## c/2 diagonal telegraph

For discussion of specific patterns or specific families of patterns, both newly-discovered and well-known.
dvgrn
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### c/2 diagonal telegraph

Has anyone had a look recently at a glider construction for a c/2 diagonal signal? Unlike lightspeed diagonal signals, a single c/2 pulse doesn't seem like it's obviously beyond reach these days:

Code: Select all

x = 46, y = 45, rule = B3/S23:T46,45
bo43bo$obo$bobo2bo$2bo5bo$3b2o3bo$8bo$5b3o$7bobo$9b2o$8b3o2$11b2o$14bo$12bo2bo$14bobo$15bobo$16bobo$17bobo$18bobo$19bobo$20bobo$21bobo$22bob o$23bobo$24bobo$25bobo$26bobo$27bobo$28bobo$29bobo$30bobo$31bobo$32bob o$33bobo$34bobo$35bobo$36bobo$37bobo$38bobo$39bobo$40bobo$41bobo$42bob o$43bobo$o43bo! If one pulse turns out to be buildable, presumably at the end of an arbitrarily long ship or barge, then we can do the same thing twice to put the wire back where it started... and maybe use the distance between the pulses to carry information, similar to Jormungant's high-bandwidth telegraph. Not sure about that last part. It would be nice to be able to check for passing signals with some kind of Heisenburp device, but I haven't figured out how to make that work yet -- maybe a non-stable solution could be worked out, with a clever spark applied to the trailing single bit just as the wire is recovering? The period of such a spark would have to be fairly high, though. Here at least is a proof-of-concept way to turn a c/2-diagonal signal into other signal types. The rebuilding problem is nontrivial but probably already no worse than what lightspeed telegraphs have to do. Code: Select all x = 46, y = 48, rule = LifeHistory .A$A.A$.A.A$2.A.A$3.A.A$4.A.A$5.A.A$6.A.A$7.A.A$8.A.A$9.A.A$10.A.A2.A
$11.A3.3A$12.3A.A$14.2A$15.A.2A2$16.A.A$17.3A2$19.3A$21.3A$22.A.A$23.
A.A$24.A.A$25.A.A$26.A.A$27.A.A$28.A.A$29.A.A$30.A.A$31.A.A6.2A$32.A. A5.2A$33.A.A$34.A.A$35.A.A5.2A$36.A.A4.2A$37.A.A$38.A.A$39.A.A$40.A.A$41.A.A$42.A.A$43.A.A$44.A2$39.2A$39.2A! The above is just the first thing that worked; can anyone find cheaper baits, preferably that preserve more of the wire? Terminating the wire with a ship end, or a ship-end-tie-ship, or maybe even some more complicated construct, could add more degrees of freedom to the search. ... Not sure what good all this would be, really -- we already have faster diagonal communication methods (2c/3, with an elbow option no less). A Heisenburp for a diagonal wire would be something new, I suppose. EDIT: Here's one conversion for each termination type. The rebuild would only have to be done once for each pair of signals. The block at the end of the wire looks like it could be permanent, but probably it would have to be shot down and rebuilt by whatever mechanism (slow salvo? big stable converter?) reconstructs the end of the wire. Code: Select all x = 75, y = 78, rule = LifeHistory .A$A.A$.A.A$2.A.A$3.A.A$4.A.A$5.A.A$6.A.A$7.A.A$8.A.A$9.A.A$10.A.A$11.A.A$12.ABA$13.ABA$11.2B.ABA$12.2B.ABA$12.4BABA$13.5BAB$14.6BA$15.B A3BAB$16.4B2AB$17.3A3BA$20.B3AB$22.2A2B$23.2BAB$24.BABA$25.3B$26.A.A$
27.A.A$28.A.A$29.A.A$30.A.A$31.A.A$32.A.A$33.A.A$34.A.A$35.A.A2.B$36. A.A.3B$37.ABA.3B$38.ABA.3B$39.ABA4B$40.ABA2BAB$41.A5BA$42.2A3BA$43.4B
A$44.3A2B$45.BABA$46.2B2A$47.3AB$48.4B$49.B2AB$50.3BA$51.AB.E$53.E.E$
54.E.E$55.E.E$56.E.E$57.E.E$58.E.E$51.2C6.E.E$51.2C7.E.E6.C$61.E.E4.C .C$57.C4.E.E3.C.C$56.C.C4.E.E3.C$56.C.C5.E.E$57.C7.E.E$66.E.E$67.E.E$
54.C13.E.E2.2A$53.C.C13.2E2.2A$53.2C3$35.A$34.A.A$34.A.A$35.A!
Again, this is just the first thing that worked, so there's bound to be something cheaper out there.

