The Hunting of the New Herschel Conduits
Re: The Hunting of the New Herschel Conduits
Right, just checking that with the experts since I wasn't sure. I'll be investigating Pi catalysts for Extrementhusiast's idea soon.
Tanner Jacobi
Re: The Hunting of the New Herschel Conduits
I didn't find anything better than the HtoG below, but haven't hunted very long yet. Almost everything seems to be a minor variant of this block catalyst, which leaves some junk and an awkward lastminute glider:Sokwe wrote:It might be possible to get something out of this transparent block reaction...
Code: Select all
x = 49, y = 31, rule = LifeHistory
6.16B2C.2C$4.18B.C.2C$2.13B2A3B3.C$2.11BA2BA3B2.2C$.10B.7B2.4D$2.9B.A
6B$.10B.A7B$10B3.ABA3BA$3B8.3B2A5B$2B11.2B2A4BAB$B9.2B.3B2A3B3A$D9.2B
.2B2A4BAB$D12.B2A5B27.B$11.2BABA3BAB26.2B$13.2A6B25.3B$14.A2B2A3B.2A
20.4B$14.B3A5B2AB18.4B$14.2BA9B17.4B$14.12B16.4B$15.11B15.4B$18.7B15.
4B$17.8B14.4B$13.A.10B13.4B$5.D5.4BA2BA8B4.3B3.4B$5.CA2.2A4B5A7B2A2.
9B$5.CA2.A3BA4B2A2B2A3BABA.8B$5.D3.ABA3B3ABA2B2A5B2A7B$10.2A4BA5B2A2B
4A.6B$14.2B2.5BABA2B3.6B$19.3B2A3BA3.6B$22.B3A!
Any time you can get a new transparent object to work, I'd say it's not too boring  even transparent blocks are fairly rare. It's true that this particular converter is equivalent to an R64 plus a HtoG#1, so it's an output lane and timing that we had already.Sokwe wrote:Edit: This B>G works, but that's fairly boring...
Probably it's going to be a good idea to build an HtoG database that includes composite outputs along these lines, so that a script can be written to answer questions like: "I have a Herschel at (0,0,0), and I want a [NENWSWSE] glider to appear at (X,Y,T)  is there a known way to do this?" For large enough spacetime offsets, the answer is always "yes", but the interesting answers are the "yes" answers for smaller X/Y/T. It's nice when you can occasionally solve a layout problem with some nice compact circuitry.
 Extrementhusiast
 Posts: 1798
 Joined: June 16th, 2009, 11:24 pm
 Location: USA
Re: The Hunting of the New Herschel Conduits
Well, here's a rather interesting partial BtoB, which requires a glider to reset it:
Code: Select all
x = 17, y = 28, rule = B3/S23
14bo$13bo$13b3o16$b2o4b2o$b2o4bobo$8bo2$2bo$b3o11bo$2o2bo10b2o$16bo$
16bo$15bo!
I Like My Heisenburps! (and others)

 Posts: 87
 Joined: December 20th, 2014, 8:30 am
Re: The Hunting of the New Herschel Conduits
Here is period 244 oscillator:Extrementhusiast wrote:Well, here's a rather interesting partial BtoB, which requires a glider to reset it:Code: Select all
x = 17, y = 28, rule = B3/S23 14bo$13bo$13b3o16$b2o4b2o$b2o4bobo$8bo2$2bo$b3o11bo$2o2bo10b2o$16bo$ 16bo$15bo!
Code: Select all
x = 307, y = 307, rule = B3/S23
146b2obo$146bob2o25bo$173b3o$147b5o20bo$146bo4bo20b2o22b2obobo$145bo2b
o47b2ob2obo$142bo2bob2o43bo9b3o$141bobobo5bo38b3o3b5o4bo$142bo2bo4bobo
36bo5bo4b6o$145b2o2bo2bo13b3o7b2o11b2o4bob3o$150b2o16bo7b2o18bo2bo2b2o
$142b2o23bo29b4o3bo$141bobo2b2o9bo41bo3b2o$141bobobobo8b2obobo$140b2ob
o2bo8b2o2b3o49b2o$139bo3bo2b2o8bo2bobo49bo$140bobo3b2o9b2o3b2o45bobo$
139b2obo2b3o10b3ob2o45b2o$142bobo14b2o$139b2obobo19b2o$139b2obo2bo18bo
$143b2o20b3o$167bo$189b2o$189b2o$164bo10b2o$162b3o9bobo$161bo12bo$161b
2o10b2o$153b2o$153b2o6$170b2o$170bo41b2o$168bobo41bobo$168b2o44bo$214b
