x = 1, y = 4, rule = B2ce3iny5i/S02c
o$o2$o!
10soups/second
Would search, but I'm going to the mall today soon.
x = 1, y = 4, rule = B2ce3iny5i/S02c
o$o2$o!
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!
Saka wrote:Possibly smallest apgcode for a spaceship? (xq8_b)Code: Select allx = 1, y = 4, rule = B2ce3iny5i/S02c
o$o2$o!
10soups/second
Would search, but I'm going to the mall today soon.
wwei23 wrote:You said you go to bed at 9 but you posted this past 11.
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!
Saka wrote:Possibly smallest apgcode for a spaceship? (xq8_b)Code: Select allship
x = 1, y = 4, rule = B2ce3i4t/S02c
o$o2$o!
x = 16, y = 22, rule = B2cek3ai4t/S02c
15bo3$9b2obo3$15bo5$2obo7bo10$2obo!
x = 5, y = 2, rule = B2cek3ai4t/S02c
2bo$o3bo!
x = 4, y = 2, rule = B3/S23
ob2o$2obo!
x = 26, y = 4, rule = B3-k4j/S23-c
4b3o$4bobo14bo2b2o$4b3o15b3o$3o20bo!
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!
Saka wrote:c/27d and (1,2)c/31 in one rule... but lots of yls (One puffer but shows up a lot)Code: Select allx = 26, y = 4, rule = B3-k4j/S23-c
4b3o$4bobo14bo2b2o$4b3o15b3o$3o20bo!
x = 20, y = 29, rule = B3-k4j/S23-c
2o16b2o$2o16b2o9$3b3o$5bo$5bo$4bo2$4bo$5bo$5bo$3b3o9$2o16b2o$2o16b2o!
wwei23 wrote:I managed to get a friend to help me with B3/S23 1x256X2+1, but both our computers are having a little trouble with Calcyman's raised minimum soups per haul. We have only managed to get one haul in. Anyone up for the challenge, and we will not give up. We are going to crack the bottom of the Liszt!
drc wrote:wwei23 wrote:I managed to get a friend to help me with B3/S23 1x256X2+1, but both our computers are having a little trouble with Calcyman's raised minimum soups per haul. We have only managed to get one haul in. Anyone up for the challenge, and we will not give up. We are going to crack the bottom of the Liszt!
Just search D4_+1 for christ's sake! Those soups actually generate correctly and I'm pretty sure calcyman's getting extremely tired of this.
Also, B3-k4j/S23-c hit a breeder ~2k soups in so I'm too scared to search it
x = 9, y = 5, rule = B2ei3ikr4cj/S01c2-in3cijq4ckqrtz5cejnr6in7
4bo3$2b2ob2o$o2b3o2bo!
x = 56, y = 10, rule = B2ei3ikr4cj/S01c2-in3cijq4ckqrtz5cejnr6in7
4bo$53b2o$3bo35b2o2b2o2b2o6bo$3b2o34bo3bo3bo4b3o$o3bo46bo$3b2o48bo$3bo
34bo3bo3bo3bo3b2o$55bo$4bo47bob2o$52bo!
x = 56, y = 12, rule = B2ei3ikr4cj/S01c2-in3cijq4ckqrtz5cejnr6in7
4bo2$3bo$3b2o48b2o$o3bo34b2o2b2o2b2o6bo$3b2o34bo3bo3bo4b3o$3bo47bo$53b
o$4bo33bo3bo3bo3bo3b2o$55bo$52bob2o$52bo!
drc wrote:I'll try and search that soon, the most i found was that twin bees is almost a p122 shuttle:Code: Select allx = 20, y = 29, rule = B3-k4j/S23-c
2o16b2o$2o16b2o9$3b3o$5bo$5bo$4bo2$4bo$5bo$5bo$3b3o9$2o16b2o$2o16b2o!
x = 26, y = 39, rule = B3-k4j/S23-c
3bo18bo$2bobo16bobo$2bobo16bobo$b2ob2o14b2ob2o2$b2ob2o14b2ob2o$2bob2o
14b2obo$o24bo$2o22b2o7$6b2o$3b2ob2o$5bo3bobo$10bo2$10bo$5bo3bobo$3b2ob
2o$6b2o7$2o22b2o$o24bo$2bob2o14b2obo$b2ob2o14b2ob2o2$b2ob2o14b2ob2o$2b
obo16bobo$2bobo16bobo$3bo18bo!
wwei23 wrote:10000000 and just for 1x256X2+1.
muzik wrote:Can we get more people searching b026s1 on 1x256? I have a gut feeling that the 2c/8 and 2c/16 might be capable of appearing from soup naturally.
x = 27, y = 7, rule = B/S3-a
3bo$2b3o7b3o7b3o$bo3bo5bobobo5bobobo$2o3b2o3b2o3b2o3b2o3b2o$bo3bo5bo3b
o5bobobo$2b3o7b3o7b3o$3bo9bo!
x = 14, y = 14, rule = R7,C0,M1,S65..112,B64..89,NM
5b2o$4b5o$3b8o$2b11o$b13o$3o4b7o$2o6b6o$2o6b6o$2o5b7o$b2o3b8o$b12o$2b
10o$3b6o$5b3o!
wwei23 wrote:B/S3-a, I've turned up empty-handed. But still lives exist in this rule, they really do. So, who will get the first still life?
x = 32, y = 7, rule = B3-c4i/S1c2-ck34a
15bo5bo$16b2o4bo4bo$15b2o3b3o5bo$2o$ob2o25b2o$ob2o27bo$2o27b3o!
x = 4, y = 2, rule = B3/S23
ob2o$2obo!
wwei23 wrote:Can't think of a better place to put this, so here we go:
Alexey Nigin wrote:After all, one can just post it to /dev/null with the same effect, except for conserved bandwidth.
x = 17, y = 10, rule = B3/S23
b2ob2obo5b2o$11b4obo$2bob3o2bo2b3o$bo3b2o4b2o$o2bo2bob2o3b4o$bob2obo5b
o2b2o$2b2o4bobo2b3o$bo3b5ob2obobo$2bo5bob2o$4bob2o2bobobo!
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