AforAmpere
Posts: 1111
Joined: July 1st, 2016, 3:58 pm

### Re: c/2 diagonal telegraph

dvgrn wrote:Has anyone had a look recently at a glider construction for a c/2 diagonal signal? Unlike lightspeed diagonal signals, a single c/2 pulse doesn't seem like it's obviously beyond reach these days:
Is there any predecessor, or something that collides with the barge that is known to make the signal? That would make things a lot easier. Based on the patterns given, there doesn't seem to be a clear way to collide something with a barge to give the signal, as there's already a barge being laid behind it, but on a different lane.
Wildmyron and I manage the 5S project, which collects all known spaceship speeds in Isotropic Non-totalistic rules.

Things to work on:
- Find a (7,1)c/8 ship in a Non-totalistic rule

dvgrn
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### Re: c/2 diagonal telegraph

AforAmpere wrote:Is there any predecessor, or something that collides with the barge that is known to make the signal? That would make things a lot easier.
Nope, nothing known. That's the challenge.

To send one of these signals repeatably along a given finite length of wire, we'd need a glider recipe that produces that structure, optionally with some trailing junk that can be cleaned up with additional gliders.

A naive estimate of the difficulty is that this is a "40-bit" problem -- there are about 40 cells worth of space dust that will have to be constructed. That's maybe about the same as the weekender, which has about 80 cells but it's symmetrical -- or 25P3H1V0.1, which has more like 50 or 60 space-dust cells participating in the action (including both ON and OFF cells).

That makes it look like it might take 50-100 gliders to get one of these signals started -- a lot more than a 2c/3 diagonal signal, for sure, but maybe it's not completely impossible.

Extrementhusiast
Posts: 1832
Joined: June 16th, 2009, 11:24 pm
Location: USA

### Re: c/2 diagonal telegraph

dvgrn wrote:That makes it look like it might take 50-100 gliders to get one of these signals started -- a lot more than a 2c/3 diagonal signal, for sure, but maybe it's not completely impossible.
Half of a signal built in 69 gliders, with room for improvement:

