Calcyman, I think? wrote:Find a string S with a given prefix P, that when you run the QR code of SHA-256(S), it generates a pentadecathlon/whatever you want.
(Also, page 103 reached!)
Calcyman, I think? wrote:Find a string S with a given prefix P, that when you run the QR code of SHA-256(S), it generates a pentadecathlon/whatever you want.
#C Favorite Gun. Found by me.
x = 4, y = 6, rule = B2e3i4at/S1c23cijn4a
o2bo$4o3$4o$o2bo!
testitemqlstudop wrote:Me, but calcyman doesn't have enough time
#C Favorite Gun. Found by me.
x = 4, y = 6, rule = B2e3i4at/S1c23cijn4a
o2bo$4o3$4o$o2bo!
x = 3, y = 3, rule = B26/S2|B358/S3
2o$2bo$obo!
x = 3, y = 3, rule = B26/S2|B358/S3
2o$2bo$obo!
PkmnQ wrote:Yesterday my seatmate was doing something with her green ballpen (she doesn't know why it happened and I wasn't looking) and it exploded. At first I thought someone threw green paint. It was on my index finger, my wrist, my uniform, my pants and some of my books, notebooks, and pad paper.
I like green anyway.
Hunting wrote:I really want a OCA:SparseMethuseLife page for this rule, and LifeViewer Aliases, and other things when this rule is explored. I know the fact that this rule is not really interesting, since it's almost impossible to have a gun or rake or something like that and thus engineering is highly limited, but I believe it have potential too.
#C Favorite Gun. Found by me.
x = 4, y = 6, rule = B2e3i4at/S1c23cijn4a
o2bo$4o3$4o$o2bo!
x = 24, y = 10, rule = B368/S23jnr4aqrz5
o$o$b2o$obo17bo2bo$3o17b4o$21b2o2$8bo$9bo$7b3o!
testitemqlstudop wrote:Here's something to bend you minds:
Define x as ∑(infinity)1.
x is effectively 1 * infinity, or infinity.
By definition, x-x = inf-inf = inf.
However, when collapsing the summation, we get ∑(infinity)(1-1) = 0.
testitemqlstudop wrote:Is user "moose" Moosey or what?
lim(x->1)(Σ(inf)(1-x))
lim(x->1)(Σ(inf)(1-x)) >> Σ(inf)(1-1)
#C Favorite Gun. Found by me.
x = 4, y = 6, rule = B2e3i4at/S1c23cijn4a
o2bo$4o3$4o$o2bo!
testitemqlstudop wrote:lim(x->1)(Σ(inf)(1-x))
What are you even summing over in "Σ(inf)(1-x)"? I only understand it as "adding (1-x) infinite times", which would be identical to infinity.
However, the statementlim(x->1)(Σ(inf)(1-x)) >> Σ(inf)(1-1)
is wrong, because you are defining Σ(inf)(1-1) as 0. The value of 0*inf is undefined. Proof: Suppose otherwise, that 0*inf = x. Hence, x/0 = inf, but division by 0 is inherently undefined. (Don't even think about defining limits for x/0, that's not what I'm trying to get at here.)
So you can't compare anything to Σ(inf)0.
Moosey wrote:Can somebody send a MWSS, a HWSS, and some still lives into the life wormhole?
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!
Saka wrote:Moosey wrote:Can somebody send a MWSS, a HWSS, and some still lives into the life wormhole?
Help: the still lives wont budge!
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