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Soup search results

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Re: Soup search results

Postby BlinkerSpawn » January 10th, 2017, 5:05 pm

This is as close as I know how to get:
x = 11, y = 12, rule = B3/S23
7b2o$o7b2o$2o7bo$2bo3bo$2o3b3o$o3bo$4bob2obo$5bobo2$8b3o2$8b3o!

EDIT: Eureka! (kinda):
x = 16, y = 15, rule = B3/S23
10bo$8b2o$9b2o$3o$2bo$3o3b3o$5bo2bo$5bob2o$6bo5bo$7bo2b2o$11b2o2$13b3o
$13bo$14bo!

EDIT 2: Assembled; 10 gliders:
x = 28, y = 24, rule = B3/S23
21bo$21bobo$21b2o$5bo6bo$6bo6bo$4b3o4b3o3$23bo$23bobo$3o20b2o$2bo$bo$
10b2o$11b2o$10bo3$17b2o$8b2o6b2o$9b2o7bo7b2o$8bo3b3o10b2o$12bo14bo$13b
o!
Last edited by BlinkerSpawn on January 10th, 2017, 7:31 pm, edited 1 time in total.
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Re: Soup search results

Postby mniemiec » January 10th, 2017, 7:22 pm

A recent soup produced a 26-bit P6 oscillator http://catagolue.appspot.com/object/xp6_45a2zw66w7bcczy366w4o68/b3s23. This made me think about clocks as rocks, and it occurred to me that I had previously overlooked one 21-bit P6 (one half of this one), plus one 20-bit P8 (the only 20-bit P8 of which I am aware). These two can be easily synthesized from 12 and 14 respectively, although the one from this soup forms too quickly to yield a viable predecessor, and an attempt to synthesize it by prute force is missing two steps (adding two close blocks). I think inserters exist to do this; I seem to recall somebody posting some syntheses that do something like this, but I can't find any examples. A way to add an adjacent clock would also prove useful, although the only one I know of does so with the stator cells aligned the other way.
x = 189, y = 88, rule = B3/S23
128bo$127bo$91bo35b3o12bo$91bobo46boo$91boo48boo$123bobo10bobo$91bo18b
oo12boo4boo4boo$90boo17bobbo11bo4bobbo4bo$90bobo16bobbo16bobbo$110boo
18boo$135bo$3bobo38bo89bo22boo$3boo39bobo16boo18boo18boo18boo9b3o16boo
bobboboo$4bo39boo17boobboo14boobboo14boobboo14boobboo24bo4bobboo$47b3o
17boo18boo18boo18boo28bo$o46bo108bo$boo19bo19bo5bo13bo19bo19bo19bo10b
oo17bo$oo20bobo17bobo17bobo17bobo17bobo17bobo7boo18bobo$4boo15bobo17bo
bo17bobo17bobo17bobo17bobo10bo16bobo$3boo18bo19bo19bo19bo19bo19bo29bo$
5bo$$bo$boo$obo6$164bo$162bobo5bo$163boo4bo$169b3o3$77bo99bobbo$78bo3b
o18boo13bo4boo18boo18boo17bo$76b3oboo18bobbo10bobo3bobbo12boobbobbo12b
oobbobbo12bo4bo$81boo17bobbo11boo3bobbo12boobbobbo12boobbobbo12boobbob
o$101boo9boo7boo18boo18boo18boboo$111bobo$o6bobo31bo71bo$boo4boo17bo
12bobo4bo14boo3bo14boo3bo14boo3bo14boo3bo14boo3bo14boo3bo14bo4bo$oo6bo
18boo11boo5boo12boo4boo12boo4boo12boo4boo12boo4boo12boo4boo12boo4boo
12boo4boo$5bo6boo11boo10boo6boo18boo18boo18boo18boo18boo18boo18boo$5b
oo4boo14bo8bobo8bo19bo19bo19bo19bo19bo19bo19bo$4bobo6bo24bo15$43bo$41b
oo$42boo$$29bobo$30boo$30bo$$144bo$142bobo5bo$56bo19bo19bo39bo6boo4bo
16bo$54bobo17bobo3bo13bobo37bobo12b3o12bobo$55bobo17bobobbobo12bobo37b
obo27bobo$55bo19bo4boo13bo39bo29bo$170bo$81bo19boo38boo27bo$30b3o48boo
17bobbo32boobbobbo22bo4bo$32bo5bo41bobo17bobbo11bobobo16boobbobbo22boo
bbobo$31bo4bobo62boo38boo28boboo$37boobboo$o6bobo32boo$boo4boo17bo14bo
4bo19bo19bo19bo34boo3bo24bo4bo$oo6bo18boo18boo18boo18boo18boo32boo4boo
22boo4boo$5bo6boo11boo18boo18boo18boo18boo38boo28boo$5boo4boo14bo19bo
19bo19bo19bo39bo29bo$4bobo6bo!

EDIT:
BlinkerSpawn wrote:This is as close as I know how to get: ... Eureka! (kinda): ...

This yields a 10-glider synthesis. Unfortunately, replacing the house by an attached beehive or loaf isn't as simple as I had previously thought. (A beehive could be turned into the others).
x = 109, y = 24, rule = B3/S23
21bobo$21boo$22bo$4bo6bo$5boo5boo$4boo5boo$39boo20bo19bo18boo$39bobo
18bobo17bobo16bobbo$23bobo15bo18bobo16bobbo17bobo$23boo14boboboo16bob
oo15booboo16boboo$oo22bo14boobbobb3o14bobb3o14bobb3o14bobb3o$boo40bo
19bo19bo19bo$o43boobo16boobo16boobo16boobo$10boo36bo19bo19bo19bo$9bobo
35boo18boo18boo18boo$11bo3$17boo$8boo7bobo$7bobo7bo8boo$9bo3boo11bobo$
12boo12bo$14bo!