Code: Select all

x = 822, y = 52, rule = B3/S23
767bo$767bobo$767b2o$757bo$bo39bo50bo48bo53bo53bo51bo42bo48bo41bo46bo
56bo48bo49bo49bo46bo21bobo34bo$obo37bobo48bobo46bobo51bobo51bobo49bobo 40bobo46bobo39bobo44bobo54bobo46bobo47bobo47bobo44bobo20b2o34bobo$bobo
37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo46bo
bo47bobo47bobo44bobo56bobo$2bobo37bobo48bobo46bobo51bobo51bobo49bobo 40bobo46bobo39bobo44bobo54bobo46bobo47bobo47bobo44bobo13bo42bobo$3bobo
37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo46bo
bo47bobo47bobo44bobo13bo42bobo$4bobo37bobo48bobo46bobo51bobo51bobo49bo bo40bobo46bobo39bobo44bobo54bobo46bobo47bobo47bobo13bo30bobo10b3o12bob o28bobo$5bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44b
obo54bobo46bobo47bobo47bobo11bo32bobo24b2o30bobo$6bobo37bobo48bobo46bo bo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo46bobo47bobo7bo39bob o10b3o31bobo24bo31bobo$7bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo
46bobo39bobo44bobo54bobo46bobo47bobo4bobo40bobo44bobo56bobo$8bobo37bob o48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo46bobo47b obo4b2o3bo37bobo5bobo36bobo56bobo$9bobo37bobo48bobo46bobo51bobo51bobo
49bobo40bobo46bobo39bobo44bobo54bobo46bobo47bobo6b2o39bobo5b2o8bo21bo
6bobo22bo33bobo$10bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo 39bobo44bobo54bobo46bobo47bobo6b2o39bobo4bo9bobo20bo6bobo19b2o35bobo$
11bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bo
bo46bobo47bobo9bo37bobo13b2o19b3o7bobo19b2o35bobo$12bobo37bobo48bobo 46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo46bobo47bobo8bob o36bobo44bobo6b2ob2o45bobo$13bobo37bobo48bobo46bobo51bobo51bobo49bobo
40bobo46bobo39bobo44bobo54bobo46bobo47bobo7b2o38bobo5bo38bobo4bobob2o
46bobo$14bobo37bobo48bobo46bobo13bo37bobo51bobo49bobo40bobo46bobo39bob o44bobo54bobo46bobo47bobo47bobo3bobo29bo8bobo3bobo19bobo28bobo$15bo39b
o50bo48bo9bo3bo39bo9b2o4bo37bo51bo42bo48bo41bo46bo56bo48bo49bo49bo5b2o
30bo8bo5b2o13bobo3b2o30bo2bo$16b3o37b3o48b3o46b3o7b2ob3o38b3o5bo2bob2o 39b3o49b3o40b3o46b3o39b3o44b3o54b3o46b3o47b3o47b3o11b2o19b3o9b3o17b2o 5bo31bo$18bo39bo5bo44bo48bo6b2o45bo5bo2bo2b2o40bo51bo42bo48bo41bo46bo
56bo48bo49bo49bo11bobo32bo18bo39b2o$63bo155b2o496bo$10bo12bobo32bo4b3o
43bo48bo53bo53bo51bo42bo48bo41bo46bo56bo48bo49bo49bo28b3o15bo60b3o$8bo bo12b2o31b3o48b3o2b2o42b3o2b2o47b3o2b2o47b3o2b2o2b2o41b3o2b2o2b2o32b3o 2b2o2b2o38b3o2b2o2b2o31b3o2b2o2b2o36b3o2b2o2b2o46b3o2b2o2b2o38b3o2b2o 2b2o39b3o2b2o2b2o39b3o2b2o2b2o22bo13b3o2b2o2b2o52b2o$9b2o13bo30bo50bo
5bobo40bo5bobo45bo5bobo3bobo39bo5bobo2bo40bo5bobo2bo31bo5bobo2bo37bo5b
obo2bo30bo5bobo2bo35bo5bobo2bo45bo5bobo2bo37bo5bobo2bo38bo5bobo2bo38bo
5bobo2bo21bo13bo5bobo2bo53bobo$12b2o6b2o34b3o7bobo38b3o3bo9bo32b3o4bo 46b3o4bo3b2o2b3o36b3o4b3o42b3o4b3o33b3o4b3o39b3o4b3o32b3o4b3o37b3o4b3o 47b3o4b3o39b3o4b3o40b3o4b3o40b3o4b3o37b3o4b3o56b3o$13b2o5bobo35bo7b2o
41bo12bo35bo3bo49bo3bo5bo2bo40bo3bo47bo3bo38bo3bo8bo35bo3bo37bo3bo42bo
3bo52bo3bo9bo34bo3bo45bo3bo45bo3bo42bo3bo58bo$12bo7bo46bo47b2o5b3o37b 2o52b2o8bo43b2o50b2o41b2o5b2o40b4o38b4o43b4o53b4o6bobo36b6o44b6o32bo 11b6o41b6o53bo3b2o$116b2o103b2o12b3o76bo54b2o2b2o42bo41bo46bo57bo5b2o
42bo50bo32bo16bo46bo52bo5bo$68b3o44bo3b3o45b2o51bo2bo11bo36bo39bobo7b 2o6bo34b2o2bobo42b2o42bo46bo56b3o46b3o47bo2b2o30b3o12bo2b2o17b3o12bo9b o2b2o54bo2b2o$68bo50bo48b2ob3o46bo2bo12bo34b2o40b2o7bobo3b2o35bo3bo37b
o6bo43b2o44bo8bo47bo48bo49bobo47bobo22bo11bobo7bobo$69bo50bo46bo3bo49b 2o48bobo49bo5b2o32bobo42bo3bobo89b2o7bobo45b2o5b2o3bo36b2o7b2o39b2o37b 3o8b2o22bo12bobo7b2o14bo$172bo144bo45b2o41b3o3b2o5bo30bobo60b2o54b2obo
42bo2b2o81bo46bo23b2o$317b2o6bobo90b2o31b2o115bo3b3o40b2o3bo79bo71bobo$316bobo6b2o91bobo30bo162bobo138bo$326bo411b2o14b2o$409b3o3b3o32b2o12b
3o40b2o230b2o13bobo$327b2o82bo5bo31bobo12bo42bobo228bo$326b2o82bo5bo
34bo3bo9bo37b2o2bo$328bo125b2o46bobo249b2o$454bobo47bo248bobo$755bo2$
763bo$762b2o$762bobo$400b3o$402bo109bo$401bo109b2o$511bobo!

