My number is larger [GAME]
Re: My number is larger [GAME]
that's way too big a jump imo
we're not even out of tetration yet, let alone into expansion
we're not even out of tetration yet, let alone into expansion
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Re: My number is larger [GAME]
Code: Select all
if the Ackermann function is considered to be past up-arrows:
2↑↑9
else:
A(4, 6)
I am tentatively considering myself back.
Re: My number is larger [GAME]
they're basically the same thing, so either is fineMathAndCode wrote: ↑November 27th, 2020, 8:55 pmCode: Select all
if the Ackermann function is considered to be past up-arrows: 2↑↑9 else: A(4, 6)
wdym? if you're asking what 2^^6 is, it's 2 tetrated to the 6 = 2^2^2^2^2^2 (associative right; that is, (2^(2^(2^(2^(2^2))))))
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Re: My number is larger [GAME]
Moosey wrote: ↑November 27th, 2020, 9:43 pmthey're basically the same thing, so either is fineMathAndCode wrote: ↑November 27th, 2020, 8:55 pmCode: Select all
if the Ackermann function is considered to be past up-arrows: 2↑↑9 else: A(4, 6)
wdym? if you're asking what 2^^6 is, it's 2 tetrated to the 6 = 2^2^2^2^2^2 (associative right; that is, (2^(2^(2^(2^(2^2))))))
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f(0)=1
f(x) = 3 ↑^f(x-1) 3
// This is my 3856th post
Re: My number is larger [GAME]
I would say this is too much a jump
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Re: My number is larger [GAME]
it's to much of a jump
it's roughly g3856
anyway 2^^15
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Re: My number is larger [GAME]
Well, I don't know any googology or what is g.
So
Code: Select all
f(0)=1
f(y)=y↑↑f(f(y-1), y)
Re: My number is larger [GAME]
you don't define how f takes two arguments, that's not even definedHunting wrote: ↑November 29th, 2020, 11:59 amWell, I don't know any googology or what is g.
So
f(3856)Code: Select all
f(0)=1 f(y)=y↑↑f(f(y-1), y)
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Re: My number is larger [GAME]
Sry ignore the second argumentMoosey wrote: ↑November 29th, 2020, 12:14 pmyou don't define how f takes two arguments, that's not even definedHunting wrote: ↑November 29th, 2020, 11:59 amWell, I don't know any googology or what is g.
So
f(3856)Code: Select all
f(0)=1 f(y)=y↑↑f(f(y-1), y)
it was left there when simplifying
Re: My number is larger [GAME]
ok, that's still illdefined though: observe:Hunting wrote: ↑November 29th, 2020, 12:16 pmSry ignore the second argumentMoosey wrote: ↑November 29th, 2020, 12:14 pmyou don't define how f takes two arguments, that's not even definedHunting wrote: ↑November 29th, 2020, 11:59 am
Well, I don't know any googology or what is g.
So
f(3856)Code: Select all
f(0)=1 f(y)=y↑↑f(f(y-1), y)
it was left there when simplifying
f(4) = 4^^f(f(3)) = 4^^f(27) -> eventually references f(4) again, thus f(4) and everything above is illdefined
f(3) = 3^^f(f(2)) = 3^^2 = 27
f(2) = 2^^f(f(1)) = 2
f(1) = 1
I'd recommend you make it f(y+1) = y^^f(y) or something so that it's defined and pentation level (but that's still WAAAAY too big)
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Re: My number is larger [GAME]
Dang. I still need two argumentsMoosey wrote: ↑November 29th, 2020, 12:18 pmok, that's still illdefined though: observe:
f(4) = 4^^f(f(3)) = 4^^f(27) -> eventually references f(4) again, thus f(4) and everything above is illdefined
f(3) = 3^^f(f(2)) = 3^^2 = 27
f(2) = 2^^f(f(1)) = 2
f(1) = 1
I'd recommend you make it f(y+1) = y^^f(y) or something so that it's defined and pentation level (but that's still WAAAAY too big)
f(x, 0)=1
f(x, y)=y↑↑f(x-1, f(x, y-1))
Isn't pentation too trivial as it's just adding an arrow to tetration?
Re: My number is larger [GAME]
not at this point, noHunting wrote: ↑November 29th, 2020, 1:03 pmDang. I still need two argumentsMoosey wrote: ↑November 29th, 2020, 12:18 pmok, that's still illdefined though: observe:
f(4) = 4^^f(f(3)) = 4^^f(27) -> eventually references f(4) again, thus f(4) and everything above is illdefined
f(3) = 3^^f(f(2)) = 3^^2 = 27
f(2) = 2^^f(f(1)) = 2
f(1) = 1
I'd recommend you make it f(y+1) = y^^f(y) or something so that it's defined and pentation level (but that's still WAAAAY too big)
f(x, 0)=1
f(x, y)=y↑↑f(x-1, f(x, y-1))
Isn't pentation too trivial as it's just adding an arrow to tetration?
still illdefined since x will go to 0 and you don't have a condition for that
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Re: My number is larger [GAME]
2 ↑^(2^^^8) 8
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Re: My number is larger [GAME]
// That looks pretty large in comparison to the last number.
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x = 5, y = 9, rule = B3-jqr/S01c2-in3
3bo$4bo$o2bo$2o2$2o$o2bo$4bo$3bo!
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x = 7, y = 5, rule = B3/S2-i3-y4i
4b3o$6bo$o3b3o$2o$bo!
Re: My number is larger [GAME]
// yup, 2{2^^^8}8 is a touch large compared to 2^^^8Hdjensofjfnen wrote: ↑November 30th, 2020, 9:44 pm// That looks pretty large in comparison to the last number.
2^^^12
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Re: My number is larger [GAME]
It's getting boring
2^^^(2^^6)
Re: My number is larger [GAME]
that's exactly the same but ok
3^^^^3 = g1
note: inductively, 3^^^^3 > 2^^^^4 = 2^^^2^^^4
3^^^^3 = 3^^^3^^^3
3^^^3 > 2^^^4
2^4 = 16 > 3^3 = 27
3^^^^3 = g1
note: inductively, 3^^^^3 > 2^^^^4 = 2^^^2^^^4
3^^^^3 = 3^^^3^^^3
3^^^3 > 2^^^4
2^4 = 16 > 3^3 = 27
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