(EDIT: Apparently, you solved it exactly the same way!)
Last edited by mniemiec on January 10th, 2017, 7:57 pm, edited 1 time in total.
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Re: Soup search results

Postby Extrementhusiast » January 10th, 2017, 7:49 pm

This was my far more expensive approach:
x = 23, y = 16, rule = B3/S23
8bo5bobo$6bobo6b2o$7b2o6bo5bo$20bo$20b3o$11b2ob2o$11bo3bo$o11b3o7bo$b
2o17b2o$2o19b2o$4b2o6b3o$5b2o4bo3bo$4bo6bob2obo$12bobo2bo$15bobo$16bo!

I also found a way to get there from one of the other variants:
x = 21, y = 18, rule = B3/S23
9bobo$9b2o$10bo8bo$2o16bo$o3b2o12b3o$bobobo6bo$5bob2o3bobo2bo$3ob2obob
o2b2o2b2o$7bobo6bobo$7b2o4$6b2o$7b2o$6bo5bo$11b2o$11bobo!
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Re: Soup search results

Postby Goldtiger997 » January 12th, 2017, 8:37 am

Can anyone use any of these reductions of symmetric soups for a better synthesis of french kiss?:

x = 26, y = 21, rule = B3/S23
obo$b2o$bo4$7bo9bo$7b2o6bobo$5b3o8b2o$6bo$18bo$7b2o8b3o$7bobo6b2o$7bo
9bo4$23bo$22b2o$22bobo!


x = 34, y = 30, rule = B3/S23
2$3b3o8$7bo$6bobo$5bo2bo9b2o$6b2o3b2o4bobo$11bobo2b2o$13b2o2bobo$11bob
o4b2o3b2o$11b2o9bo2bo$22bobo$23bo8$25b3o!


x = 34, y = 24, rule = B3/S23
3$3bo$2bobo$2bobo$3bo3$26bo$5b2o20bo$4bo2bo$4bo2bo17b2o$4b2o17bo2bo$
23bo2bo$3bo20b2o$4bo3$27bo$26bobo$26bobo$27bo!


x = 61, y = 34, rule = B3/S23
2$31b2o$32bo$7b2o19b2ob2o$6b3o20bobo$5b5o20bo$4b2o3b2o$5b2obo3bobo$6b
2o$7bob2o2bob3o$11b3obo2b2o$21bo$19b2obo$16bo4b2o24b2o$16b2o24b2o4bo$
42bob2o$43bo$45b2o2bob3o$47b3obo2b2obo$57b2o$50bobo3bob2o$54b2o3b2o$
34bo20b5o$33bobo20b3o$32b2ob2o19b2o$32bo$32b2o!


x = 29, y = 19, rule = B3/S23
4$19b2o$11b2o5bo2bo$10bo2bo4bo2b2o$3b2o5bo2bo3bo2b2o$2bo2bo5b2o4b4o$3b
2o$24b2o$8b4o4b2o5bo2bo$7b2o2bo3bo2bo5b2o$6b2o2bo4bo2bo$7bo2bo5b2o$8b
2o!
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Re: Soup search results

Postby BlinkerSpawn » January 12th, 2017, 11:14 am

Sure, 18G:
x = 110, y = 90, rule = B3/S23
40bo$38b2o$39b2o25$12bo$obo7b2o$b2o8b2o$bo3$11bo$9b2o$10b2o2$3bo9bo$4b
2o6bo$3b2o7b3o$72bo20b2o$73bo19bo$14bo15bo40b3o16b2obo$15bo13bo45b2o
12bo2bo$13b3o13b3o42bo2bo11bo14b2o$9b3o13b3o47b2o14bo11bo2bo$11bo13bo
62bo2bo12b2o$10bo15bo60bob2o16b3o$87bo19bo$86b2o20bo$26b3o7b2o$28bo6b
2o$27bo9bo2$29b2o$30b2o$29bo3$39bo$28b2o8b2o$29b2o7bobo$28bo25$2o$b2o$
o!
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Re: Soup search results

Postby AbhpzTa » January 12th, 2017, 3:45 pm

10G:
x = 57, y = 46, rule = B3/S23
55bo$54bo$4bo49b3o$2bobo$3b2o2$37bo16bo$36bo15b2o$36b3o14b2o2$37bo$36b
2o$36bobo21$18bobo$19b2o$19bo2$2b2o14b3o$3b2o15bo$2bo16bo2$52b2o$52bob
o$3o49bo$2bo$bo!
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Re: Soup search results

Postby mniemiec » January 12th, 2017, 4:51 pm

Goldtiger997 wrote:Can anyone use any of these reductions of symmetric soups for a better synthesis of french kiss?: ...

BlinkerSpawn wrote:Sure, 18G: ...

From 16, based on predecessor #3:
x = 126, y = 30, rule = B3/S23
39bo$37boo$38boo$77bo$78bo$76b3o$50boo28boo$9bobo21bo15bobbo26bobbo$3b
o5boo20boo17boo28boo$4boo4bo21boo$3boo52boo28boo28boo$11bo46bo29bo29bo
$12bo16bobo9boo15boboo26boboo26boboo$10b3o17boo8boo17bobbo26bobbo26bo
bbo$30bo11bo19bo29bo29bo$o11bo47bo29bo29bo$boo8boo17b3o27bobbo26bobbo
26bobbo$oo9bobo16bo30boobo26boobo26boobo$31bo32bo29bo29bo$38boo24boo
28boo28boo$9boo21bo4boo$10boo20boo5bo31boo28boo$9bo21bobo36bobbo26bobb
o$71boo28boo$104b3o$104bo$105bo$3boo$4boo$3bo!

EDIT:
AbhpzTa wrote:10G: ...

(oops!) Nice! This also reduces 1 20- and the 2 21-bit variants to < 1 glider/bit.
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Re: Soup search results

Postby Goldtiger997 » January 13th, 2017, 10:09 pm

AbhpzTa wrote:10G:
x = 57, y = 46, rule = B3/S23
55bo$54bo$4bo49b3o$2bobo$3b2o2$37bo16bo$36bo15b2o$36b3o14b2o2$37bo$36b
2o$36bobo21$18bobo$19b2o$19bo2$2b2o14b3o$3b2o15bo$2bo16bo2$52b2o$52bob
o$3o49bo$2bo$bo!


Very nice!

I'm reposting something I already posted in the birthdays thread because I did not think it was actually a suitable thread.