As this method ends up with a boatload of excess boat, here's a cheap way to get rid of that meta-boatload:

Code: Select all

x = 66, y = 54, rule = B3/S23
27bo$25b2o$26b2o7$11bo$10bobo$11bobo$12bobo$13bobo$14bobo$15bobo18bo$
16bobo15b2o$17bobo15b2o$18bobo$19bobo$20bobo8b2o$21bobo7b2o$22bobo$bo 21bobo$b2o21bobo$obo22bobo$26bobo$27bobo$28bobo$29bobo$21b2o7bobo$21b 2o8bobo$32bobo$17bo15bobo$17b2o15bobo$16bobo16bobo$36bobo$37bobo$38bob
o22bo$39bobo21bobo$40bobo20b2o$41bobo$42bobo$43bobo$44bobo$45bobo$46bo
bo$47bobo$48bobo$49b2o2$51bo$50b2o$50bobo!

(Removing the blocks would allow the front two gliders to form a flat end instead of a pointed one.)
I Like My Heisenburps! (and others)

A for awesome
Posts: 2046
Joined: September 13th, 2014, 5:36 pm
Location: 0x-1
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### Re: c/2 diagonal telegraph

dvgrn wrote:It would be nice to be able to check for passing signals with some kind of Heisenburp device, but I haven't figured out how to make that work yet -- maybe a non-stable solution could be worked out, with a clever spark applied to the trailing single bit just as the wire is recovering? The period of such a spark would have to be fairly high, though.
One of these signals can eat a glider, and presumably anything shaped like it — a possible avenue for a (pseudo-)Heisenburp:

