The Hunting of the New Herschel Conduits

For discussion of specific patterns or specific families of patterns, both newly-discovered and well-known.
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A for awesome
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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 12th, 2015, 11:13 pm

Sokwe wrote:
A for awesome wrote:A possibly new H-to-B:

Code: Select all

x = 30, y = 29, rule = LifeHistory
15.C$13.3C$12.C$7.2C3.2C15.C$5.2B2CB3.B13.3C$5.4B4.4B9.C$5.15B6.2C$.B
3.16B2.5B$2CB.22B$2C23B2C$.B.22B2C$4.20B.B$5.19B$5.18B$6.16B$6.15B$5.
19B$4.2C17BDB$4.2CB.16BD$5.B2.16B2D$10.11B3CD$11.11BCDB$12.B2.5B3C2B$
14.3B2.6B$13.C2.CB.7B$13.4C4.B.4B$24.4B$13.2C10.4B$13.2C11.4B!
Actually an H-to-R, but there is only one connection that I know of.
The boat and loaf variants of the R->B work equally well here. Unfortunately, the only B->X that connects to the output seems to be BBx187H. Even this only works in a limited number of cases. e.g.,

Code: Select all

x = 80, y = 58, rule = LifeHistory
51.2A$B49.B2AB$2B49.2B$3B47.2B$4B38.2A5.4B$.4B36.B2AB2.10B$2.4B29.A2B
4.15B$3.4B27.ABAB5.13B2A$4.4B26.A2BAB2.15B2A$5.4B26.2A2B2.14B.B$6.4B
26.19B$7.4B7.A7.2A9.4BD13B$8.4B6.3A6.A9.4B3D11B2.2A$9.4B8.A5.A.AB6.5B
D14BA.A$10.4B6.2A6.A.AB.B3.19B3.A$11.4B5.6B3.A3B2A3.18B3.2A$12.4B6.5B
.3B.B2A2.19B$13.4B4.9B3.B4.17B$14.4B2.11B7.17B$15.18B2.20B$16.22BD15B
$12.2A3.21BDBD4B.7B$13.A4.20B3D4B2.6B$13.A.AB.21B2D2BDB3.6B$14.2A24B
3D2B5.4B$15.17B.5B.2BD4B3.B2A2B$17.30B3.2A.B2A$8.A10.16B.12B5.BA.A$8.
3A8.15B3.12B7.A$11.A7.14B5.7B.4B6.2A$10.2A3.B3.13B7.6B2.4B$10.8B.12B
8.7B2.4B$12.18B9.7B3.4B$12.17B10.8B.6B22.B$11.17B11.16B20.3D$9.18B12.
17B19.BDB$7.19B13.18B17.2B3D$7.2BE15B15.18B16.5B$6.3BEBE4B.9B17.11B.
4B14.7B$7.2B3E4B2.7B17.13B.4B5.2A5.8B$6.5BE4B4.5B16.20B3.B2AB3.8B$5.
10B3.5B16.B.21B3.3B2.9B$4.4B10.2A15.2A.2A23B3.B2.4B.6B$4.3B12.A16.A.A
.B.30B.7B$2.4B10.3A15.A.A.A.A38B$2.2A12.A17.2A3.2A.B.35B$3.A39.32B2A
3B$3A40.32B2A2B$A41.36B$40.A35B$38.3A2.7B.22B2.2B$37.A5.7B3.7B.8B.2B
2.B2AB$37.2A4.7B4.5B5.6B5.2A$43.5B6.4B8.4B$41.2AB.2B7.4B7.B2A2B$40.A.
AB10.B2AB8.2A$40.A14.2A$39.2A!
I didn't know about the loaf, but the only boat I know of blocks the incoming B.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by Sokwe » November 13th, 2015, 2:18 am

A for awesome wrote:the only boat I know of blocks the incoming B.
The boat seems to work in this example:

