## Challenges

A forum where anything goes. Introduce yourselves to other members of the forums, discuss how your name evolves when written out in the Game of Life, or just tell us how you found it. This is the forum for "non-academic" content.

### Re: Challenges

toroidalet wrote:Challenge: Find a pattern that doesn't die out in R6,C0,M1,S34..58,B34..45,NM, which I am terming "Bugs but I literally changed the range to 6 and it's still miraculously stable."

x = 9, y = 9, rule = R6,C0,M1,S34..58,B34..45,NM9o$9o$9o$9o$9o$9o$9o$9o$9o!

There's a couple still lifes, I'm currently apgsearching this rule, and there's only one object every ~1563 soups as of now, most of which are the 9x9 square I just posted.
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drc

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### Re: Challenges

Saka wrote:
83bismuth38 wrote:is a c/1 knightship possible?

x = 11, y = 19, rule = R5,C4,M0,S83..98,B10..108,NN:T1000,1000$4.C$5.CB$5.2CBA$5.2C2BA$5.2C2B2A$5.2C2B2A$5.2C2B2A$5.2C2B2A$4.3C2B2A$4.2C3B2A$3.3C2B3A$2.3C3B2A$.3C3B3A$2.C3B3A$4.B3A$6.A!

that rule does not work in golly.
x = 8, y = 10, rule = B3/S233b2o$3b2o$2b3o$4bobo$2obobobo$3bo2bo$2bobo2bo$2bo4bo$2bo4bo$2bo! No football of any dui mauris said that. 83bismuth38 Posts: 453 Joined: March 2nd, 2017, 4:23 pm Location: Still sitting around in Sagittarius A... ### Re: Challenges Challenge: Find a spaceship in B2c3-ej/S23 It should be possible, although it's probably very slow and hard to find. This post was brought to you by the letter D, for dishes that Andrew J. Wade won't do. (Also Daniel, which happens to be me.) Current rule interest: B2ce3-ir4a5y/S2-c3-y drc Posts: 1664 Joined: December 3rd, 2015, 4:11 pm Location: creating useless things in OCA ### Re: Challenges drc wrote:Challenge: Find a spaceship in B2c3-ej/S23 It should be possible, although it's probably very slow and hard to find. Found with gfind: x = 29, y = 14, rule = B2c3-ej/S2314bobo$13bobo$6bo7bobo$5bob2ob2obobo$4bobobobobobo$3bobob2o2bobo12bobo$2bo4b4obo12bobo$bo3bob2obo15bobo$ob2o5bobo13bobo$bo5b2obo13bobo$2bobo4bo11b3obo$2b3obobo10b2obobo$3bobobo9bo2bobo$6bo10b3obo!

Last edited by Goldtiger997 on August 27th, 2017, 5:25 am, edited 1 time in total.
Things to work on:
• Work on the snowflakes orthogonoid

Goldtiger997

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### Re: Challenges

83bismuth38 wrote:
Saka wrote:
x = 11, y = 19, rule = R5,C4,M0,S83..98,B10..108,NN:T1000,1000$4.C$5.CB$5.2CBA$5.2C2BA$5.2C2B2A$5.2C2B2A$5.2C2B2A$5.2C2B2A$4.3C2B2A$4.2C3B2A$3.3C2B3A$2.3C3B2A$.3C3B3A$2.C3B3A$4.B3A$6.A!

that rule does not work in golly.

The modification needed for the rule to work is very easy, and I assume you can do it. Please don't be too lazy...
If you're the person that uploaded to Sakagolue illegally, please PM me.
x = 17, y = 10, rule = B3/S23b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5bo2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo! (Check gen 2) Saka Posts: 2767 Joined: June 19th, 2015, 8:50 pm Location: In the kingdom of Sultan Hamengkubuwono X ### Re: Challenges It turns out that Bugs but I literally changed the range to 6 and it's still miraculously stable has a c/3 diagonal ship: x = 10, y = 10, rule = R6,C0,M1,S34..56,B33..45,NM5b2o$4b3o$3b5o$4o3b3o$b4o2b3o$2b4ob2o$3b5o$4b3o$5b2o$6bo!

Challenge: Find a spaceship made of smaller spaceships made of smaller spaceships.
Another challenge: Find a nontrivial spaceship where 2 appropriately-timed copies may pass through each other.
x = 4, y = 2, rule = B3/S23ob2o$2obo! (Check Gen 2) toroidalet Posts: 912 Joined: August 7th, 2016, 1:48 pm Location: my computer ### Re: Challenges toroidalet wrote:It turns out that Bugs but I literally changed the range to 6 and it's still miraculously stable has a c/3 diagonal ship: x = 10, y = 10, rule = R6,C0,M1,S34..56,B33..45,NM5b2o$4b3o$3b5o$4o3b3o$b4o2b3o$2b4ob2o$3b5o$4b3o$5b2o$6bo!

