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Solitaire of Life

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Re: Solitaire of Life

Postby A for awesome » February 12th, 2018, 10:43 am

31x2:
x = 26, y = 12, rule = LifeHistory
C14.C$C2A12.C2A$3.C14.C$2.A14.A$2.2C2A3.2A6.2C2A$6.C2.A11.C$4.2C.A.C
9.2C.A.C$3.A2.C2.2A7.A2.C.2A$3.2C.C.A9.2C.C$5.A2.C11.A.AC.A$5.A.A12.A
.A.2A$6.C14.C!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Solitaire of Life

Postby gmc_nxtman » February 12th, 2018, 4:57 pm

Population should be minimal, but bounding box isn't.
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Re: Solitaire of Life

Postby A for awesome » February 12th, 2018, 5:58 pm

30 cells, minimal bounding box:
x = 10, y = 12, rule = LifeHistory
C$C2A$3.C$2.A2.A$2.2CA.A$6.C2A$4.2C3.C$3.A2.C.2A$3.2C.C.A$5.A2.C$5.A.
A$6.C!

EDIT: In case that's optimal, here's another challenge:
x = 12, y = 12, rule = LifeHistory
5.C2$3.C3.C$4.C.C$.C3.C$C5.C.C.C$.C3.C5.C$2.C7.C$7.C$4.C.C$.C$2.C.C!
#C [[ ANGLE 45 ]]
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Solitaire of Life

Postby PHPBB12345 » February 12th, 2018, 8:12 pm

A for awesome wrote:30 cells, minimal bounding box:
RLE

EDIT: In case that's optimal, here's another challenge:
RLE

WLS prepared (not solution):
x = 12, y = 12, rule = LifeHistory
5.C2$3.C3.C$4.CDC$.C2.DCD$C3.2DC.C.C$.C3.C5.C$2.C7.C$7.C$4.C.C$.C$2.C
.C!

x = 12, y = 12, rule = LifeHistory
5.A2$3.A2D2A$4.ADAD$.A.ADA2D$A.DA2D3A.A$.A2.2A2D3.A$2.A7.A$7.A$4.A.A$
.A$2.A.A!
Last edited by PHPBB12345 on February 12th, 2018, 8:34 pm, edited 1 time in total.
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Re: Solitaire of Life

Postby BlinkerSpawn » February 12th, 2018, 8:28 pm

A for awesome wrote:EDIT: In case that's optimal, here's another challenge:
x = 12, y = 12, rule = LifeHistory
5.C2$3.C3.C$4.C.C$.C3.C$C5.C.C.C$.C3.C5.C$2.C7.C$7.C$4.C.C$.C$2.C.C!
#C [[ ANGLE 45 ]]

That one was... rather interesting to work on: (44)
x = 12, y = 15, rule = LifeHistory
4.AC$5.A$3.C2.AC$3.AC.C$.CA2.C2.A$C2.A2.CACAC$.C2.AC5.C$2.CA2.2A2.CA$
4.A2.C$4.CAC$.C$.ACAC$4.A$3.A$3.2A!
[[ ANGLE 45 ]]

EDIT: 42
x = 12, y = 13, rule = LifeHistory
5.CA$5.A$3.CA2.C$2.A.C.CA$.C3.C2.2A$C5.C.C.C$AC3.CA.A2.C$2.C.A2.A.AC$
2.A.A2.C$.2A.C.CA$.C2.A$2.C.C$3.A!
Last edited by BlinkerSpawn on February 12th, 2018, 9:04 pm, edited 2 times in total.
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Re: Solitaire of Life

Postby A for awesome » February 12th, 2018, 8:35 pm

BlinkerSpawn wrote:(44)
rle

Not optimal.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Solitaire of Life

Postby BlinkerSpawn » February 18th, 2018, 10:15 am

Never got word back on my 42-cell solution, so I'll go ahead and post this:
x = 5, y = 9, rule = LifeHistory
C3.C$.C.C$2.C$C3.C$.C.C$2.C$C3.C$.C.C$2.C!
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Re: Solitaire of Life

Postby gameoflifemaniac » February 18th, 2018, 10:29 am

BlinkerSpawn wrote:Never got word back on my 42-cell solution, so I'll go ahead and post this:
x = 5, y = 9, rule = LifeHistory
C3.C$.C.C$2.C$C3.C$.C.C$2.C$C3.C$.C.C$2.C!