2o7$204b2o$172b2o30b2o$172bobo$174bo20b2obo$174b2o19bob2o$164b2o$164b
2o$145bob2o56b2o$145b2obo55bo2bo6b2o$204bo8bobo$154b2o47bo3bo5bo$154b
2o46bo4bo4b2o$204bobo$206b2o$206b2o$193b2o9bob2ob2o$194bo10bobo$194bob
o9bo$164b2o29b2o15b2o$164bo47b2o$162bobo$161b3o$147bo11b3o33b2o$147b3o
10b2o32bobo$150bo8bo34bo$149b2o42b2o4$148b2o31b2o$148b2o31bo14b2o$179b
obo14b2o13b2o$179b2o30bo$212b3o$149b3o62bo$152bo$142b2o67b2o$142b2o5b
2o59bo2bob2o$150b2o3b2o54bobob2o$150b2o4b2o39bo13bobo$149bo2b5o40b2o9b
3o2bob2o$149b7o39bob2o9b2o3bobo$150bo44b3o10b2o2bo3bo$84b2obobo53b2o6b
o43bobo11bo2bob2o$40bo14b2o27b2ob2obo52b2o63bobobobo$38b3o14bo24b2o8b
3o115b2o2bobo$37bo18b3o6b2o13bo3b5o4bo118b2o$14bo22b2o19bo6b2o11bobo2b
o4b6o55b2o27b2o$14b3o61b2o3bob2o62b2o14b2o11b2o$17bo66b2obob3o74bo$16b
2o27b2o39bo5bo70b3o37b2o$35b2o2bobo3bobob3o35bo3b2o70bo39bo$34b3obo3bo
2bobo40bo115b3o$33b2o6bo3b3o51b2o105bo$7b2o25bob5o3bo3bo50bo$6bobo2b2o
22b4o4bo4bo48bobo$6bobobobo24bo6bo3bo48b2o$5b2obo2bo33bo$4bo3bo$5bobo
3b2o$4b2obobo2bo$7bobo40b2o$4b2obobobo39bo25b2o$4b2obo2bo39bo13b2o3b2o
6b2o$8b2o40b2o13bo3bo$62b3o5b3o$62bo9bo$6b2o$7bo$7bobo13b2o$8b2o13b2o
5$159bo$158bo$76bo81b3o$76b3o$79bo$78b2o9b3obobo$89b3o3bo$9b2o76b2o$9b
2o14b2o60bo3b3o$b2o22bo25bo35bo3bo$2bo23b3o20b3o36bo2bo$2bobo23bo19bo
40bo2bo$3b2o43b2o42bo$36bo55bo$36b3o52b3o$39bo51b3o$38b2o51bo2bo$21b2o
69bo193b2obobo$21bo74bo49b2o4b2o132b2ob2obo$19bobo30b2o11bo28b2obo48b
2o4bobo137b3o4bo$19b2o4b2o25b2o11b3o29bo55bo68b2o62b5o4bo2bobo$26bo41b
o28b2o116b2o5b2o61bo5b5o3bo$26bobo38b2o14bo63bo67b2o68bob3o$27b2o53bo
63b3o102b2o33bo6bo3b5o$82b3o60b2o2bo15b2o84bo35bo2bobobo2bo4bo2b2o$
165b2o50b2o17b2o14bo36b2o2b2o5bo2bo2bo$217b2o17bo14b2o47b2obobo$35bo
175b2o21bobo60bo5bob2o$33b2o4bo104bo66b2o21b2o60bobo4bo$33bo5b2o16b2o
188bo48bo2bo2b2o$28b2o2b3o5b2o15b2o82bo9b2o12b2o79bo2bo47b2o$24bo3b2o
10bo99bobo8b2o11bobo79bo29b2o$8b2o13bo8bo2b2o2bo100b2o4b2o3bo13bo83bo
26b2o$3b2o2bo2bo13b2o6bo205b3o6b2o$3bo4bobo14bo7bobo35b2o21b2o50b2o2bo
87bo6bob2obo$2obo5bo24bo35bobo21b2o142bobo7bob2o$bobob2o9bo37b2o14bo
17b2o149b2o3bo2b3ob2o$o2bo2bo5b2o3bo36bo14b2o17b2o155bo4bo$2o2bo4bo2bo
5bo36bo86b2o$5b5o3b3obob2o33b2o82bo3b2o134b2o$18b2obo68b2o47b2o97b2o
38bobo$7bo3b6o4bo61b2o5b2o46b2o68b2o28bo41bo$6bobo2bo4b5o62b2o68bo55bo
29b3o11b2o25b2o4b2o$7bo4b3o137bobo4b2o48bobo29bo11b2o30bobo$14bob2ob2o
132b2o4b2o49b2o73bo$15bobob2o263b2o$267b2o$267bo$268b3o$270bo$257b2o
43b2o$198bo59bo19bo23bobo$197b2o56b3o20b3o23bo$197bobo55bo25bo22b2o$
280b2o13bo$294b3o$211b2o73b3o7bo$211b2o14b2o57bo2bo$227bo58bo2bo$228b
3o56bobo$230bo7$282b2o13b2o$282b2o13bobo$219b2o78bo$219b2o78b2o$234bo
9bo$234b3o5b3o$237bo3bo13b2o26bo13b2o$228b2o6b2o3b2o13bo26bobo10bo2bob
2o$228b2o25bo27b2o11b2obob2o$255b2o20b2o16bobobo$211b2o64b2o15bobo2bob
2o$211b2o80bo4b2obo$216b2o69b2o7bobo3bo$216b2o69b2o7bobob2o$208b2o17bo
bo64bobobobo$207bobo16bo2bo28b2o34b2o2bobo$207bo19bo2bob2o24b2o38b2o$
100bo105b2o22bo2bo51b2o$100b3o128b2o52b2o$103bo39bo70b2o2b2o11b2o$102b
2o37b3o70bobobo2bo67b2o$140bo74bo6bo66bo$127b2o11b2o14b2o61b3obo3b2o
61b3o$116b2o9b2o27b2o55b5o5bo2bobo11b2o6bo19b2o22bo$93b2o20bobo95bo4b
5o3bo13b2o6b3o18bo$92bobo2b2o12b2o4bo96b3o8b2o24bo14b3o$92bobobobo11bo
bo49b2o52bob2ob2o27b2o14bo$91b2obobo12b2obo49b2o53bobob2o$90bo3bo15b2o
bo44b2o$91bob2o2bo13b3o44b2o$90b2obob4o$93bobobo$90b2obobobo$90b2obo2b
o66b2o$94b2o67b2o2$92bo$92b3o$95bo30b2o$94b2o13b2o14bobo$109b2o14bo$
