17 in 17: Efficient 17-bit synthesis project

[Freywa]

#71 in 12G from soup; onerous cleanup likely improvable.

You didn't solve #71 (which is merely reduced to 17 now), you solved #272.

27 remain:

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#3 xs17_025ic826z6511
#11 xs17_03pa39cz321
#34 xs17_0c9jc4goz321
#64 xs17_0j9cz122139c
#65 xs17_0j9cz122d93
#70 xs17_0j9qj4cz23
#71 xs17_0kq2c871z641
#72 xs17_0mp2c826z641
#73 xs17_0mp2c84cz641
#79 xs17_1784cggzy332ac
#87 xs17_259m453z311
#112 xs17_31ke0dbz032
#113 xs17_31ke0mqz032
#128 xs17_358mi8czx65
#135 xs17_39c84k8zxbd
#164 xs17_4ai312kozx123
#166 xs17_4ai3wmqzx123
#196 xs17_8k4b9czwdb
#210 xs17_at16853z32
#247 xs17_gbdz12131e8
#252 xs17_ggc2dicz1ac
#266 xs17_jhke0dbz1
#267 xs17_jhke0mqz1
#280 xs17_mp2c826z65
#281 xs17_mp2c84cz65
#293 xs17_wo86picz6221
#295 xs17_xkq23zck3z023