Here is an 18-20 glider synthesis of trans-skewed poles which I think previously had no synthesis:

x = 106, y = 96, rule = B3/S23
14bo$12bobo$13b2o9$2bo$obo$b2o15$67bo$65b2o$56bo9b2o$57b2o$56b2o$60bo$
60bobo$46bo13b2o$47bo$45b3o2bo$49bobo$49bobo$50bo5$54bo$54bo$54bo$51bo
$51bo$51bo5$55bo$54bobo$54bobo$55bo2b3o$58bo$44b2o13bo$43bobo$45bo$48b
2o$47b2o$38b2o9bo$39b2o$38bo15$103b2o$103bobo$103bo9$91b2o$91bobo$91bo
!
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Re: Soup search results

Postby mniemiec » January 14th, 2017, 3:05 am

Goldtiger997 wrote:Here is an 18-20 glider synthesis of trans-skewed poles which I think previously had no synthesis: ...

Extrementhusiast had previously posted this 20-glider synthesis on 2015-08-06. Either yours or his would be cheaper if there were appropriate 3-glider syntheses of the beehive+blinker constellations.
x = 235, y = 32, rule = B3/S23
112bobo$113boo8bo$113bo10bo$122b3o$126bo$47bo78bobo$48boo76boo6bo$47b
oo83boo$121bo11boo$45bo36bo29bo9bo$45boo35bo29bo7b3o$4bo39bobo35bo29bo
40boo38boo28boo$5bo19bo29bo29bo29bo37bo32bo6bo29bo$3b3o18bobo27bobo27b
obo27bobo37bobo27bobo7bobo27bobo$16bo7bobo27bobo27bobo27bobo32boo5boo
11boo14boobboo5boo11boo15boo$3o12bo9bo29bo29bo29bo34bo6bobbo9bo19bo6bo
bbo9bo16bobbo$bbo12b3o14bo29bo29bo29bo24bo9bobbo6bo19bo9bobbo6bo19bobb
o$bo29bobo27bobo27bobo27bobo23boo11boo5boo18boo11boo5boobboo17boo$12b
3o16bobo27bobo27bobo27bobo37bobo37bobo7bobo17bobo$12bo19bo29bo29bo29bo
41bo39bo6bo22bo$13bo57bobo21bo29bo37boo38boo28boo$71boo22bo19b3o7bo$
72bo22bo19bo9bo$103boo11bo$69boo33boo$68boo33bo6boo$70bo38bobo$111bo$
113b3o$113bo10bo$114bo8boo$123bobo!

EDIT: FYI, the only known period 3+ oscillators up to 21 bits lacking syntheses are these 5 P3s and 1 P4:
x = 112, y = 10, rule = B3/S23
o19booboo15boo5boo11boo18boo18boo8boo$3o4booboo8bo4booboo10bo5bobo11bo
19bo19bobo4boobbo$3boboo4bo9boo6bo11boboobboo12bobo17bobo17b3obo$bbo6b
oo13bobobo14bo26bo32bo3b3o$bboobobo16bo4b3o16bobo11bobo3b3o11bobo22bo$
7bo23bo11bobo3boo11bo4bo14bo4boo15bobo$44bo19bobobo15bobobo17bo$63boo
bboo14boobbo$88b3o$90bo!
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Re: Soup search results

Postby Goldtiger997 » January 14th, 2017, 3:35 am

mniemiec wrote:
Goldtiger997 wrote:Here is an 18-20 glider synthesis of trans-skewed poles which I think previously had no synthesis: ...

Extrementhusiast had previously posted this 20-glider synthesis on 2015-08-06. Either yours or his would be cheaper if there were appropriate 3-glider syntheses of the beehive+blinker constellations.
Extrementhusiast's synthesis

...


I wrote:...Here is an 18-20 glider synthesis of trans-skewed poles which I think previously had no synthesis:

x = 106, y = 96, rule = B3/S23
14bo$12bobo$13b2o9$2bo$obo$b2o15$67bo$65b2o$56bo9b2o$57b2o$56b2o$60bo$
60bobo$46bo13b2o$47bo$45b3o2bo$49bobo$49bobo$50bo5$54bo$54bo$54bo$51bo
$51bo$51bo5$55bo$54bobo$54bobo$55bo2b3o$58bo$44b2o13bo$43bobo$45bo$48b
2o$47b2o$38b2o9bo$39b2o$38bo15$103b2o$103bobo$103bo9$91b2o$91bobo$91bo
!


However, the beehives in my synthesis are not necessary because they are made just to create r-pentominos. Possibly one of the other "still-life + glider = r-pentomino" collisions could be used such that the constellation with that still life and the blinker could be made in 3-gliders.


P.S. It bothers me that currently the hexapole can be synthesised in 8 gliders whereas the pentapole takes 10 gliders.
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Re: Soup search results

Postby mniemiec » January 14th, 2017, 4:43 am

Goldtiger997 wrote:However, the beehives in my synthesis are not necessary because they are made just to create r-pentominos. Possibly one of the other "still-life + glider = r-pentomino" collisions could be used such that the constellation with that still life and the blinker could be made in 3-gliders.

I only know of 3 within the budget - one loaf+glider, your beehive+glider, and another beehive+glider that fails because the glider hits the blinker, and no way to make either+blinker from 3 gliders. Others may have more extensive R-pentomino or 3-glider-to-constellation libraries.
Goldtiger997 wrote:P.S. It bothers me that currently the hexapole can be synthesised in 8 gliders whereas the pentapole takes 10 gliders.

Bob Shemyakin found a 5-glider quadpole synthesis on 2015-03-28, making pentapole 9 gliders:
x = 67, y = 22, rule = B3/S23
bo$bobo$boo$$bo$bbo4bo11boo18boo18boo$3o4bobo9bobo17bobo17bobo$7boo$
21bobo17bobo17bobo$$23bobo17bobo17bobo$3o21boo18boo20bo$bbo5b3o54boo$b
o6bo42bobo$9bo41boo$52bo$$37b3o12boo$39bo12bobo$38bo9bo3bo$48boo$47bob
o!
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Re: Soup search results

Postby mniemiec » January 14th, 2017, 7:41 pm

Extrementhusiast wrote:I also found a way to get there from one of the other variants: ...

