The Hunting of the Elementary Conduits

[EvinZL]

HL58R only requires one catalyst to clean up everything besides the first natural glider. It even cleans up the Herschel's first block.

Code: Select all

x = 23, y = 31, rule = LifeHistory
12.D$10.3D$11.D7$2.C$3C$C.C$C12$16.2A.A$16.2A.3A$22.A$16.2A.3A$17.A.A$17.A.A$18.A!

Nice! that makes F131c?

Code: Select all

x = 43, y = 41, rule = LifeHistory
25.A$24.A.A$24.A.A$23.2A.3A$24.B4.A$22.B2AB3A$18.3B.B2A.A$17.6B$16.6B
$17.7B$17.7B$10.15B$9.17B$9.17B$10.16B$9.15B$7.17B$5.19B$5.2BC16B$4.
3BCBC4B.9B$5.2B3C4B.10B$4.5BC4B.11B.2B3.2B2.2B$3.22B.13BD$2.4B6.27BDB
D$.4B7.16B2A9B3DB$4B9.15B2A11BD$13.11B.15B$14.10B3.2B.3B.B$15.3BD3B$
15.2B3D2B$16.3BDB$17.3B$18.4B$17.2A.2A$16.ABABABA$14.3A.B.A.A$13.A4.A
.A.3A$14.3A.2A.A3.A$16.A4.A2.2A$18.3A$17.2A!

[MathAndCode]

Nice! that makes F131c?

There's a partial conduit that would make extracting R sequences formed in this manner much easier.

Here is a demonstration of the sheer number of sacrifical objects that work.

Code: Select all

x = 30, y = 45, rule = TripleB3S23
16.2G$16.2G2$23.G.2G$23.2G.G7$21.G$20.G.G$21.2G$4.CB$4.AGE$5.F.G$6.2G10$29.G$28.2G$27.2G$28.2G7$2.2G$.G.G16.2G$.G18.G.G$2G20.G$5.2G15.2G$6.G$3.3G$3.G!

Code: Select all

x = 30, y = 45, rule = TripleB3S23
16.2G$16.2G2$23.G.2G$23.2G.G7$21.G$20.G.G$21.2G$6.2B$6.F$4.AE.G$4.A.2G10$29.G$28.2G$27.2G$28.2G7$2.2G$.G.G16.2G$.G18.G.G$2G20.G$5.2G15.2G$6.G$3.3G$3.G!

Code: Select all

x = 30, y = 45, rule = TripleB3S23
16.2G$16.2G2$23.G.2G$23.2G.G7$21.G$20.G.G$21.2G$5.2B$3.DEC$3.DAD.G$6.2G10$29.G$28.2G$27.2G$28.2G7$2.2G$.G.G16.2G$.G18.G.G$2G20.G$5.2G15.2G$6.G$3.3G$3.G!

Code: Select all

x = 30, y = 45, rule = TripleB3S23
16.2G$16.2G2$23.G.2G$23.2G.G7$21.G$20.G.G$3.2A2D14.2G$2.BC.D$2.B.CAE$5.B.G$6.2G10$29.G$28.2G$27.2G$28.2G7$2.2G$.G.G16.2G$.G18.G.G$2G20.G$5.2G15.2G$6.G$3.3G$3.G!

Code: Select all

x = 30, y = 45, rule = TripleB3S23
16.2G$16.2G2$23.G.2G$23.2G.G7$21.G$4.2A14.G.G$3.DE16.2G$2.BF.E$2.B.B.E$5.B.G$6.2G10$29.G$28.2G$27.2G$28.2G7$2.2G$.G.G16.2G$.G18.G.G$2G20.G$5.2G15.2G$6.G$3.3G$3.G!

For two of the sacrificial objects in the last example, while the reaction still works in the sense that another R-pentomino is created in the correct place and time, the reaction also creates junk that destroys one or more catalysts in the previous conduit. This can be fixed by adding more still lifes far enough away to interfere with the reaction with the R-pentomino.

Code: Select all

x = 32, y = 45, rule = TripleB3S23
18.2G$18.2G2$25.G.2G$25.2G.G5$2D$2D$23.G$6.2A14.G.G$5.DE16.2G$4.BF.E$4.B.B.E$7.B.G$8.2G2$3.2A$3.2A7$31.G$30.2G$29.2G$30.2G7$4.2G$3.G.G16.2G$3.G18.G.G$2.2G20.G$7.2G15.2G$8.G$5.3G$5.G!

