Thread For Requesting Help

[Tawal]

I'm searching to get the red Boat from the white Pi by catalysing it in front and sides.
Can someone help ?
My machine is already busy.
Thanks.

Code: Select all

x = 6, y = 3, rule = LifeHistory
.D.3C$D.D2.C$.2D3C!

Edit:
Why I need this Boat :

Code: Select all

x = 31, y = 29, rule = LifeHistory
2$7.A$8.A$6.3A8$14.A.3D$13.A.A2.D$14.2A3D8$16.2C$16.C.C$18.C$18.2C!

I think this Glider+Boat reaction needs more investigation …

[confocaloid]

A known block factory can place the bait block into the Galumpher, as shown below. However, if the bait block is absent, the input glider lane is no longer transparent, and an input glider will damage the block factory.

Can anyone suggest a replacement block factory, which also works in this situation, and will leave the input glider lane transparent if the block is absent?

Code: Select all

x = 61, y = 80, rule = LifeHistory
11.2A.2A$12.A.A$7.2A.A5.A.2A$6.A.A.2A3.2A.A.A$5.A2.B2.BA.AB2.B2.A$5.
7AB.B7A$9.3B.B.3B$7.3AB.3B.B3A$6.A.BA3BA3BAB.A$6.2A3.BABAB3.2A$11.BAB
AB$11.2BA2B$11.2B.2B$9.B.5B$7.9B$7.8B2A$6.2A6BA2BA4.A$6.2AB.5B2AB3.A.
A$7.B2.8B2.2BAB$10.8B3.2B$11.8B.2B$11.13B$11.15B$9.17B$7.18B$7.2BC15B
$6.3BCBC11B$7.2B3C11B$6.5BC11B2.2A$5.18B.B2A2B$4.4B7.8B2.4B$4.3B8.14B
$2.4B9.14B$2.2CB10.7B2D4B$3.C6.2B3.7B2D5B4.2B$3C4.6B.B.13B.B.6B$C6.
31B$6.33B$7.31B$7.31B$5.32B$5.33B$4.2A33B$4.2A33B$5.B.32B$7.12B.17B.B
2A$8.2B.25B2.BA.A$12.24B5.A$12.24B5.2A$12.25B$8.A.2A21B.4B$6.3AB2AB2.
18B2.4B$5.A4.B5.17B3.4B$6.3A.2A4.B2.14B4.4B$8.A.A4.2A2.13B6.4B$8.A.A
4.A4.5B2.4B8.4B$9.A3.A.A6.B5.5B7.4B$13.2A6.3B7.2A8.4B$21.B2AB6.A10.4B
$22.2A8.3A8.4B5.A$34.A9.4B4.3A$45.4B6.A$46.4B4.2A$47.4B$48.3B4$16.A$
17.A$12.A4.A$13.5A$59.A$58.A.A$59.2A2$59.2A$60.A$58.A$58.2A!

[MathAndCode]

The still life xs26_4a9b8bqiczca23 had a known synthesis at least since 2022-07-05.
There seems to be no easy way to add the block, to construct the "diehard" still life (xs30_354cwmmz65139d543)?

Code: Select all

x = 16, y = 10, rule = B3/S23
5b2o$b2obo2bo$b2ob2obo5bo$5bob2o4bobo$5bo7b2o$2b2obob2o$2bo2bo2bo$obo
2bobo4b2o$2o4bo4b2o$13bo!

It might be easier to make it from something else.

Code: Select all

x = 17, y = 21, rule = B3/S23
5bo$4b2o$bo$b2o3b2o3bo$obo2bobo2bobo$5bo4b2o$o5b4o5b2o$9bo4bo$6b2o6bo
$2b2o3b2o4bo2bo$2bo2bo3bo2bo3bo$3b6o4b2o$14bo$5bob2o$3b3ob2o$2bo8bo$2b
2o6b2o2$13bobo$3bo2b2obo3b2o$4b2o2bob2o!

Code: Select all

x = 14, y = 17, rule = B3/S23
4b2o$5bo$8b2o$bob3o4bo$3b2ob2o$3bo4b2obo$8b2obo$2o3b2obo$o2bo2bo2bobo
$b5o$9b2o$3bo4bo4bo$b3o2b2o3bobo$o6bo2bo$2o5b3obo$6b2o$11bo!

xs19_354cz6513156 already has a synthesis, but that is the more difficult-looking one to get the goal from, and I don't know how to turn it or xs24_3hu0mmz643w346 into xs41_354c0ccz65139d5izx69d116a4.

[Gustone]

I need 2 slow salvoes using only this colour and direction of glider and this starting object

Code: Select all

x = 3, y = 54, rule = B3/S23
bo$o$3o42$b2o$b2o6$o$o$o!

one to make a NW glider of the same colour, the other to make a SW glider of unspecified colour
gliders can come in any phase
block debris allowed
EDIT: now only need the SW one, or a NW one under 4 gliders

[Entity Valkyrie 2]

A known block factory can place the bait block into the Galumpher, as shown below. However, if the bait block is absent, the input glider lane is no longer transparent, and an input glider will damage the block factory.