Code: Select all

x = 80, y = 58, rule = LifeHistory
51.2A$B49.B2AB$2B49.2B$3B47.2B$4B38.2A5.4B$.4B36.B2AB2.10B$2.4B36.15B
$3.4B36.13B2A$4.4B15.2A16.15B2A$5.4B15.A16.14B.B$6.4B14.A.AB12.15B$7.
4B7.A6.A.AB.B8.2BD13B$8.4B6.3A5.A3B2A6.3B3D11B2.2A$9.4B8.A3.3B.B2A7.
3BD14BA.A$10.4B6.2A3.2B3.B8.17B3.A$11.4B5.8B6.2A.19B3.2A$12.4B6.7B5.A
.A19B$13.4B4.9B5.AB.17B$14.4B2.11B7.17B$15.18B2.20B$16.22BD15B$12.2A
3.21BDBD4B.7B$13.A4.20B3D4B2.6B$13.A.AB.21B2D2BDB3.6B$14.2A24B3D2B5.
4B$15.17B.5B.2BD4B3.B2A2B$17.30B3.2A.B2A$8.A10.16B.12B5.BA.A$8.3A8.
15B3.12B7.A$11.A7.14B5.7B.4B6.2A$10.2A3.B3.13B7.6B2.4B$10.8B.12B8.7B
2.4B$12.18B9.7B3.4B$12.17B10.8B.6B22.B$11.17B11.16B20.3D$9.18B12.17B
19.BDB$7.19B13.18B17.2B3D$7.2BE15B15.18B16.5B$6.3BEBE4B.9B17.11B.4B
14.7B$7.2B3E4B2.7B17.13B.4B5.2A5.8B$6.5BE4B4.5B16.20B3.B2AB3.8B$5.10B
3.5B16.B.21B3.3B2.9B$4.4B10.2A15.2A.2A23B3.B2.4B.6B$4.3B12.A16.A.A.B.
30B.7B$2.4B10.3A15.A.A.A.A38B$2.2A12.A17.2A3.2A.B.35B$3.A39.32B2A3B$
3A40.32B2A2B$A41.36B$40.A35B$38.3A2.7B.22B2.2B$37.A5.7B3.7B.8B.2B2.B
2AB$37.2A4.7B4.5B5.6B5.2A$43.5B6.4B8.4B$41.2AB.2B7.4B7.B2A2B$40.A.AB
10.B2AB8.2A$40.A14.2A$39.2A!
-Matthias Merzenich

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Re: The Hunting of the New Herschel Conduits

Post by Kazyan » November 13th, 2015, 3:28 am

A new Bellman result for the R-pentomino allows, uh, this:

Code: Select all

x = 39, y = 40, rule = LifeHistory
12.A$11.A.A$11.A.A4.A$9.3A.2A3.3A$8.A4.B7.A$9.3AB2A5.2A$11.A.2A.B3.6B
$13.5B4.5B$14.5B2.6B$14.13B$10.B3.13B$8.19B$4.22B$2.24B$.26B$2.26B$2.
27B$.D23B.4B$2D23B2.4B$.2DB.B.B.16B3.4B$9.16B4.4B$8.21B.4B$7.29B$8.
29BD$10.5B2C18B3DB$12.4B2C17BDBD$13.3BC18BD$14.10B4.2B2.2B$14.10B$14.
6B$15.5B$14.4B.B$13.4BA4B$13.2ABABA.2A$14.ABA.A.A$14.A.A.A2.3A$15.2A.
A4.A$17.A$17.A.A$18.2A!
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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 13th, 2015, 2:04 pm

Sokwe wrote:
A for awesome wrote:the only boat I know of blocks the incoming B.
The boat seems to work in this example:

Code: Select all

rle
Sorry, that's because I was stupid and didn't actually check with the live objects.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by Extrementhusiast » November 13th, 2015, 5:29 pm

Meanwhile, a very different C-to-Pi:

Code: Select all

x = 32, y = 29, rule = LifeHistory
10.A$9.A.A4.2A3.A$9.A.A5.A2.A.A$A7.2A.2A2.A4.A.A$3A12.5A.A$3.A4.2A.4A
4.A$2.2A4.2A.A2.A.A3.A$15.A.A3.A$16.A3.2A5$25.2A$6.3C15.A.A$5.C2.C15.
2A$5.2C21.2A$28.A.A$30.A$30.2A7$9.D.D$9.D.D$9.3D!
This C-to-G is also possible:

Code: Select all

x = 24, y = 28, rule = LifeHistory
10.A$9.A.A$9.A.A$A7.2A.3A$3A11.A$3.A4.2A.3A$2.2A4.2A.A2$22.2A$22.A$
20.A.A$20.2A3$6.3C$5.C2.C$5.2C10$12.2A$12.2A!
Also, perhaps we should look for Pi-to-Xs with a certain transparent block:

Code: Select all

x = 123, y = 25, rule = LifeHistory
118.A$15.2A99.3A$15.2A59.2A37.A6.A$76.2A37.2A3.3A$119.A$4.2C16.2A45.
2C3.4A34.2C5.2A$4.2C16.A46.2C3.A2.A34.2C$20.A.A$20.2A2$3D62.3D40.3D7.
2C$D64.D12.2C28.D8.2C$3D62.3D9.2C29.3D7.2C$78.C40.C8$8.3C7.2A$9.C8.A.
A$9.3C8.A$20.2A!
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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 15th, 2015, 4:39 pm