This made me think about other ways to make the remaining 19-bit variant (that can be turned into the 20-bit loaf ones that yield the missing 25-bit molds and 26-bit jams). From the "close but no cigar" department. Maybe somebody can finish/rescue this:
x = 239, y = 24, rule = B3/S23
14bo$bbo12boo$obo11boo3bo48bobo$boo8bo7bobo47boo$9bobo7boo48bo57bo$10b
oo114bo66bo$73b4o49b3o64bobo$69bo3bo3bo25boo18boo22bobobo41boo26bobobo
$17bo51bobobo29boo18boo21bo5bo67bo5bo$17bobo20boo18boo7boo3bobbo12boo
6boo10boo6boo10boo6boo20boo6boo10boo6boo10boo11boo15boo$17boo21bo19bo
29bo6bobo10bo6bobo10bo6bobo12bo7bo6bobo10bo6bobo10bo6boo4boo11bo3bo$
28bo12boboo16boboo26boboobbo13boboobbo13boboobbo11bobo9boboobbo13boboo
bbo13boboo18bobo5boboo$26boo17bo19bo29boboo16boboo16boboo26boboo16bob
oo4boo10bo29bo$4bo22boo11b3obbobboo10b3obbobboo20b3obbo14b3obbo14b3obb
o13bo10b3obbo14b3obbo7bobo4b3obbo17bo6b3obbo$4boo38boobobo14boobobo24b
oo18boo18boo28boo18boo7bo10boo28boobo$3bobo41bo19bo98boo18boo18bobo27b
obo$47bobo17bobo79bo16bobo17bobo17bobo14bo12bobo$48boo18boo97bo19bo3b
oo14bo29bo$16boo5boo165boo$15boo5boo162boo4bo$17bo6bo48boo110bobo$6bo
65boo113bo$6boo66bo$5bobo!
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Re: Soup search results

Postby Kazyan » January 15th, 2017, 2:23 am

Another "sparse" p2 has appeared: https://twitter.com/conwaylifebot/statu ... 5856801793

If Mark's site is correct, this is one of the 13 unsynthesized 16-bit oscillators. Proof of concept synthesis, but not a practical one:

x = 18, y = 23, rule = B3/S23
4bo$4bo$4bo4$16bo$15bo$6bo8b3o$5bobo5bo$5bobo4bobo$6bo5bobo$obo10bo$b
2o$bo4$8bo$7b2o$2b2o3bobo$3b2o$2bo!


If there is a component to shorten a barberpole, it also solves one of the three remaining 15-bit oscillators (again according to Mark's site).

EDIT: It's not up-to-date with regards to the 15-bit oscillators, but I still can't tell if this one has been checked off.
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Re: Soup search results

Postby mniemiec » January 15th, 2017, 4:19 am

Kayzan wrote:Another "sparse" p2 has appeared: ... If Mark's site is correct, this is one of the 13 unsynthesized 16-bit oscillators.
Proof of concept synthesis, but not a practical one: ...

When there is no synthesis yet, even a ludicrously expensive one is good!
Kayzan wrote:If there is a component to shorten a barberpole, it also solves one of the three remaining 15-bit oscillators (again according to Mark's site).

Sadly, there is no such component known yet, and it would likely be very difficult. When I discussed this topic with Dave Buckinhgam years ago, he said that lengthening a barber pole was relatively easy (he had several converters to do so, and I found several other related ones), but that I would not likely find a way to shorten one.
Kayzan wrote:It's not up-to-date with regards to the 15-bit oscillators, but I still can't tell if this one has been checked off.