124b2o4$112b2o42b2o$112bo43bo$110bobo44b3o$110b2o47bo$143b2o$142bobo$
93b2o47bo$93b2o15b2o29b2o$110bobo$112bo$112b2o4$93b2o56b2o$93bo57b2o$
91bobo$91b2o65bob2o$158b2obo$141b2o$141b2o$108b2obo19b2o12b2o$108bob2o
20bo$132bobo16bo$101b2o30b2o6b3o7bo4b2o$101b2o37bo3bo5b2o3bo2bo$139bo
5bo9bo3bo$139bo6b3o5b2o3bo$139bo6b2o6bo3bo$140bo3bob3o7bob2obo$141b3o
3bobo3bo2bob2ob2o$147b2o4bo4b2obo$91b2o54bobo3b2o5bo$92bo44b2o8b3o6b4o
$92bobo41bobo9b2o8bo$93b2o41bo$135b2o3$148bo$147bo$147b3o$152b2o$107b
2o43b2o$107b2o23b2o10b2o$132bo12bo$130bobo9b3o$130b2o10bo$116b2o$116b
2o$139bo$99b2o38b3o20b2o$99b2o5b4o32bo18bo2bob2o$106bo2b2o30b2o17bobob
ob2o$107bo2b2o48bobobo$96b2o9bo2bo48b4obob2o$95bobo10b2o50bo2b2obo$95b
o67bo3bo$94b2o65bobob2o$159bobobobo$102b2ob3o51b2o2bobo$102bob4o55b2o$
103bo3bo2bo18b2o24b2o$108b2obo4b2o11b2o23bo2bo2b2o$101b5o5bo5bo36bobo
4bo2bo$101bo4b5o3b3o38bo5bobobo$102b3o9bo43b2obo2bo$104bob2ob2o47bo2bo
$105bobob2o22b2o20bo4bo$134bo20b5o$131b3o$131bo25b2obo$157bob2o!
Re: The Hunting of the New Herschel Conduits
There's likely a compact way to hook that up to one of the more complicated BtoH subcomponents, and point an escaping glider back via Snark. Might be small enough to use for something.Extrementhusiast wrote:Well, here's a rather interesting partial BtoB, which requires a glider to reset it:Code: Select all
x = 17, y = 28, rule = B3/S23 14bo$13bo$13b3o16$b2o4b2o$b2o4bobo$8bo2$2bo$b3o11bo$2o2bo10b2o$16bo$ 16bo$15bo!
No word on the PiinBellman front yet. The search is currently exploring what it can do after placing a block like so:
Code: Select all
x = 9, y = 3, rule = B3/S23
3o4b2o$2bo4b2o$3o!
Tanner Jacobi
Re: The Hunting of the New Herschel Conduits
Don't let me discourage anyone, but every one of the obvious immediate glider outputs that I tried  R64, Fx77, F166 (i.e., changing to a dependentconduit output glider), etc.  need a colorchanging Snark. And the second natural glider from L112 and L156 doesn't happen to line up, and I don't think there's an HtoG that can make that adjustment. Using a HtoG kind of defeats the purpose of making a new conduit, anyway.Kazyan wrote:There's likely a compact way to hook that up to one of the more complicated BtoH subcomponents, and point an escaping glider back via Snark. Might be small enough to use for something.
It's much easier at p4/5/6/7/8 (and even then it gets big and slow pretty fast):
Code: Select all
x = 169, y = 59, rule = LifeHistory
119.A2$117.A.3A$29.A89.2A.A8.A$28.3A88.A.2A6.3A$27.3A.A88.3A.A3.A$28.
A3.A8.A86.2A$29.A3.A5.3A80.A$30.A.3A3.A87.A$31.3A4.2A85.A.A$2A30.A93.
2A2.2A$2A.A32.A93.2A$4.A8.A21.A.A$.A9.3A22.2A2.2A$2.A.2A4.A29.2A$4.2A
4.2A2$8.A$7.A.A$8.2A2.2A$12.2A4$156.2A$156.2A5.2A$163.2A$127.2A$128.A
$127.A33.2A$127.2A32.2A$3.2C4.2A101.2C4.2A47.2A$3.2C4.A.A100.2C4.A.A
46.2A$10.A108.A$42.A$4.A35.3A70.A$3.3A33.A72.3A15.2A$2.2A2.A20.D11.2A
70.2A2.A14.2A$25.3D$25.D.D$25.D3$67.D$65.3D72.2A$48.2A15.D.D73.A$48.
2A15.D72.3A18.3D$25.2A49.A61.A20.D$24.A.A48.A.A80.3D$24.A50.A.A$23.2A
10.2A39.A$36.A$33.3A9.2A$33.A11.A$46.A$45.2A$163.2A$162.A2.A$163.2A!
Re: The Hunting of the New Herschel Conduits
I don't think this catalyst is quite compatible with the nearby eater...but I really wish it was. If nothing else, it should be kept in mind if a similar spark ever appears.