I think this is a new H-to-G, SW18?T140? (I'm not sure where the zero-points are):

Code: Select all

x = 29, y = 35, rule = LifeHistory
6.A$5.A.A$5.A.A$3.3A.2A$2.A4.B$3.3AB2AB4.3B$5.A.2AB.2B.4B$9.9B$9.9B$
9.10B$9.10B$9.10B2.2A$7.12B2.A.A.2A$7.12B4.A.A$7.13B2.2A.A$8.11B.4B.A
.2A$9.13B4A2.A$8.12B.BAB2.2A$6.16B.3A$5.18B2.A$5.17B3.A.A$6.16B4.2A$
5.16B$3.18B$.21B$.2BC19B$3BCBC4B.7B2.4B$.2B3C4B2.6B3.4B$5BC4B3.6B3.4B
$9B6.4B4.4B$2B12.B2A2B5.4B$B14.2A.B2A4.4B$18.BA.A4.3B$21.A5.2B$21.2A
5.B!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

http://conwaylife.com/wiki/A_for_all

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Re: The Hunting of the New Herschel Conduits

Post by thunk » November 15th, 2015, 6:08 pm

A for awesome wrote:I think this is a new H-to-G, SW18?T140? (I'm not sure where the zero-points are):

Code: Select all

rle
HSE19T106, actually.

And I'm pretty sure I don't have one of those in the collection. Same mod-8 timing as the last compound H->G (SE19T42).
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Re: The Hunting of the New Herschel Conduits

Post by gmc_nxtman » November 16th, 2015, 11:43 am

Pretty sure it's actually a HSE19T134.

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Re: The Hunting of the New Herschel Conduits

Post by thunk » November 16th, 2015, 1:03 pm

gmc_nxtman wrote:Pretty sure it's actually a HSE19T134.
No. The timings are measured from when the (proleptic) output glider crosses the vertical line through the initial object. In this case, the glider forms at 134 ticks, but it is 7fd to the east of this line. 134-(4*7)=106, and that's the timing.
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Re: The Hunting of the New Herschel Conduits

Post by dvgrn » November 16th, 2015, 1:09 pm

gmc_nxtman wrote:Pretty sure it's actually a HSE19T134.
Yeah, thunk has it right -- HSE19T106. It's probably safer not to calculate the statistics manually at all. The H-to-G analyzer script is right about what name should be assigned, pretty much by definition, unless someone finds a bug in the code.

You can select an H-to-G and run the script from the clipboard. The only caveat is that at the moment you have to have run something like pop-plot.py since the last time you opened Golly, so that Golly has the glife module already loaded. Golly doesn't know where to find the glife module when it's starting from clipboard.py stored in one of Golly's temporary file locations.

I should really patch the recognizer script to remove that annoying dependency. Will put it on the short To-Do list. EDIT: Done. If anyone sees any errors when running H-to-Gstats16November2015.py, please let me know.

-- That "H-to-G converter collection" thread is still a good place to put new H-to-Gs, by the way. This thread is already pretty long, and H-to-Gs seem to turn up several times more often than other X-to-Y conduits.

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Re: The Hunting of the New Herschel Conduits

Post by Kazyan » November 17th, 2015, 6:42 pm

No conduit today, but an odd Spartan catalyst (from Bellman) for the back of an R-pentomino:

Code: Select all

x = 13, y = 10, rule = B3/S23
6bo$5b3o$7bo3$6b2o3bo$3bobobo2bobo$b3ob2o4bo$o$2o!
It works for the natural R pointing the "wrong way" during the Herschel's evolution. I've also seen a few R-pentominoes pointing the wrong way when trying to make conduits, so this might be useful for perturbations somewhere.

It may be a little unwieldy because of the pseudo eater-on-ship, but at least it's the "easy" orientation.