FYI, here is my current list of unsynthesized P2s up to 18 bits: 1 14, 2 15s, 6 16s, 24 17s, and 52 18s. Of these, the last 16, 6 of the 17s, and the last 22 18s are trivial, applying grow-barberpole converter to a smaller unsynthethesized one.
x = 149, y = 114, rule = B3/S23
bb3o11boo13boo13boo13boo4boo7boo16bo13bobo10boo$16bobob3o8boboboo9bobo
bb3o7bobo4bo7bobob3o9bobobo11bobboo8bobobo$boobbobo28bo28bobo24bo5bo7b
obboo14bo$6bo9bobbobo10bobbo10bobboobo8bobbo11bobbobo9bobo4bobo11boo9b
obbo$bbo4boo8bo4bo10bo13bo5bo8bo3b3o8bo15bo5bo6boo14bo$4bo12bo3boo10bo
bobo9bo4boo8bo14bo3bobo11bobobo12bo9boobobo$4bobo29boo44boo13bo10bobo
17bo$110bo16boo6$boo5boo6boo5boo6boo4bo8boo3b3o7boobboo9boobboo10bobb
3o8boo13boo13boo$bobo3bobo6bobo3bobo6bobobobboo6bo14bobbobo9bobobbo10b
o13bo6boo6bobo12bobobb3o$35bo11boboobo9bo17bo10bobbobboo8bobo4bo12b3o$
3bobobo8bobboobo10bo3bo27bo11bo33bobo9bobo10bobboobo$17bo14bo13b3o3bob
o6bobo12bobbobo9bobobobbo8bobbo15bobo8bo$bb3ob3o8bo3b3o8boob3o15boo6bo
bobboo8boo4bo8boo3bo11bo3b3o7b3o4bo7bo4bobo$61bo3bo15boo13bo11bo19boo
13boo7$boo13boobb3o8b3o12b3o12boo13boobb3o11bo11boo13boo13boo$bobobo
10bo36boo6bobbobo9bo17boboboo6bobo12bobo3bo8bobob3o$5bobo9bobobboo8bob
oob3o7boboobobo8bobbobo8bobobboo8bo6bo27bo$3bo5bo21bo14bo21bo29bo7bobb
oob3o8bobobbo7bobbobo$bbo6bo8bobbobbo6boo3bobo7boo3bobbo7boo4bo9bo3bo
8boo14bo29bo$bboobobobo9bo3bo15bo13bo11boo13bo16bobo7bo3bobo8b3obobo8b
o3bobo$7bo11bo3bo14boo13bo9boo11boobbo12bobobboo14bo14bo14bo$65bo12bo
16bo17boo13boo13boo6$bboo13boo12boo13boo13boo4boo7boo3bo9boo5bo7boo3bo
bo8bo3bo9boo$bbobo12bobo11bo3boo9bobo12bobo4bo7bo4bo9bo6bo7bo4bo10bobo
bboo7bobobboo$21bo10bobobo13bo14bobo9bobobbo9bobobobbo7bobo4boo6bobo
15bobo$bbobboo10bo3bo26bobboo10bo49bo12bo11bo$7bo14bo9boobbo29bo10bo3b
obo8bobbobobo7bo3bo11bo17bo$boo13boo16bo13bobobo9bobobbo8bobbobobo9bo
6bo5bobbobo13bobo9bobo$7bobo12bobo11bobo9boo12boobboo8boo5bo9bo5boo5b
oo13boobbobo9boobbobo$3bobobboo8bobobboo14bo12bobo68bo3bo14boo$5bo14bo
17boo13boo5$boo4bo10bo12boo4bo9bo14bo14bo3bo9boo13boo3bo9bo3bo14bo$bob
o3bo10bo4boo6bo5bo9bo6boo6bobo12bo3bobo7bobo5boo5bo4bobo7bo3bobo12bobo
$5bobbo7bobbo4bo7bobobobbo6bobbo3bobo6bobobo9bobbo20bo6bobo10bobbo14bo
5bobo$3bo17bobo44bo15boo5bobboobobo14boo12boo6boo6bo$6boo8boobbo11bobb
obboo6boboboobo9bo4bobo6boo13bo15bo12boo17bo6boo$bbobo17b3o8bo12boo14b
o6bo14bo7bo3bobbo7bo6bo12bobbo7bobo5bo$bboobb3o8b3o13bobb3o13b3o7boobo
bobo6b3obobo15bo8boobobo10bobo3bo12bobo$67bo14bo15bo13bo12bo3bo14bo6$
bboo12boo13boobo13boo12bo14boo12boo13boo15bobo$bbobo11bobobobo8bo3boo
12bo12bo14bobo11bobo12bobo16bo12bobo$6bo13bo11bo15bo3bo8bobbo16bobo37b
oo4bo12bo$bbobbobo10bo4boo9bo3boo10bobobo14boo6bo3bo9bobboo3bo6bobboo
3boo7bo4boo6boo4bo$7bo14bo11bo4bo6boo6bo6boboboobobo13boo6bo6bo7bo7bo
22bo4boo$boo15boobobo11boobo14bobo5boo13boo5bo8bo3boobbo6bo3boobo9boo
4bo9bo$7bobo37bo5bo13bobbo11bobo41bo4boo7bo4bo$3bobobboo7b3o17b3o9bobo
17bo8bobo17bobo12b3o12bo12bo4boo$5bo43bo19bo10bo18boo27bobo12bo$143bob
o4$bbobo14bo14bo14bo11boo6boo5boobboo9boo13boo13boo13boo$4bo14bobo12bo
bo12bobo9bobo6bo5bobobbo9bobo12bobo12bobo5bo6bobo5bo$oo4bo10bo14bo5bo
8bo5bo13bobo10bo18boo11b3o14bo10bobobo$bbo19boo14bo14bo9bobo11bo15bobo
4bo7bobo12bobobobbo7bo3bobo$6boo8boo6bo6boo6bo6boo6bo11bobbo6bobbobo
15bobo11bobo$3boo57b3o3bo7boo15bobbo10b3o13bobbobobo7bobobbo$8bo9bo6b
oo6bo6boo6bo6boo11bo12bobo10bo3b3o12bobo8bo4boo7boobbo$4bo4boo8boo13bo
14boo31boo10bo19boo8bo17bo$6bo18bo8bo5bo14bo$6bobo12bobo12bobo12bobo$
23bo14bo14bo3$boo13boo13boo13boo4bo8boo4bo8boo4bo8boo13boo4bo8boo13boo
$bobo5boo5bobo5boo5bobo4bo7bo5bo8bo5bo8bobo3bo8bobo12bo5bo8bobo12bobo$
10bo14bo12bo8bobobobbo7boboobbo11bobbo11bobo9bobobobbo$3bobobobo8bobob
obo8boboobbo36bobbo13bo3bo25bobo3boo5bobboob3o$49bo3boo6b3obbobo8bo3bo
bo15bo9bo3boo15bo6bo$3bobbob3o6b3obobbo7b3obbobo37bo15bobo4boo20b3oboo
bo7bo3bobo$4bo18bo16bo8b3ob3o12bobo12bobo7boobbo10bobobo$4bo18bo15boo
28boo13boo11bobo8bobo17b3o12bobo$108bo35boo5$boo13boo3bo9boo3bo9boo3bo
9boo13boo$bobo3bo8bo4bo9bo4bobo7bo4bobo7bobo12boboboo$7bo9bobobbo9bobo
12bobo15bo15bo$3bobobbo30boo13boo7bobboo9bobbo$16b3obobo11bo14bo28bo$
bb3obobo26bo3bo10boobbo8bobobo10bobobo$22bobo10bo27boo$8bobo14bo11bobo
12bobo12bobo12bobo$9boo13boo12boo13boo15bo14bo$69boo13boo!
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Re: Soup search results