Can anyone suggest a replacement block factory, which also works in this situation, and will leave the input glider lane transparent if the block is absent?

Code: Select all

x = 61, y = 80, rule = LifeHistory
11.2A.2A$12.A.A$7.2A.A5.A.2A$6.A.A.2A3.2A.A.A$5.A2.B2.BA.AB2.B2.A$5.
7AB.B7A$9.3B.B.3B$7.3AB.3B.B3A$6.A.BA3BA3BAB.A$6.2A3.BABAB3.2A$11.BAB
AB$11.2BA2B$11.2B.2B$9.B.5B$7.9B$7.8B2A$6.2A6BA2BA4.A$6.2AB.5B2AB3.A.
A$7.B2.8B2.2BAB$10.8B3.2B$11.8B.2B$11.13B$11.15B$9.17B$7.18B$7.2BC15B
$6.3BCBC11B$7.2B3C11B$6.5BC11B2.2A$5.18B.B2A2B$4.4B7.8B2.4B$4.3B8.14B
$2.4B9.14B$2.2CB10.7B2D4B$3.C6.2B3.7B2D5B4.2B$3C4.6B.B.13B.B.6B$C6.
31B$6.33B$7.31B$7.31B$5.32B$5.33B$4.2A33B$4.2A33B$5.B.32B$7.12B.17B.B
2A$8.2B.25B2.BA.A$12.24B5.A$12.24B5.2A$12.25B$8.A.2A21B.4B$6.3AB2AB2.
18B2.4B$5.A4.B5.17B3.4B$6.3A.2A4.B2.14B4.4B$8.A.A4.2A2.13B6.4B$8.A.A
4.A4.5B2.4B8.4B$9.A3.A.A6.B5.5B7.4B$13.2A6.3B7.2A8.4B$21.B2AB6.A10.4B
$22.2A8.3A8.4B5.A$34.A9.4B4.3A$45.4B6.A$46.4B4.2A$47.4B$48.3B4$16.A$
17.A$12.A4.A$13.5A$59.A$58.A.A$59.2A2$59.2A$60.A$58.A$58.2A!

This doesn't fully solve the problem — it just absorbs the problematic glider before it can hit the block. Also, there isn't an easy way to remove the block.

Code: Select all

x = 64, y = 80, rule = B3/S23
14b2ob2o$15bobo$10b2obo5bob2o$9bobob2o3b2obobo$8bo6bobo6bo$8b7o3b7o2$
10b3o7b3o$9bo2bo3bo3bo2bo$9b2o4bobo4b2o$15bobo$16bo2$4bo$3bobo$3bobo3b
2o7b2o$b3ob2o2b2o6bo2bo4bo$o17b2o4bobo$b3ob2o18bo$3bob2o6$12bo$12bobo$
12b3o$14bo13b2o$28b2o4$26bo$25bo8$7b2o$7b2o2$42b2o$42bobo$44bo$44b2o2$
11bob2o$9b3ob2o$8bo$9b3ob2o$11bobo4b2o$11bobo4bo$12bo3bobo$16b2o16b2o$
25b2o7bo$25b2o8b3o17bo$37bo17b3o$58bo$57b2o5$17bo$15bo3bo$20bo$15bo4bo
$16b5o$62bo$61bobo$62b2o2$62b2o$63bo$61bo$61b2o!

[Gustone]

Code: Select all

x = 3, y = 54, rule = B3/S23
bo$o$3o42$b2o$b2o6$o$o$o!

New question: how do i brute force all 4-glider suitable slow salvoes with this target in reasonable time?

[Tawal]

A known block factory can place the bait block into the Galumpher, as shown below. However, if the bait block is absent, the input glider lane is no longer transparent, and an input glider will damage the block factory.

Can anyone suggest a replacement block factory, which also works in this situation, and will leave the input glider lane transparent if the block is absent?