Code: Select all

x = 46, y = 45, rule = B3/S23
bo$obo12bo$bobo2bo7bo$2bo5bo5b3o$3b2o3bo$8bo$5b3o$7bobo$9b2o$8b3o2$11b2o$14bo$12bo2bo$14bobo$15bobo$16bobo$17bobo$18bobo$19bobo$20bobo$21bobo$22bob o$23bobo$24bobo$25bobo$26bobo$27bobo$28bobo$29bobo$30bobo$31bobo$32bob o$33bobo$34bobo$35bobo$36bobo$37bobo$38bobo$39bobo$40bobo$41bobo$42bob o$43bobo$44bo! x₁=ηx V ⃰_η=c²√(Λη) K=(Λu²)/2 Pₐ=1−1/(∫^∞_t₀(p(t)ˡ⁽ᵗ⁾)dt) $$x_1=\eta x$$ $$V^*_\eta=c^2\sqrt{\Lambda\eta}$$ $$K=\frac{\Lambda u^2}2$$ $$P_a=1-\frac1{\int^\infty_{t_0}p(t)^{l(t)}dt}$$ http://conwaylife.com/wiki/A_for_all Aidan F. Pierce dvgrn Moderator Posts: 6734 Joined: May 17th, 2009, 11:00 pm Location: Madison, WI Contact: ### Re: c/2 diagonal telegraph Extrementhusiast wrote:Half of a signal built in 69 gliders, with room for improvement... Wow! I know I'm easily impressed by these things, but that's very impressive. How long did it take to find? And what's your next research project? The given cost doesn't seem to count adding the tail on the long^N boat -- there are sixty-nine gliders in the synthesis as it stands, with the tail already added. A for awesome wrote:One of these signals can eat a glider, and presumably anything shaped like it — a possible avenue for a (pseudo-)Heisenburp... Can't just go aiming gliders at the long^N boat, though. Things won't turn out too well if it turns out there _isn't_ a signal going by. As it is, the only way to tell that there was a signal is the absence of a huge horrible explosion. It's possible to suppress the glider at the last minute with a kickback reaction, and it still interacts, but unfortunately doesn't make a big enough spark to be detectable, I think: Code: Select all x = 106, y = 48, rule = B3/S23 59bo$58bobo$59bobo$bo13bo44bobo12bo$obo13b2o43bobo12b2o$bobo11b2o45bob
o10b2o$2bobo2bo55bobo$3bo5bo12bo41bobo15bo$4b2o3bo11bo43bobo13bo$9bo
11b3o42bobo12b3o$6b3o58bobo$8bobo57bobo$10b2o57bobo$9b3o58bobo$71bobo$
12b2o58bobo$15bo57bobo$13bo2bo57bobo$15bobo57bobo$16bobo57bobo$17bobo 57bobo$18bobo57bobo$19bobo57bobo$20bobo57bobo$21bobo57bobo$22bobo57bob
o$23bobo57bobo$24bobo57bobo$25bobo57bobo$26bobo57bobo$27bobo57bobo$28b
obo57bobo$29bobo57bobo$30bobo57bobo$31bobo57bobo$32bobo57bobo$33bobo 57bobo$34bobo57bobo$35bobo57bobo$36bobo57bobo$37bobo57bobo$38bobo57bob
o$39bobo57bobo$40bobo57bobo$41bobo57bobo$42bobo57bobo$43bobo57bobo$44b
o59bo!
Maybe something with a colliding *WSS and glider, or two gliders making a bigger spark?

Based on Extrementhusiast's burning-and-then-stabilizing reactions, I guess there's some hope of a double-width-line crosser mechanism -- don't know about an all-on-one-side one, though, at least without a painful amount of universal constructor trickery.

Extrementhusiast
Posts: 1832
Joined: June 16th, 2009, 11:24 pm
Location: USA

### Re: c/2 diagonal telegraph

dvgrn wrote:
Extrementhusiast wrote:Half of a signal built in 69 gliders, with room for improvement...
Wow! I know I'm easily impressed by these things, but that's very impressive. How long did it take to find? And what's your next research project?

The given cost doesn't seem to count adding the tail on the long^N boat -- there are sixty-nine gliders in the synthesis as it stands, with the tail already added.
Quite a long while, actually, especially since I built it wrong the first time!

Code: Select all

x = 44, y = 41, rule = B3/S23
bo$obo$bobo$2bobo$3bobo$4bobo$5bobo14bo$6bobo11bobo$7bobo11b2o5bobo$8b obo5bobo9b2o$9bobo5b2o10bo$10bobo4bo15bo$11bobo17b2o$5bo6bobo17b2o$6b
2o5bobo$5b2o7bobo$15bobo23bobo$16bo18bobo3b2o$17b3o15b2o5bo$6bo8bobo2b o15bo$7b2o5bobo3bo$6b2o7bo5b2o2b2o$19bobobo2bo$18bobo2b3o$18bobobo$19b o2b6o$20b2o6bo$23b2o2bobo$24bo3bobo7bo$10b2o10bo6bobo5b2o$11b2o9b2o6bo
bo4bobo$10bo20bobo$32bobo$13b2o18bobo$12bobo19bobo$14bo15b2o3bobo$30bo
bo3bobo$30bo6bo$21b3o$21bo$22bo!

I decided to start from the tail, as it's relatively easy to construct, and I didn't know the exact configuration that everything would be left in with regard to excess boat removal.

EDIT: And the first three gliders have been saved!