As I have stated before in other threads, it should be easy to complete for someone with knowledge of enough catalysts.

[MathAndCode]

Here's an E→S.

Code: Select all

x = 11, y = 16, rule = LifeHistory
6.A$5.A.A$5.A.A$4.2A.3A$10.A$4.2A.3A$4.2A.A4$.3C$2C$.2C$2.2D$.2D$2D!

Also, here's a way to turn it into a B-heptomino, but a block is turned into a beehive. Thank Kazyan I know how to change it back. It even clears the B's first natural block in case one wants a Herschel output.

Code: Select all

x = 31, y = 35, rule = LifeHistory
26.C$25.C$25.3C11$4.3D$5.D$3.3D7$12.3C$11.2C$12.2C3.D$5.2A10.2D$5.2A11.2D$17.2D$2.A$.A.A$A2.A$.2A2$12.2A$12.2A!

[Entity Valkyrie 2]

Example of E conduit that doesn't connect to anything?

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x = 12, y = 31, rule = EV2QuadColor
10.2E$10.E$8.E.E$8.2E7$G$G.G$3G$.G4$3.2E$3.2E10$.3H$3.H$2.3H!

[MathAndCode]

Example of E conduit that doesn't connect to anything?

I know that this particular example could have been found through other means, but has someone done a systematic search of placing blocks and possibly beehives in the paths of common methuselahs and recording the instances where the object is put back, at least temporarily?

[EvinZL]

Example of E conduit that doesn't connect to anything?

I know that this particular example could have been found through other means, but has someone done a systematic search of placing blocks and possibly beehives in the paths of common methuselahs and recording the instances where the object is put back, at least temporarily?

That is called CatForce

[MathAndCode]

That is called CatForce

Sorry; I'm still somewhat unfamiliar with what all of the automated programs do.

[Entity Valkyrie 2]

Well, I found this conduit as an accidental discovery: I originally didn't have that block (in the form of E-to-B), but then I realized that putting a block there just gets it eaten by a spark, and is regenerated by the B, so that became a E-to-H.

I do everything by hand, so I have never used CatForce.

[MathAndCode]

Well, I found this conduit as an accidental discovery: I originally didn't have that block (in the form of E-to-B), but then I realized that putting a block there just gets it eaten by a spark, and is regenerated by the B, so that became a E-to-H.

I do everything by hand, so I have never used CatForce.

I tried suppressing the initial block with a block that would have been placed as part of the blockade, but I didn't think of your transparent block.

[Kazyan]

I think we're slightly overselling what CatForce does. You give it an input file that contains the methuselah, a list of catalysts, and a region that you want it to put those catalysts in. Then it checks all the ways you can possibly put catalysts there even if th placement doesn't make sense, up to 1 or 2 or 3 or however many catalysts at a time (because if you ask it to check all of the ways you could place 5 blocks or eaters, you will not finish that search).

I have done reasonably-comprehensive 2-catalyst searches on H, B, R, C, Q, G, W, and P signals, in no particular order, along with honey farm explosions and LoM explosions. I have not checked the speculative objects being discussed recently, but I can run such searches for I, E, etc. if that would be helpful.

[MathAndCode]

I have done reasonably-comprehensive 2-catalyst searches on H, B, R, C, Q, G, W, and P signals, in no particular order, along with honey farm explosions and LoM explosions. I have not checked the speculative objects being discussed recently, but I can run such searches for I, E, etc. if that would be helpful.

The I-heptomino seems easier to feed into conduits than the E-heptomino, but that could be a fluke that will go away when someone who knows more catalysts investigates this.
The main reason that I tend to investigate non-standard objects is because I want to be useful, and I will be more useful finding a previously unknown I→B than an already widely known H→B. I focus on patterns that I've seen turn up before in order to be more useful.
Speaking of investigating objects not commonly used in conduits, I'll probably investigate the thunderbird next unless you can think of something more useful.



Edit: The best that I have so far is the active region making three boats that I found some conduits for earlier.

Code: Select all

x = 7, y = 13, rule = LifeHistory
6.A$4.3A$3.A$3.2A4$.C$C.C2$.C$.C$.C!

Another edit: Here's an inaccessible R.