Code: Select all

x = 61, y = 80, rule = LifeHistory
11.2A.2A$12.A.A$7.2A.A5.A.2A$6.A.A.2A3.2A.A.A$5.A2.B2.BA.AB2.B2.A$5.
7AB.B7A$9.3B.B.3B$7.3AB.3B.B3A$6.A.BA3BA3BAB.A$6.2A3.BABAB3.2A$11.BAB
AB$11.2BA2B$11.2B.2B$9.B.5B$7.9B$7.8B2A$6.2A6BA2BA4.A$6.2AB.5B2AB3.A.
A$7.B2.8B2.2BAB$10.8B3.2B$11.8B.2B$11.13B$11.15B$9.17B$7.18B$7.2BC15B
$6.3BCBC11B$7.2B3C11B$6.5BC11B2.2A$5.18B.B2A2B$4.4B7.8B2.4B$4.3B8.14B
$2.4B9.14B$2.2CB10.7B2D4B$3.C6.2B3.7B2D5B4.2B$3C4.6B.B.13B.B.6B$C6.
31B$6.33B$7.31B$7.31B$5.32B$5.33B$4.2A33B$4.2A33B$5.B.32B$7.12B.17B.B
2A$8.2B.25B2.BA.A$12.24B5.A$12.24B5.2A$12.25B$8.A.2A21B.4B$6.3AB2AB2.
18B2.4B$5.A4.B5.17B3.4B$6.3A.2A4.B2.14B4.4B$8.A.A4.2A2.13B6.4B$8.A.A
4.A4.5B2.4B8.4B$9.A3.A.A6.B5.5B7.4B$13.2A6.3B7.2A8.4B$21.B2AB6.A10.4B
$22.2A8.3A8.4B5.A$34.A9.4B4.3A$45.4B6.A$46.4B4.2A$47.4B$48.3B4$16.A$
17.A$12.A4.A$13.5A$59.A$58.A.A$59.2A2$59.2A$60.A$58.A$58.2A!

Perhaps by replacing the top Block of Galumpher with Eater1 (broken Galumpher = the Block doesn't reappear).
I found a Block factory which works but doesn't let escape the Glider in absence of Block

Code: Select all

x = 62, y = 71, rule = LifeHistory
15.B$13.5B8.A$12.6B6.3A$12.2B3E2B4.A$12.2BE4B4.2A$5.2A5.B3E4B.4B$4.B
2AB4.11B$5.2B5.12B$3.5B.15B$3.9B.11B$3.10B3.7B$3.11B.8B$3.19B$3.19B$
3.20B$3.20B.B$3.21B2A$4.20B2A4.C$5.B.18B3.3C$7.18BD.C$8.16B2.D2C$10.
19B$11.16B$7.21B$7.15B2D4B$8.14B2D5B4.2B$7.14B2.6B.B.6B$7.31B$6.33B$
7.31B$7.31B$5.32B$5.33B$4.2A33B$4.2A33B$5.B.32B$7.12B.17B.B2A$8.2B.
25B2.BA.A$12.24B5.A$12.24B5.2A$12.25B$8.A.2A21B.4B$6.3AB2AB2.18B2.4B$
5.A4.B5.17B3.4B$6.3A.2A4.B2.14B4.4B$8.A.A4.2A2.13B6.4B$8.A.A4.A4.5B2.
4B8.4B$9.A3.A.A6.B5.5B7.4B$13.2A6.3B7.2A8.4B$21.B2AB6.A10.4B$22.2A8.
3A8.4B5.A$34.A9.4B4.3A$45.4B6.A$46.4B4.2A$47.4B3.5B$48.4B4.4B$49.4B.
6B$50.10B$2.A.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.11B$A.2BA
56B$2.3BA56B$A4BA56B$.5A55B$.58BA$3.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B.B
.B.B.B.B.B.B.B.B.B.3BABA$58.B2A$59.B$59.2A$60.A$58.A$58.2A!

Edit:
May be the leftmost Block of the factory can be replaced to let the Glider escape …

[confocaloid]

[...] Perhaps by replacing the top Block of Galumpher with Eater1 (broken Galumpher = the Block doesn't reappear). [...]

Well, the idea was to keep the Galumpher functional, while also allowing to add/remove the bait block. If successful, that would lead to a permanent switch, where the input glider is either reflected back or allowed to pass through depending on the state of the switch.
There might be a block factory/keeper/toggle that would work here, although finding a small solution might not be too likely.
"Broken Galumpher" means that the idea of a permanent switch no longer works.

[Tawal]

…
"Broken Galumpher" means that the idea of a permanent switch no longer works.

This "broken Galumpher" remove the bait Block when used.
Then the Block factory is there to restore the bait Block.
I understand that you need the back Glider in order to restore the Boat.
In this case, you ABSOLUTELY need a Block Toggle Factory which lets escape the Glider.

But there still a question : how do you restore the Boat if the bait Block is not there ?

Edit:
OK, you need a Toggle Block factory with transparent lane for the escaped Glider, so you can duplicate and reflect the escaped Glider to restore the Boat.

[confocaloid]

[...] But there still a question : how do you restore the Boat if the bait Block is not there ? [...]

Well, the boat-bit was just an example (which apparently turned out to be a distraction from the main idea).

The main idea is just this. As shown, it is incomplete. The left side works as intended; the block factory can be used to install the bait block, and the Galumpher (with the bait block present) is functional. However, the right side fails, because the input glider lane is not transparent when the Galumpher's bait block is absent.