Closeup of the catalyst doing its thing:
EDIT: It can also handle certain formations of preblock via a slightly different mechanism.
Code: Select all
x = 18, y = 11, rule = LifeBellman
13E$13E$10E2C$9E3.C$4E2C5.2C$4EC.2C$3E3.C.C$3E2C2.2C7.2A$3EC11.2A$4E
12.2A$5E12.A!
Code: Select all
x = 12, y = 10, rule = B3/S23
2b2obo$2bob2o2bo$6b3o$o2b2o$4ob2o$5bobo2b2o$2b2o2b2o2b2o$2bo6b2o$obo7b
o$2o!
Code: Select all
x = 13, y = 10, rule = B3/S23
2b2obo$2bob2o2bo$6b3o$o2b2o$4ob2o$5bobo2bo$2b2o2b2o2bo$2bo6b4o$obo7bo$
2o!
Tanner Jacobi
 A for awesome
 Posts: 1904
 Joined: September 13th, 2014, 5:36 pm
 Location: 0x1
 Contact:
Re: The Hunting of the New Herschel Conduits
An Htowing converter:
Unfortunately, the wing may be too close to the compound catalyst to do anything with; I have tried to manually place catalysts to get the reaction away from there, with no success.
Code: Select all
x = 56, y = 49, rule = LifeHistory
9.2C$8.C.C$8.C$3.C.2C.2C2.2B3.C$3.2C.C.7B.C.C$6.C3.6B.C$6.2C2.6B10.2C
$4.2C4.6B10.C$5.C4.6B7.BC.C$5.C.CB.6B3.3B.B2C$6.2CB.14B$8.16B$9.14B$
8.16B$8.18B$6.22B$6.19BC2B$5.13B.4BCBC3B$5.12B2.4B3C2B$2.3D12B2.4BC5B
$.D2BD13B2.10B$BDBD14B9.4B$.BD16B9.4B$3.16B10.4B$5.4B.10B10.4B$6.15B
10.4B$6.15B11.4B$5.16B12.4B$4.17B13.4B$4.16B15.4B$5.11B20.4B$7.5B.3B
21.4B$9.B3.5B20.4B$8.3B4.B2C21.4B$7.B2CB5.C23.4B$8.2C7.3C21.4B$19.C
22.4B$43.4B$44.4B$45.4B$46.4B$47.4B$48.4B$49.4B$50.4B$51.4B$52.BDBD$
53.B2D$54.D!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)
$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$
http://conwaylife.com/wiki/A_for_all
Aidan F. Pierce
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)
$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$
http://conwaylife.com/wiki/A_for_all
Aidan F. Pierce
Re: The Hunting of the New Herschel Conduits
Not quite workable in its current form, is it? There are two failures, one with the first snake which just barely gets hit by a fading spark at T=257, and one where an output glider at T=264 gets caught in a way that shuts off the input circuit at T=387.kiho park wrote:It convert a Herschel to Herschel and RPentomino...
Edit : 1H to 2HCode: Select all
x = 136, y = 75, rule = LifeHistory 55.2A$54.B2AB$54.3B$55.B$53.5B$53.B3D2B$53.2BD3B$53.2B3DB$53.6B$53.6B $53.6B$53.5B$52.6B$53.6B$52.7B$52.6B$52.6B$52.6B$51.8B$52.8B$51.9B$ 51.9B$51.10B$51.5B2A3B9.2A10.B$51.5B2A4B9.A8.5B$51.11B9.A.AB4.6B$51. 4BD7BA.A6.2AB.B2.6B$53.B3D4B2.2A.A7.13B$39.A13.D2B2D2B6.A8.12B$39.3A 11.5B8.2A5.14B$42.A10.5B9.2B3.16B$30.2A9.2A9.6B8.6B.15B4.3B$31.A5.3B. 5B.3B2.8B6.22B.7B$31.A.AB.4B3.20B2.22B.B2A5B$32.2AB.27B2.23BA2BA5B$ 34.55B2A6B$34.62B$34.51B.6B.2B$34.46B.2B2.8B.B$17.2B13.47B7.6B.B2A$ 17.3B12.43B15.B3.A.A$17.4B10.2A13B2.9B.B3.B3.10B19.2A$18.4B9.2AB.12B 2.7B11.9B$19.4B9.B.13B.9B8.11B$7.2A3.2A6.4B11.11B3.7B9.2A3.2B3D2B$6.B 2AB.B2AB6.4B10.10B4.7B10.A3.2BD4B$7.2B2.3B3.B4.4B8.11B3.9B6.3A4.B3D4B .2B$8.3B.3B.4B3.4B6.11B5.7B7.A6.12B$2A5.7B.13B4.13B6.3B16.14B$.A5.23B .16B4.5B14.15B23.2A$.A.AB.19B.8B.4B2A7B6.2A15.14B24.A$2.2AB.33B2A7B6. A19.11B23.A$4.45B6.3A15.13B2.2B18.2A$4.33BD12B7.A14.19B8.2A8.B$4.33B 2D10B21.B.21B6.A.A7.3B$5.33B2D7B19.2A.2A22B7.AB6.6B$7.31BD10B18.A.A.B .21B5.2B3.B2.10B$5.32BD12B15.A.A.A.A23B.B2.19B3.2B2.6B$5.2A3.26B3.12B 14.2A3.2A.B.19B.12BD3B2A15BD3B$6.A3.20B4.B6.10B23.33B2D2B2A15BDBDB.2B $3.3A6.15B7.2A7.7B24.21B2D11B2D18B3D3B2A$3.A8.11B12.A9.2B2.BA22.23B2D 10BD21BDB.B2A$11.13B10.A14.A.A19.A24BD10BD24B2.B$10.15B9.2A14.2A17.3A 2.7B.17B.4B5.13B.B$10.16B42.A5.7B3.7B.12B5.7B.B$10.17B41.2A4.7B4.5B4. 8B$10.16B48.5B6.4B5.6B$12.14B46.2AB.2B7.4B6.4B$11.4B.2B2A6B45.A.AB10. B2AB$10.4B2.2B2A6B45.A14.2A$9.4B2.11B44.2A$8.4B4.2B3D4B$7.4B5.3BD4B$ 6.4B7.2B3D2B$6.3B8.7B!
