ConwayLife.com

2c/4o: x = 7, y = 5, rule = R3,C0,S2,B3,N+ bo$obo2b2o$3bo$bob2obo$bobo2bo! 3c/4o partial (can't find a way to end this pattern): x = 91, y = 10, rule = R3,C0,S2,B3,N+ 19bobo49bo17b2o$12b2o3bo3b2o38bo2bo22bo$13bobo6b2o4b2o4bobo2b2o12bobob 5o2bobo2bo3bo12bo$3bob2obo5bo6bo4bo3bobo5bo14bo3bo11bobo2bobo2...

Some c/2o spaceships: x = 37, y = 90, rule = R2,C0,S4-6,B5-6,N# c/3o: x = 30, y = 8, rule = R2,C0,S4-6,B5-6,N# Also just a question: How do you find these spaceships? I found them by factoriosrc . This program was originally written for factorio , but now it also supports some other HROT rules.

Some c/2o spaceships: x = 37, y = 115, rule = R2,C0,S4-6,B5-6,N# 10b2o5b2o8bo$2bobobo2b3o3b2obo2bobo11bo$b2o2b2o2b2obobo4bo3b2ob2obo3bo bo$3o2bo4b2o2bo7bob3ob2o3b2obo$b2o2b2o2b2obobo4bo3b2ob2o2b4obo$2bobobo 2b3o3b2obo2bobo6bo2b2obo$10b2o5b2o8bobo3bobo$35bo13$5b3o14bo$2b2o6bo9b ob2o7bo$b8obobo5b2o3b2...

2c/2:

c/4o: x = 59, y = 6, rule = R3,C0,S2,B3,N+ 10b3o20bob5o$2o5b3o42bo2b2o$19b2o2bo3bob3obo4bo6b3o6bo$b2obobo9b2obo3b o3bobob2o3bobo2bo3bo6bob2o$2bo2bo3b2o34b2obo3bo2b2obo$15bobo6bob2o! c/2d: x = 5, y = 12, rule = R3,C0,S2,B3,N+ 2bo$bobo$o$bobo$3bo$o$2b2o$2bo$2bo$bo$4bo$3bo! x = 27, y = 27, rule = R3,C0...

Smaller c/3o: x = 13, y = 6, rule = R3,C0,S2,B3,N+ 4bobo3bo$bo3bo4b3o$b2o$2bobo$3bobo$o6bo! x = 26, y = 11, rule = R3,C0,S2,B3,N+ 22b2obo$13bobo$10bobo7b3o$3o6bob3o11bo$5bo9bo2$5bo9bo$3o6bob3o11bo$10b obo7b3o$13bobo$22b2obo! Smaller 2c/3o: x = 34, y = 8, rule = R3,C0,S2,B3,N+ 7bo$6bo2b2o$3o3bo$11bo1...

My factoriosrc is still in development. Currently it is still slow and lacks many features, but at least it shows that rlifesrc's algorithm does work for Factorio. There isn't a web version yet. In fact, making a GUI is much more complicated than writing the core algorithm. I think I cannot finish i...

Some p6 moon guns in B2/S4567: x = 55, y = 6, rule = B2/S4567 4b2o13b2o13b2o13b2o$b8o7b8o7b8o7b8o$3o4b3o5b3o4b3o5b4o2b4o5b3ob2ob3o$ 3bo2bo10b6o9b6o9b6o$18b4o11b4o11b4o$18bo2bo11bo2bo11bo2bo! The first two guns also work in B2/S456. Some p4 moon guns in B26/S3456: x = 51, y = 8, rule = B26/S3456 4b2o...

Thanks. Is it fixed now? Yes, I can search for (-1,2)c/5 spaceship. But still can't search for c/4 diagonal in MAP. (rule=MAP..., Period=4, dx=1, dy=1, diagonal search order). Partial in ShipWorld: x = 100, y = 100, rule = B3acijy4-a5cjkr6-in78/S2n3-c4-aijz5-jy6-k oo..oo...............................

I found a strange error while trying to search for (-1,2)c/5 spaceship. Period=5 dx=-1 dy=2 Diagonal width=10 APPLY SETTIGS See screenshot below (message from browser's console) I know that p5 knightships are impossible in Life, but the same bug happens with B3678/S34678 (Day and Night), B3acijy4-a...

rlifesrc gives the wrong orientation for MAP rules. For example, the following result for a p2 oscillator in Life with transition 3 toggled: x = 10, y = 10, rule = MAPERYXfhZofugWaH7oaIDogBZofuhogOiAaIDogIAAgAAWaH7oaIDogGiA6ICAAIAAaIDogIAAgACAAIAAAAAAAA ..........$ ..........$ ..........$ ............

