Random posts

[Hunting]

Me, but calcyman doesn't have enough time

If HE(the person who created the initial idea) doesn't have enough time, why don't do it yourself/ourselves/whatever?

There's 0.0016583% chance for a pentadecathlon to appear.

[Moosey]

have a touch of CA-based furious piano music.
Also see:
http://tones.wolfram.com/generate/GRh4r ... csGG9ko2Pp

[Moosey]

It was a dark and stormy afternoon. The fog* was dense except during the stormer parts of the stormy weather (which were dark) during the stormy afternoon and night (which was dark and stormy).

* I know this is all different from the actual text of the dark and stormy night thing, but...

[PkmnQ]

It's not everyday a green ballpen expoldes. Want more details?

[testitemqlstudop]

YES

[PkmnQ]

Yesterday my seatmate was doing something with her green ballpen (she doesn't know why it happened and I wasn't looking) and it exploded. At first I thought someone threw green paint. It was on my index finger, my wrist, my uniform, my pants and some of my books, notebooks, and pad paper.

I like green anyway.

[Hunting]

Yesterday my seatmate was doing something with her green ballpen (she doesn't know why it happened and I wasn't looking) and it exploded. At first I thought someone threw green paint. It was on my index finger, my wrist, my uniform, my pants and some of my books, notebooks, and pad paper.

I like green anyway.

"Green hair!" -- Rarity

--

It looks like people have forgot about this rule, when I wrote:

I really want a OCA:SparseMethuseLife page for this rule, and LifeViewer Aliases, and other things when this rule is explored. I know the fact that this rule is not really interesting, since it's almost impossible to have a gun or rake or something like that and thus engineering is highly limited, but I believe it have potential too.

[Moosey]

Morley relative.

Code: Select all

x = 24, y = 10, rule = B368/S23jnr4aqrz5
o$o$b2o$obo17bo2bo$3o17b4o$21b2o2$8bo$9bo$7b3o!

Common c/61, unusual p32 fake-rro, glider


Unrelated.

[testitemqlstudop]

Here's something to bend you minds:

Define x as ∑(infinity)1.
x is effectively 1 * infinity, or infinity.
By definition, x-x = inf-inf = inf.
However, when collapsing the summation, we get ∑(infinity)(1-1) = 0.

[Moosey]

Here's something to bend you minds:

Define x as ∑(infinity)1.
x is effectively 1 * infinity, or infinity.
By definition, x-x = inf-inf = inf.
However, when collapsing the summation, we get ∑(infinity)(1-1) = 0.

That only works if you have cardinals; w-w is not well defined in the simplest system involving transfinite ordinals, since you can’t subtract from limit ordinals.

[Moosey]

I’m in a curd-y mood today. Stay awhey.

[Moosey]

Oddly, in America, wolfram|alpha predicts 17 Bobs are born per year.
What the crumbs?

[fluffykitty]

Actually inf-inf=undefined so you're fine

[testitemqlstudop]

Is user "moose" Moosey or what?

[Moosey]

Is user "moose" Moosey or what?

Nope

[Moosey]

Particles emitted by inspiring things = stirrions

[Moosey]

lim(x->1)(Σ(inf)(1-x)) >> Σ(inf)(1-1)
Ha, testitem!

EDIT:
What is the sum of the p series for p=3? (p=2 is apparently (pi^2)/6)
p=4? p=5? p=n ∀n>1?

[testitemqlstudop]

lim(x->1)(Σ(inf)(1-x))

What are you even summing over in "Σ(inf)(1-x)"? I only understand it as "adding (1-x) infinite times", which would be identical to infinity.

However, the statement

lim(x->1)(Σ(inf)(1-x)) >> Σ(inf)(1-1)

is wrong, because you are defining Σ(inf)(1-1) as 0. The value of 0*inf is undefined. Proof: Suppose otherwise, that 0*inf = x. Hence, x/0 = inf, bu division by 0 is inherently undefined. (Don't even think about defining limits for x/0, that's not what I'm trying to get at here.)

So you can't compare anything to Σ(inf)0.

[Hunting]

B2ce/S012ce4i

[Moosey]

lim(x->1)(Σ(inf)(1-x))

What are you even summing over in "Σ(inf)(1-x)"? I only understand it as "adding (1-x) infinite times", which would be identical to infinity.

However, the statement

lim(x->1)(Σ(inf)(1-x)) >> Σ(inf)(1-1)

is wrong, because you are defining Σ(inf)(1-1) as 0. The value of 0*inf is undefined. Proof: Suppose otherwise, that 0*inf = x. Hence, x/0 = inf, but division by 0 is inherently undefined. (Don't even think about defining limits for x/0, that's not what I'm trying to get at here.)

So you can't compare anything to Σ(inf)0.

I’m sorry, but Σ(inf)0 =/= “your 0*inf” — it’s equal to 0+0+0+0+0+0+0+0+0+0+0+0+0+0... = 0.
While Σ(n)(k) = nk for finite, constant n and k, Σ(inf)0 =/= “0*inf”. You’re just adding 0 infinitely many times. While this IS mutiplication, it’s clear that 0+0+0+0+0+0+0+0+0+0+0+0+0=0ω. So maybe I should be more precise.
Σ(ω)(1-1) << lim(x->1)(Σ(ω)(1-x))

Basically, inf isn’t a number so of course 0*inf is undefined. In contrast, 0w is defined as 0.

[Moosey]

Can somebody send a MWSS, a HWSS, and some still lives into the life wormhole?

[Saka]

Can somebody send a MWSS, a HWSS, and some still lives into the life wormhole?

Help: the still lives wont budge!

[Moosey]

Can somebody send a MWSS, a HWSS, and some still lives into the life wormhole?

Help: the still lives wont budge!

Just start them there
I bet one of them will make a 31.4

[Hunting]

Why people are ignoring my apgsearch request? Sorry if I'm doing attention grabbing.

[testitemqlstudop]

My lifeviewer sandbox because I can't install golly on this temporary laptop

alife

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x = 0, y = 0, rule = B2a3-a/S23
o!

elife

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x = 0, y = 0, rule = B2e3-e/S23
o!

clife

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x = 0, y = 0, rule = B2c3-c/S23
o!

klife

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x = 0, y = 0, rule = B2k3-k/S23
o!

ilife

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x = 0, y = 0, rule = B2i3-i/S23
o!

nlife

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x = 0, y = 0, rule = B2n3-n/S23
o!

alife2

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x = 0, y = 0, rule = B3/S2-a34a
o!

elife2

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x = 0, y = 0, rule = B3/S2-e34e
o!

clife2

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x = 0, y = 0, rule = B3/S2-c34c
o!

klife2

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x = 0, y = 0, rule = B3/S2-k34k
o!

ilife2

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x = 0, y = 0, rule = B3/S2-i34i
o!

nlife2

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x = 0, y = 0, rule = B3/S2-n34n
o!