Postby Extrementhusiast » January 15th, 2017, 10:03 pm

That one other P2 variant mentioned recently:
x = 194, y = 38, rule = B3/S23
142bo$64bo76bo$65bo75b3o$63b3o73bo$67bo72bo$67bobo68b3o$67b2o$114bo$
113bo26bobo$2o53b2o44b2o6b2o2b3o14b2o8b2o15b2o26b2o$o17b2o35bo17b3o25b
o6bo2bo18bo10bo15bo27bo$bob2o3b2o4b2ob2o37bob2o3b2o8bo28bob2o2bob2o19b
ob2o23bob2o24bob2o$5bobobo3bobo3bo40bobobo9bo31bobo26bo7bo18bo27bo$3o
2bobo5b2o40b3o2bobo38b3o2bobo21b3o2bo7bobo11b3o2bo22b3o2bo$4b2ob2o20bo
29b2ob2o41b2ob2o24b2ob2o4b2o16b2obo24b2obo$29bobo29bo2bo42bo2bo25bo2bo
23bobo25bobo$13b2o14b2o30bobo43bobo26bobo24bo2bo24bobo$b2o9bo2bo46bo
45bo28bo16bo9bobo25bo$o2bo8bo2bo139b2o8bo$o2bo3b2o4b2o139b2o$b2o4bobo
103bo28bo$7bo105bo28bo27bo$14b2o97bo28bo27bo$4bo9bobo153bo$4b2o8bo45b
3o46b3o3b3o20b3o3b3o10bo$3bobo151b2o7b3o3b3o$64b2o47bo28bo13bobo4b2o$
63bo2bo46bo28bo21b2o4bo$63bo2bo46bo28bo20bo6bo$64b2o104bo2$62bo$62b2o$
61bobo2$76b3o$76bo$77bo!

It's probably possible to get to the traffic light with only two cleanup gliders, although that would probably require a computer search.

mniemiec wrote:
Kayzan wrote:If there is a component to shorten a barberpole, it also solves one of the three remaining 15-bit oscillators (again according to Mark's site).

Sadly, there is no such component known yet, and it would likely be very difficult. When I discussed this topic with Dave Buckinhgam years ago, he said that lengthening a barber pole was relatively easy (he had several converters to do so, and I found several other related ones), but that I would not likely find a way to shorten one.


I found a way, although it isn't applicable here:
x = 15, y = 27, rule = B3/S23
5bo$5bobo$5b2o2$o$b2o$2o3$10b2o$9bobo$b2o$obo4bobo4bo$2bo3bo5b2o$6b2o
5b2o6$3o9bo$2bo8b2o$bo9bobo2$6b2o$6bobo$6bo!


However, based off of the predecessor, here is a final step for the 15-bit version:
x = 32, y = 29, rule = B3/S23
31bo$29b2o$30b2o$7bo$8b2o13bo$7b2o3bobo6b2o$12b2o8b2o$13bo2$6bo$4bobo
10b2o$b2o2b2o9bobo$obo8bo4bo$2bo7bobob2obo$10bob2obobo5b2o$8b2obo4bo5b
2o$8bo2bo12bo$2bo6b2o$2b2o$bobo$14b2o$13bobo$15bo4b2o$20bobo$20bo2$13b
2o$12bobo$14bo!


EDIT: The prior steps:
x = 184, y = 34, rule = B3/S23
125bobo$125b2o$126bo$110bo$111b2o15bobo$110b2o16b2o$129bo4$83bo29bo$
18bo65b2o28bo42bo$18bobo62b2o27b3o40b2o$18b2o136b2o$83bo26b2o$9bobo71b
2o24bobo40b2o$10b2o10b2o38b2o18bobo6b2o18bo7b3o5b2o24bo5b2o21b2o$10bo
10bobo20bo16bobo26bobo33bobo18b2o3bo5bobo20bobo$21bo23b2o14bo28bo35bo
19bobo3b2o4bo17bo4bo$obo14bob2obo21b2o11bob2obo23bob2obo30bob2obo20bo
5bob2obo15bobob2obo$b2o2b2o10b2obobo34b2obobo23b2obobo30b2obobo26b2obo
bo15bob2obobo$bo2bobo14bo33b2o4bo22b2o4bo29b2o4bo25b2o4bo14b2obo4bo$6b
o47bobo26bobo33bobo29bobo19bo2bo$55bo26bobo33bobo29bobo21b2o$82b2o34b
2o30b2o$10b3o$12bo133bo5b2o$11bo134b2o4bobo$18b3o124bobo4bo$18bo29bo$
19bo27b2o$43bo3bobo$44b2o$43b2o!
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Re: Soup search results