Code: Select all

x = 787, y = 51, rule = B3/S23
732bo$732bobo$732b2o$722bo$bo39bo50bo48bo53bo53bo51bo42bo48bo41bo46bo
56bo63bo49bo46bo21bobo34bo$obo37bobo48bobo46bobo51bobo51bobo49bobo40bo bo46bobo39bobo44bobo54bobo61bobo47bobo44bobo20b2o34bobo$bobo37bobo48bo
bo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo61bobo47bobo
44bobo56bobo$2bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bo bo44bobo54bobo61bobo47bobo44bobo13bo42bobo$3bobo37bobo48bobo46bobo51bo
bo51bobo49bobo40bobo46bobo39bobo44bobo54bobo61bobo47bobo44bobo13bo42bo
bo$4bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo 54bobo61bobo47bobo13bo30bobo10b3o12bobo28bobo$5bobo37bobo48bobo46bobo
51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo61bobo47bobo11bo32bobo
24b2o30bobo$6bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bob o44bobo54bobo61bobo7bo39bobo10b3o31bobo24bo31bobo$7bobo37bobo48bobo46b
obo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo61bobo4bobo40bobo
44bobo56bobo$8bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bo bo44bobo54bobo61bobo4b2o3bo37bobo5bobo36bobo56bobo$9bobo37bobo48bobo
46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo61bobo6b2o39bobo
5b2o8bo21bo6bobo22bo33bobo$10bobo37bobo48bobo46bobo51bobo51bobo49bobo 40bobo46bobo39bobo44bobo54bobo61bobo6b2o39bobo4bo9bobo20bo6bobo19b2o 35bobo$11bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo46bobo39bobo44b
obo54bobo61bobo9bo37bobo13b2o19b3o7bobo19b2o35bobo$12bobo37bobo48bobo 46bobo51bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo61bobo8bobo36bob o44bobo6b2ob2o45bobo$13bobo37bobo48bobo46bobo51bobo51bobo49bobo40bobo
46bobo39bobo44bobo54bobo61bobo7b2o38bobo5bo38bobo4bobob2o46bobo$14bobo 37bobo48bobo46bobo13bo37bobo51bobo49bobo40bobo46bobo39bobo44bobo54bobo 61bobo47bobo3bobo29bo8bobo3bobo19bobo28bobo$15bo39bo50bo48bo9bo3bo39bo
9b2o4bo37bo51bo42bo48bo41bo46bo56bo63bo49bo5b2o30bo8bo5b2o13bobo3b2o
30bo2bo$16b3o37b3o48b3o46b3o7b2ob3o38b3o5bo2bob2o39b3o49b3o40b3o46b3o 39b3o44b3o54b3o61b3o47b3o11b2o19b3o9b3o17b2o5bo31bo$18bo39bo5bo44bo48b
o6b2o45bo5bo2bo2b2o40bo51bo42bo48bo41bo46bo56bo63bo49bo11bobo32bo18bo
39b2o$63bo155b2o461bo$10bo12bobo32bo4b3o43bo48bo53bo53bo51bo42bo48bo
41bo46bo56bo63bo49bo28b3o15bo60b3o$8bobo12b2o31b3o48b3o2b2o42b3o2b2o 47b3o2b2o47b3o2b2o2b2o41b3o2b2o2b2o32b3o2b2o2b2o38b3o2b2o2b2o31b3o2b2o 2b2o36b3o2b2o2b2o46b3o2b2o2b2o53b3o2b2o2b2o39b3o2b2o2b2o22bo13b3o2b2o 2b2o52b2o$9b2o13bo30bo50bo5bobo40bo5bobo45bo5bobo3bobo39bo5bobo2bo40bo
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52bo5bobo2bo38bo5bobo2bo21bo13bo5bobo2bo53bobo$12b2o6b2o34b3o7bobo38b 3o3bo9bo32b3o4bo46b3o4bo3b2o2b3o36b3o4b3o42b3o4b3o33b3o4b3o39b3o4b3o 32b3o4b3o37b3o4b3o47b3o4b3o14bo39b3o4b3o40b3o4b3o37b3o4b3o56b3o$13b2o
5bobo35bo7b2o41bo12bo35bo3bo49bo3bo5bo2bo40bo3bo47bo3bo38bo3bo8bo35bo
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bo$580bo139bo$579b2o$579bobo146bo$727b2o$727bobo$400b3o$402bo$401bo!

