ConwayLife.com

* many occurrences are in thread names (e.g. "Rules 1 transition from Life") which are automatically copied from the first post, unless the post's author changes the default subject line. In a sense, all these occurrences in thread names "belong" to the first post and could be counted as just one o...

Sorry to bring this up again but

In my experience, both terms are in use, but "transition" seems significantly more commonly used than "condition". Just from a descriptive linguistics standpoint, it makes more sense to use "transition".

This seems actually pretty tricky ngl. I'm not sure that there are a whole lot of barriers that WE have control over (seeing as we're literally a chat forum with very little barriers to entry), a lot of the issues probably just come from disproportional male exposure/access to science education etce...

protip: when a mod locks a thread, you probably shouldn't create a nearly identical thread with a couple haphazard added "rules" in a futile attempt to prevent it from going the same direction as the original.

Interesting loop: x = 75, y = 61, rule = B3/S23 35bo$33b3o$32bo$17b2o13b2o$18bo$18bobo$19b2o$25bo$24bobo$23b2ob2o8bo$ 24bo2bo9bo$24b2ob2o6b3o$25bobo$26bo$26bo$5b2o18bobo4b2o$6bo20bo4bo$5bo 7bo8b2obo7b3o$5b2o6bo8b3o10bo$2o19bo$o2b4o4b3o8b2o21bobo$bobo2bo3bob2o 3bobo2b2o22b2o$2o2b2o4b2o5bobo6bo19bo$2...

Well, GOL is omniperiodic now, thanks to the p41 that glider_rider found. That's one big unproven conjecture, PROVEN.

but that doesn't prove anything because UC(H,Q) can be 0 Wel, no, it can't be, because it's going to be a valid Turing machine, and by your definition that means it's not going to output 0, which only happens if it's not a valid turing machine. Out of curiosity, exactly where do you think is the fl...

saying every colored turing machine can be emulated by colorless one is like saying that every English sentence can be written in Basic English so English is no more powerful than Basic English I'm done I give up I literally have no idea how on earth you could possibly use this kind of argument as ...

Have you heard of SmoothLife ? It's basically a position-continuous time-continuous rule (you could also argue that states are continuous, I guess, though the line between continuous and non-continuous states in a position-continuous system is pretty fuzzy. semirelevant side note: I wonder what othe...

by the way I didn't find any proof against the existence of a circle-free turing machine that solves the halting problem all proof rely on the fact the halting decider accept an input you can emulate accepting input by imagining that the turing machine has extra states necessary to write the input ...

you didn't read my last comment. you're proof does not work please tell me what the error in my proof is, then. As far as I can tell your post just provided an example of the construction I provided in my proof... called on a different turing machine, and, wow! If you don't do the construction of t...

because life patterns have the same behavior regardless of colors no counter example can be constructed They have the same behavior within the CA, i.e. you cannot internally distinguish them. But you can distinguish them externally , because they're different states. Suppose colorized life solved t...

Why aren't any new periods coming up like p19 or p41? More or less, the answer boils down to "we have no efficient way to search for them". And we have no idea how complex the simplest p19s or p41s would be. If they exist (and proving otherwise would be absurdly difficult. I don't think there's a w...

In Ohhhhhhhhh's rule, a bun can hassle a block: x = 9, y = 12, rule = R4,C0,S2-3,21-26,30-35,B3,27-32,NW090000000900000009000000000000000000000000000000000000000000010101000000090000010001000009000000010101000000000000000000000000000000000000000000090000000900000009 b2o$o2bo$obo$obo4$3bo3$8bo$7b2o! ...

I request for a search of all 9-cell patterns to see which one last the longest. There are 9-cell patterns lasting arbitrarily long: x = 1173, y = 1172, rule = B3/S23 2bo$obo$b2o1168$1171b2o$1171b2o! You couldn't exhaustively search all 9-cell patterns, anyway, since there's a (countable) infinity ...

Something that I've been posting about on discord recently is that self-inverse rules have an additional "secret inverse" (if you will) attained by negating all the transitions: Original rule x = 99, y = 40, rule = B34k6-ae78/S2ae34-k678 48b51o$48b51o$48b51o$48b51o$48b51o$48b51o$48b51o$48b51o$48b51o...

We have B3/S023 and B3/S27, anything else? dots are B3/S x = 249, y = 341, rule = R4,C0,S9,14,16-17,21,23-24,30-31,37-38,44-45,51-52,58-59,B3,10,17,21,24,31,38,45,52,59,NW100010001000000000000000000000777000100707001000777000000000000000000000100010001 o23bo12$100bo4$40bo19bo7bo11bo4$o3bo15bo7bo15b...

Remember the ltl slowships? saka and I found some in small-radius hrot and even ltl rules: R5 rules c/96 (musi) x = 12, y = 12, rule = R5,C0,S42-71,B37-71,73 4b3o$4b4o$b8o$2b8o$5ob5o$b3o3b5o$4o4b4o$b3o3b5o$10o$b9o$2b6obo$3bobobo ! 2c/31o (saka) x = 12, y = 12, rule = R5,C0,S42-71,B37-71,73 4b3o$3b4o...

76e/100 = 2.065894...

Wyirm wrote: ↑

August 10th, 2022, 11:39 am

1+1/10phi = 2.06180339887 (+0.000445493986028)

I'm assuming you meant 2+1/(10phi) here.

I feel like the game works much better the way we've done it. Restricting it to integers makes it pointless. well, the original idea was to eventually get to enormous (i.e. googological) numbers. Though as it's been going right now is fine as well imo. Btw: π-√(5/8)=1.8766815 (+.0001386) Who will b...

It's not too hard to construct an object that does this in an arbitrarily extensible fashion (e.g. this is 1035):

pi-4/pi = approx 1.86835310 (+0.0107)

HotWheels9232 wrote: ↑

June 11th, 2022, 7:16 pm

Pi/cube root of 9~1.83721453

how are you getting this exactly? Afaict it's approximately 1.51032022.

27log_(e^17)(pi) (+0.0181004)

(a slight increase in pace, I suppose) 7/4

The integral from 0 to 4 of mod(1,mod(4,x)) dx (where mod(a,b) is the modulo operator). Approximately 1.59246343...