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x = 603, y = 214, rule = B3/S23
218bo198b3o$217b2o197bo3bo$218bo201bo$218bo200bo$218bo199bo$218bo198bo
$217b3o196b5o4$17b3o17bo19b3o17b3o19bo16b5o16b3o16b5o16b3o17b3o17b3o
17bo19b3o17b3o19bo16b5o16b3o16b5o16b3o17b3o17b3o17bo19b3o17b3o19bo16b
5o16b3o16b5o16b3o17b3o$16bo3bo15b2o18bo3bo15bo3bo17b2o16bo19bo3bo19bo
15bo3bo15bo3bo15bo3bo15b2o18bo3bo15bo3bo17b2o16bo19bo3bo19bo15bo3bo15b
o3bo15bo3bo15b2o18bo3bo15bo3bo17b2o16bo19bo3bo19bo15bo3bo15bo3bo$16bo
3bo16bo22bo19bo16bobo16bo19bo22bo16bo3bo15bo3bo15bo3bo16bo22bo19bo16bo
bo16bo19bo22bo16bo3bo15bo3bo15bo3bo16bo22bo19bo16bobo16bo19bo22bo16bo
3bo15bo3bo$16bobobo16bo21bo18b2o16bo2bo17b3o16b4o19bo17b3o17b4o15bobob
o16bo21bo18b2o16bo2bo17b3o16b4o19bo17b3o17b4o15bobobo16bo21bo18b2o16bo
2bo17b3o16b4o19bo17b3o17b4o$16bo3bo16bo20bo21bo15b5o19bo15bo3bo17bo17b
o3bo19bo15bo3bo16bo20bo21bo15b5o19bo15bo3bo17bo17bo3bo19bo15bo3bo16bo
20bo21bo15b5o19bo15bo3bo17bo17bo3bo19bo$16bo3bo16bo19bo18bo3bo18bo16bo
3bo15bo3bo17bo17bo3bo15bo3bo15bo3bo16bo19bo18bo3bo18bo16bo3bo15bo3bo
17bo17bo3bo15bo3bo15bo3bo16bo19bo18bo3bo18bo16bo3bo15bo3bo17bo17bo3bo
15bo3bo$17b3o16b3o17b5o16b3o19bo17b3o17b3o18bo18b3o17b3o17b3o16b3o17b
5o16b3o19bo17b3o17b3o18bo18b3o17b3o17b3o16b3o17b5o16b3o19bo17b3o17b3o
18bo18b3o17b3o9$156b2obo276b2o2b2o134bo$b3o152bob2o275bo2bo2bo133bobo
2b2o$o3bo155b2o274bobobo134bo2bo2bo$o3bo152b2o2bo273b2o2bo136bob2o$obo
bo151bob2o276bo138b2o$o3bo151bo278bo140bo$o3bo150b2o278b2o138bo$b3o
571b2o13$36b2ob2o120b2o413bo$bo34bob2o117b2o2bo413bobo$2o39bo114bo2bob
o413bo2bob2o$bo35b2ob2o115bob2o415bob2obo$bo35bo118b2o417b2o$bo33bobo
119bo418bo$bo33b2o118bo419bo$3o152b2o418b2o13$157bo77b2o3b2o277bo$b3o
152bobo2b2o72bo2bo2bo276bobo$o3bo151bo2bo2bo74b2obo276bobobo$4bo152bob
2o77bob2o275bobobo$3bo152b2o79bo277b2o3bo$2bo154bo78bo278bo$bo153bo80b
2o278bo$5o150b2o360bo$516b2o12$17bo139bo77b2o363bo$b3o12bobo2b2o133bob
o76bo2bob2o357bobo$o3bo12bobo2bo133bo2bob2o74b2obo358bo2bo$4bo14b2o
136bob2obo75bo2bo355b2obobo$2b2o14bo137b2o79bo2b2o355bo2b2o$4bo11b3o
138bo78bo361bo$o3bo10bo139bo80b2o357b3o$b3o11b2o138b2o438bo13$77b2o57b
2o200b2o$3bo74bo57bo199b3obo$2b2o72bo2b2o57bo196bo5bo$bobo72b2obo2bo
54b2o197bo5bo$o2bo74bo2b2o53bo200bo3b2o$5o70bobo57bo2b3o197bobo$3bo71b
2o59b2obo199b2o$3bo137bo$140b2o12$136b2o137b2o324bo$5o131bo138bo323b3o
$o137bo138bob2o317bo$o136b2o137b3o2bo317bo$b3o132bo143bo317b2o$4bo130b
o2b3o137b2o317bo$o3bo131b2o2bo137bo318bo$b3o134bo140bo315b2o$138b2o
138b2o315bo$596bo$597bo$596b2o9$338bo59b2o135b2o3b2o$b3o332b3o2b2o55bo
136bo2bo2bo$o3bo330bo5bo54b2o2bo136b2obo$o335bo5bo52bo2b3o137bob2o$4o
333bo3b2o53bo138b3o$o3bo333bobo56b2o136bo$o3bo334b2o57bo$b3o393bo$397b
2o12$176b2o2b2o314b2o37b2o$5o170bo2bo2bo314bo38bo2bob2o$4bo171bob3o
316bo39b2obo$3bo173bo318b2o40bo2bo$3bo174bo316bo39b3o2b2o$2bo172b3o
317bob3o35bo$2bo172bo320bobobo$2bo497bo$500b2o12$255b2o$b3o251bo2b2o$o
3bo251bobo2bo$o3bo252bo2b2o$b3o254b2o$o3bo254bo$o3bo253bo$b3o254b2o13$
155b2o$b3o152bo$o3bo151bob2o$o3bo152bobo$b4o155b2o$4bo157bo$o3bo157b3o
$b3o161bo$164b2o!

Edit: Well actually the cleanup can be improved, which solves #71 after all!

Code: Select all

x = 21, y = 28, rule = B3/S23
bo8bo$obo5b2o$b2o6b2o3$7b2o$7b2o2$13bo$12bobo$7bo4bo2bo2b2o$7b3o3b2o3b
obo$10bo7bo$9b2o$8bo$8bob3obo$9bobob2o6$15b2o$15b2o2$18b3o$18bo$19bo!

[Kazyan]

10G for a 18-bit still life related to #32 and #128. Alex Greason retrieved the following 7G eater-to-snake converter, and the 4G block predecessor inserter looks like it could be replaced with a lucky 3G collision. However, I couldn't find one. This could get to 16G by either finding a 9G way to make the base still life, or improving the converter.

