outrunning the Glider

Post by AforAmpere » February 26th, 2019, 8:04 pm

Moosey wrote: That's also impossible (at least for small ships) because there are infinite rational numbers between any two different rational numbers.
However, there are a finite number of rules with the glider, and if there aren't fast diagonal adjustable ships with the glider, there may only be finitely many speeds.
I manage the 5S project, which collects all known spaceship speeds in Isotropic Non-totalistic rules. I also wrote EPE, a tool for searching in the INT rulespace.

Things to work on:
- Find (7,1)c/8 and 9c/10 ships in non-B0 INT.
- EPE improvements.

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Re: Outrunning the Glider

Post by Gamedziner » February 26th, 2019, 11:02 pm

AforAmpere wrote:
Moosey wrote: That's also impossible (at least for small ships) because there are infinite rational numbers between any two different rational numbers.
However, there are a finite number of rules with the glider, and if there aren't fast diagonal adjustable ships with the glider, there may only be finitely many speeds.
If you limit the bounding box, the max period is less than or equal to 2^(number of cells in the bounding box).

Code: Select all

x = 81, y = 96, rule = LifeHistory
58.2A$58.2A3$59.2A17.2A$59.2A17.2A3$79.2A$79.2A2$57.A$56.A$56.3A4$27.
A$27.A.A$27.2A21$3.2A$3.2A2.2A$7.2A18$7.2A$7.2A2.2A$11.2A11$2A$2A2.2A
$4.2A18$4.2A$4.2A2.2A$8.2A!

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Entity Valkyrie 2
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Re: Outrunning the Glider

Post by Entity Valkyrie 2 » February 27th, 2019, 12:25 am

This is Entity Valkyrie 2.

c/3:

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x = 5, y = 5, rule = B2e3-cjnr/S2aei3
b2o$obo$3o$4bo$3bo!
Last edited by Entity Valkyrie 2 on February 27th, 2019, 12:27 am, edited 1 time in total.
Bx222 IS MY WORST ENEMY.

Please click here for my own pages.

My recent rules:
StateInvestigator 3.0
B3-kq4ej5i6ckn7e/S2-i34q6a7
B3-kq4ej5y6c/S2-i34q5e
Move the Box

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Βεν Γ. Κυθισ
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Re: Outrunning the Glider

Post by Βεν Γ. Κυθισ » February 27th, 2019, 12:26 am

Entity Valkyrie 2 wrote:This is Entity Valkyrie 2.

c/3:

Code: Select all

x = 5, y = 5, rule = B2e3-cnr/S2aei3
b2o$obo$3o$4bo$3bo!
No, it becomes ash instantly,
I AM INACTIVE AND LIKELY WILL BE FOR THE FORSEEABLE FUTURE, DON'T ATTEMPT TO TALK TO ME AS I LIKELY WON'T RESPOND.

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Re: Outrunning the Glider

Post by Entity Valkyrie 2 » February 27th, 2019, 12:29 am

Βεν Γ. Κυθισ wrote:
Entity Valkyrie 2 wrote:This is Entity Valkyrie 2.

c/3:

Code: Select all

x = 5, y = 5, rule = B2e3-cnr/S2aei3
b2o$obo$3o$4bo$3bo!
No, it becomes ash instantly,
I forgot the "j" in B2e3-cjnr/S2aei3! Fixed.

Code: Select all

x = 5, y = 5, rule = B2e3-cjnr/S2aei3
b2o$obo$3o$4bo$3bo!
Bx222 IS MY WORST ENEMY.

Please click here for my own pages.

My recent rules:
StateInvestigator 3.0
B3-kq4ej5i6ckn7e/S2-i34q6a7
B3-kq4ej5y6c/S2-i34q5e
Move the Box

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77topaz
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Re: Outrunning the Glider

Post by 77topaz » February 28th, 2019, 1:00 am

AlephAlpha wrote:3c/11:

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x = 13, y = 13, rule = B2ik3aijn4iqw5cky6c7c/S02-ci3-ciqy4ir5acq6k7c
11bo$12bo$10b3o8$2bo$b2o$3o!
This rule also has a small 2c/8 orthogonal:

Code: Select all

x = 2, y = 6, rule = B2ik3aijn4iqw5cky6c7c/S02-ci3-ciqy4ir5acq6k7c
2o$2o2$bo2$bo!
Unfortunately, it is explosive.

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Re: Outrunning the Glider

Post by Redstoneboi » March 12th, 2019, 6:16 am

Code: Select all

x = 4, y = 5, rule = B3ai4a/S2e34aeiwz5iqr6a
bo$3o$2bo$2b2o$3bo!
rule that's golfed to have a small explosive seed, modified a bit giving this c/3d with population going 8-9-10
c(>^w^<c)~*
This is 「Fluffy」
「Fluffy」is my sutando.
「Fluffy」has the ability to engineer r e p l i c a t o r s.
「Fluffy」likes to watch spaceship guns in Golly.
「Fluffy」knows Natsuki best girl.

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