Challenge: Find a spaceship made of smaller spaceships made of smaller spaceships.
Another challenge: Find a nontrivial spaceship where 2 appropriately-timed copies may pass through each other.

BBILCTRT6&ISMS isn't 6,34,56,33,45, it's 6,34,45,34,58, at least that's what I thought.

Isn't this the census?
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drc

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### Re: Challenges

Find a unstable pattern that is not a oscillator and remains the same population for as long as possible.
One big dirty Oro. Yeeeeeeeeee...

gameoflifemaniac

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### Re: Challenges

gameoflifemaniac wrote:Find a unstable pattern that is not a oscillator and remains the same population for as long as possible.

I think I know what you mean, but even if this doesn't count --

Code: Select all
x = 7, y = 3, rule = B3/S233o2b2o$o4b2o$bo!#C [[ THUMBNAIL THUMBSIZE 2 ]]

-- you haven't really excluded boring things like a glider aimed at something painfully far away:

x = 1000004, y = 1000004, rule = B3/S232o$o1000000$1000001b3o$1000001bo$1000002bo!

dvgrn
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### Re: Challenges

dvgrn wrote:
gameoflifemaniac wrote:Find a unstable pattern that is not a oscillator and remains the same population for as long as possible.

I think I know what you mean, but even if this doesn't count --

Code: Select all
x = 7, y = 3, rule = B3/S233o2b2o$o4b2o$bo!#C [[ THUMBNAIL THUMBSIZE 2 ]]

-- you haven't really excluded boring things like a glider aimed at something painfully far away:

x = 1000004, y = 1000004, rule = B3/S232o$o1000000$1000001b3o$1000001bo$1000002bo!

I meant finitely long as possible.
One big dirty Oro. Yeeeeeeeeee...

gameoflifemaniac

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### Re: Challenges

gameoflifemaniac wrote:
dvgrn wrote:-- you haven't really excluded boring things like a glider aimed at something painfully far away:

x = 1000004, y = 1000004, rule = B3/S232o$o1000000$1000001b3o$1000001bo$1000002bo!

I meant finitely long as possible.

The second pattern dvgrn submitted (the one I have quoted) goes for a finite amount of time.
(And it maintains population 1 generation longer if you use an appropriately-placed blinker instead)
LifeWiki: Like Wikipedia but with more spaceships. [citation needed]

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### Re: Challenges

BlinkerSpawn wrote:The second pattern dvgrn submitted (the one I have quoted) goes for a finite amount of time.
(And it maintains population 1 generation longer if you use an appropriately-placed blinker instead)

Darn. I guess you win now... unless I can somehow think of a number bigger than a million.

dvgrn
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### Re: Challenges

gameoflifemaniac wrote:
dvgrn wrote:-- you haven't really excluded boring things like a glider aimed at something painfully far away:

x = 1000004, y = 1000004, rule = B3/S232o$o1000000$1000001b3o$1000001bo$1000002bo!

I meant finitely long as possible.

The limit for how long it takes is ∞.
(for z = lim(z) as z->∞)x = (z)+4, y = (z)+4, rule = B3/S232o$o(z)$(z+1)b3o$(z+1)bo$(z+2)bo!
Gamedziner

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### Re: Challenges

CHALLENGE: give me the ability to find a rule that actually sparks mild interest.

this is a joke, don't take it seriously please. but if you CAN, please do.
x = 8, y = 10, rule = B3/S233b2o$3b2o$2b3o$4bobo$2obobobo$3bo2bo$2bobo2bo$2bo4bo$2bo4bo$2bo! No football of any dui mauris said that. 83bismuth38 Posts: 453 Joined: March 2nd, 2017, 4:23 pm Location: Still sitting around in Sagittarius A... ### Re: Challenges Saka wrote: 83bismuth38 wrote: Saka wrote: x = 11, y = 19, rule = R5,C4,M0,S83..98,B10..108,NN:T1000,1000$4.C$5.CB$5.2CBA$5.2C2BA$5.2C2B2A$5.2C2B2A$5.2C2B2A$5.2C2B2A$4.3C2B2A$4.2C3B2A$3.3C2B3A$2.3C3B2A$.3C3B3A$2.C3B3A$4.B3A$6.A! that rule does not work in golly. The modification needed for the rule to work is very easy, and I assume you can do it. Please don't be too lazy... WHAT DID YOU DO WRONG?! I CAN'T FIGURE IT OUT FOR THE LIFE (no pun intended) OF ME!!! x = 8, y = 10, rule = B3/S233b2o$3b2o$2b3o$4bobo$2obobobo$3bo2bo$2bobo2bo$2bo4bo$2bo4bo$2bo!