When I saw the title I thought it was guessing programming languages. Programming language 2: 咩系 |解|？ 佢个老豆叫 |object| 佢有啲咩? -> |台阶| 佢识得 |爬楼梯| -> { 如果 |自己嘅 台阶 系 1| 嘅话 -> { 畀我睇下 |自己嘅 台阶| 点样先? } 定系 |自己嘅 台阶 系 2| 嘅话 -> { 畀我睇下 |自己嘅 台阶| 点样先? } 唔系 嘅话 -> { |1, 2| 拍住上 -> |备忘录| i 从 2 行到 |自己嘅 台阶| |备忘录| -> |加啲|:...

When I saw the title I thought it was guessing programming languages. Programming language 1: функ фибоначи(=>n) если n = 0 то возврат 0 все если n = 1 то возврат 1 все возврат фибоначи(n - 1) + фибоначи(n - 2) конец Is this Луа? (Russian?) translation: function fibonacci(=>n) if n = 0 then return ...

When I saw the title I thought it was guessing programming languages. Programming language 1: функ фибоначи(=>n) если n = 0 то возврат 0 все если n = 1 то возврат 1 все возврат фибоначи(n - 1) + фибоначи(n - 2) конец Programming language 2: 咩系 |解|？ 佢个老豆叫 |object| 佢有啲咩? -> |台阶| 佢识得 |爬楼梯| -> { 如果 |自己嘅...

It seems that the proof of Theorem 1.2 (No Thin Gardens of Eden) on page 22 is incomplete. The last sentence of the proof says that: moving the alive cell from A to Y does not affect the evolution of any of the other 3×3 blocks to its right (which can be done via a simple case analysis). But there i...

GitHub connection bad(probably banned in other places, as tested), so I’ll report a bug of rlifesrc here Rule:B2/S Width:13 Height:20 Period:6 dx:0 dy:6 Diagonal width:0 Transformation:flip| Symmetry:C1 Max cell count:0 Search order:automatic Choice of state for unknown cells:alive Skip patterns wi...

GitHub connection bad(probably banned in other places, as tested), so I’ll report a bug of rlifesrc here Rule:B2/S Width:13 Height:20 Period:6 dx:0 dy:6 Diagonal width:0 Transformation:flip| Symmetry:C1 Max cell count:0 Search order:automatic Choice of state for unknown cells:alive Skip patterns wi...

Given that we haven't found a single example of an odd period... True... But I think at least one exists. It probably isn't omniperiodic, but I think there is at least an odd period How can an odd-period oscillator (EDIT: possibly excluding p1 still lives, I'm not sure) exist in a B0 rule simulated...

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A new c/4d and two tagalongs: x = 52, y = 15, rule = B2n3/S23-q 10bo19bo19bo$7b5o15b5o15b5o$5bo5bo13bo5bo13bo5bo$ob3o15bob3o15bob3o$o 4bo2b2obo8bo4bo2b2obo8bo4bo2b2obo$b4o5bo10b4o5bo10b4o5bo2$7b3o17b3o17b 3o$5bo19bo12bo6bo$8b2o10b3o5b2o8b2o8b2o$8b2o12b3o3b2o9bo8b2o$5bo12bo3b 2obo12b3o4bo$7bo10bob3o...

A new c/4d and two tagalongs: x = 52, y = 15, rule = B2n3/S23-q 10bo19bo19bo$7b5o15b5o15b5o$5bo5bo13bo5bo13bo5bo$ob3o15bob3o15bob3o$o 4bo2b2obo8bo4bo2b2obo8bo4bo2b2obo$b4o5bo10b4o5bo10b4o5bo2$7b3o17b3o17b 3o$5bo19bo12bo6bo$8b2o10b3o5b2o8b2o8b2o$8b2o12b3o3b2o9bo8b2o$5bo12bo3b 2obo12b3o4bo$7bo10bob3o4...

Is there a script to convert a non-totalistic hex rule to a MAP rule?

An interesting replicator in a hexagonal rule:
If we consider the time dimension, it is a Sierpinski tetrahedron.

A new spaceship:

I think it can be proved that (finite) still lifes do not exist. Just consider a living cell on the top row of a still life. Since S34, it must have a living neighbor on the same row, but this would contradict B2 because it is the top row.