x = 37, y = 6, rule = B3/S23
4b2o13b2o13b2o$3bo2bo11bo2bo11bo2bo$3bob2o11bob2o11bob2o$2obo12b2obo
12b2obo$o2bo12bo2bo12bo2bo$b2o14b2o14b2o!
x = 37, y = 6, rule = B3/S23
4b2o13b2o13b2o$3bo2bo11bo2bo11bo2bo$3bob2o11bob2o11bob2o$2obo12b2obo
12b2obo$o2bo12bo2bo12bo2bo$b2o14b2o14b2o!
A for awesome wrote:[nevermind]2. Find a non-explosive B1e rule.[/nevermind]
This one has been solved by @gmc_nxtman. Feel free to come up with other examples, though.
x = 20, y = 20, rule = B01/S
3obob3o2bo2b2obobo$b2o7b3o2b2o2bo$3o2bo2b3ob5obo$2bobob2obob3ob3o$ob4o
3b4o3b3o$2ob2o2bobo3b2obo$4bo2bo5bo3bo$o3b3obo2bo7bo$3obobo2b2ob4o$2bo
b2o3bobo2b2o3bo$b2ob3o2b4obo2bobo$b2obo2b3o7b3o$2bobo2bob3o2b3obo$ob2o
3b4o2bobob2o$o2bo3b3o2bo2b2obo$2o2b2obob6obob2o$3bobo2b3obob3o2bo$3o5b
5ob6o$o4bo4b2ob2obobo$5obob2o2bo2b4o!
x = 100, y = 100, rule = B01e2/S4aceikn
3o5bobo4bobo7b5ob2ob11ob4o6b3ob2ob2ob2o5bo5bobobob8o4bobo$99o$b99o$
100o$100o$100o$b98o$b98o$99o$99o$b98o$99o$b99o$100o$100o$b99o$100o$b
99o$100o$100o$b99o$b99o$b98o$b98o$b98o$b99o$100o$99o$b98o$100o$100o$
100o$b98o$99o$99o$100o$b98o$99o$99o$99o$99o$b98o$b98o$b98o$b99o$100o$b
99o$100o$b98o$b99o$b98o$99o$b98o$b99o$b98o$b99o$99o$100o$b99o$b98o$b
99o$b99o$b98o$99o$100o$b99o$99o$100o$99o$99o$99o$b98o$b98o$100o$b99o$
100o$b99o$b99o$100o$99o$99o$99o$100o$100o$b99o$b98o$b98o$100o$b98o$99o
$b98o$b98o$b98o$100o$b98o$99o$100o$99o$99o$5ob5o4bo2b3obo3b2o2b3obo3b
2ob4o2b3o2bobo2b3o4b2ob6ob2o3bo3bo3bob2o2b6o!
dvgrn wrote:Saka wrote:Is there a slowest possible spaceship for n cells?
Well, yes, for small N these do exist, of course. But there's not ever going to be a discoverable algorithm where you input N and get back the relevant slowest possible spaceship.
x = 36, y = 11, rule = B3/S23
3bo4bo4bo12b2o$2bobo2bobo2bobo12bo$bobo3bobo3bobo10bo$2bo5bo5bo11b2o$
30b2o$29bobo$29b2o$2b2o4b2o4b2o$bo2bo2bo2bo2bo2bo15bob2o$o2bo3bo2bo3bo
2bo14b2obo$b2o5b2o5b2o!
danny wrote:Challenge: Find a rule as close to CGOL that
a) retains the glider
b) has an overunity reaction from only 2G's
77topaz wrote:danny wrote:Challenge: Find a rule as close to CGOL that
a) retains the glider
b) has an overunity reaction from only 2G's
Just to clarify, by "overunity reaction" you mean a reaction that creates more than two gliders and nothing else?
x = 5, y = 12, rule = B34t/S23
3bo$2bo$2b3o7$bo$2o$obo!