Code: Select all

x = 30, y = 13, rule = B3/S23
27bobo$27b2o$28bo2$26b2o$26b2o2$7bo$5b2o19bo$3bo2b2o15bobobo$b3o17b3ob
2o$o19bo$2o18b2o!
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Re: The Hunting of the New Herschel Conduits

Post by Extrementhusiast » November 17th, 2015, 7:03 pm

I'm not exactly sure what to call it, but whatever it is, it looks pretty useful:

Code: Select all

x = 97, y = 67, rule = LifeHistory
42.2A$42.2A11.2A$54.A.A$55.A9$46.2D$45.3D$46.3D$46.2D7.2A$55.2A3$51.C
$50.3C$50.C.2C$43.2A$43.2A16$5.2A35.2A35.2A$4.B2AB10.2A21.B2AB10.2A
21.B2AB10.2A$4.5B8.A.A21.5B8.A.A21.5B8.A.A$5.5B7.BA23.5B7.BA23.5B7.BA
$5.6B7.2B22.6B7.2B22.6B7.2B$6.6B5.4B22.6B5.4B22.6B5.4B$A.A4.15B15.A.A
4.15B15.A.A4.15B$.2A4.15B16.2A4.15B16.2A4.15B$.A5.16B15.A5.16B15.A5.
16B$7.16B21.16B21.16B$7.16B21.16B21.16B$6.16B21.16B21.16B$6.3B2C10B
22.3BCD10B22.3B2D10B$7.BC2D9B24.BD2C9B24.B3D9B$7.2B2DC8B24.2B2CD8B24.
2B3D8B$6.3B2C7B2A23.3BDC7B2A23.3B2D7B2A$7.11B2A24.11B2A24.11B2A$8.11B
26.11B26.11B$10.8B29.8B29.8B$11.3BD3B30.3BD3B30.3BD3B$11.2B3D2B30.2B
3D2B30.2B3D2B$7.B3.2BDB2DB26.B3.2BDB2DB26.B3.2BDB2DB$6.2AB.9B24.2AB.
9B24.2AB.9B$6.2A10B25.2A10B25.2A10B$7.2B.8B26.2B.8B26.2B.8B$10.8B29.
8B29.8B$14.4B33.4B33.4B$15.B36.B36.B!
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Re: The Hunting of the New Herschel Conduits

Post by dvgrn » November 17th, 2015, 7:17 pm

Extrementhusiast wrote:I'm not exactly sure what to call it, but whatever it is, it looks pretty useful...
Huh. A parity-testing toad-switch! ... or something like that. It does look useful, but my imagination is failing me when it comes to specifics.

I suppose it could allow incoming data, in the form of a stream of gliders, to be pre-tested before being sent into P2 circuitry, if we actually had enough P2 circuitry to make it anything but a bother to do that. Or, possibly more interesting, we could use it to retrieve parity information from the glider stream, and use some other variation in the relative timing of the gliders to store a completely independent series of bits.

It's a little tricky to get the "completely independent" part to work in practice, though. Really it's much easier to just send two gliders in series or in parallel, through regular boring old P1 circuits.

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Re: The Hunting of the New Herschel Conduits

Post by Kazyan » November 18th, 2015, 3:08 pm

Very compact nonspartan B-to-B:

Code: Select all

x = 24, y = 24, rule = LifeHistory
4$12.A$11.A.A$10.A.A.A$10.A3.A$8.2A.3A$7.A.A.A$6.A.A2B$6.BA.B$7.5B$6.
8B$4.B.7B2D$3.A5BC4B2D$2.A.A3B3C2B2D$3.AB2.BCB2CBD$7.6B$8.4B$9.2B!
EDIT: Spartan backwards H-to-B.

Code: Select all

x = 26, y = 24, rule = LifeHistory
22.A$20.3A$19.A$19.2A$17.4B$16.3B$15.5B$12.9B$11.11B$11.5BD4B2.BA$12.
3B2D6BA.A$11.3B2D8B2A$9.6B2D6B$7.17B2A$7.2BC11B.BA.A$6.3BCBC4B.3B3.BA
$7.2B3C4B2.B$6.5BC4B$5.10B$4.4B$3.4B$2.4B$.4B$4B!
Last edited by Kazyan on November 18th, 2015, 11:03 pm, edited 1 time in total.
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Re: The Hunting of the New Herschel Conduits

Post by BlinkerSpawn » November 18th, 2015, 8:22 pm

Slightly less complicated catalyst:

Code: Select all

x = 14, y = 16, rule = LifeHistory
9.2A$8.A.A$8.A$6.2A.4A$5.A.A.A2.A$4.A.A2B$4.BA.B$5.5B$4.8B$2.B.7B2D$.
A5BC4B2D$A.A3B3C2B2D$.AB2.BCB2CBD$5.6B$6.4B$7.2B!
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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 21st, 2015, 9:55 pm

It seems like there should be some way to get a signal out of this:

Code: Select all

x = 10, y = 10, rule = LifeHistory
7.C$6.C.C$7.C4$7.C$6.3C$2C3.2C2.C$2C!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by Extrementhusiast » November 21st, 2015, 10:46 pm

R-to-glider:

Code: Select all

x = 16, y = 30, rule = LifeHistory
2.A$2.3A$5.A$4.2A14$8.C$7.3C$7.C2$12.2A$12.A.A$14.A$2.2A10.2A$3.A$3A
6.2A$A8.A$10.3A$12.A!
Some sort of signal could also potentially be gotten from the front end.