Not sure if these are repairable or not, but it might be a good problem to turn Bellman loose on. I'd still like to see some nonHerschelreceiver way to drop an Rpentomino successfully into that troublesome conduit. Once you get a chain started (of the direct BtoB version) it's an unusually prolific source of useful gliders, but as far as I know you have to do a rather weird tandemglider conversion to start things off. Is there a better way that I've missed seeing, to make a clean connection directly from a Herschel?
Speaking of Guam's stillunderused discoveries  here's another, probably silly, thought for a Bellman investigation. Is there any hope that Guam's 2G>H+G (G4 input) could be upgraded to a stable glider reflector, by catalyzing the output Bheptomino to produce one of the white input gliders?
Code: Select all
x = 82, y = 68, rule = LifeHistory
12.B2A47.B2A$10.2BA2BAB43.2BA2BAB$10.3B2A3B42.3B2A3B$8.12B38.12B$7.
14B36.14B$8.13B37.13B$8.14B36.14B$7.15B35.15B$7.14B36.14B$7.13B37.13B
$7.B3D4B.3B38.B3D4B.3B$7.2BD4B43.2BD4B$7.2B3D2B43.2B3D2B$7.6B44.6B$6.
7B43.7B$5.8B42.8B$4.8B42.8B$3.9B41.9B$3.3B.6B40.3B.6B$3.2B.7B40.2B.7B
$3.B2.6B41.B2.6B$6.6B44.6B$6.6B44.6B$5.8B42.8B$6.8B42.8B$5.9B41.9B$5.
9B41.9B$5.10B40.10B$5.5B2C3B40.5B2C3B$5.5B2C4B39.5B2C4B$5.11B39.11B$
5.4BD7BC.2C34.4BD7BC.2C$7.B3D4B2.2C.C36.B3D4B2.2C.C$.2A4.D2B2D2B9.CB
26.2A4.D2B2D2B$2.A4.6B9.BCBC26.A4.6B$2.A.AB.6B8.2B2C27.A.AB.6B$3.2AB.
7B6.4B29.2AB.7B$5.8B6.4B32.8B$6.7B5.4B34.7B$6.7B4.4B35.7B8.CB$2.B4.7B
2.4B32.B4.7B6.BCBC$.A2B.B.6B2.4B32.A2B.B.6B6.2B2C$A.A15B32.A.A11B4.4B
$.AB.13B34.AB.3B2A5B3.4B$4.12B38.3B2A4B3.4B$4.11B39.8B3.4B$5.10B40.5B
EB2.4B$3.14B36.3B2A2BEBE4B$3.15B35.3B2A2B2E6B$2.2A14B.2B31.2A14B.2B$
2.2A6BE9B2A30.2A16B2A$3.7BEBE5B.B2A31.15B.B2A$5.5B2E6B2.B34.13B2.B$5.
14B36.14B$7.12B38.12B$7.2B2A9B37.2B2A9B$8.B2A5B.4B36.2B2A5B.4B$8.9B.
4B36.9B.4B$8.9B2.4B35.9B2.4B$6.2A.8B3.4B32.2A.8B3.4B$6.A2.6B6.4B31.A
2.6B6.4B$4.A.A3.5B7.4B28.A.A3.5B7.4B$4.2A3.6B8.4B27.2A3.6B8.4B$10.4B
10.4B32.4B10.4B$11.2B12.4B32.2B12.4B$12.2B12.4B32.2B12.4B$11.B2AB12.
4B30.B2AB12.4B$12.2A14.4B30.2A14.4B!
 Extrementhusiast
 Posts: 1798
 Joined: June 16th, 2009, 11:24 pm
 Location: USA
Re: The Hunting of the New Herschel Conduits
Well, you didn't try F171:dvgrn wrote:Don't let me discourage anyone, but every one of the obvious immediate glider outputs that I tried  R64, Fx77, F166 (i.e., changing to a dependentconduit output glider), etc.  need a colorchanging Snark. And the second natural glider from L112 and L156 doesn't happen to line up, and I don't think there's an HtoG that can make that adjustment. Using a HtoG kind of defeats the purpose of making a new conduit, anyway.Kazyan wrote:There's likely a compact way to hook that up to one of the more complicated BtoH subcomponents, and point an escaping glider back via Snark. Might be small enough to use for something.