I Like My Heisenburps! (and others)

dvgrn
Moderator
Posts: 6734
Joined: May 17th, 2009, 11:00 pm
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### Re: c/2 diagonal telegraph

Extrementhusiast wrote:EDIT: And the first three gliders have been saved!...
Okay, then if my count is right, a full c/2 signal would now take 67+2+67+4 = 140 gliders to get started. Here's an incremental recipe pattern with 50-cell spacing, in case anyone wants to leave off the last two frames and try chris_c's script on it to get a full synthesis.

Code: Select all

x = 956, y = 51, rule = LifeHistory
833.A$833.A.A$833.2A$823.A$.A49.A49.A49.A49.A49.A48.A50.A49.A49.A49.A
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40.A32.A16.A49.A43.A5.A27.A.A16.A.A$65.2A2.A.A106.3A43.A3.3A46.2A46.A 2.A11.A33.A37.A.A7.2A6.A41.2A2.A.A43.2A50.A49.A6.A42.3A9.2A36.A2.2A 30.3A12.A2.2A20.3A12.A9.A2.2A45.A2.2A47.A.A$69.2A107.A49.A49.2A.3A41.
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282.A134.A52.2A42.3A3.2A5.A38.A.A58.2A6.A128.A49.A23.2A89.A.A21.A.A$417.2A6.A.A98.2A39.2A59.2A4.2A127.A74.A.A89.A.A20.2A$416.A.A6.2A99.A.
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5.A42.A3.A9.A353.A.A$428.A141.2A248.2A114.A.A$570.A.A246.A.A115.A.A$692.A128.A116.A.A$691.2A246.2A$691.A.A135.A$828.2A111.A$828.A.A109.2A$508.3A429.A.A$510.A$509.A!
Not sure yet how best to extract information at the other end. For a high-bandwidth option, maybe count the number of ticks between the two half-signals and convert to binary somehow. Has anybody hunted for bait still lifes, or a custom extension at the far end, that can get a signal out while doing less damage than my initial proof of concept?

This is all a construction exercise with highly questionable utility, of course -- anyone with any sense would use a 2c/3 wire instead of one of these. So I think I'll be patient and wait for a script-built glider-to-c/2 converter.

Extrementhusiast
Posts: 1832
Joined: June 16th, 2009, 11:24 pm
Location: USA

### Re: c/2 diagonal telegraph

A much simpler termination that works even at the minimum separation of halves:

Code: Select all

x = 71, y = 90, rule = B3/S23
30b2o$30b2o$40b2o$40bo$38bobo$38b2o9$34b2o$34bobo$36bo$36b2o2$bo$obo$b
obo$2bobo$3bobo13b2o$4bobo12b2o$5bobo$6bobo$7bobo$8bobo$9bobo$10bobo$
11bobo$12bobo$8b2o3bobo$7bo2bo3bobo9bo$7bobo5bobo8b3o$8bo7bobo10bo$17b
obo8b2o$18bobo$19bobo9b2o$20bobo7bobo$21bobo6b2o$22bobo$23bobo$24bobo$
25bobo$26bobo$27bobo$28bobo$29bobo$30bobo$31bobo$32bobo$33bobo$34bobo$
35bobo$36bobo$37bobo$38bobo$39bobo$40bobo$41bobo$42bobo$43bobo$44bobo$
45bobo$46bo2bo$47bo$49b2o2$51b3o$51b2o$52bobo$54b3o$53bo$53bo3b2o$53bo
5bo$55bo2bobo$59b2o$60b2o$61bo$61bobo$63b2obo$63bo2bo2bo$64bo3b2o$66b 2ob2o$67b2o$68bo$68bobo\$69b2o!

All that needs to be reconstructed is a loaf and a whole lotta boat. (The HFx107B can also be replaced with an HSW10T108 or either form of HNE16T14.)
I Like My Heisenburps! (and others)

dani
Posts: 1002
Joined: October 27th, 2017, 3:43 pm
Location: New Jersey, USA
Contact:

### Re: c/2 diagonal telegraph

Just wanted to say I'm rooting for you all, even if I have no idea how this stuff works. Very nice job with the post above, it seems quite easy now...perhaps longboats could be added while extending the tub afterwards to reduce cost, idk
she/her
moose#0915