Ideally, there would be an easy way to add the bait block, and an easy way to remove the bait block, and the device would either reflect input gliders back along the same path (as the Galumpher) or let input gliders pass through (as empty space) depending on whether the bait block is present or absent.

Code: Select all

x = 130, y = 75, rule = LifeHistory
11.2A.2A65.2A.2A$12.A.A67.A.A$7.2A.A5.A.2A57.2A.A5.A.2A$6.A.A.2A3.2A.
A.A55.A.A.2A3.2A.A.A$5.A2.B2.BA.AB2.B2.A53.A2.B2.BA.AB2.B2.A$5.7AB.B
7A53.7AB.B7A$9.3B.B.3B61.3B.B.3B$7.3AB.3B.B3A57.3AB.3B.B3A$6.A.BA3BA
3BAB.A55.A.BA3BA3BAB.A$6.2A3.BABAB3.2A55.2A3.BABAB3.2A$11.BABAB65.BAB
AB$11.2BA2B65.2BA2B$11.2B.2B65.2B.2B$9.B.5B63.B.5B$7.9B61.9B$7.8B2A
60.8B2A$6.2A6BA2BA4.A53.2A6BA2BA4.A$6.2AB.5B2AB3.A.A52.2AB.5B2AB3.A.A
$7.B2.8B2.2BAB53.B2.8B2.2BAB$10.8B3.2B57.8B3.2B$11.8B.2B59.8B.2B$11.
13B57.13B$11.15B55.15B$9.17B53.17B$7.18B52.18B$7.2BC15B52.2BD15B$6.3B
CBC11B53.3BDBD11B$7.2B3C11B54.2B3D11B$6.5BC11B2.2A49.5BD11B2.2A$5.18B
.B2A2B46.18B.B2A2B$4.4B7.8B2.4B45.4B7.8B2.4B$4.3B8.14B45.3B8.14B$2.4B
9.14B43.4B9.14B$2.2CB10.7B2D4B44.2CB10.7B2D4B$3.C6.2B3.7B2D5B4.2B38.C
6.2B3.7B2D5B4.2B$3C4.6B.B.13B.B.6B32.3C4.6B.B.13B.B.6B$C6.31B32.C6.
31B$6.33B37.33B$7.31B39.31B$7.31B39.31B$5.32B38.32B$5.33B37.33B$4.2A
33B35.2A33B$4.2A33B35.2A33B$5.B.32B36.B.32B$7.12B.17B.B2A36.12B.17B.B
2A$8.2B.25B2.BA.A36.2B.25B2.BA.A$12.24B5.A40.24B5.A$12.24B5.2A39.24B
5.2A$12.25B45.25B$8.A.2A21B.4B40.A.2A21B.4B$6.3AB2AB2.18B2.4B37.3AB2A
B2.18B2.4B$5.A4.B5.17B3.4B35.A4.B5.17B3.4B$6.3A.2A4.B2.14B4.4B35.3A.
2A4.B2.14B4.4B$8.A.A4.2A2.13B6.4B36.A.A4.2A2.13B6.4B$8.A.A4.A4.5B2.4B
8.4B35.A.A4.A4.5B2.4B8.4B$9.A3.A.A6.B5.5B7.4B35.A3.A.A6.B5.5B7.4B$13.
2A6.3B7.2A8.4B38.2A6.3B7.2A8.4B$21.B2AB6.A10.4B45.B2AB6.A10.4B$22.2A
8.3A8.4B45.2A8.3A8.4B$34.A9.4B56.A9.4B$45.4B66.4B$46.4B66.4B$47.4B66.
4B$48.3B67.3B8$57.3A67.3A$57.A69.A$58.A69.A!

[Tawal]

Well, the boat-bit was just an example (which apparently turned out to be a distraction from the main idea).

Well, i wasn't understood that

So, as I said, you need a Toggle Block factory for the Galumpher's bait Block.
Because when functional Galumpher is used, the bait Block still there.
A second send on the Toggle factory will delete the bait Block.
Or another way to destroy the bait Block …

Edit:
With the "broken Galumpher", you can use a Block Keeper instead.

[WhiteHawk]

How do I get a p62 loop out of this Color-changing composite reflector?

Code: Select all

x = 49, y = 52, rule = B3/S23
17b2ob2o$18bobo$bo11b2obo5bob2o$2bo9bobob2o3b2obobo16bo$3o8bo6bobo6bo
13b3o$11b7o3b7o5b2o5bo$31b3obo4b2o$13b3o7b3o4bo4bo$12bo2bo3bo3bo2bo4b
3obob2o$12b2o4bobo4b2o6bobo2bo$18bobo15b2o$19bo16bo$35bo$34bo2bo$34bo
3bo$26b2o6bo3bo$26b2o5b2o3bo6b2obo$34bo2bo7bob2o$17bo19b2o$15bobo20b2o
$16b2o20b2o$17bo$17b2o5b2o$16bo2bo4bobo$12b2o3bobo6bo$8b2obobo4bo7b2o
$9bobo9b2o$8bo2b2o8bo$9b2o11b3o$11b2o11bo$11bo$12bo$11b2o$38bo$36b2ob
2o$36b2ob2o$36b2o2b2o$36b3obo$35b5o$34bo3bo$35bo$37b2o$36bo5b2o$38bo3b
2o$38bo$35b3o3$34b2o$30b2obobo$30bob2obobo$36b2o!