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x = 84, y = 36, rule = B3/S23
4bo$2bobo$3b2o2$13bo5bo$8bo5bo5bo$9bo2b3o3b3o$7b3o9$18bo53b2o$16bobo
50b2o2bo$17b2o48bo2bobo$67b2o2bo$69b2o$69bo6bo5bo$7b2o58bobo5bo5bo$6bo
bo23bo34b2o6b3o3b3o$8bo22b2o29b3o$31bobo30bo7b2o$bo61bo8bobo2b2o$b2o
63bo5bo4bobo$obo63b2o9bo$65bobo$71b2o$13b2o56bobo$14b2o55bo$7b2o4bo$8b
2o$7bo!

#247 (xs17_gbdz12131e8) mysteriously dropped to 16G without announcement, as well. The improvement uses boilerplate components, and Alex Greason has rerun transfer.py again, so that's probably where it came from. Automated synthesis has come a long way.

[Goldtiger997]

#128 in 16G after much fiddling about:

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x = 43, y = 37, rule = B3/S23
35bo$33b2o$34b2o2$2bo$obo20bobo4bo$b2o4bo15b2o3b2o$8bo15bo4b2o$6b3o$
12bobo$13b2o$13bo4$36bo$35bo$35b3o2$21b3o$23bo$22bo2$17b3o18b2o$19bo
18bobo$6b3o9bo19bo$8bo$7bo4b2o20b2o$13b2o18b2o$12bo22bo$18b2o$17bobo$
19bo$31bo$30b2o8b2o$30bobo7bobo$40bo!

Removing some gliders results in the same still-life but with a shillelagh instead of a snake in 12G:

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x = 29, y = 27, rule = B3/S23
27bo$26bo$26b3o2$o$b2o13bo5bo$2o14bobo2bo$5bobo8b2o3b3o$6b2o$6bo6bo$
11bobo$12b2o$21bo$21b2o$20bobo2$17bo$17b2o$6bo9bobo$6b2o$5bobo$11b3o
12b3o$13bo12bo$12bo14bo$15b3o$17bo$16bo!

The base reaction comes from this soup. The still-life itself appears at generation 13 which made this synthesis quite difficult. I was unable to find any cheap inserters for the pond predecessor, and all the methods I found of making the junk in the top right were too sparky to allow cheap methods for the bottom part of the reaction. If someone can make the pond more cheaply and make the junk in the top-right "unmessily" and cheaply then that may solve #34 via a snake-to-carrier conversion.

[Freywa]

#128 in 16G after much fiddling about:

Congratulations, you've knocked out the entire xx8 row of stills!

[Kazyan]

#73 in 15G:

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x = 70, y = 38, rule = B3/S23
4bobo$5b2o$5bo2$16bo$7bo8bobo$5bobo8b2o$6b2o4$4bo$2bobo$3b2o2$12bo$11b
o$11b3o4$51b2o$51bo2bob2o$bo51b3o2bo$b2o54bo$obo52b2o$55bo7bo5bo$53bob
o5b2o4b2o$53b2o7b2o4b2o$8b2o38b2o$8bobo38b2o8bo$8bo39bo9b2o4bo$4b3o51b
obo2b2o$6bo44b3o9bobo$5bo47bo$52bo5bo$57b2o$57bobo!

EDIT: #281 in 16G:

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x = 115, y = 42, rule = B3/S23
bo$2bo$3o$40bobo$40b2o$20bo20bo$21bo$9bo9b3o$10bo$8b3o5$100bo$99bobo$
95b2obo2bo$95bob2obo$100b2o$100bo7bo5bo$98bobo5b2o4b2o$98b2o7b2o4b2o$
93b2o$94b2o8bo$24b2o67bo9b2o4bo$23bobo77bobo2b2o$13bo11bo2b2o66b3o9bob
o$13b2o12b2o69bo$12bobo14bo9b3o55bo5bo$39bo62b2o$40bo61bobo9$50b3o$50b
o$51bo!