Code: Select all
x = 68, y = 55, rule = B3/S23
31b2o$30bobo$24b2o4bo$22bo2bo2b2ob4o$22b2obobobobo2bo$25bobobobo$25bob
ob2o$26bo2$39b2o$30b2o7bo$30b2o5bobo$37b2o7$27b2o$28bo16bo$25b3o17b3o$
25bo22bo$47b2o6$65bo$39b2o24bo$40bo24b3o$40bobo24bo$41b2o3$35bo$16b2o
17b3o$17bo20bo$16bo20b2o$16b2o$b2o4b2o$b2o4bobo$8bo2$2bo$b3o15b2o15bo$
2o2bo14b2o15bo$36b3o$38bo2$45b2o$46bo$43b3o$43bo!
I Like My Heisenburps! (and others)
Re: The Hunting of the New Herschel Conduits
Oddly enough, I did try F171, but apparently had something lined up wrong. That seems like a reasonablesized conduit, worth rolling into Hersrch.Extrementhusiast wrote:Well, you didn't try F171...
I thought about that, but unless the preceding conduit is a 180degree turn, it will take several Snarks to deliver the glider to the right place. Worth looking into a little, but it's going to increase the size quite a bit more.Extrementhusiast wrote:Also, something else: what if the reset glider came from the conduit before this, instead of after?
Re: The Hunting of the New Herschel Conduits
Code: Select all
x = 13, y = 21, rule = B3/S23
10bo$9bobo$6bo2bobo$6b4ob2o$4b2o$3bo2b4ob2o$3b2obo2bob2o$2obo2bobo$o2b
obobo$2b2ob2o5$4b2o$4b2o4bobo$10b2o$11bo2$10b2o$10b2o!
Tanner Jacobi
 Extrementhusiast
 Posts: 1798
 Joined: June 16th, 2009, 11:24 pm
 Location: USA
Re: The Hunting of the New Herschel Conduits
However, it would likely decrease the recovery time.dvgrn wrote:I thought about that, but unless the preceding conduit is a 180degree turn, it will take several Snarks to deliver the glider to the right place. Worth looking into a little, but it's going to increase the size quite a bit more.Extrementhusiast wrote:Also, something else: what if the reset glider came from the conduit before this, instead of after?
I Like My Heisenburps! (and others)
Re: The Hunting of the New Herschel Conduits
Hmm. Starting catgl pattern:Kazyan wrote:Looks interesting. If it's no good for a stable GtoH or similar, it's probably usable as a PitoH subcomponent. The bait block can be a boat/beehive/whatever works to create a Pi, too.Code: Select all
x = 13, y = 21, rule = B3/S23 10bo$9bobo$6bo2bobo$6b4ob2o$4b2o$3bo2b4ob2o$3b2obo2bob2o$2obo2bobo$o2b obobo$2b2ob2o5$4b2o$4b2o4bobo$10b2o$11bo2$10b2o$10b2o!
Code: Select all
x = 39, y = 31, rule = LifeHistory
35.A2.A2$33.A2.A2$31.A2.A2$29.A2.A2$27.A2.A2$10.C14.A2.A$9.C.C$6.C2.C
.C11.A2.A$6.4C.2C$4.2C5.BD8.A2.A$3.C2.4CB2A$3.2C.A2.CD2A6.A2.A$2C.C2.
ABA$C2.C.CBA9.A2.A$2.2C.CA$5.D9.A2.A2$13.A2.A$4.D$4.CA8.A$4.CA4.A.A$
4.D5.2A$11.A2$10.2A$10.2A!
Code: Select all
x = 139, y = 38, rule = LifeHistory
35.A2.A96.A2.A2$33.A2.A96.A2.A2$31.A2.A96.A2.A2$29.A2.A96.A2.A2$27.A
2.A96.A2.A2$10.C14.A2.A81.C14.A2.A$9.C.C97.C.C$6.C2.C.C11.A2.A79.C2.C
.C11.A2.A$6.4C.2C93.4C.2C$4.2C15.A2.A79.2C15.A2.A3.2C$3.C2.4C.2A90.C
2.4C.2A15.2A$3.2C.A2.C.2A6.A2.A80.2C.A2.C.2A6.A2.A$2C.C2.A.A91.2C.C2.
A.A$C2.C.C.A9.A2.A79.C2.C.C.A9.A2.A$2.2C.CA95.2C.CA$15.A2.A96.A2.A2$
13.A2.A96.A2.A$22.AC111.AC$4.CA8.A7.AC80.CA8.A20.AC$4.CA4.A.A91.CA4.A
.A$10.2A98.2A$11.A99.A2$10.2A98.2A$10.2A98.2A$19.2A.C$19.2A.3C$25.C$
19.2C.3C$20.C.C$20.C.C$21.C!
I'm running a T=16..60 3catalyst search, just to see if anything interesting happens to show up. As with any search with Catgl 1.0.3, it's important to emphasize that this search will cover approximately 0% of the actual search space...!
Re: The Hunting of the New Herschel Conduits
No kidding:dvgrn wrote:It's certainly not a hopeless case.
Code: Select all
x = 26, y = 21, rule = B3/S23
10bo$9bobo$6bo2bobo$6b4ob2o$4b2o$3bo2b4ob2o$3b2obo2bob2o$2obo2bobo$o2b
obobo$2b2ob2o4$24bo$4b2o17bobo$4b2o4bobo10bobo$10b2o12bo$11bo2$10b2o$
10b2o!
Tanner Jacobi
Re: The Hunting of the New Herschel Conduits
Not surprisingly, the threecatalyst search didn't turn up anything new.