[Tawal]

How do I get a p62 loop out of this Color-changing composite reflector?

Just doubling your reflector and shift to obtain a Nx62 length :
13 x 62

Code: Select all

x = 110, y = 114, rule = LifeHistory
60.2A$60.A.A.2A.A$62.A.A.2A$61.B2A$62.2B$57.B2.BA2B$55.5B2AB$55.4BABA
B$54.2A4BA3B$54.2AB.BA5B$55.B.3B2A3B$58.B2A4B$56.2B2A3BAB$56.6BAB$56.
2A5B$55.BA5BA$55.7BA$56.BA3BAB$56.2B3A2B$55.8B22.2A$54.10B21.A$53.10B
23.A$52.4B.7B9.A11.2A$51.4B3.6B9.3A8.B2.2A$50.4B4.6B12.A7.B2A2.A$49.
4B5.6B11.2A6.2B.A.A$48.4B5.8B5.2A3.4BA2B.BA.A.2A$47.A3B5.8B7.A5.BABA
3B2A$46.BABA6.9B6.A.AB.2BA2BA3B$45.2B2A7.9B7.2AB.3B3AB$44.4B7.10B9.9B
$43.4B8.3B2A5B9.5B2A2B$42.4B8.11B9.5B2A2B$41.4B9.4BABA5B.3B2.B2.6BA2B
$40.4B5.2A.A7BA2B2A20B$39.4B6.A.2A2.4B2AB3A5B2A14B$38.4B14.2B3AB2A6B
2A15B$37.4B17.B2AB3A23B$36.4B20.2B2A19B2.4B$35.4B21.B2AB2.2B3.5B.B.B
6.4B$34.4B22.3AB10.B.2BA2B6.4B$33.4B22.B3AB12.BABAB7.4B$32.A3B22.BA2B
A.A6.2A3.BABAB3.2A3.4B$31.A3B23.B2A.A.3A4.A.BA3BA3BAB.A4.4B$30.B3A22.
4B2.A4.A4.3AB.3B.B3A6.4B10.2A$29.4B23.2A4.A.3A7.3B.B.3B9.4B9.A$28.4B
25.A5.2A5.7AB.B7A.2A3.2BAB10.A$27.4B23.3A13.A2.B2.BA.AB2.B2.A.A5.B2AB
5.5A$26.4B24.A16.A.A.2A3.2A.A.A2.A5.2B2A4.A$25.4B43.2A.A5.A.2A3.A.AB.
4B3A2.4A$24.4B49.A.A9.2AB.4B3A3.AB.A$9.A13.4B49.2A.2A10.5B2A2B7A$9.3A
10.4B65.8B2A2BAB2.2A$12.A8.4B66.9B2A.BABA2.A$11.2A7.4B67.10B3.A.A.2A$
11.5B3.4B67.8B8.A$13.3B2.4B67.9B7.2A$3.2A7.9B67.4B2.3B$3.A8.4BA3B67.
4B3.5B$2A.A.B3.7BABA67.4B7.2A$A2.3AB.2B2A4B2AB66.4B8.A$.2A2.BA3B2A7B
65.2A2B10.3A$3.4A12B10.2A.2A49.2B2A13.A$3.A.2B3.7B.B2A9.A.A49.2BAB$4.
3AB2.7B.BA.A3.2A.A5.A.2A43.4B$7.A4.4B5.A2.A.A.2A3.2A.A.A16.A24.4B$2.
5A5.4B5.A.A2.B2.BA.AB2.B2.A13.3A23.4B$2.A10.4B3.2A.7AB.B7A5.2A5.A25.
4B$4.A9.4B9.3B.B.3B7.3A.A4.2A23.4B$3.2A10.4B6.3AB.3B.B3A4.A4.A2.4B22.
4B$16.4B4.A.BA3BA3BAB.A4.3A.A.2AB23.4B$17.4B3.2A3.2AB2A3.2A6.A.A2BAB
22.4B$18.3BA7.5B12.2B2AB22.4B$19.3BA6.5B.B10.4B22.4B$20.3AB6.B.B.5B3.
2B2.4B21.4B$21.4B2.2B2AB2A16B20.4B$22.5B2A5BA17B17.A3B$23.4B2A5B2A2B
2A14B14.B2AB$24.2BABA5B2A2B2A15B2.2A.A6.BABA$25.2B3A3BABA11BA9BA.2A5.
4B$26.2B2A3B2A2.B2.3B.2B3A7B9.4B$27.9B9.B2A3B2A3B8.4B$27.9B9.7BA2B8.
4B$27.9B9.4BA3BAB7.4B$27.2B2A3B.B2A7.3B2A3BA7.4B$25.3BA2BA2B.BA.A6.B
2A4BAB6.4B$24.2A3BABAB5.A7.8B5.4B$20.2A.A.AB.2BA4B3.2A5.A5BAB5.4B$21.
A.A.2B6.2A11.6B5.4B$20.A2.2AB7.A12.A4BA4.4B$21.2A2.B8.3A9.2BA2BA3.4B$
23.2A11.A9.2B3A2B.4B$23.A23.6B2A2B$24.A21.8B2A$23.2A22.6BAB$47.7B$47.
7B$47.8B$47.8B$47.7B$46.8B$45.BA7B$45.ABA4B$45.BABA4B.B$45.2B2A3B.B2A
$46.8B2A$47.8B$47.8B$46.4B2.B$46.2B$46.2AB$42.2A.A.A$42.A.2A.A.A$48.
2A!