EDIT 2: #252 in 16G:

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x = 144, y = 48, rule = B3/S23
31bobo101bo$31b2o8bo86bo6bobo$32bo8bobo85bo5b2o$41b2o84b3o$46bo87bo7bo
$46bobo83bobo6bo$46b2o85b2o6b3o2$92bo$91bo$81b2o8b3o37b2o$81bobo47bobo
$83bo10b2o37bo$83b2o3b2o4bobo36b2o3bo$85bobobo4bo40bobobo$85bobo47bobo
bo$86bobo47bobo$87bo49bo$19bobo$19b2o$20bo3$19b2o$19bobo$19bo9$42b2o$
41b2o$43bo4$53bo$52b2o$13bo38bobo$13b2o$12bobo$2o45b2o$b2o44bobo$o46bo
!

EDIT 3: #87 in 16G. Same idea as the 17G version, but using a vessel that can be activated in 2G rather than 3G:

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x = 129, y = 42, rule = B3/S23
119bo$117b2o$118b2o2$101bobo$102b2o$102bo13bobo$116b2o$117bo2$102bo23b
obo$100bobo23b2o$101b2o24bo4$124bo$13bo49bo49bo9bo$13b3o47b3o47b3o7b3o
$16bo49bo49bo$13b3o47b3o47b3o$13bo49bo49bo$49bo10bo49bo$2bo45bo10bobo
47bobo$obo45b3o9bobo45bobobo$b2o58b2o45bo2b2o$107b2o$9b2o36b3o$5b2o2bo
bo35bo$4bobo2bo38bo$6bo4$123bo$122b2o$122bobo3$66b2o$66bobo$66bo!

EDIT 4: Idea for #79. A better way to active the rightmost block would probably do the trick.

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x = 51, y = 38, rule = B3/S23
18bo4bo$19b2o3b2o$18b2o3b2o2$48bo$48bobo$48b2o3$2bo8bo$3bo5b2o$b3o6b2o
5$33bo$32bobo$25b2ob2o2b2o$3o22b2ob2o$2bo$bo29bo$31b3o$34bo$33b2o7$14b
2o$13bobo$15bo$31b3o$8b2o21bo$9b2o21bo$8bo!

[Extrementhusiast]

EDIT 4: Idea for #79. A better way to active the rightmost block would probably do the trick.

Code: Select all

RLE

#79 in sixteen gliders using a slightly different method:

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x = 105, y = 23, rule = B3/S23
97bo$58bo36b2o$57bo38b2o$57b3o$42bo9bobo38bo$43b2o8b2o36b2o8b2o$6bo35b
2o9bo35bo2b2o6bobo$5bo32bo48bobo10bo$5b3o31b2o47b2o9b2o$obo35b2o55b2ob
o$b2o47b2o32bobo8bob2o$bo47bobo2bobo28b2o$49bo4b2o29bo16bo$48b2o5bo46b
obo$42bo59b2o$42b2o$41bobo50bo$88b3o3b2o$90bo2bobo$89bo$100bo$100b2o$
99bobo!

However, it seems to be possible to save one more glider on the right with a lucky four-glider collision somewhat demonstrated by the following:

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x = 14, y = 15, rule = B3/S23
9bo$10bo$8b3o$3o$2bo8bo$obo8bobo$bo9b2o$4b2o$4bo$5bo4b2o$4b2o3b2o$3bo
7bo$b3o$o$2o!

[Freywa]

Priority should be given to solving these three pairs of still lifes:

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x = 56, y = 29, rule = B3/S23
b2o$bo21b2o3b2o19b2o3b2o$3bo19bo2bo2bo19bo2bo2bo$2b2o21b2obo22b2obo$bo
24bob2o22bob2o$o2b3o19bo23b3o$b2obo19bo24bo$6bo17b2o$5b2o12$b2o$bo21b
2o24b2o$3bo19bo2bob2o19bo2bob2o$2b2o21b2obo22b2obo$bo24bo2bo22bo2bo$o
2b3o19bo2b2o19b3o2b2o$b2o2bo18bo24bo$3bo20b2o$3b2o!