No football of any dui mauris said that.

83bismuth38

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### Re: Challenges

83bismuth38 wrote:
Saka wrote:R5,C4,M0,S83..98,B10..108,NN:T1000,1000

WHAT DID YOU DO WRONG?! I CAN'T FIGURE IT OUT FOR THE LIFE (no pun intended) OF ME!!!

Here's a hint: how many neighboring cells does the range-5 von Neumann neighborhood contain?
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Apple Bottom

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### Re: Challenges

Apple Bottom wrote:
83bismuth38 wrote:
Saka wrote:R5,C4,M0,S83..98,B10..108,NN:T1000,1000

WHAT DID YOU DO WRONG?! I CAN'T FIGURE IT OUT FOR THE LIFE (no pun intended) OF ME!!!

Here's a hint: how many neighboring cells does the range-5 von Neumann neighborhood contain?

ok:
x = 20, y = 9, rule = R5,C4,M0,S61..61,B10..61,NN:T1000,10004.11A$3.15A$2.A11B5A$2.15B3A$.B11C5B2A$.15C3B$C11.5C2B$15.3C$16.2C!
but how did he make that mistake in the first place?
x = 8, y = 10, rule = B3/S233b2o$3b2o$2b3o$4bobo$2obobobo$3bo2bo$2bobo2bo$2bo4bo$2bo4bo$2bo! No football of any dui mauris said that. 83bismuth38 Posts: 453 Joined: March 2nd, 2017, 4:23 pm Location: Still sitting around in Sagittarius A... ### Re: Challenges Can somebody show me all still lives up to 15 bits in one RLE, please? https://www.youtube.com/watch?v=q6EoRBvdVPQ One big dirty Oro. Yeeeeeeeeee... gameoflifemaniac Posts: 720 Joined: January 22nd, 2017, 11:17 am Location: There too ### Re: Challenges gameoflifemaniac wrote:Can somebody show me all still lives up to 15 bits in one RLE, please? This is a simple copy/paste from 25 different RLE files within two clicks of Mark Niemiec's main Life page, producing about a 20K RLE file with 2435 objects in it (if I've done all the math right). To get someone interested in doing the work, it may be worth explaining why you want it, and whether you also want pseudo still lifes -- there are 45 source files in that case -- and also whether it matters how the objects are organized, and why you can't just do the job yourself. dvgrn Moderator Posts: 5328 Joined: May 17th, 2009, 11:00 pm Location: Madison, WI ### Re: Challenges Challenge: Create the largest object possible (and/or prove that infinitely many objects are synthesizable) using only 1 glider per step and a 2-glider base. All collisions must settle before the next collision can begin. This post was brought to you by the letter D, for dishes that Andrew J. Wade won't do. (Also Daniel, which happens to be me.) Current rule interest: B2ce3-ir4a5y/S2-c3-y drc Posts: 1664 Joined: December 3rd, 2015, 4:11 pm Location: creating useless things in OCA ### Re: Challenges drc wrote:Challenge: Create the largest object possible (and/or prove that infinitely many objects are synthesizable) using only 1 glider per step and a 2-glider base. All collisions must settle before the next collision can begin. Ooh, I know this one! A year ago simeks came up with the basis for a slow salvo to stretch a ship. These days you can just figure out how to clean up the leftover junk from either of those reactions to get a block at a decent distance, and feed either of those two initial constellations into slmake (with a ship or a long boat instead of a long long ship as the base object to be extended). Tell slmake that the starting block location is at (-1, -1) from where you know it will end up, and run another round of compilation with slmake, building just the blinker or the loaf+blocks constellation that will be used up in each new cycle -- and hey presto, if you have an unlimited-length slow salvo, you can get an unlimited number of different still lifes. x = 216, y = 213, rule = LifeHistory52.C$2C49.C.C$C.C49.C.C$.2C50.2C5$7.C52.2C$7.C51.C2.C$7.C52.C.C$55.2C4.C$55.2C3$61.2C$61.2C2$11.2A$11.A.A$11.A3$80.2A$80.A.A$80.A21$35.2A$34.2A$36.A17$66.3A$66.A$67.A29$83.2A$82.2A$84.A17$112.2A$111.2A$113.A19$143.2A$143.A.A$143.A23$167.2A$166.2A$168.A47$213.2A$213.A.A$213.A!

In point of fact it's well within reach now to write a universal script that will solve this problem for any constructable object that you can throw at it. Given a glider recipe for any object, we know how to create a constellation of small still lifes that can be hit with a single glider to produce that exact arrangement of gliders.