[WhiteHawk]

How do I get a p62 loop out of this Color-changing composite reflector?

Just doubling your reflector and shift to obtain a Nx62 length :
13 x 62

Code: Select all

Thanks.

I was looking originally looking for a snark-less solution, though it turns out I can't use it for my original purpose anyway

[confocaloid]

How do I get a p62 loop out of this Color-changing composite reflector? [...]

The reflector you posted is stable, which means you don't have to worry about phases.

Begin by making a working closed glider track, with four reflectors placed in an arbitrary correctly-aligned way:

Code: Select all

x = 145, y = 145, rule = B3/S23
70b2o$70bobob2obo$72bobob2o$72b2o5$64b2o$64b2o5b2o$71bobo$72bobo$73bo
7$95b2o$95bo$96bo$83bo11b2o$83b3o11b2o$86bo8b2o2bo$85b2o9bobo$80b2o7bo
4bobob2o$81bo6bobo3b2o$81bobo4bo2bo$82b2o5b2o2$68b2o$68b2o2$59b2obo$
59bob2o17b2o$80b2o4$88bo$70b2o15bobo$69bo2bobo6b2o4bobo4b2o$69b2obob3o
4bo2bo3bo3bo2bo$72bo4bo4b3o7b3o$24bobo39b2o4bob3o$23bob2o40bo5b2o5b7o
3b7o$23bo40b3o13bo6bobo6bo$19bob2ob3o19b2o16bo16bobob2o3b2obobo$19b2ob
obo2bo14b2o2bobo33b2obo5bob2o$26b2o14bobobo2bo37bobo$44bobob2o36b2ob2o
$43b2obo$28bo17bob2o$27bobo16bobo2bo$26bo2bo11b2o4bo2b2o$27b2o11bo2bo$
41b2o4bo2b2o$24b2o20bobo2bo$23bobo20bob2o59b2o$23bo19b2obo63bo$22b2o4b
2o14bobob2o59bo$29bo12bobobo2bo59b2o$26b3o6b2o5b2o2bobo$26bo8b2o9b2o
48b2o37b2o$97bo37b2o$97bobo$b2o41bo53b2o$2bo40bobo66b2o$bo41bobo55b2o
9b2o$b2o8bo30b2ob2o54bobo39b2o$3bo6bobo33bo56bo30b2o8bo$b3o5bobo30b4o
53b4o30bobo5b3o$o8b2o30bo56bo33bobo6bo$2o39bobo54b2ob2o30bo8b2o$31b2o
9b2o55bobo41bo$31b2o66bobo40bo$45b2o53bo41b2o$45bobo$8b2o37bo$8b2o37b
2o48b2o9b2o8bo$96bobo2b2o5b2o6b3o$34b2o59bo2bobobo12bo$35bo59b2obobo
14b2o4b2o$34bo63bob2o19bo$34b2o59b2obo20bobo$93bo2bobo20b2o$93b2o2bo4b
2o$101bo2bo11b2o$32bo60b2o2bo4b2o11bo2bo$33bo59bo2bobo16bobo$31b3o61b
2obo17bo$98bob2o$54b2ob2o36b2obobo$55bobo37bo2bobobo14b2o$50b2obo5bob
2o33bobo2b2o14bo2bobob2o$49bobob2o3b2obobo16bo16b2o19b3ob2obo$48bo6bob
o6bo13b3o40bo$48b7o3b7o5b2o5bo40b2obo$68b3obo4b2o39bobo$50b3o7b3o4bo4b
o$49bo2bo3bo3bo2bo4b3obob2o$49b2o4bobo4b2o6bobo2bo$55bobo15b2o$56bo4$
63b2o$63b2o17b2obo$82bob2o2$75b2o$75b2o2$54b2o5b2o$53bo2bo4bobo$49b2o
3bobo6bo$45b2obobo4bo7b2o$46bobo9b2o$45bo2b2o8bo$46b2o11b3o$48b2o11bo$
48bo$49bo$48b2o7$71bo$70bobo$71bobo$72b2o5b2o$79b2o5$71b2o$67b2obobo$
67bob2obobo$73b2o!