[Kazyan]

The method for #79 would work for #285 as well, given a 4G bookend-or-equivalent inserter to dodge the python. Since python-at-snake is 7G thanks to Goldtiger, it sounds plausible.

Anyway, #65 in 15G. A 1G cleanup for the upper right transformation may exist. EDIT: Fixed; I got a timing wrong an Ian07 pointed it out.

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x = 91, y = 42, rule = B3/S23
90bo$88b2o$89b2o3$84bo$66bo15b2o$59b2o5bobo14b2o$60b2o4b2o$59bo$67bo$
66b2o$66bobo12bo$81bobo$81b2o8$bo$2bo16bo32bo$3o16bobo31bo$19b2o30b3o$
9bobo56b2o$10b2o53b2o2bo$10bo53bo2b2o$52bo11bobo$12bo40bo11b2o$12bobo
36b3o$12b2o$3b2o80bo$2bobo79b2o$4bo79bobo4$68bo$67b2o$67bobo!

A related method could work for #196, but I can't quite make it fit under the 16G limit. Second pair of eyes on this would be appreciated. This would complete it, but two gliders have to pass through each other.

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x = 26, y = 32, rule = LifeHistory
17.A.A$17.2A$18.A$2.A$3.2A15.A.A$2.2A16.2A$21.A2$24.A$23.A$5.A17.3A$
6.A$4.3A2$2.2E$.E.E$3.E7.3A3$14.2A$2.E8.2A2.A$E.E7.A2.2A$.2E7.A.A$11.
2A3$2.A$A.A$.2A$10.2A$9.2A$11.A!

EDIT 2: #280 in 16G, using a similar idea:

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x = 87, y = 37, rule = B3/S23
65bo$58b2o5bobo$59b2o4b2o18bo$37bo20bo25bo$38b2o26bo17b3o$37b2o26b2o$
65bobo12bo$80bobo$80b2o2$49bobo$50b2o$50bo$o$b2o53bo$2o52b2o$6bo48b2o$
6bobo$6b2o2$67b2o$7bo44bobo9b2o2bo$b2o3b2o45b2o9bob2o$2b2o2bobo44bo$bo
5$84b2o$83b2o$85bo2$53b2o$52bobo16b2o$54bo15b2o$72bo!

[chris_c]

A related method could work for #196, but I can't quite make it fit under the 16G limit. Second pair of eyes on this would be appreciated. This would complete it, but two gliders have to pass through each other.

Code: Select all

x = 26, y = 32, rule = LifeHistory
17.A.A$17.2A$18.A$2.A$3.2A15.A.A$2.2A16.2A$21.A2$24.A$23.A$5.A17.3A$
6.A$4.3A2$2.2E$.E.E$3.E7.3A3$14.2A$2.E8.2A2.A$E.E7.A2.2A$.2E7.A.A$11.
2A3$2.A$A.A$.2A$10.2A$9.2A$11.A!

Using an equivalent but different 3G reaction in the lower left:

Code: Select all

x = 26, y = 38, rule = B3/S23
17bobo$17b2o$18bo$2bo$3b2o15bobo$2b2o16b2o$21bo2$24bo$23bo$5bo17b3o$6b
o$4b3o2$2b2o$bobo$3bo7b3o3$14b2o$11b2o2bo$10bo2b2o$10bobo$11b2o7$3o$2b
o$bo$8b2o$8bobo$2b2o4bo$3b2o$2bo!

[Kazyan]

Welcome back, Chris.