Code: Select all

x = 23, y = 19, rule = LifeHistory
14.A$13.A.A$14.A2$12.5A$12.A4.A$3.A11.A2.A$3.3A9.2A.A2.A$6.A5.A5.A.A.A$5.2A4.A.A4.A2.A$11.A2.A2.AC$12.2A3.2D$18.2D$9.C$8.C.C2$9.C$9.C$9.C!

[dvgrn]

Another edit: Here's an inaccessible R.

Code: Select all

x = 23, y = 19, rule = LifeHistory
14.A$13.A.A$14.A2$12.5A$12.A4.A$3.A11.A2.A$3.3A9.2A.A2.A$6.A5.A5.A.A.A$5.2A4.A.A4.A2.A$11.A2.A2.AC$12.2A3.2D$18.2D$9.C$8.C.C2$9.C$9.C$9.C!

I don't understand this part of the post at all. It seems to show a thunderbird destroying an eater 3. Somewhere after T=50 an R-pentomino does appear in the ash from the eater 3, but not exactly in the position shown... and anyway, what in Conway's name would be the point of getting an R-pentomino out, if you have to destroy a whole eater 3 to do it?

[Jackk]

Another edit: Here's an inaccessible R.

Code: Select all

x = 23, y = 19, rule = LifeHistory
14.A$13.A.A$14.A2$12.5A$12.A4.A$3.A11.A2.A$3.3A9.2A.A2.A$6.A5.A5.A.A.A$5.2A4.A.A4.A2.A$11.A2.A2.AC$12.2A3.2D$18.2D$9.C$8.C.C2$9.C$9.C$9.C!

I don't understand this part of the post at all. It seems to show a thunderbird destroying an eater 3. Somewhere after T=50 an R-pentomino does appear in the ash from the eater 3, but not exactly in the position shown... and anyway, what in Conway's name would be the point of getting an R-pentomino out, if you have to destroy a whole eater 3 to do it?

If you let the eater 3 bite the reaction and then delete it, you get the shown R. I suppose the idea could be to replace the eater 3 with a sacrificial SL that is restored later. In fact, the eater 1 survives the resulting R, leaving only the HF and TL.

EDIT: Example below.

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x = 17, y = 13, rule = LifeHistory
A$3A$3.A$2.2A5.A$8.A.A4.D$9.2A3.2D$15.2D$6.C$5.C.C2$6.C$6.C$6.C!

[MathAndCode]

If you let the eater 3 bite the reaction and then delete it, you get the shown R. I suppose the idea could be to replace the eater 3 with a sacrificial SL that is restored later. In fact, the eater 1 survives the resulting R, leaving only the HF and TL.

EDIT: Example below.

Code: Select all

x = 17, y = 13, rule = LifeHistory
A$3A$3.A$2.2A5.A$8.A.A4.D$9.2A3.2D$15.2D$6.C$5.C.C2$6.C$6.C$6.C!

Yes, that's what I meant.



Edit: Here's a partial conduit that might be able to be cleaned up..

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x = 63, y = 22, rule = LifeHistory
3.A$3.3A$6.A$5.2A$42.3D$42.D.D$42.D.D$4.2D$3.2D$2A2.2D52.2A$2A3.D23.C26.A2.A$28.C.C25.3A2$29.C26.2A.A.2A$29.C27.A.2A.A$29.C27.A$3.2A51.2A$4.A6.2A$3.A8.A35.2A$3.2A4.3A36.A.A$9.A40.A$50.2A!

[Scorbie]

Ohh... that makes what you mean more clear

Just a note: restoring sacrificial still lifes are super hard and rare (or we'd have lots of snark-sized glider reflectors now)
So don't put your hopes too high.

[MathAndCode]

Ohh... that makes what you mean more clear

Just a note: restoring sacrificial still lifes are super hard and rare (or we'd have lots of snark-sized glider reflectors now)
So don't put your hopes too high.

I guess that you have a point, especially since there's not much room for such a catalyst. Typically, when I find a sacrificial object, I wonder whether or not it can be replaced with a permanent catalyst, but that's obviously not feasible in this case.

[dvgrn]

I guess that you have a point, especially since there's not much room for such a catalyst. Typically, when I find a transparent catalyst, I wonder whether or not it can be replaced with a permanent catalyst, but that's obviously not feasible in this case.

Small technical note: a "transparent catalyst" is a catalyst that gets restored exactly as it was, after all of its cells get turned off at some point -- like the transparent block in BFx59H.

If an object gets destroyed and not restored, it's just plain not a catalyst. Common terms are "sacrificial object" or "bait object".