EDIT: P110 gun showcasing a periodic B110:

Code: Select all

x = 43, y = 50, rule = B3/S23
29bo$28bobo$29bo$41b2o$15b2o24b2o$15b2o2$3b2o$3bobob2obo$5bobob2o$4b2o
bo$7bo$8b2o$4bo5bo$3bobo3b3o$4bo5bo$8b2o$7bo$4b2obo16b3o$5bobob2o12bo
3bo$3bobob2obo17bo$3b2o29b2o$23b2o3bo5bo$25b3o7b3o$37bo$5bo$5b3o7b3o$
8bo5bo3b2o$7b2o29b2o$14bo17bob2obobo$15bo3bo12b2obobo$16b3o16bob2o$35b
o$33b2o$32bo5bo$31b3o3bobo$32bo5bo$33b2o$35bo$35bob2o$32b2obobo$32bob
2obobo$38b2o2$26b2o$2o24b2o$2o$13bo$12bobo$13bo!
Although for a single Herschel, it requires something more like this:

Code: Select all

x = 57, y = 52, rule = B3/S23
47b2o$36bo10b2o$35bobo$36bo10b4o$46bo4bobo$22b2o22b2o2b2ob3o$22b2o32bo
$50b2ob3o$10b2o38b2obo$10bobob2obo$12bobob2o$11b2obo$14bo$15b2o33b2o$
11bo5bo32bobo$10bobo3b3o33bo$11bo5bo34b2o$15b2o$14bo$11b2obo16b3o$12bo
bob2o12bo3bo$10bobob2obo17bo$10b2o29b2o$30b2o3bo5bo$32b3o7b3o$44bo$12b
o$12b3o$15bo$14b2o29b2o$39bob2obobo$39b2obobo$42bob2o$42bo$40b2o$3b2o
34bo5bo$4bo33b3o3bobo$4bobo32bo5bo$5b2o33b2o$42bo$42bob2o$39b2obobo$
39bob2obobo$3bob2o38b2o$b3ob2o$o32b2o$b3ob2o2b2o22b2o$3bobo4bo$6b4o10b
o$19bobo$8b2o10bo$8b2o!
Also, a relatively iffy R-to-B:

Code: Select all

x = 24, y = 21, rule = LifeHistory
A$3A$3.A$2.2A3$22.2A$22.2A5$18.C$17.3C.2D$17.C4.2D$21.2D$21.D3$15.2A$
15.2A!
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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 22nd, 2015, 3:54 pm

What appears to be a new R-to-G, given that there appear to be no drifter catalyses in the conduit collection:

Code: Select all

x = 22, y = 22, rule = LifeHistory
6.2C$3.2C2.C$.3C.2C6.2C$C4.B7.C.C2.2C$.3CB2C8.C3.C$3.C.2C4.4C.3C$5.4B
2.C2.C.C$7.2B3.B.CBCB3C$5.5B.4B2CBC2.C$5.13B2.2C$4.14B$3.14B$3.B2C12B
$3.2B2C10B$3.2BC13B$3.10B4.2C$3.10B4.C$4.9B5.3C$5.2B3.4B6.C$4.4B3.4B$
4.B2CB4.4B$5.2C6.4B!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by Extrementhusiast » November 25th, 2015, 2:47 pm

A possible start for an R-to-LWSS:

Code: Select all

x = 19, y = 19, rule = LifeHistory
9.A$8.A.A$8.A.A$7.2A.2A$7.A$8.A.2A$6.A.A.2A$A.2A.A.A$2A.A.A$3.A.A$3.
2A2$6.2A$6.2A3$16.2C$17.2C$17.C!
It looks to me like the block will have to be made transparent.

