My number is larger [GAME]

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Moosey
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Re: My number is larger [GAME]

Post by Moosey » November 27th, 2020, 8:45 pm

that's way too big a jump imo

we're not even out of tetration yet, let alone into expansion
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MathAndCode
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Re: My number is larger [GAME]

Post by MathAndCode » November 27th, 2020, 8:55 pm

Code: Select all

if the Ackermann function is considered to be past up-arrows:
    2↑↑9
else:
    A(4, 6)
I am tentatively considering myself back.

Hunting
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Re: My number is larger [GAME]

Post by Hunting » November 27th, 2020, 9:40 pm

Moosey wrote:
November 27th, 2020, 12:11 pm
2^^6 (sorry, quite a jump)
What does this mean

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Re: My number is larger [GAME]

Post by Moosey » November 27th, 2020, 9:43 pm

MathAndCode wrote:
November 27th, 2020, 8:55 pm

Code: Select all

if the Ackermann function is considered to be past up-arrows:
    2↑↑9
else:
    A(4, 6)
they're basically the same thing, so either is fine
Hunting wrote:
November 27th, 2020, 9:40 pm
Moosey wrote:
November 27th, 2020, 12:11 pm
2^^6 (sorry, quite a jump)
What does this mean
wdym? if you're asking what 2^^6 is, it's 2 tetrated to the 6 = 2^2^2^2^2^2 (associative right; that is, (2^(2^(2^(2^(2^2))))))
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Hunting
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Re: My number is larger [GAME]

Post by Hunting » November 27th, 2020, 9:53 pm

Moosey wrote:
November 27th, 2020, 9:43 pm
MathAndCode wrote:
November 27th, 2020, 8:55 pm

Code: Select all

if the Ackermann function is considered to be past up-arrows:
    2↑↑9
else:
    A(4, 6)
they're basically the same thing, so either is fine
Hunting wrote:
November 27th, 2020, 9:40 pm
Moosey wrote:
November 27th, 2020, 12:11 pm
2^^6 (sorry, quite a jump)
What does this mean
wdym? if you're asking what 2^^6 is, it's 2 tetrated to the 6 = 2^2^2^2^2^2 (associative right; that is, (2^(2^(2^(2^(2^2))))))

Code: Select all

f(0)=1
f(x) = 3 ↑^f(x-1) 3
f(3856)

// This is my 3856th post

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Re: My number is larger [GAME]

Post by wzkchem5 » November 28th, 2020, 2:20 am

Hunting wrote:
November 27th, 2020, 9:53 pm
f(0)=1
f(x) = 3 ↑^f(x-1) 3[/code]

f(3856)

// This is my 3856th post
I would say this is too much a jump
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Hunting
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Re: My number is larger [GAME]

Post by Hunting » November 28th, 2020, 3:53 am

wzkchem5 wrote:
November 28th, 2020, 2:20 am
Hunting wrote:
November 27th, 2020, 9:53 pm
f(0)=1
f(x) = 3 ↑^f(x-1) 3[/code]

f(3856)

// This is my 3856th post
I would say this is too much a jump
Well this is my best attempt at something non-trivial (i. e. not just adding arrows)

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Re: My number is larger [GAME]

Post by Moosey » November 29th, 2020, 11:54 am

Hunting wrote:
November 28th, 2020, 3:53 am
wzkchem5 wrote:
November 28th, 2020, 2:20 am
Hunting wrote:
November 27th, 2020, 9:53 pm
f(0)=1
f(x) = 3 ↑^f(x-1) 3[/code]

f(3856)

// This is my 3856th post
I would say this is too much a jump
Well this is my best attempt at something non-trivial (i. e. not just adding arrows)
it's to much of a jump
it's roughly g3856

anyway 2^^15
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Hunting
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Re: My number is larger [GAME]

Post by Hunting » November 29th, 2020, 11:59 am

Moosey wrote:
November 29th, 2020, 11:54 am
Hunting wrote:
November 28th, 2020, 3:53 am
wzkchem5 wrote:
November 28th, 2020, 2:20 am


I would say this is too much a jump
Well this is my best attempt at something non-trivial (i. e. not just adding arrows)
it's to much of a jump
it's roughly g3856
Well, I don't know any googology or what is g.

So

Code: Select all

f(0)=1
f(y)=y↑↑f(f(y-1), y)
f(3856)

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Moosey
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Re: My number is larger [GAME]

Post by Moosey » November 29th, 2020, 12:14 pm

Hunting wrote:
November 29th, 2020, 11:59 am
Moosey wrote:
November 29th, 2020, 11:54 am
Hunting wrote:
November 28th, 2020, 3:53 am


Well this is my best attempt at something non-trivial (i. e. not just adding arrows)
it's to much of a jump
it's roughly g3856
Well, I don't know any googology or what is g.

So

Code: Select all

f(0)=1
f(y)=y↑↑f(f(y-1), y)
f(3856)
:thinking: you don't define how f takes two arguments, that's not even defined
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Hunting
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Re: My number is larger [GAME]

Post by Hunting » November 29th, 2020, 12:16 pm

Moosey wrote:
November 29th, 2020, 12:14 pm
Hunting wrote:
November 29th, 2020, 11:59 am
Moosey wrote:
November 29th, 2020, 11:54 am

it's to much of a jump
it's roughly g3856
Well, I don't know any googology or what is g.

So

Code: Select all

f(0)=1
f(y)=y↑↑f(f(y-1), y)
f(3856)
:thinking: you don't define how f takes two arguments, that's not even defined
Sry ignore the second argument

it was left there when simplifying

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Moosey
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Re: My number is larger [GAME]

Post by Moosey » November 29th, 2020, 12:18 pm

Hunting wrote:
November 29th, 2020, 12:16 pm
Moosey wrote:
November 29th, 2020, 12:14 pm
Hunting wrote:
November 29th, 2020, 11:59 am


Well, I don't know any googology or what is g.