#295 in 16G, after finding a way to dodge the python and noticing that python-at-snake cost 6G instead of 7G:

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x = 163, y = 39, rule = B3/S23
150b2o$19bo130b2o$18bo$18b3o127b2o$84bo62bobo$69bo13bo65bo$67bobo13b3o
$35bo32b2o9bobo$34bo45b2o$34b3o43bo$70bo$68bobo$69b2o10bo8b2o11bo56b2o
$81b2o7bo10b2o57bo$80bobo8bo10b2o57bo$92bo69bo$91b2o68b2o$2o4bobo78b2o
bo69bo$b2o3b2o79bob2o69bo$o6bo150b2o$158bo$159bo$156b3o$156bo3$2b2o$3b
2o$2bo2$5b3o$5bo$6bo66bo4b2o$73b2o2bobo$72bobo4bo2$84b2o$83bobo$85bo!

This brings us down to fifteen still lifes. The hitlist grid is now so sparse that it's actually hard to identify the remaining few.

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#3 xs17_025ic826z6511
#11 xs17_03pa39cz321
#34 xs17_0c9jc4goz321
#64 xs17_0j9cz122139c
#70 xs17_0j9qj4cz23
#72 xs17_0mp2c826z641
#112 xs17_31ke0dbz032
#113 xs17_31ke0mqz032
#135 xs17_39c84k8zxbd
#164 xs17_4ai312kozx123
#166 xs17_4ai3wmqzx123
#210 xs17_at16853z32
#266 xs17_jhke0dbz1
#267 xs17_jhke0mqz1
#293 xs17_wo86picz6221

Code: Select all

x = 147, y = 47, rule = B3/S23
2b3o17bobo15b3obobo13b3obobo13b3ob3o13b3ob3o13bobob3o13bobob3o$4bo17bo
bo17bobobo13bo3bobo15bobobo15bo3bo13bobo3bo13bobo3bo$2b3o17bobo15b3ob
3o13b3ob3o15bobobo15bob3o13bobob3o13bobob3o$4bo17bobo17bo3bo13bobo3bo
15bobobo15bobo15bobobo15bobo3bo$2b3o17bobo15b3o3bo13b3o3bo15bob3o15bob
3o13bobob3o13bobob3o4$2bo18b2ob2o16b2o17b2o23b2o14bo17b2o3b2o13b2o$bob
o2b2o13bob2o18bo17bo20b2o2bo14bobo2b2o12bo2bo2bo13bo2bob2o$2bobo2bo18b
o14bo2b2o17bo17bo2bobo14bo2bo2bo14b2obo16b2obo$4b2o16b2ob2o14b2obo2bo
14b2o18bob2o16bob2o17bob2o16bo2bo$3bo18bo20bo2b2o13bo19b2o18b2o19bo19b
o2b2o$b3o16bobo17bobo17bo2b3o16bo19bo18bo19bo$o19b2o18b2o19b2obo15bo
19bo20b2o18b2o$2o64bo13b2o18b2o$65b2o14$ob3ob3o10bob3obobo11bob3ob3o
11b3obob3o11b3ob3ob3o9b3ob3ob3o9b3ob3ob3o$o3bobo12bobo3bobo11bobo3bo
15bobobobo13bobo3bo13bobo5bo11bobobo3bo$ob3ob3o10bob3ob3o11bob3ob3o11b
3obobobo11b3ob3ob3o9b3ob3o3bo9b3ob3ob3o$o3bo3bo10bobobo3bo11bobobobobo
11bo3bobobo11bo3bobobobo9bo3bobo3bo9bo5bo3bo$ob3ob3o10bob3o3bo11bob3ob
3o11b3obob3o11b3ob3ob3o9b3ob3o3bo9b3ob3ob3o4$2o21b2o18bo17b2o2b2o13b2o
3b2o13b2o23bo$o20b3obo15b3o2b2o12bo2bo2bo13bo2bo2bo13bo2bob2o17bobo$2b
ob2o14bo5bo13bo5bo14bobobo16b2obo16b2obo18bo2bo$b3o2bo14bo5bo13bo5bo
12b2o2bo18bob2o16bo2bo15b2obobo$5bo16bo3b2o14bo3b2o13bo18b3o17b3o2b2o
15bo2b2o$3b2o18bobo17bobo14bo19bo19bo22bo$3bo20b2o18b2o14b2o58b3o$4bo
115bo$3b2o!