Seems like what we really ought to do is to automate the transparentobject stage of the search better. Given a promising result, try dropping all likely common objects at all possible locations nearby, and try say a 1catalyst search for each such object and see if the object ever happens to be restored.
Ptbsearch can do this already, but is there a catglbased way to do it that would be more efficient? It's the usual problem of defining searches that cover as much of the likely part of the search space as possible, with as little time wasted as possible researching the same space again and again (e.g., different eaters for the same glider.)
For me this new variant is actually a step or two down the hopefulness scale  you've repaired the bait block but only at the cost of a beehive, which is less likely to reappear than the block was, and there's no output glider yet. But I do love to be proved wrong.Kazyan wrote:No kidding:dvgrn wrote:It's certainly not a hopeless case.
Code: Select all
#C [sacrificial beehive restores the bait block] x = 26, y = 21, rule = LifeHistory 10.C$9.C.C$6.C2.C.C$6.4C.2C$4.2C6.D$3.C2.4C.2A$3.2C.A2.CD2A$2C.C2.A.A $C2.C.C.A$2.2CDCA4$4.D19.A$4.CA17.A.A$4.CA4.A.A10.A.A$4.D5.2A12.A$11. A2$10.2A$10.2A!
Seems like what we really ought to do is to automate the transparentobject stage of the search better. Given a promising result, try dropping all likely common objects at all possible locations nearby, and try say a 1catalyst search for each such object and see if the object ever happens to be restored.
Ptbsearch can do this already, but is there a catglbased way to do it that would be more efficient? It's the usual problem of defining searches that cover as much of the likely part of the search space as possible, with as little time wasted as possible researching the same space again and again (e.g., different eaters for the same glider.)
Re: The Hunting of the New Herschel Conduits
A block almost works in the same location, and various other small objects make it work too, which is why I'm running Bellman for it. But I currently have 106m prunes for too many actives cells and only 3.5m for catalyst recovery, which I'm taking to mean "this can't be catalyzed; it just explodes no matter what you do". Oh well.dvgrn wrote:For me this new variant is actually a step or two down the hopefulness scale  you've repaired the bait block but only at the cost of a beehive, which is less likely to reappear than the block was, and there's no output glider yet. But I do love to be proved wrong.
Seems like what we really ought to do is to automate the transparentobject stage of the search better. Given a promising result, try dropping all likely common objects at all possible locations nearby, and try say a 1catalyst search for each such object and see if the object ever happens to be restored.
Ptbsearch can do this already, but is there a catglbased way to do it that would be more efficient? It's the usual problem of defining searches that cover as much of the likely part of the search space as possible, with as little time wasted as possible researching the same space again and again (e.g., different eaters for the same glider.)
Good idea for transparency searching. I've noticed quite a few transparent blocks in existing conduit collections...Block> B > Block + H is a thing that happens more often than I expected. I'm sure it wouldn't be too hard to reuse most of catgl's code for a transparency.py script or somesuch.
Code: Select all
#C Secondary transparent block reaction and output Herschel, but primary block becomes an awkwardlyplaced beehive instead of being restored. Whoops.
x = 27, y = 25, rule = B3/S23
10bo$9bobo$6bo2bobo$6b4ob2o$4b2o$3bo2b4ob2o$3b2obo2bob2o$2obo2bobo$o2b
obobo$2b2ob2o18b2o$25bo$23bobo$23b2o2$4b2o$4b2o4bobo$10b2o$11bo2$10b2o
$10b2o3$16b2o$16b2o!
EDIT2: Not a Bellman find, but one of the more obscure catalysts. There's a blinker that needs gliderassisted cleanup, but there's a smallbutusable plume that results off in a good direction. Haven't seen a conduit with this interaction in use yet...
Code: Select all
x = 17, y = 16, rule = B3/S23
5b2o$5bobo$6b2o$2b2o$bobo$bo$2o7$14b3o$15bo$13b3o!
Tanner Jacobi
 A for awesome
 Posts: 1904
 Joined: September 13th, 2014, 5:36 pm
 Location: 0x1
 Contact:
Re: The Hunting of the New Herschel Conduits
This has just got to be known:
Code: Select all
x = 38, y = 44, rule = LifeHistory
24.3D$24.DBD$23.BDBDB$23.5B$23.6B$22.7B$11.C10.8B$11.3C8.9B$14.C7.9B$
13.2C6.10B$13.5B2.13B$15.18B.2B$14.2C19B2C$14.2C17B.B2C$15.B.17B.B$
17.16B$18.14B$19.8B2.4B$20.7B3.4B$17.11B3.4B$16.12B4.4B$16.12B5.2BDB$
16.11B7.2B2D$16.B3C4B.4B6.2D$16.2BC4B4.2C$16.2B3C2B4.C$16.6B6.3C$15.
7B8.C$14.4B.B$13.4B$12.4B$11.4B$10.4B$9.4B$8.4B$7.4B$6.4B$5.4B$4.4B$
3.4B$2.4B$.D3B$D3B$3D!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)
$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$
http://conwaylife.com/wiki/A_for_all
Aidan F. Pierce
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)
$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$
http://conwaylife.com/wiki/A_for_all
Aidan F. Pierce
 Extrementhusiast
 Posts: 1798
 Joined: June 16th, 2009, 11:24 pm
 Location: USA
Re: The Hunting of the New Herschel Conduits
Yes, that's the Htopi converter used in the Fx176 conduit.A for awesome wrote:This has just got to be known:Code: Select all
RLE
I Like My Heisenburps! (and others)
Re: The Hunting of the New Herschel Conduits
Do we already have an H>2G that does this or a differentcatalyst duplicate of this?