And theoretically we can compile any constellation of small still lifes with slmake. The result is a slow salvo recipe aimed at a single block, which we can create with two gliders.

I wish somebody would write that script, actually. It would make horribly inefficient seed patterns, at least if it was written the easy way -- but it would be fun to watch a huge constellation collapse into a relatively tiny object.

Probably it's not a good idea to try compiling something like a Gemini spaceship this way, due to memory limitations, but in principle it would work just like any other glider recipe.

dvgrn
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### Re: Challenges

Find an arrangement of 3 polyomino sparks summing to 9 cells (with no pair kingwise-connected) that evolves into a spark consisting of a single nonomino after >5 gens.
Examples of invalid patterns:
Invalid because the only polyominoes formed after >5 gens are a hexomino and a domino:
x = 7, y = 4, rule = B3/S233bo$4o2bo$o$4b2o! Invalid, because the nonomino spark is formed at gen. 1: x = 6, y = 5, rule = B3/S23bo$bo$5bo$2b2obo$3o! Invalid, because two of the polyominoes are touching (and the nonomino formed in gen. 5 is not a spark): x = 5, y = 6, rule = B3/S232bo$3o$obo$3b2o2$2bo! There are probably multiple solutions. EDIT: There are. x₁=ηx V ⃰_η=c²√(Λη) K=(Λu²)/2 Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt) $$x_1=\eta x$$ $$V^*_\eta=c^2\sqrt{\Lambda\eta}$$ $$K=\frac{\Lambda u^2}2$$ $$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$ http://conwaylife.com/wiki/A_for_all Aidan F. Pierce A for awesome Posts: 1728 Joined: September 13th, 2014, 5:36 pm Location: 0x-1 ### Re: Challenges This still life x = 8, y = 10, rule = B3/S235bo$2o2bobo$o3bobo$b3obo$3bo$4bo$2bob3o$bobo3bo$bobo2b2o$2bo!

is the second-smallest still life with the property that its halves can be slid by one cell to create two similar still lives:
x = 30, y = 10, rule = B3/S235bo11bo10bo$2o2bobo5b2o2bobo4b2o2bobo$o3bobo5bo3bobo4bo3bobo$b3obo7b3obo6b3obo$3bo11bo10bo$5bo10bo9bo$3bob3o6bob3o5bob3o$2bobo3bo4bobo3bo3bobo3bo$2bobo2b2o4bobo2b2o3bobo2b2o$3bo10bo9bo! Which is the smallest? You could probably solve this easily with LLS but please don't LifeWiki: Like Wikipedia but with more spaceships. [citation needed] BlinkerSpawn Posts: 1835 Joined: November 8th, 2014, 8:48 pm Location: Getting a snacker from R-Bee's ### Re: Challenges toroidalet wrote:Challenge: Find a pattern that doesn't die out in R6,C0,M1,S34..58,B34..45,NM, which I am terming "Bugs but I literally changed the range to 6 and it's still miraculously stable." A 9x9 square is a p8 oscillator: x = 9, y = 9, rule = R6,C0,M1,S34..58,B34..45,NM9o$9o$9o$9o$9o$9o$9o$9o$9o! And this is a p2 one: x = 11, y = 9, rule = R6,C0,M1,S34..58,B34..45,NM3b5o$2b7o$b2o4b3o$3o5b3o$3o5b3o$3o5b3o$b4o3b2o$2b7o$3b5o! EDIT: Catagolue has a census for this rule, which additionally lists various still lifes. Last edited by 77topaz on February 1st, 2018, 6:47 pm, edited 1 time in total. 77topaz Posts: 1330 Joined: January 12th, 2018, 9:19 pm ### Re: Challenges BlinkerSpawn wrote:You could probably solve this easily with LLS but please don't LLS actually gives several smaller patterns than the one you've given. x = 32, y = 24, rule = B3/S235b2o10b2o10b2o$4bobo9bobo9bobo$3bo11bo11bo$2bob2o8bob2o8bob2o$bobo2bo6bobo2bo6bobo2bo$o2bobo7bo2bobo7bo2bobo$b2obo9b2obo9b2obo$3bo12bo12bo$obo10bobo10bobo$2o11b2o11b2o5$3b2obo8b2obo8b2obo$3bob2o8bob2o8bob2o2$4b3o9b3o9b3o$3bo2bo8bo2bo8bo2bo$o2bo9bo2bo9bo2bo$3o10b3o10b3o2$2obo9b2obo9b2obo$ob2o9bob2o9bob2o!

Admittedly there is one particularly small solution, which is probably the one you're looking for.

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