[MathAndCode]

Small technical note: a "transparent catalyst" is a catalyst that gets restored exactly as it was, after all of its cells get turned off at some point -- like the transparent block in BFx59H.

If an object gets destroyed and not restored, it's just plain not a catalyst. Common terms are "sacrificial object" or "bait object".

Whoops! Thank you for pointing that out. I have edited my post in order to prevent potential confusion.



Edit: Can anyone get a ∏→2H out of this?

Code: Select all

x = 11, y = 5, rule = LifeHistory
.2D5.2D$D.D5.D.D$D3.3A3.D$2D.DA.AD.2D$2.2DA.A2D!
#C [[ PASTET 9 PASTE C3.C! 3 -3 ]]

I suspect that extracting both Herschels at the same time will be difficult, but extracting at least one looks feasible.

[Hunting]

Small technical note: a "transparent catalyst" is a catalyst that gets restored exactly as it was, after all of its cells get turned off at some point -- like the transparent block in BFx59H.

If an object gets destroyed and not restored, it's just plain not a catalyst. Common terms are "sacrificial object" or "bait object".

Whoops! Thank you for pointing that out. I have edited my post in order to prevent potential confusion.



Edit: Can anyone get a ∏→2H out of this?

Code: Select all

x = 11, y = 5, rule = LifeHistory
.2D5.2D$D.D5.D.D$D3.3A3.D$2D.DA.AD.2D$2.2DA.A2D!
#C [[ PASTET 9 PASTE C3.C! 3 -3 ]]

I suspect that extracting both Herschels at the same time will be difficult, but extracting at least one looks feasible.

First try:

Code: Select all

x = 12, y = 7, rule = LifeHistory
10.A$9.A.A$.2D5.2DA$D.D5.D.D$D3.3A3.D$2D.DA.AD.2D$2.2DA.A2D!

Replacing pond bait would be difficult, however. And how to get rid of that blocky-block?

[MathAndCode]

And how to get rid of that blocky-block?

It's possible to send some chaos back there that could clean it up.

Code: Select all

x = 32, y = 25, rule = LifeHistory
27.A$26.A.A$26.A.A$25.2A.3A$31.A$25.2A.3A$16.2D7.2A.A$15.D.D$15.D3.3A$15.2D.DA.A$17.2DA.A8$3.A.2A$.3A.2A$A$.3A.2A$3.A.A$3.A.A$4.A!
#C [[ PASTET 9 PASTE C! 18 3 ]]

Unfortunately, this method doesn't work, so we'll either need another way to send chaos back or to use different catalysts so that different objects are left behind initially.
Also, I'd like to replace the dot spark.



Edit: This is p2, but we'll have to be pretty quick about perturbing the Herschel for the next conduit.

Code: Select all

x = 17, y = 17, rule = LifeHistory
3.A6.A$.A.A4.3A$2.A.A2.A$2.A4.2A3$.2D$D.D$D3.3A$2D.DA.A5.2A$2.2DA.A3.A2.A$10.3A2$10.2A.A.2A$11.A.2A.A$11.A$10.2A!

[Jormungant]

Well well, I believe that anything that appears to rely on a spark or some cut-and-paste magic should go in the periodic Hershell conduit thread. I guess it would be fine if it is a near-miss that one could hope to solve with some search automation, but a plausible fix requires a spark, then that belongs to that thread. The more we find, the harder it gets, not everything works with stable circuitry, and it does not need to be. p8/p30/p120 mechanisms are way more fun to make in my opinion, and there is plenty of interactions to catalog and organize (when they fully work that is).

Well, I am not here to complain only, I am posting in this thread, So... maybe I should post a genuinely new h-to-h elementary conduit with repeat time 243 which fits the bill?