Code: Select all
x = 27, y = 30, rule = B3/S23
10bo$8b3o$7bo$7b2o2$4b2o$4bobo$2o3b2o$2o23b2o$24bobo$24bo$23b2o$22bo$
22b3o$25bo$24b2o2$21b2o$21bobo$23bo$23b2o5$14b3o$5b2o8bo$6bo6b3o$3b3o$
3bo!
Tanner Jacobi
Re: The Hunting of the New Herschel Conduits
Holy tandem gliders, Kazyan! (Sorry, couldn't resist.)Kazyan wrote:Do we already have an H>2G that does this or a differentcatalyst duplicate of this?
Yes, that's a variant of a known H>G6 in Calcyman's collection. Useful for making adjustable B=backward and Bx=backward flipped Herschel conduits, since G2, G5, and G6 can be caught by standard Herschel transceivers:
Code:
Select all
#C [[ AUTOSTART STOP 409 HEIGHT 300 THEME 9 ]]
x = 140, y = 103, rule = B3/S23
52bo$50b3o$49bo$49b2o2$46b2o$46bobo85bo$42b2o3b2o63b2o9b2o7b3o$42b2o
23b2o43b2o9b2o6bo$66bobo62b2o$66bo$65b2o$64bo$64b3o$67bo$66b2o2$63b2o
68b2obo$63bobo67b2ob3o$65bo73bo$65b2o66b2ob3o$134bobo$134bobo$135bo2$
56b3o67b3o$47b2o8bo59b2o8bo$48bo6b3o60bo6b3o$45b3o67b3o$10b2o33bo34b2o
33bo$10b2o68b2o$6bo69bo$6b3o67b3o$9bo53b2o14bo53b2o$8b2o11bo41bobo12b
2o11bo41bobo$20bobo7b2o33bo24bobo7b2o33bo$20bobo7b2o33b2o23bobo7b2o33b
2o$21bo69bo5$18b2o68b2o$18b2o68b2o$4b2o68b2o$4b2o68b2o$2o68b2o$2o68b2o
14$24b2o68b2o$23bobo67bobo$24bo69bo7$26b2obo66b2obo$26bob2o66bob2o2$
19b2o68b2o$19b2o68b2o7$9b2o68b2o$10bo69bo$10bobo67bobo$11b2o68b2o6$18b
3o67b3o$18bo69bo$17b3o67b3o8$22b2o68b2o$21bo2bo66bo2bo$22b2o68b2o!
Re: The Hunting of the New Herschel Conduits
Another HtoG, but boring, and again, might be a duplicate (though it does involve a Bellman result this time.)
I guess with the first escaping glider and the actual HtoG part, it could be handy for closing the signal loop on "bootstrapped" guns.
Code: Select all
x = 30, y = 28, rule = B3/S23
17bo$16bobo$16bobo$4bo10b2ob3o$4b3o14bo$7bo7b2ob3o$6b2o7b2obo4$25bo$
24bobo$25bo3$25b2o$26bo$2b2o22bob2o$3bo21b2ob2o$3o$o$4b2o$3bobo$3bo$2b
2o$17b3o4b2o$18bo5b2o$16b3o!
Tanner Jacobi
 A for awesome
 Posts: 1904
 Joined: September 13th, 2014, 5:36 pm
 Location: 0x1
 Contact:
Re: The Hunting of the New Herschel Conduits
On a different note, a loafertopi converter:
Code: Select all
x = 27, y = 22, rule = LifeHistory
7.2C$6.B2CB$6.3B$6.2B$.B3.5B$2CB.2C2BCB2C$2CBC2BC2B2CB$.3BCBC5B$.4BC
6B$3.8BC5B.2B$3.6B3C9B$4.4BC12B$5.4BC10B$6.4B2C9B$8.13B$8.13B4.B$9.
14B.B2C$9.2B3D11B2C$10.BD12B.B$11.3D9B$13.8B$14.5B!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)
$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$
http://conwaylife.com/wiki/A_for_all
Aidan F. Pierce
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)
$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$
http://conwaylife.com/wiki/A_for_all
Aidan F. Pierce
Re: The Hunting of the New Herschel Conduits
This one needs to wait until pretty late in the Herschel's evolution to work. I haven't figured anything out with it.
Code: Select all
x = 30, y = 17, rule = B3/S23
$21b2o$21b2o2$o$obo$3o$2bo21b2o$24bo$25bo$24b2o$21b2o$21bob3o$22bo3bo$
23bo2bo$24bobob2o$23b2ob2obo!
Tanner Jacobi
Re: The Hunting of the New Herschel Conduits
Hmm. Adding a block here extracts a glider, and protects the catalyst from immediate destruction, and gets a Herschel out to the north. But it's probably still a bit too messy to be a very likely candidate for a complete cleanup:Kazyan wrote:This one needs to wait until pretty late in the Herschel's evolution to work. I haven't figured anything out with it.
Code:
Select all
x = 30, y = 22, rule = B3/S23
21b2o$21b2o2$o$obo$3o$2bo21b2o$24bo$25bo$24b2o$21b2o$21bob3o$22bo3bo$
23bo2bo$24bobob2o$23b2ob2obo5$14b2o$14b2o!
#C [[ THUMBNAIL ]]