Postby Goldtiger997 » Yesterday, 9:08 pm

mniemiec wrote:...
FYI, here is my current list of unsynthesized P2s up to 18 bits: 1 14, 2 15s, 6 16s, 24 17s, and 52 18s. Of these, the last 16, 6 of the 17s, and the last 22 18s are trivial, applying grow-barberpole converter to a smaller unsynthethesized one.
x = 149, y = 114, rule = B3/S23
bb3o11boo13boo13boo13boo4boo7boo16bo13bobo10boo$16bobob3o8boboboo9bobo
bb3o7bobo4bo7bobob3o9bobobo11bobboo8bobobo$boobbobo28bo28bobo24bo5bo7b
obboo14bo$6bo9bobbobo10bobbo10bobboobo8bobbo11bobbobo9bobo4bobo11boo9b
obbo$bbo4boo8bo4bo10bo13bo5bo8bo3b3o8bo15bo5bo6boo14bo$4bo12bo3boo10bo
bobo9bo4boo8bo14bo3bobo11bobobo12bo9boobobo$4bobo29boo44boo13bo10bobo
17bo$110bo16boo6$boo5boo6boo5boo6boo4bo8boo3b3o7boobboo9boobboo10bobb
3o8boo13boo13boo$bobo3bobo6bobo3bobo6bobobobboo6bo14bobbobo9bobobbo10b
o13bo6boo6bobo12bobobb3o$35bo11boboobo9bo17bo10bobbobboo8bobo4bo12b3o$
3bobobo8bobboobo10bo3bo27bo11bo33bobo9bobo10bobboobo$17bo14bo13b3o3bob
o6bobo12bobbobo9bobobobbo8bobbo15bobo8bo$bb3ob3o8bo3b3o8boob3o15boo6bo
bobboo8boo4bo8boo3bo11bo3b3o7b3o4bo7bo4bobo$61bo3bo15boo13bo11bo19boo
13boo7$boo13boobb3o8b3o12b3o12boo13boobb3o11bo11boo13boo13boo$bobobo
10bo36boo6bobbobo9bo17boboboo6bobo12bobo3bo8bobob3o$5bobo9bobobboo8bob
oob3o7boboobobo8bobbobo8bobobboo8bo6bo27bo$3bo5bo21bo14bo21bo29bo7bobb
oob3o8bobobbo7bobbobo$bbo6bo8bobbobbo6boo3bobo7boo3bobbo7boo4bo9bo3bo
8boo14bo29bo$bboobobobo9bo3bo15bo13bo11boo13bo16bobo7bo3bobo8b3obobo8b
o3bobo$7bo11bo3bo14boo13bo9boo11boobbo12bobobboo14bo14bo14bo$65bo12bo
16bo17boo13boo13boo6$bboo13boo12boo13boo13boo4boo7boo3bo9boo5bo7boo3bo
bo8bo3bo9boo$bbobo12bobo11bo3boo9bobo12bobo4bo7bo4bo9bo6bo7bo4bo10bobo
bboo7bobobboo$21bo10bobobo13bo14bobo9bobobbo9bobobobbo7bobo4boo6bobo
15bobo$bbobboo10bo3bo26bobboo10bo49bo12bo11bo$7bo14bo9boobbo29bo10bo3b
obo8bobbobobo7bo3bo11bo17bo$boo13boo16bo13bobobo9bobobbo8bobbobobo9bo
6bo5bobbobo13bobo9bobo$7bobo12bobo11bobo9boo12boobboo8boo5bo9bo5boo5b
oo13boobbobo9boobbobo$3bobobboo8bobobboo14bo12bobo68bo3bo14boo$5bo14bo
17boo13boo5$boo4bo10bo12boo4bo9bo14bo14bo3bo9boo13boo3bo9bo3bo14bo$bob
o3bo10bo4boo6bo5bo9bo6boo6bobo12bo3bobo7bobo5boo5bo4bobo7bo3bobo12bobo
$5bobbo7bobbo4bo7bobobobbo6bobbo3bobo6bobobo9bobbo20bo6bobo10bobbo14bo
5bobo$3bo17bobo44bo15boo5bobboobobo14boo12boo6boo6bo$6boo8boobbo11bobb
obboo6boboboobo9bo4bobo6boo13bo15bo12boo17bo6boo$bbobo17b3o8bo12boo14b
o6bo14bo7bo3bobbo7bo6bo12bobbo7bobo5bo$bboobb3o8b3o13bobb3o13b3o7boobo
bobo6b3obobo15bo8boobobo10bobo3bo12bobo$67bo14bo15bo13bo12bo3bo14bo6$
bboo12boo13boobo13boo12bo14boo12boo13boo15bobo$bbobo11bobobobo8bo3boo
12bo12bo14bobo11bobo12bobo16bo12bobo$6bo13bo11bo15bo3bo8bobbo16bobo37b
oo4bo12bo$bbobbobo10bo4boo9bo3boo10bobobo14boo6bo3bo9bobboo3bo6bobboo
3boo7bo4boo6boo4bo$7bo14bo11bo4bo6boo6bo6boboboobobo13boo6bo6bo7bo7bo
22bo4boo$boo15boobobo11boobo14bobo5boo13boo5bo8bo3boobbo6bo3boobo9boo
4bo9bo$7bobo37bo5bo13bobbo11bobo41bo4boo7bo4bo$3bobobboo7b3o17b3o9bobo
17bo8bobo17bobo12b3o12bo12bo4boo$5bo43bo19bo10bo18boo27bobo12bo$143bob
o4$bbobo14bo14bo14bo11boo6boo5boobboo9boo13boo13boo13boo$4bo14bobo12bo
bo12bobo9bobo6bo5bobobbo9bobo12bobo12bobo5bo6bobo5bo$oo4bo10bo14bo5bo
8bo5bo13bobo10bo18boo11b3o14bo10bobobo$bbo19boo14bo14bo9bobo11bo15bobo
4bo7bobo12bobobobbo7bo3bobo$6boo8boo6bo6boo6bo6boo6bo11bobbo6bobbobo
15bobo11bobo$3boo57b3o3bo7boo15bobbo10b3o13bobbobobo7bobobbo$8bo9bo6b
oo6bo6boo6bo6boo11bo12bobo10bo3b3o12bobo8bo4boo7boobbo$4bo4boo8boo13bo
14boo31boo10bo19boo8bo17bo$6bo18bo8bo5bo14bo$6bobo12bobo12bobo12bobo$
23bo14bo14bo3$boo13boo13boo13boo4bo8boo4bo8boo4bo8boo13boo4bo8boo13boo
$bobo5boo5bobo5boo5bobo4bo7bo5bo8bo5bo8bobo3bo8bobo12bo5bo8bobo12bobo$
10bo14bo12bo8bobobobbo7boboobbo11bobbo11bobo9bobobobbo$3bobobobo8bobob
obo8boboobbo36bobbo13bo3bo25bobo3boo5bobboob3o$49bo3boo6b3obbobo8bo3bo
bo15bo9bo3boo15bo6bo$3bobbob3o6b3obobbo7b3obbobo37bo15bobo4boo20b3oboo
bo7bo3bobo$4bo18bo16bo8b3ob3o12bobo12bobo7boobbo10bobobo$4bo18bo15boo
28boo13boo11bobo8bobo17b3o12bobo$108bo35boo5$boo13boo3bo9boo3bo9boo3bo
9boo13boo$bobo3bo8bo4bo9bo4bobo7bo4bobo7bobo12boboboo$7bo9bobobbo9bobo
12bobo15bo15bo$3bobobbo30boo13boo7bobboo9bobbo$16b3obobo11bo14bo28bo$
bb3obobo26bo3bo10boobbo8bobobo10bobobo$22bobo10bo27boo$8bobo14bo11bobo
12bobo12bobo12bobo$9boo13boo12boo13boo15bo14bo$69boo13boo!


I mistakenly thought I found this p2 16-bit oscillator in the list above and found a synthesis for it:

x = 5, y = 8, rule = B3/S23
o2b2o$obobo$o$2bo$2bo$o$obobo$o2b2o!


It is quite a cheap synthesis so I'll post it anyway. What was the previously known synthesis?