Code: Select all

x = 118, y = 88, rule = LifeHistory
4$4.C$4.B2C$4.2C5$99.B2A$97.2BA2BAB$97.3B2A3B$95.12B$94.14B$95.7BDBD
3B$95.7B2D5B$94.9BD5B$94.14B$94.13B$75.2A17.B3D4B.3B$70.2A.A2.A17.2BD
4B$70.2A.2A19.2B3D2B$73.B11.2A7.6B$70.2AB2AB2.2B4.B2AB5.7B$71.A.2A6B.
7B3.8B$69.A3.26B$69.2A5.23B$76.17B.2BD3B$76.16B.2B3D2B$76.18B2DBDB4.
2A$71.2B3.23B4.A$70.2AB3.23B.BA.A$70.2AB3.4BA3BD14B.B2A$71.B4.3BABA2B
DBD14B$73.5BA2BA2B2D15B$74.5B2A19B$74.25B.2B.3B$73.31BA2B$72.2A29BABA
B$72.2A23BD6BA2B$73.2B.7B2.11B3D8B$77.6B2.11BD10B$80.2B3.22B$80.3B3.
15B$79.BC2.B2.15B$79.C.C2.4B2.10B$80.2C2.2C3.14B$85.CB.14B2C$80.5C3.
14B2CB$80.C8.15B$81.2C6.15B$82.C5.17B$55.B23.3C3.16B$54.3B22.C4.16B$
54.4B26.16B$55.4B10.A13.16B$56.4B7.3A12.20B$57.4B5.A15.20B$58.4B4.2A
15.20B$51.2A6.9B14.22B$52.A7.6B14.24B$52.A.2A5.6B3.B2.2B2.26B$53.A2.A
4.19BD13B.10B$54.2AB3.6BC13BDBD4B.7B2.2B4.2A$55.9BCBC2B2A9B3D4B2.3B.B
4.B4.A$56.9B2C2B2A11BD4B4.2B2A3.2A4.3A$57.29B4.BA2.A4.A6.A$57.17B.B
15.3A5.A.A$58.15B27.2A$58.15B18.3A$59.13B5.A3.2A8.A2.A$61.13B2.A.A3.A
10.2A$60.8B4.2A.A.A3.A$60.6B6.2ABA4.A$60.5B8.B2.5A.A$60.B.B5.2A.A.2A.
A4.A.A$61.3B4.A.2A.A2.A.2A2.A$60.B2AB11.2A.A.2A$61.2A!

It is getting harder to find these, but that's how it should be ^^. The might be a hidden B-to-h in there, but I could not find a "normal" way to produce that B (but I found "a" way)

addendum, stylish variant:

Code: Select all

x = 119, y = 102, rule = LifeHistory
21$6.C$6.B2C$6.2C5$101.B2A$99.2BA2BAB$99.3B2A3B$97.12B$96.14B$97.7BDB
D3B$97.7B2D5B$96.9BD5B$96.14B$96.13B$77.2A17.B3D4B.3B$72.2A.A2.A17.2B
D4B$72.2A.2A19.2B3D2B$75.B11.2A7.6B$72.2AB2AB2.2B4.B2AB5.7B$73.A.2A6B
.7B3.8B$71.A3.26B$71.2A5.23B$78.17B.2BD3B$78.16B.2B3D2B$78.18B2D2BD$
73.2B3.23B$72.2AB3.23B$72.2AB3.4BA3BD14B$73.B4.3BABA2BDBD14B$75.5BA2B
A2B2D15B$76.5B2A19B$76.25B.B$75.29B$74.2A28B.B$74.2A23BD5B2A$75.2B.7B
2.11B3D4BA.A$79.6B2.11BD4B.2B.A$82.2B3.16B2.B2A.A$82.3B3.14B3.B2.A.A$
81.BC2.B2.15B3.2A2.A$81.C.C2.4B2.10B5.A.A$82.2C2.2C3.14B2.A.2A$87.CB.
14B2C.A.A$82.5C3.14B2CBA.A$82.C8.15B2.A$83.2C6.15B$84.C5.17B$57.B23.
3C3.16B$56.3B22.C4.16B$56.4B26.16B$57.4B10.A13.16B$58.4B7.3A12.20B$
59.4B5.A15.20B$60.4B4.2A15.20B$53.2A6.9B14.22B$54.A7.6B14.24B$54.A.2A
5.6B3.B2.2B2.26B$55.A2.A4.19BD13B.10B$56.2AB3.6BC13BDBD4B.7B2.2B4.2A$
57.9BCBC2B2A9B3D4B2.3B.B4.B4.A$58.9B2C2B2A11BD4B4.2B2A3.2A4.3A$59.29B
4.BA2.A4.A6.A$59.17B.B15.3A5.A.A$60.15B27.2A$60.15B18.3A$61.13B5.A3.
2A8.A2.A$63.13B2.A.A3.A10.2A$62.8B4.2A.A.A3.A$62.6B6.2ABA4.A$62.5B8.B
2.5A.A$62.B.B5.2A.A.2A.A4.A.A$63.3B4.A.2A.A2.A.2A2.A$62.B2AB11.2A.A.
2A$63.2A!