#C [[ ZOOM 6 AUTOSTART PAUSE 2 ]]
x = 844, y = 376, rule = B3/S23
294bo56bo28bo$148bo28bo29bo26bo29bo28bo29bo26bo28bo56bo$147bo28bo29bo
26bo29bo29b3o26bo27b3o26b3o25bo27bo$147b3o26b3o27b3o24b3o27b3o56b3o81b
o28b3o$406b3o4$350bo$148b3o27b3o139bo28b2o85bo$148bo29bo30bo27bo30bo
23b2o25b2o28bobo24b2o30bo26b2o$149bo29bo28b2o26b2o29b2o23bobo24bobo54b
obo28b2o26bobo$208bobo25bobo28bobo22bo83bo30bobo7$535bo$469bo32bo31bo
92bo$410bo25bo31bo32bo32b3o28bo32bo27bo$409bo25bo32b3o30b3o60bo32bo28b
3o$186bo26bo27bo26bo26bo25bo27bo26bo32b3o23b3o126b3o30b3o$156bo28bo26b
o27bo26bo26bo25bo27bo26bo$155bo29b3o24b3o25b3o24b3o24b3o23b3o25b3o24b
3o$155b3o4$404b3o25b3o89b2o$176b3o26b3o26b3o25b3o25b3o24b3o26b3o25b3o
29bo27bo21b2o33b2o30bobo30b2o60b2o$144b3o31bo28bo28bo27bo27bo26bo28bo
27bo28bo27bo23b2o33b2o31bo31b2o22b2o36b2o$146bo30bo28bo28bo27bo27bo26b
o28bo27bo80bo34bo64bo25b2o34bo$145bo435bo16$800bo$799bo38bo$745bo53b3o
35bo$744bo92b3o$744b3o3$306bo$274bo30bo$273bo15bo15b3o533b3o$273b3o12b
o459bo92bo$288b3o456b2o44b2o47bo$747bobo44b2o$793bo4$308b2o$308bobo$
266b2o21b2o17bo$265bobo21bobo$267bo21bo13$595bo$594bo$594b3o2$494bo44b
o126bo$460bo32bo44bo126bo$459bo33b3o42b3o124b3o$459b3o3$594b2o$594bobo
$594bo2$459bo35b2o35b2o$458b2o35bobo35b2o121b2o$458bobo34bo36bo124b2o$
656bo11$165bo$164bo$81bo39bo42b3o$43bo36bo39bo75bo$42bo37b3o37b3o72bo
68bo$42b3o150b3o65bo20bo$bo261b3o17bo$o282b3o$3o3$159b2o31bo$35b3o80b
2o40b2o29b2o$3b3o31bo38b2o40bobo38bo31bobo$3bo32bo40b2o39bo161bo$4bo
71bo181b2o19b2o$257bobo19bobo$259bo17$458bo$395bo61bo42bo$394bo62b3o
39bo$394b3o102b3o$503b3o$399bo103bo$398b2o104bo$398bobo54b2o$454bobo$
456bo23$106bo$105bo151bo207bo$105b3o148bo207bo$256b3o205b3o222bo$688bo
$641bo46b3o$640bo$640b3o185bo$827bo$259b3o565b3o$259bo203bo$98b2o160bo
201b2o$99b2o361bobo$98bo$641bo42b2o$640b2o41bobo$640bobo42bo2$813b2o$
814b2o$813bo12$497bo$496bo$496b3o6$499bo$498b2o$498bobo16$259bo$258bo$
258b3o264bo$162bo361bo$161bo362b3o$161b3o3$257bo$256b2o266b3o$256bobo
265bo$525bo3$153b2o$152bobo$154bo16$510bo$509bo$509b3o5$510b3o$56bo16b
o436bo$55bo16bo438bo$55b3o14b3o7$74bo$51b2o20b2o$52b2o19bobo$51bo13$
278bo239bo$277bo239bo$277b3o237b3o6$277b3o$277bo$278bo$508b2o$507bobo$
509bo24$527bo$526bo$526b3o7$524bo$523b2o$523bobo9$246bo58bo40bo$245bo
58bo40bo$245b3o56b3o38b3o3$63bo13bo$62bo13bo$62b3o11b3o168b3o$247bo43b
3o$248bo44bo$292bo56b2o$349bobo$349bo3$58b2o21b2o$58bobo20bobo$58bo22b
o!
x = 19, y = 14, rule = B3-q/S23
17bo$16bo$16b3o9$2o$b2o$o!
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
Hdjensofjfnen wrote:Challenges:
1) Find a Life oscillator with a 1 cell rotor.
2) Find a c/2 in a B2a rule.
x = 3, y = 2, rule = B2a3e/S1c2c3e
obo$bo!
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
x = 19, y = 8, rule = B3/S23
18bo$16b2o$17b2o2$bo$2bo9bo$3o7b2o$11b2o!
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
Hdjensofjfnen wrote:Challenges:
Find an oscillator in Life with period p, with n cells in its rotor, where p > n.
Find an oscillator in Life, with period greater than 2, in which one of the phases is the stator (plus no cells).
danny wrote:Hdjensofjfnen wrote:Challenges:
Find an oscillator in Life with period p, with n cells in its rotor, where p > n.
Find an oscillator in Life, with period greater than 2, in which one of the phases is the stator (plus no cells).
1. Phoenices
2. Cuphook
x = 8, y = 8, rule = B3/S23
3bo4b$3bobo2b$bo6b$6b2o$2o6b$6bob$2bobo3b$4bo!
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
cordership3 wrote:For #1, the p(2^44497 - 1) oscillator should work.
x = 4, y = 5, rule = B356/S23
bo$2o$2b2o$bobo$2bo!
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
x = 4, y = 11, rule = B2en3-eknq/S234q
2o$2bo$2o6$2bo$bobo$bobo!
x = 16, y = 16, rule = B2en3-eknq/S234q
obobob4ob2ob2o$ob7o3b4o$4b5o$2bo2b2ob3o4bo$bo6bo3b2o$ob2ob2o4bo2bo$2b
2o11bo$3o5b2ob2o2bo$o2b4obobo2b2o$bo3b5obobo$bobo2bo2bob4o$2bo3b4o4b2o
$bob2o2b2o5bo$o2b2obo3b2obo$2b2obo2b4o2bo$o2b2o!
x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
Hdjensofjfnen wrote:This puffer is very picky. It needs every single non-totalistic birth and survival condition except one. What is it?Code: Select allx = 4, y = 5, rule = B356/S23
bo$2o$2b2o$bobo$2bo!
non-totalistic
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