EDIT: Found a way to let the FNG through for a P220 gun:

Code: Select all

x = 58, y = 50, rule = LifeHistory
38.A8.2A4.A$37.A.A7.A.A2.A.A$38.A10.4A2.A$48.A4.A.A$24.2A22.2A2.2A.2A
$24.2A30.A$52.2A.A$12.2A38.2A.A.A$12.A.A.2A.A36.2A$14.A.A.2A$13.2A.A$
15.2A$17.2A33.2A$13.A3.A2.A31.A.A$12.A.A3.A.A33.A$13.A3.A2.A33.2A$17.
2A$15.2A$13.2A.A$14.A.A.2A$12.A.A.2A.A$12.2A29.2A$43.A$44.3A$46.A$14.
A$14.3A$17.A6.2A$16.2A5.A.A21.2A$8.A16.A15.A.2A.A.A$7.A.A11.A19.2A.A.
A$7.A.A10.A23.A.2A$5.3A.2A9.A2.2A19.2A$4.A16.3A18.2A$5.3A.2A11.A17.A
2.A3.A$7.A.2A29.A.A3.A.A$40.A2.A3.A$2A40.2A$.A42.2A$.A.A40.A.2A$2.2A
37.2A.A.A$6.2A33.A.2A.A.A$5.A.A39.2A$5.2A$35.2A$35.2A2$8.A13.A$7.A13.
A.A$7.3A12.A!
The P110 gun has a three-way tie for smallest stabilization (in terms of area):

Code: Select all

x = 52, y = 186, rule = LifeHistory
35.A$34.A.A$35.A$47.2A$21.2A25.A$20.A2.A12.3A$21.2A12.A3.2A$9.2A23.A
5.A$9.A.A.2A.A8.2A7.A4.A9.A.A$11.A.A.2A8.A.A9.A7.A5.A$10.2A.A11.A.2A
8.A9.A3.A$11.3A8.6A8.A10.A2.A$14.2A5.A4.A21.A$10.A3.A6.A2.A9.2A$9.A.A
2.2A.2A3.2A11.A$10.A3.A$14.2A$11.3A$10.2A.A$11.A.A.2A$9.A.A.2A.A$9.2A
29.2A$40.A$41.3A$43.A$11.A$11.3A$14.A$13.2A29.2A$38.A.2A.A.A$38.2A.A.
A$41.A.2A$41.3A$39.2A$2.2A36.A3.A$3.A15.A11.2A3.2A.2A2.A.A$3.A.A13.2A
9.A2.A6.A3.A$4.2A22.A4.A5.2A$18.A8.6A8.3A$17.A8.2A.A11.A.2A$17.A9.A.A
8.2A.A.A$2A13.A4.A7.2A8.A.2A.A.A$A.A.2A8.A5.A23.2A$2.A.2A8.2A3.A12.2A
$.A14.3A12.A2.A$.2A.2A26.2A$2.A.A$2.A.A14.A$3.A14.A.A$19.A21$35.A$34.
A.A$35.A$47.2A$21.2A25.A$20.A2.A12.3A$21.2A12.A3.2A$9.2A23.A5.A$9.A.A
.2A.A8.2A7.A4.A9.A.A$11.A.A.2A8.A.A9.A7.A5.A$10.2A.A11.A.2A8.A9.A3.A$
11.3A8.6A8.A10.A2.A$14.2A5.A4.A21.A$10.A3.A6.A2.A9.2A$9.A.A2.2A.2A3.
2A11.A$10.A3.A$14.2A$11.3A$10.2A.A$11.A.A.2A$9.A.A.2A.A$9.2A29.2A$40.
A$41.3A$43.A$11.A$11.3A$14.A$13.2A29.2A$38.A.2A.A.A$38.2A.A.A$41.A.2A
$41.3A$39.2A$2A38.A3.A$.A17.A11.2A3.2A.2A2.A.A$.A.A15.2A9.A2.A6.A3.A$
2.2A24.A4.A5.2A$7.A10.A8.6A8.3A$7.A9.A8.2A.A11.A.2A$9.A7.A9.A.A8.2A.A
.A$8.3A4.A4.A7.2A8.A.2A.A.A$2.2A4.A.A3.A5.A23.2A$.A.A3.2A5.2A3.A12.2A
$.A6.2A6.3A12.A2.A$2A6.2A22.2A$8.A.A$9.A9.A$18.A.A$19.A17$35.A$34.A.A
$35.A$47.2A$21.2A25.A$20.A2.A12.3A$21.2A12.A3.2A$9.2A23.A5.A$9.A.A.2A
.A8.2A7.A4.A9.A.A$11.A.A.2A8.A.A9.A7.A5.A$10.2A.A11.A.2A8.A9.A3.A$11.
3A8.6A8.A10.A2.A$14.2A5.A4.A21.A$10.A3.A6.A2.A9.2A$9.A.A2.2A.2A3.2A
11.A$10.A3.A$14.2A$11.3A$10.2A.A$11.A.A.2A$9.A.A.2A.A$9.2A29.2A$40.A$
41.3A$43.A$11.A$11.3A$14.A$13.2A29.2A$38.A.2A.A.A$38.2A.A.A$41.A.2A$.
A39.3A$.3A35.2A$4.A35.A3.A$3.2A14.A11.2A3.2A.2A2.A.A$19.2A9.A2.A6.A3.
A$5.2A21.A4.A5.2A$4.A2.A10.A8.6A8.3A$2A5.A9.A8.2A.A11.A.2A$A.A6.A7.A
9.A.A8.2A.A.A$.A2.2A9.A4.A7.2A8.A.2A.A.A$14.A5.A23.2A$14.2A3.A12.2A$
16.3A12.A2.A$6.A25.2A$6.2A$19.A$18.A.A$19.A!
Apparently, these are new size records for guns of these periods (admittedly, not by that much).
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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 27th, 2015, 2:10 pm