well, might be it is not really new in the end, but that's within expectations I suppose. Somehow I expected that the folowing did not work:

Code: Select all

x = 72, y = 86, rule = LifeHistory
7$51.B2A$49.2BA2BAB$49.3B2A3B$47.12B$46.14B$47.7BDBD3B$47.7B2D5B$46.
9BD5B$46.14B$46.13B$32.2A12.B3D4B.3B$33.A12.2BD4B$33.A.AB9.2B3D2B$34.
2AB9.6B$36.4B5.7B$35.6B3.8B$35.6B2.8B$30.2A4.15B$30.A2.AB.9B.2BD3B$
31.3AB.8B.2B3D2B$28.3A3.12B2DBDB4.2A$27.A3.A.18B4.A$28.3A3.3B2A12B.BA
.A$31.3AB.A2BA11B.B2A$30.A2.AB.B2A14B$30.2A5.16B$34.7B2.9B$30.2A2.7B
2.8B.2B.3B$30.A2.AB2A.2B3.13BA2B$31.3ABABAB4.12BABAB$35.A.A2.A2.6BD6B
A2B$33.3A.4A2.5B3D8B$32.A3.A6.5BD10B$32.2A2.A.A4.5B3A2B$37.2A4.5BA2BA
B$42.11B$B41.7B3A$2B39.5B5A3B$3B37.6B5A2B$4B36.13B$.4B36.BA5B2A3B4.A$
2.4B35.A4B3A2B5.2A$3.4B33.A3B2ABA9B$4.4B29.11BA4B$5.4B27.2BA5B4A4B$6.
4B26.BAB2A3BA7B$7.4B10.A13.2BA5BA7B$8.4B7.3A12.2A2BAB2A12B$9.4B5.A15.
2A3BA14B$10.4B4.2A15.20B$3.2A6.9B14.22B$4.A7.6B14.24B$4.A.2A5.6B3.B2.
2B2.26B$5.A2.A4.19BD13B.10B$6.2AB3.6BA13BDBD4B.7B2.2B4.2A$7.9BA.A2B2A
9B3D4B2.3B.B4.B4.A$8.8B.2A2B2A11BD4B4.2B2A3.2A4.3A$9.29B4.BA2.A4.A6.A
$9.17B.4B12.3A5.A.A$10.15B3.2B22.2A$10.15B3.3B12.3A$11.13B5.A2B.2A8.A
2.A$13.13B2.A.A2B.A10.2A$12.8B4.2A.A.AB2.A$12.6B6.2ABA4.A$12.5B8.B2.
5A.A$12.B.B5.2A.A.2A.A4.A.A$13.3B4.A.2A.A2.A.2A2.A$12.B2AB11.2A.A.2A$
13.2A!

[dvgrn]

well, might be it is not really new in the end, but that's within expectations I suppose. Somehow I expected that the folowing did not work:

Code: Select all

x = 72, y = 86, rule = LifeHistory
7$51.B2A$49.2BA2BAB$49.3B2A3B$47.12B$46.14B$47.7BDBD3B$47.7B2D5B$46.
9BD5B$46.14B$46.13B$32.2A12.B3D4B.3B$33.A12.2BD4B$33.A.AB9.2B3D2B$34.
2AB9.6B$36.4B5.7B$35.6B3.8B$35.6B2.8B$30.2A4.15B$30.A2.AB.9B.2BD3B$
31.3AB.8B.2B3D2B$28.3A3.12B2DBDB4.2A$27.A3.A.18B4.A$28.3A3.3B2A12B.BA
.A$31.3AB.A2BA11B.B2A$30.A2.AB.B2A14B$30.2A5.16B$34.7B2.9B$30.2A2.7B
2.8B.2B.3B$30.A2.AB2A.2B3.13BA2B$31.3ABABAB4.12BABAB$35.A.A2.A2.6BD6B
A2B$33.3A.4A2.5B3D8B$32.A3.A6.5BD10B$32.2A2.A.A4.5B3A2B$37.2A4.5BA2BA
B$42.11B$B41.7B3A$2B39.5B5A3B$3B37.6B5A2B$4B36.13B$.4B36.BA5B2A3B4.A$
2.4B35.A4B3A2B5.2A$3.4B33.A3B2ABA9B$4.4B29.11BA4B$5.4B27.2BA5B4A4B$6.
4B26.BAB2A3BA7B$7.4B10.A13.2BA5BA7B$8.4B7.3A12.2A2BAB2A12B$9.4B5.A15.
2A3BA14B$10.4B4.2A15.20B$3.2A6.9B14.22B$4.A7.6B14.24B$4.A.2A5.6B3.B2.
2B2.26B$5.A2.A4.19BD13B.10B$6.2AB3.6BA13BDBD4B.7B2.2B4.2A$7.9BA.A2B2A
9B3D4B2.3B.B4.B4.A$8.8B.2A2B2A11BD4B4.2B2A3.2A4.3A$9.29B4.BA2.A4.A6.A
$9.17B.4B12.3A5.A.A$10.15B3.2B22.2A$10.15B3.3B12.3A$11.13B5.A2B.2A8.A
2.A$13.13B2.A.A2B.A10.2A$12.8B4.2A.A.AB2.A$12.6B6.2ABA4.A$12.5B8.B2.
5A.A$12.B.B5.2A.A.2A.A4.A.A$13.3B4.A.2A.A2.A.2A2.A$12.B2AB11.2A.A.2A$
13.2A!