Put one glider on the track, and measure the period of the resulting glider loop oscillator (which will be equal to the glider track length). In this example, the period is 1156 ticks.
Since 1156 ≡ 40 (mod 62), and 40 is a multiple of 8, it is sufficient to reduce one of two "diagonal dimensions" by 40/8 = 5 cells (assuming that is possible geometrically). After that, the glider track length becomes 1116 ≡ 0 (mod 62).
Then it suffices to put 1116/62 = 18 equally spaced circulating gliders on the track. That can be done by repeatedly evolving the pattern in 62-tick steps, and pasting a glider into the same place on the track.

Here is a completed p62 glider loop oscillator, the glider track length is 1116, there are 18 circulating gliders:

Code: Select all

#C [[ THEME Catagolue ]]
x = 140, y = 140, rule = B3/S23
70b2o$70bobob2obo$72bobob2o$72b2o2$71bo$70b2o$69bobo$64b2o4bo$64b2o3bo
$70b2o$69b2o$68b2o3bo$72bo$66b2o$66bo5bo$72bo$67bo3bo$68b3o$95b2o$95bo
$96bo$83bo11b2o$83b3o11b2o$86bo8b2o2bo$85b2o9bobo$80b2o7bo4bobob2o$57b
o23bo6bobo3b2o$57bobo21bobo4bo2bo$57b2o23b2o5b3o2$68b2o19b2o$89b2o$68b
obo20bo$59b2obo7bo2b2o$59bob2o6b2ob3o5b2o$68b3ob2o6b2o$69b2ob3o$72b2o$
71b2o$70b3o15bo$70b3o14bobo$42bo26bo2bobo6b2o4bobo4b2o$41bo27b2obob3o
4bo2bo3bo3bo2bo$41b3o28bo4bo4b3o7b3o$24bobo39b2o4bob3o$23bob2o40bo5b2o
5b7o3b7o9bo$23bo40b3o13bo6bobo6bo8b2o$19bob2ob3o19b2o16bo16bobob2o3b2o
bobo9bobo$19b2obobo2bo14b2o2bobo33b2obo5bob2o$26b2o14bobobo2bo37bobo$
44bobob2o36b2ob2o$43b2obo$46bob2o$28b2o3b2o11bobo2bo52b2o$27bobo3bobo
5b2o4bo2b2o53bo$27bo7bo4bo2bo60bo$27bo3bo3bo5b2o4bo2b2o52b2o$24b2o2bo
5bo11bobo2bo$23bobo7bo12bob2o41b2o37b2o$23bo4bo3bo10b2obo45bo37b2o$22b
2o4bo15bobob2o42bobo10b2o$29bo12bobobo2bo43b2o9bob2o13b2o$26b3o6b2o5b
2o2bobo55bo2bo12b2o$26bo8b2o9b2o48b2o6b2ob2ob3o9bo$96bobo6bo2b2o2bo25b
2o$98bo7bo5bo16b2o8bo$b2o41bo49b4o9bo2b2o16bobo5b3o$2bo40bobo47bo14b2o
17bobo6bo$bo41bobo47b2ob2o30bo8b2o$b2o8bo30b2ob2o47bobo41bo$3bo6bobo
17b2o14bo47bobo40bo$b3o5bobo16b2o2bo9b4o49bo41b2o$o8b2o16bo5bo7bo$2o
25bo2b2o2bo6bobo$17bo9b3ob2ob2o6b2o48b2o9b2o8bo$18b2o12bo2bo55bobo2b2o
5b2o6b3o$17b2o13b2obo9b2o43bo2bobobo12bo$33b2o10bobo42b2obobo15bo4b2o$
8b2o37bo45bob2o10bo3bo4bo$8b2o37b2o41b2obo12bo7bobo$88bo2bobo11bo5bo2b
2o$34b2o52b2o2bo4b2o5bo3bo3bo$35bo60bo2bo4bo7bo$34bo53b2o2bo4b2o5bobo
3bobo$34b2o52bo2bobo11b2o3b2o$90b2obo$93bob2o$49b2ob2o36b2obobo$50bobo
37bo2bobobo14b2o$45b2obo5bob2o33bobo2b2o14bo2bobob2o$32bobo9bobob2o3b
2obobo16bo16b2o19b3ob2obo$33b2o8bo6bobo6bo13b3o40bo$33bo9b7o3b7o5b2o5b
o40b2obo$63b3obo4b2o39bobo$45b3o7b3o4bo4bo28b3o$44bo2bo3bo3bo2bo4b3obo
b2o27bo$44b2o4bobo4b2o6bobo2bo26bo$50bobo14b3o$51bo15b3o$67b2o$66b2o$
65b3ob2o$58b2o6b2ob3o$58b2o5b3ob2o6b2obo$65b2o2bo7bob2o$48bo20bobo$49b
2o$49b2o19b2o2$48b3o5b2o23b2o$48bo2bo4bobo21bobo$44b2o3bobo6bo23bo$40b
2obobo4bo7b2o$41bobo9b2o$40bo2b2o8bo$41b2o11b3o$43b2o11bo$43bo$44bo$
43b2o$69b3o$68bo3bo$67bo$67bo5bo$72b2o$67bo$66bo3b2o$69b2o$68b2o$70bo
3b2o$69bo4b2o$68bobo$68b2o$68bo2$66b2o$62b2obobo$62bob2obobo$68b2o!