A maybe-salvageable transparent block:

Code: Select all

x = 17, y = 8, rule = LifeHistory
16.A$5.2A7.3A$5.2A6.A$13.2A2$.C$3C$C!
I haven't found any way to keep the eater from getting destroyed, though.
Edit: Another one:

Code: Select all

x = 20, y = 6, rule = LifeHistory
2A16.2A$2A16.2A2$8.C$7.3C$7.C!
This time it's the transparent block that I can't salvage:

Code: Select all

x = 20, y = 6, rule = LifeHistory
2A16.2A$2A16.2A2$8.C$7.3C$7.C!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » November 30th, 2015, 10:05 pm

Another D-to-G:

Code: Select all

x = 24, y = 31, rule = LifeHistory
13.C$.2C8.3C$C2BC6.C$BCBC2B4.2C$2BC9B$2.8B$4.11B2.B5.B$4.11B.3B3.2B$
4.15B2.3B$5.19B$3.20B$2.20B$3.4B3C11B$3.3BC2BC11B$3.2BC2BC13B$3.3B2C
14B$3.18B$2.19B$.21B$.7B.13B$2.19B$2.21B$2.22B$2.13B2.6B$4.12B2.3B$5.
10B$5.8B$11.B$10.3B$10.B2CB$11.2C!
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by A for awesome » December 4th, 2015, 10:21 pm

A D-to-R:

Code: Select all

x = 29, y = 21, rule = LifeHistory
19.B$7.B2.2B.B4.3B$5.11B2.3B$.B2.18B$2CB.20B$2C23B$.B.11BD10B$3.10B3D
9B$2.13BD7B.B2C$3.20B.BC.C$3.19B5.C$2.21B4.2C$3.19B$3.18B$4.5B3C9B$4.
4BC2BC9B$6.BC2BC8B.B2C$6.2B2C8B2.BC.C$8.7B.B6.C$8.3B.2B9.2C$9.B!
Not sure if there's an output, though.
x₁=ηx
V ⃰_η=c²√(Λη)
K=(Λu²)/2
Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt)

$$x_1=\eta x$$
$$V^*_\eta=c^2\sqrt{\Lambda\eta}$$
$$K=\frac{\Lambda u^2}2$$
$$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$

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Re: The Hunting of the New Herschel Conduits

Post by Extrementhusiast » December 8th, 2015, 9:39 pm

A very simple periodic conduit, HFx55Bp4/5/6/7/8/others:

