to mods:I am just an alternative account of HotWheels9232. Last time I didn't understand the forum rules and what is notable, so I ended up putting quite a lot of useless things on the forums. This time, I will be on the forums, but I will only post useful things, and won't go too much on the sandbox, where I seem to be making a lot of posts.
Getting back on topic, I'd like to install JLS. So first question is:Is there a version of JLS that can be used to search in INT rules?
Edit #1 8 hours later: I want to install apgsearch, and have decided to use hacked apgsearch v1(for INT rules). But it keeps giving errors. I am not at my computer, so cannot post the errors. Another question is: How do I split strings into a list in python?
qqd wrote: ↑June 29th, 2023, 1:38 am
Is this p1920 oscillator trivial? It doesn't seem so, but on a closer look, it doesn't seem like any cell oscillates at the full period (derived from
51P384):
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x = 30, y = 25, rule = B3/S23
17b2o2bo$13b2o2b2o3bo$13b2o7bo$18b4o3$11b2o$b2o8b2o$2bo$bo$b2o$3bo5b3o
$b3o$o$2o2$16b2o10b2o$10b2obo2bo12bo$14bo11b3o$11b2o13bo$9bo2bo14b2o$
9bo2bo15bo$11bo15bo$17b2o8b2o$17b2o!
Yes. The top-right corner is p(5x64)=320, and the bottom-left corner is p(6x64)=384. Because it is just different period-multiplying factory suppressions, it is trivial(because they cannot interact). I hope it is clear enough.
Edit #2 18 hours after last edit:
Is there a reversible range-1 INT rule which actually has a reverse rule? The reverse rule(note that is must also have a reverse rule has to have the Range-1 INT rule as its reverse)can have a custom neighborhood, any range that is not infinity, and even INT LTL rules, which I have a notation for, though it gets quite a lot unwieldier as more complex rules come. Here is the notation:
It is basically the same as hensel notation(I'm getting a little of topic here, but instead of the transitions being letters, it is a string of n hexadecimal digits(where n is ((2*range+1)^2-1)/4) in parentheses. Let's work through an example here, say we want to make a cell be born here:
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x = 5, y = 5, rule = LifeSuper
4BA$5B$2BDBA$2BA2B$4BA!
Now if the bottom left corner is on, it will be a 1. But if it is off, it will be a 0. The next step is to work to the left, doing the same thing, 1 if it is on, 0 if it is off. When we hit the left side, we loop back to the right, and move up 1 row. Repeat(also skip over the center cell). The end result should be a binary number with 24 digits. Now we work through all the rotations and reflections with the same procedure, and see which is the smallest. The final step is to turn into hexadecimal, wrap in parentheses, and we're done!
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x = 5, y = 5, rule = LifeSuper
ABABA$5B$BAD2B$5B$5B!
We find this is the smallest, so we need to turn 000000000000100000010101 into hexadecimal, so (000815) will be the name of the transition(note we left the left 0s)
Back to the original question, I can prove S8 exists easily. For a range-n reverse rule, draw a sufficiently large(say, 10n though much smaller things should be possible) rectangle in the range 1 rule. Evolve it 1 generation. I will assume the range 1 rule doesn't have s8 and prove by contradiction. Then the center 10n-2x10n-2 patch must die, but if the reverse rule is run on that pattern, the center cells cannot "know" that there are any cells alive(so they won't be born), because the void is too large. But the center cells were on at the start. Contradiction. A similar arguments with these two agars
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x = 58, y = 15, rule = B3/S23
41b17o$8b3o30bobobobobobobobobo$6b3ob3o28b17o$4b3ob3ob3o26bobobobobobo
bobobo$2b3ob3ob3ob3o24b17o$3ob3ob3ob3obo24bobobobobobobobobo$ob3ob3ob
3ob3o24b17o$3ob3ob3ob3o26bobobobobobobobobo$2b3ob3ob3o28b17o$4b3ob3o
30bobobobobobobobobo$6b3o32b17o$41bobobobobobobobobo$41b17o$41bobobobo
bobobobobo$41b17o!
can prove at least one of these statements are true:
The rule contains B8
The rule contains S6i
The rule contains both S4e and S5y
Other agars should probably give even more information, but I haven't tried yet.
Edit 3 quite a while after last edit:
Is this thread dying? Also 2 more agars
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x = 376, y = 87, rule = B3/S23
348b28o$348bo2bo2bo2bo2bo2bo2bo2bo2bo2bo$348b28o$348bo2bo2bo2bo2bo2bo
2bo2bo2bo2bo$348b28o$348bo2bo2bo2bo2bo2bo2bo2bo2bo2bo$348b28o$348bo2bo
2bo2bo2bo2bo2bo2bo2bo2bo$348b28o$348bo2bo2bo2bo2bo2bo2bo2bo2bo2bo$348b
28o$348bo2bo2bo2bo2bo2bo2bo2bo2bo2bo$348b28o$348bo2bo2bo2bo2bo2bo2bo2b
o2bo2bo$348b28o$348bo2bo2bo2bo2bo2bo2bo2bo2bo2bo$348b28o$348bo2bo2bo2b
o2bo2bo2bo2bo2bo2bo$348b28o64$28o2$28o2$28o!
First shows S2i or B6i
2nd shows S4t or S4e or B7e
Oh right, the checkerboard agar so S4c or B4e
My 1st post!