Here it is 12 gliders:

x = 34, y = 61, rule = B3/S23
4$11bo$10bo$10b3o3$11bo$12b2o$11b2o$15b2o$14bobo$16bo4$17bo$17bobo$17b
2o$8bobo$9b2o$9bo3$6bo$7bo$5b3o2$2b3o$4bo$3bo2$15bo$14b2o$14bobo$6b2o$
5bobo$7bo3$20bo$19bo$19b3o$15b3o$15bo$16bo4$10b3o$10bo$11bo!


It kind of looks like the gliders would collide when rewound but in fact they don't:

EDIT:
Extrementhusiast wrote:...
EDIT: The prior steps:
prior steps that I had no luck constructing myself


Great!

That makes 42 gliders in total:

x = 417, y = 35, rule = B3/S23
295bobo$295b2o$296bo$280bo$281b2o15bobo$49bo230b2o16b2o$47bobo249bo
101bo$48b2o7bo341b2o$57bobo4bo335b2o$57b2o4bo313bo$63b3o110bo3bo78bo
23bo94b2o13bo$177bobo23bo56b2o22bo40bo51b2o3bobo6b2o$175b3ob3o21bobo
53b2o21b3o38b2o57b2o8b2o$67b2o134b2o119b2o57bo$57bo8b2o191bo20b2o$56bo
11bo19bo29bo29bo29bo15bobo62b2o18bobo38b2o54bo$56b3o28bobo27bobo27bobo
27bobo15b2o10b2o28b2o19bobo6b2o12bo7b3o5b2o22bo5b2o28b2o15bobo10b2o$
86bobo3b2o22bobo3b2o22bobo27bobo16bo10bobo10bo16bobo27bobo27bobo16b2o
3bo5bobo27bobo12b2o2b2o9bobo21b2o$54b2o30bo5b2o22bo5b2o22bo29bo29bo13b
2o14bo29bo29bo17bobo3b2o4bo24bo4bo13bobo8bo4bo23bobob3o$31b2o20bobo5b
2o19bob2obo24bob2obo24bob2obo24bob2obo7bobo14bob2obo11b2o11bob2obo24bo
b2obo24bob2obo18bo5bob2obo22bobob2obo14bo7bobob2obo$3o28b2o22bo5b2o19b
2obobo24b2obobo6b2o16b2obobo24b2obobo8b2o2b2o10b2obobo24b2obobo24b2obo
bo24b2obobo24b2obobo22bob2obobo22bob2obobo5b2o15bo2bobo$2bo83bo29bo7bo
bo19bo29bo9bo2bobo14bo23b2o4bo23b2o4bo23b2o4bo23b2o4bo21b2obo4bo21b2ob
o4bo5b2o17bo4bo$bo122bo66bo37bobo27bobo27bobo27bobo26bo2bo26bo2bo12bo
16bo3b2o$3b3o224bo27bobo27bobo27bobo28b2o21bo6b2o$3bo254b2o28b2o28b2o
52b2o$4bo190b3o173bobo$197bo116bo5b2o62b2o$196bo117b2o4bobo60bobo$203b
3o107bobo4bo64bo4b2o$203bo19bo166bobo$204bo17b2o166bo$218bo3bobo$219b
2o162b2o$218b2o162bobo$384bo!


Only one 15-bit oscillator left; muttering moat 1.

EDIT 2:

Here's one of the unsolved 17-bit p2s in 15 gliders:

x = 34, y = 55, rule = B3/S23
31bo$31bobo$31b2o8$10bobo$11b2o$11bo$19bobo$10bo8b2o$9bo10bo$9b3o$obo$
b2o10bobo$bo11b2o$14bo5$16bobo$16b2o$17bo$19b2o$19bobo$19bo4$14bo$bo
11b2o4b3o$b2o10bobo3bo$obo17bo$9b3o$9bo$10bo3$24bo$23b2o$23bobo$7bo$7b
2o$6bobo4$31b2o$31bobo$31bo!


EDIT 3:

Here's one of the unsolved 18-bit p2s in 16 gliders:

x = 49, y = 58, rule = B3/S23
11bo$12bo$10b3o4$15bo$13bobo$14b2o4$2bo$obo$b2o3$23bo$22bobo$22bo2bo$
23b2o6$36bo$15b2o19bobo$14bo2bo14b2o2b2o$11b2o2b2o14bo2bo$10bobo19b2o$
12bo6$24b2o$23bo2bo$24bobo$25bo3$46b2o$46bobo$46bo4$33b2o$33bobo$33bo
4$36b3o$36bo$37bo!
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Re: Soup search results

Postby chris_c » Today, 9:15 am

Extrementhusiast wrote:The prior steps


This gives a 5 glider reduction and yields 16.897 and 16.1086 in 14 and 13 gliders respectively:

x = 35, y = 44, rule = LifeHistory
29.A$23.A5.A.A$21.2A6.2A$15.A6.2A$13.A.A$14.2A10$3A$2.A$.A4$22.E.2E$
22.2E.E$20.2E$19.E.E$18.E.E$18.2E15$.2A30.2A$A.A29.2A$2.A31.A!
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Re: Soup search results

Postby AbhpzTa » 34 minutes ago

Goldtiger997 wrote:Here it is 12 gliders:

x = 34, y = 61, rule = B3/S23
4$11bo$10bo$10b3o3$11bo$12b2o$11b2o$15b2o$14bobo$16bo4$17bo$17bobo$17b
2o$8bobo$9b2o$9bo3$6bo$7bo$5b3o2$2b3o$4bo$3bo2$15bo$14b2o$14bobo$6b2o$
5bobo$7bo3$20bo$19bo$19b3o$15b3o$15bo$16bo4$10b3o$10bo$11bo!


It kind of looks like the gliders would collide when rewound but in fact they don't:


10G:
x = 23, y = 50, rule = B3/S23
12bo$11bo$11b3o3$12bo$13b2o$12b2o$16b2o$15bobo$17bo8$o$b2o$2o$14bo$12b
2o$13b2o3$13b2o$12b2o$3b2o9bo$4b2o$3bo8$21bo$20bo$20b3o$16b3o$16bo$17b
o4$11b3o$11bo$12bo!
AbhpzTa
 
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