Code: Select all

x = 186, y = 43, rule = LifeHistory
11.D39.D39.D39.D39.D$10.3D37.3D37.3D37.3D37.3D$10.D.2D36.D.2D36.D.2D
36.D.2D36.D.2D5$3.2A38.2A38.2A38.2A38.2A$3.A39.A39.A39.A39.A$A4.A34.A
4.A34.A4.A34.A4.A34.A4.A$6A34.6A34.6A34.6A34.6A2$2.2A38.2A38.2A38.2A
38.2A$2.A39.A39.A39.A39.A$A.A16.2A19.A.A16.2A19.A.A16.2A19.A.A16.2A
19.A.A16.2A$2A16.A2.A18.2A16.A2.A18.2A16.A2.A18.2A16.A2.A18.2A16.A2.A
$19.2A38.2A38.2A38.2A38.2A3$7.3D37.3D37.3D37.3D37.3D$8.D39.D39.D39.D
39.D$8.3D6.A.A28.3D7.2A28.3D6.A2.A27.3D37.3D6.A.A$20.A36.4A39.A34.2A
43.A$16.A2.A36.A4.A34.A4.A33.2A39.A4.A2.2A$15.A.A.A35.2A4.2A33.2A2.A.
A33.A3.A.3A31.2A.A2.A.2A$15.A2.A36.2A4.2A38.A.2A30.A3.6A35.2A$16.2A
38.A4.A72.A6.A$57.4A74.5A$58.2A41.A2.A$101.2A34.5A$136.A6.A$137.A3.6A
$138.A3.A.3A$137.2A$137.2A3$9.2A38.2A38.2A38.2A38.2A$9.2A38.2A38.2A
38.2A38.2A2$8.C7.A.2A28.C7.A.2A28.C7.A.2A28.C7.A.2A28.C7.A.2A$7.3C6.
2A.A27.3C6.2A.A27.3C6.2A.A27.3C6.2A.A27.3C6.2A.A$7.C.2C36.C.2C36.C.2C
36.C.2C36.C.2C!
Replacing the sparker with a hook with tail turns it into a period-tripler:

Code: Select all

x = 103, y = 43, rule = LifeHistory
12.D39.D39.D$11.3D37.3D37.3D$11.D.2D36.D.2D36.D.2D5$4.2A38.2A38.2A$4.
A39.A39.A$.A4.A34.A4.A34.A4.A$.6A34.6A34.6A2$3.2A38.2A38.2A$3.A39.A
39.A$.A.A16.2A19.A.A16.2A19.A.A16.2A$.2A16.A2.A18.2A16.A2.A18.2A16.A
2.A$20.2A38.2A38.2A$54.2A$A39.A13.2A24.A11.2A$3A5.3D29.3A5.3D29.3A5.
3D.2A$3.A5.D33.A5.D33.A5.D$2.A6.3D30.A6.3D30.A6.3D$2.2A38.2A38.2A15$
10.2A38.2A38.2A$10.2A38.2A38.2A2$9.C7.A.2A28.C7.A.2A28.C7.A.2A$8.3C6.
2A.A27.3C6.2A.A27.3C6.2A.A$8.C.2C36.C.2C36.C.2C!
But I just want a stable way to remove that darn block!
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Re: The Hunting of the New Herschel Conduits

Post by dvgrn » December 8th, 2015, 10:40 pm

Extrementhusiast wrote:A very simple periodic conduit, HFx55Bp4/5/6/7/8/others...
Replacing the sparker with a hook with tail turns it into a period-tripler...
But I just want a stable way to remove that darn block!
That's a very nice new straight-line period tripler -- easy to chain together to make high-period guns with very small bounding boxes (long and narrow). But yes, a stable version would be nice.

It's technically within the reach of current technology. You just have to route a signal around to rebuild a block:

Code: Select all

x = 22, y = 43, rule = LifeHistory
11.D$10.3D$10.D.2D5$3.2A$3.A$A4.A$6A2$2.2A$2.A$A.A16.2A$2A16.A2.A$19.
2A3$7.3D$8.D9.2A$8.3D7.2A16$9.2A$9.2A2$8.C7.A.2A$7.3C6.2A.A$7.C.2C!
... or convert a pond back into a beehive in the same location, or any number of other similarly unlikely transformations. Is there enough room for Bellman to find a better solution?

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Re: The Hunting of the New Herschel Conduits

Post by BlinkerSpawn » December 9th, 2015, 12:41 am

dvgrn wrote:Or any number of other similarly unlikely transformations.
Like turning a LOM into a hive?

Code: Select all

x = 22, y = 43, rule = LifeHistory
11.D$10.3D$10.D.2D5$3.2A$3.A$A4.A$6A2$2.2A$2.A$A.A16.2A$2A16.A2.A$19.
2A3$7.3D$8.D$8.3D5.2A$15.A2.A$16.2A14$9.2A$9.2A2$8.C7.A.2A$7.3C6.2A.A
$7.C.2C!
Another potential bait reaction, although I don't like the idea of replacing periodic conduits with periodic conduits:

Code: Select all

x = 22, y = 43, rule = LifeHistory
11.D$10.3D$10.D.2D5$3.2A$3.A$A4.A$6A2$2.2A$2.A$A.A16.2A$2A16.A2.A$19.
2A3$7.3D$8.D8.A$8.3D6.A$17.A15$9.2A$9.2A2$8.A7.A.2A$7.3A6.2A.A$7.A.2A
!
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