Darn! Now there's no particular reason for me to post the fact that four cells can be saved in the welded catalyst in your wonderful mutated Bandersnatch:

Code: Select all

x = 105, y = 77, rule = LifeHistory
C$B2C$2C5$95.B2A$93.2BA2BAB$93.3B2A3B$91.12B$90.14B$91.7BDBD3B$91.7B
2D5B$90.9BD5B$90.14B$90.13B$71.2A17.B3D4B.3B$66.2A.A2.A17.2BD4B$66.2A
.2A19.2B3D2B$69.B11.2A7.6B$66.2AB2AB2.2B4.B2AB5.7B$67.A.2A6B.7B3.8B$
65.A3.26B$65.2A5.23B$72.17B.2BD3B$72.16B.2B3D2B$72.18B2DBDB$67.2B3.
23B$66.2AB3.23B$66.2AB3.4BA3BD14B$67.B4.3BABA2BDBD13B$69.5BA2BA2B2D
14B$70.5B2A19B$70.25B.2B$69.30B$68.2A29B$68.2A23BD5B2A2B$69.2B.7B2.
11B3D4BABAB$73.6B2.11BD8BAB$76.2B3.19B2ABA$76.3B3.15B2.B2.A.A$75.BC2.
B2.15B3.2A2.A$75.C.C2.4B2.10B5.A.A$76.2C2.2C3.14B2.A.2A$81.CB.14B2C.A
.A$76.5C3.14B2CBA.A$75.E2.E6.15B2.A$75.2E8.15B$84.17B$51.B29.16B$50.
3B27.16B$50.4B26.16B$51.4B10.A13.16B$52.4B7.3A12.20B$53.4B5.A15.20B$
54.4B4.2A15.20B$47.2A6.9B14.22B$48.A7.6B14.24B$48.A.2A5.6B3.B2.2B2.
26B$49.A2.A4.19BD13B.10B$50.2AB3.6BC13BDBD4B.7B2.2B4.2A$51.9BCBC2B2A
9B3D4B2.3B.B4.B4.A$52.9B2C2B2A11BD4B4.2B2A3.2A4.3A$53.29B4.BA2.A4.A6.
A$53.17B.B15.3A5.A.A$54.15B27.2A$54.15B18.3A$55.13B5.A3.2A8.A2.A$57.
13B2.A.A3.A10.2A$56.8B4.2A.A.A3.A$56.6B6.2ABA4.A$56.5B8.B2.5A.A$56.B.
B5.2A.A.2A.A4.A.A$57.3B4.A.2A.A2.A.2A2.A$56.B2AB11.2A.A.2A$57.2A!

(I liked the stylish variant.)

Might there be some R source that would allow that extra glider from the Bandersnatch to escape? That would probably just make the repeat time worse, of course, but a having new output glider lane/timing is always better than not having it.

[MathAndCode]

It is getting harder to find these, but that's how it should be ^^. The might be a hidden B-to-h in there, but I could not find a "normal" way to produce that B (but I found "a" way)

Where is it? I only see two Bs, one produced from an R-pentomino, which I consider to the normal way to produce a B, and one as a syringe intermediate, which I doubt that you're talking about because the syringe has been well-known for several years.