Commentary: #3 looks like it should have been knocked out ages ago, but that triad of still lifes has surprisingly few ways to get stuck together like that. Close relatives of #3 have few or no soups.

#164, the black lagoon, is wholly unsurprising as an endgame still life.

#166 is a little surprising, but makes sense in retrospect. Cis-hooks with tails get in the way of components, and can't cheaply be built after-the-fact. #166 isn't hard to synthesize; it's here because all of the cheap ways to do it can't fit.

#293 is the current most expensive still life, at 26 gliders. It looked like a piece of cake, but its characteristic geometry is minimal, if that makes any sense--so it has zero simplified relatives, zero soups, and the ugly end of a hook-with-tail is right in the middle of everything.

The others are more-or-less expected as finalists, mostly consisting of difficult carrier and snake motifs in awkward orientations.

[Extrementhusiast]

Reducing one solved and one unsolved SL, although no changes to the list are made:

Code: Select all

x = 149, y = 102, rule = B3/S23
101bo$43bo58bo$42bo57b3o$42b3o3$106bo$59bo47bo$58bo46b3o$58b3o48bobo$
109b2o$110bo$96bo17b2o$97bo16bo$95b3o17bo$116bo6bobo$115b2o6b2o$24b2o
4bobo78b2obo9bo$25b2o3b2o79bob2o$24bo6bo7$26b2o$27b2o$26bo2$29b3o67b2o
3b3o$29bo70b2o4bo$30bo68bo5bo2$110b3o$112bo$111bo33$72bobo$3bo68b2o$2b
o70bo71bo$2b3o138b2o$137bobo4b2o$138b2o$138bo3$140bo$46bo91bobo$47b2o
90b2o3bo$46b2o94b2o$bo141b2o$2bo$3o107bo$4b2o94b2o7bo29b2o$4bobo35b3o
55bobo6b3o27bobo3bo$4bo53bo39b2o2bo34b2o2bo2bobo$46bo10bobo37bo2b2o4b
3o27bo2b2o3bobo$46bo9bo2bo38bo7bo30bo7bo$46bo5b3o2b2o40b3o5bo30b3o$54b
o46bo38bo$13b3o37bo$13bo116bo16b2o$14bo116b2o13b2o$130b2o10b2o4bo$134b
3o5bobo$136bo5bo$135bo$138bo$138b2o$137bobo!

EDIT: If #3 apparently can't be done by soup, let's do it the old-fashioned way in just ten gliders:

Code: Select all

x = 33, y = 31, rule = B3/S23
19bo$17b2o$18b2o2$6bo$4bobo$5b2o19bo$24b2o6bo$25b2o3b2o$31b2o4$6bobo$
7b2o$7bo$13bo$5b2o6bobo$4bobo6b2o$6bo3$28b2o$27b2o$29bo3$3o$2bo9b3o3b
2o$bo12bo2b2o$13bo5bo!

[Hdjensofjfnen]

#79 in sixteen gliders using a slightly different method:

Code: Select all

x = 105, y = 23, rule = B3/S23
97bo$58bo36b2o$57bo38b2o$57b3o$42bo9bobo38bo$43b2o8b2o36b2o8b2o$6bo35b
2o9bo35bo2b2o6bobo$5bo32bo48bobo10bo$5b3o31b2o47b2o9b2o$obo35b2o55b2ob
o$b2o47b2o32bobo8bob2o$bo47bobo2bobo28b2o$49bo4b2o29bo16bo$48b2o5bo46b
obo$42bo59b2o$42b2o$41bobo50bo$88b3o3b2o$90bo2bobo$89bo$100bo$100b2o$
99bobo!