So

Code: Select all

f(0)=1
f(y)=y↑↑f(f(y-1), y)
f(3856)
:thinking: you don't define how f takes two arguments, that's not even defined
Sry ignore the second argument

it was left there when simplifying
ok, that's still illdefined though: observe:

f(4) = 4^^f(f(3)) = 4^^f(27) -> eventually references f(4) again, thus f(4) and everything above is illdefined
f(3) = 3^^f(f(2)) = 3^^2 = 27
f(2) = 2^^f(f(1)) = 2
f(1) = 1

I'd recommend you make it f(y+1) = y^^f(y) or something so that it's defined and pentation level (but that's still WAAAAY too big)
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Hunting
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Re: My number is larger [GAME]

Post by Hunting » November 29th, 2020, 1:03 pm

Moosey wrote:
November 29th, 2020, 12:18 pm
Hunting wrote:
November 29th, 2020, 12:16 pm
Moosey wrote:
November 29th, 2020, 12:14 pm


:thinking: you don't define how f takes two arguments, that's not even defined
Sry ignore the second argument

it was left there when simplifying
ok, that's still illdefined though: observe:

f(4) = 4^^f(f(3)) = 4^^f(27) -> eventually references f(4) again, thus f(4) and everything above is illdefined
f(3) = 3^^f(f(2)) = 3^^2 = 27
f(2) = 2^^f(f(1)) = 2
f(1) = 1

I'd recommend you make it f(y+1) = y^^f(y) or something so that it's defined and pentation level (but that's still WAAAAY too big)
Dang. I still need two arguments

f(x, 0)=1
f(x, y)=y↑↑f(x-1, f(x, y-1))

Isn't pentation too trivial as it's just adding an arrow to tetration?

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Re: My number is larger [GAME]

Post by Moosey » November 29th, 2020, 7:27 pm

Hunting wrote:
November 29th, 2020, 1:03 pm
Moosey wrote:
November 29th, 2020, 12:18 pm
Hunting wrote:
November 29th, 2020, 12:16 pm

Sry ignore the second argument

it was left there when simplifying
ok, that's still illdefined though: observe:

f(4) = 4^^f(f(3)) = 4^^f(27) -> eventually references f(4) again, thus f(4) and everything above is illdefined
f(3) = 3^^f(f(2)) = 3^^2 = 27
f(2) = 2^^f(f(1)) = 2
f(1) = 1

I'd recommend you make it f(y+1) = y^^f(y) or something so that it's defined and pentation level (but that's still WAAAAY too big)
Dang. I still need two arguments

f(x, 0)=1
f(x, y)=y↑↑f(x-1, f(x, y-1))

Isn't pentation too trivial as it's just adding an arrow to tetration?
not at this point, no
still illdefined since x will go to 0 and you don't have a condition for that
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Re: My number is larger [GAME]

Post by Moosey » November 30th, 2020, 11:09 am

2^^32
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Re: My number is larger [GAME]

Post by EvinZL » November 30th, 2020, 11:19 am

2^^^5

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Moosey
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Re: My number is larger [GAME]

Post by Moosey » November 30th, 2020, 12:37 pm

2^^^6 // thx
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Re: My number is larger [GAME]

Post by NoAyeBeardo » November 30th, 2020, 2:10 pm

2^^^8
Not inactive any more! :D

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Re: My number is larger [GAME]

Post by Hunting » November 30th, 2020, 9:18 pm

2 ↑^(2^^^8) 8

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Re: My number is larger [GAME]

Post by Hdjensofjfnen » November 30th, 2020, 9:44 pm

Hunting wrote:
November 30th, 2020, 9:18 pm
2 ↑^(2^^^8) 8
// That looks pretty large in comparison to the last number.

Code: Select all

x = 5, y = 9, rule = B3-jqr/S01c2-in3
3bo$4bo$o2bo$2o2$2o$o2bo$4bo$3bo!

Code: Select all

x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!

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Re: My number is larger [GAME]

Post by Moosey » November 30th, 2020, 10:47 pm

Hdjensofjfnen wrote:
November 30th, 2020, 9:44 pm
Hunting wrote:
November 30th, 2020, 9:18 pm
2 ↑^(2^^^8) 8
// That looks pretty large in comparison to the last number.
// yup, 2{2^^^8}8 is a touch large compared to 2^^^8

2^^^12
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Re: My number is larger [GAME]

Post by Hunting » November 30th, 2020, 11:40 pm

Moosey wrote:
November 30th, 2020, 10:47 pm
Hdjensofjfnen wrote:
November 30th, 2020, 9:44 pm
Hunting wrote:
November 30th, 2020, 9:18 pm
2 ↑^(2^^^8) 8
// That looks pretty large in comparison to the last number.
// yup, 2{2^^^8}8 is a touch large compared to 2^^^8

2^^^12
It's getting boring
2^^^(2^^6)

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Moosey
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Re: My number is larger [GAME]

Post by Moosey » December 1st, 2020, 9:39 am

k
2^^^(2^^^4)
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Re: My number is larger [GAME]

Post by EvinZL » December 1st, 2020, 10:47 am

2^^^^4

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Re: My number is larger [GAME]

Post by Moosey » December 1st, 2020, 2:24 pm

that's exactly the same but ok
3^^^^3 = g1
note: inductively, 3^^^^3 > 2^^^^4 = 2^^^2^^^4
3^^^^3 = 3^^^3^^^3

3^^^3 > 2^^^4

2^4 = 16 > 3^3 = 27
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