[Entity Valkyrie 2]

Unidentified to H:

Code: Select all

x = 13, y = 48, rule = B3/S23
11b2o$11bo$9b3o16$9b2o$9b2o2$3bo$b3o$o$2o$5bo$4bobo$4b2o9$11b2o$4b2o5b
2o$5bo$5bobo$6b2o3$9b3o$10bobo$12bo$9bob2o$9b2o!

[Entity Valkyrie 2]

Darn! Now there's no particular reason for me to post the fact that four cells can be saved in the welded catalyst in your wonderful mutated Bandersnatch:

Code: Select all

x = 105, y = 77, rule = LifeHistory
C$B2C$2C5$95.B2A$93.2BA2BAB$93.3B2A3B$91.12B$90.14B$91.7BDBD3B$91.7B
2D5B$90.9BD5B$90.14B$90.13B$71.2A17.B3D4B.3B$66.2A.A2.A17.2BD4B$66.2A
.2A19.2B3D2B$69.B11.2A7.6B$66.2AB2AB2.2B4.B2AB5.7B$67.A.2A6B.7B3.8B$
65.A3.26B$65.2A5.23B$72.17B.2BD3B$72.16B.2B3D2B$72.18B2DBDB$67.2B3.
23B$66.2AB3.23B$66.2AB3.4BA3BD14B$67.B4.3BABA2BDBD13B$69.5BA2BA2B2D
14B$70.5B2A19B$70.25B.2B$69.30B$68.2A29B$68.2A23BD5B2A2B$69.2B.7B2.
11B3D4BABAB$73.6B2.11BD8BAB$76.2B3.19B2ABA$76.3B3.15B2.B2.A.A$75.BC2.
B2.15B3.2A2.A$75.C.C2.4B2.10B5.A.A$76.2C2.2C3.14B2.A.2A$81.CB.14B2C.A
.A$76.5C3.14B2CBA.A$75.E2.E6.15B2.A$75.2E8.15B$84.17B$51.B29.16B$50.
3B27.16B$50.4B26.16B$51.4B10.A13.16B$52.4B7.3A12.20B$53.4B5.A15.20B$
54.4B4.2A15.20B$47.2A6.9B14.22B$48.A7.6B14.24B$48.A.2A5.6B3.B2.2B2.
26B$49.A2.A4.19BD13B.10B$50.2AB3.6BC13BDBD4B.7B2.2B4.2A$51.9BCBC2B2A
9B3D4B2.3B.B4.B4.A$52.9B2C2B2A11BD4B4.2B2A3.2A4.3A$53.29B4.BA2.A4.A6.
A$53.17B.B15.3A5.A.A$54.15B27.2A$54.15B18.3A$55.13B5.A3.2A8.A2.A$57.
13B2.A.A3.A10.2A$56.8B4.2A.A.A3.A$56.6B6.2ABA4.A$56.5B8.B2.5A.A$56.B.
B5.2A.A.2A.A4.A.A$57.3B4.A.2A.A2.A.2A2.A$56.B2AB11.2A.A.2A$57.2A!

(I liked the stylish variant.)

Might there be some R source that would allow that extra glider from the Bandersnatch to escape? That would probably just make the repeat time worse, of course, but a having new output glider lane/timing is always better than not having it.

Which can be trivially reduced by five cells while keeping the stylish catalyst:

Code: Select all

x = 105, y = 77, rule = B3/S23
bo$2bo$3o5$96b2o$95bo2bo$96b2o7$68bo$67bobo$67bobo$65b3ob2o$64bo16b2o$
65b3ob2o10b2o$67bob2o7$66b2o$66b2o8bo$75bobo$74bo2bo$75b2o3$68b2o$68b
2o29b2o$99bobo$101bo$100b2obo$102bobo$76bo23b2o2bo$75bobo23bobo$76b2o
2b2o19bob2o$81bo16b2obo2bo$75bob4o17b2ob2o$75b2obo6$65bo$63b3o$62bo$
62b2o$47b2o$48bo$48bob2o$49bo2bo$50b2o9bo37b2o$62b2ob2o32bo$61b2o2b2o
22b2o3b2o4b3o$87bo2bo4bo6bo$87b3o5bobo$96b2o$74bo3b2o7b2obo$73bobo3bo
7bob2o$72bobo3bo$68b2obobo3bo$68b2obo2b4obo$72bobo3bobo$68b2ob2o2bo2bo
bo$69bobo2b2o3bo$57b2o10bobo$57b2o11bo!