31 cells:
x = 9, y = 12, rule = LifeHistory
2A.2A$2A.A$3.A2.A$3.E.A.E$4.E.E$5.E$3.E.A.E$2.A.E.E.A$2.A2.E2.A$3.E.A
.E$4.E.E$5.E!

EDIT: 26 cells:
x = 7, y = 11, rule = LifeHistory
2.2A$.A2.A$.E.A.E$2.E.E$3.E$.E.A.E$A.E.E.A$A2.E2.A$.E.A.E$2.E.E$3.E!

I think that's the smallest solution.
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Re: Solitaire of Life

Postby A for awesome » February 18th, 2018, 11:31 am

BlinkerSpawn wrote:Never got word back on my 42-cell solution

So sorry about that, I completely missed your edit. Is there some secret trick that I don't know about to be notified of edits to posts?

Anyway, I'm not 100% sure that 42 is optimal, given that I haven't verified with a search program, but it's the smallest I've been able to get:
x = 12, y = 12, rule = LifeHistory
4.AC$5.A$3.C2.AC$3.AC.C$.CA2.C2.A$C2.A2.CACAC$.C2.AC5.C$2.CA3.A2.CA$
4.A.AC$4.C.C$.CA.A.A$.AC.CA!

I'm surprised no one found my solution, as the "diagonalistic" nature of the puzzle should have been an obvious clue.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: Solitaire of Life

Postby wwei23 » April 17th, 2018, 9:11 pm

Can I post a puzzle?
EDIT:
My puzzle:
obbbo$bobob$obobo!
Replicator!
x = 3, y = 3, rule = B3/S234y
2bo$3o$bo!
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Re: Solitaire of Life

Postby danny » April 18th, 2018, 9:07 pm

Ahem, anyway, I've never created one of these, but here we go, an easy-but-kinda-tricky one:
x = 9, y = 11, rule = B3/S23
2o$obo2$2bobobo$5bobo$7b2o2$7bo2$6bo$4bo!

My lowest is 47 cells, but I'm a novice, so it can probably be reduced.
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Re: Solitaire of Life

Postby BlinkerSpawn » April 18th, 2018, 9:23 pm

danny wrote:Ahem, anyway, I've never created one of these, but here we go, an easy-but-kinda-tricky one:
x = 9, y = 11, rule = B3/S23
2o$obo2$2bobobo$5bobo$7b2o2$7bo2$6bo$4bo!

My lowest is 47 cells, but I'm a novice, so it can probably be reduced.

Two 28-cell solutions:
x = 25, y = 11, rule = LifeHistory
2C12.2C$C.C11.C.C.2A$2.A2.A10.A.A$2.C.C.C2.2A4.AC.C.C2.2A$3.A.C.C2.A
8.C.C2.A$5.A.2CA11.2CA$4.2A14.A$6.AC13.C$6.A12.A.A$4.A.C11.A.C$4.CA
12.CA!
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Re: Solitaire of Life

Postby A for awesome » April 18th, 2018, 10:27 pm

BlinkerSpawn wrote:Two 28-cell solutions:
x = 25, y = 11, rule = LifeHistory
2C12.2C$C.C11.C.C.2A$2.A2.A10.A.A$2.C.C.C2.2A4.AC.C.C2.2A$3.A.C.C2.A
8.C.C2.A$5.A.2CA11.2CA$4.2A14.A$6.AC13.C$6.A12.A.A$4.A.C11.A.C$4.CA
12.CA!

27-cell corollary snipe of #1:
x = 11, y = 11, rule = LifeHistory
2C$C.C$2.A2.A$2.C.C.C2.2A$3.A.C.C2.A$5.A.2CA$5.A$6.AC$7.A$4.2AC$4.C!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

http://conwaylife.com/wiki/A_for_all

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Re: Solitaire of Life

Postby wildmyron » April 19th, 2018, 12:10 am

wwei23 wrote:My puzzle:
obbbo$bobob$obobo!

This puzzle is impossible. There is no way to stabilise the centre cell (in red below) without causing one of it's neighbours to die. I suggest you at least create a solution yourself before posting another puzzle
x = 5, y = 3, rule = LifeHistory
C3.C$.CDC$C.C.C!
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