Does anyone find it humorous that you have to destroy an eater, only to get another eater just several cells to the northeast?

Anyway, my comments: #266 and #267 can easily be solved if we can get the induction coil on the left in an edgy way. Or a snake in an edgy way. Or both.

[Freywa]

Does anyone find it humorous that you have to destroy an eater, only to get another eater just several cells to the northeast?

It's not funny; it's just a method that works.

And I want the last remaining stills to be solved by the end of September.

[Extrementhusiast]

#70 in sixteen gliders:

Code: Select all

x = 128, y = 33, rule = B3/S23
22bo5bobo$20b2o6b2o96bo$21b2o6bo3bo48bo35bo6bo$obo29bo49bobo33bobo4b3o
$b2o29b3o43bo3b2o34b2o$bo77b2o34bo7b2o$28bobo47b2o36b2o4bobo$28b2o85b
2o5bo$29bo91b2o2$75b2o41b2o$74bo2bob2o31bobo2bo2bob2o$74b2o2b2o2bo30b
2o2b2o2b2o2bo$4bobo74b2o26b2o2bo10b2o$5b2o2bobo65bob2o27bobo9bob2o$5bo
3b2o66b2obo29bo9b2obo$10bo9$34b2o$34bobo$34bo3$29b3o$29bo$30bo!

[testitemqlstudop]

Does anyone find it humorous that you have to destroy an eater, only to get another eater just several cells to the northeast?

It's not funny; it's just a method that works.

And I want the last remaining stills to be solved by the end of September.

You're not helping.

[Freywa]

You're not helping.

I am, by maintaining Shinjuku. I've essentially reached the limit of my capabilities for the actual syntheses, and am merely collecting what Kazyan and Martin and those who can do the syntheses are doing.

[testitemqlstudop]

Which can literally be script automated at this point.

Just because you created an utility doesn't mean you should act like you are someone else's boss, especially when they are volunteering their own time to contribute to some meaningless-for-99.9999%-of-people project.

[Freywa]

Yes, but this project is for everyone's sake, whether we know them or not.

[testitemqlstudop]

In what way? How would Donald Trump benefit from an orderly collection of the synthesae of all 17 bitted still lives?

[calcyman]

In what way? How would Donald Trump benefit from an orderly collection of the synthesae of all 17 bitted still lives?

Conway is the Counselor to the President of the United States, which makes Conway's Game of Life of inherent interest to Donald Trump.

[testitemqlstudop]

What

https://en.wikipedia.org/wiki/John_Horton_Conway

Oh you forgot /s?

[Macbi]

Oh you forgot /s?

Right, but more specifically the joke is that Kellyanne Conway does work for Trump.

[testitemqlstudop]

Oh. I'm not the best at politics.

[Kazyan]

Freywa is helping indirectly. That being said, the project will be finished when it's finished. We might finish in a few more days, or one of these last thirteen might completely stump us both until October.

[Hdjensofjfnen]

By the way, testitemqlstudop, are you betting on that SL in your profile as the last 17-bitter to be efficiently synthesized?
EDIT:

#70 in sixteen gliders:

Code: Select all

x = 128, y = 33, rule = B3/S23
22bo5bobo$20b2o6b2o96bo$21b2o6bo3bo48bo35bo6bo$obo29bo49bobo33bobo4b3o
$b2o29b3o43bo3b2o34b2o$bo77b2o34bo7b2o$28bobo47b2o36b2o4bobo$28b2o85b
2o5bo$29bo91b2o2$75b2o41b2o$74bo2bob2o31bobo2bo2bob2o$74b2o2b2o2bo30b
2o2b2o2b2o2bo$4bobo74b2o26b2o2bo10b2o$5b2o2bobo65bob2o27bobo9bob2o$5bo
3b2o66b2obo29bo9b2obo$10bo9$34b2o$34bobo$34bo3$29b3o$29bo$30bo!

Is that not #70 or am I seeing things?