[Tawal]

How to get the red Beehive from the yellow Pi ? if there's a way …
Of course avoid to place any cell in the blue area.

Code: Select all

x = 26, y = 23, rule = LifeHistory
3B$4B$5B$5B$6B$8B$9B$10B$6BD4B$5BDBD2B$5BDBDB$6BD2B$11B$12B$12B6.3E$
13B5.EBE$14B3.BEBE$20B$21B$23B$26B$26B$25B!

Thanks.

[confocaloid]

I don't know how far "the blue area" goes and what its shape is beyond what is shown, but it looks like one of these Pi-to-X conduits might work, to route the reaction away and initiate a synthesis for the beehive:

Code: Select all

x = 443, y = 45, rule = LifeHistory
318.A$278.D3.D33.3A$277.D5.D31.A$187.2D2.2D84.D5.D22.2A7.2A$140.2D2.
2D40.D2.2D86.D5.D21.B2A2B2.5B$142.2D2.D39.D2.D88.5D23.4B.4B$143.D2.D
39.D2.D14.2A99.11B$143.D2.D39.7D11.A.A71.2D.2D20.7B.5B$140.7D59.A5.3B
62.D2.D2.D18.8B.6B78.2D.2D$187.5D14.2AB2.5B61.D2.D2.D19.15B76.D2.D2.D
$142.D43.D.D3.D15.AB.6B60.D2.D2.D20.14B76.D2.D2.D$113.2A25.7D39.D2.D
2.D13.3A8B61.2D.2D21.14B76.D2.D2.D$112.B2AB26.D2.D40.D3.D.D12.A2.9BDB
83.17B75.7D$113.3B26.D.D42.5D13.2A2.7B3DB58.2D3.D17.19B$114.B27.2D66.
8BDB57.D2.D2.D17.19B74.D3.2D18.B$112.6B72.D19.10B57.D3.D.D14.B2.19B
74.D2.D2.D16.4B$3B109.7B21.D3.2D40.7D19.7B58.D4.2D13.25B72.D2.D2.D16.
4B$4B108.7B21.D2.D2.D40.D2.D21.7B59.D4.D11.2D26B71.D2.D2.D15.5B$5B
107.11B17.D.D3.D41.D.D21.11B70.2DBD26B71.3D2.D15.6B11.D$5B105.14B16.
2D4.D42.2D19.14B54.2D.2D10.D30B90.9B8.3D$6B104.14B16.D4.D64.14B53.D2.
D2.D9.3D28B70.D3.2D12.11B7.D2B2D$8B102.15B85.15B52.D2.D2.D13.30B67.D
2.D2.D11.11B7.5B$9B101.14B68.D17.14B53.D5.D13.3B.27B66.D2.D2.D12.9B8.
5B$10B100.8B2D4B16.D45.7D17.14B54.D3.D15.B4.25B66.D2.D2.D14.10B4.7B$
6BD4B99.9B2D3B16.7D40.D4.D17.14B79.25BA65.3D2.D15.21B$5BDBD2B99.10BD
5B15.D4.D63.16B53.D.D.D20.24B.3A81.23B$5BDBDB99.18B82.18B53.3D22.22B
5.A63.D.D.D12.23B3.2A$6BD2B97.21B60.D.D.D14.21B51.5D22.22B3.2A64.3D
12.26B2.A$11B94.22B14.D.D.D42.3D14.22B52.3D23.22B68.5D11.14B2A11B.A.
2A$12B94.21B15.3D42.5D14.21B51.D.D.D23.21B69.3D11.15B2A9B.3A2.A$12B6.
3E87.10B3D6B14.5D42.3D17.10B3D6B81.10B3D6B68.D.D.D10.8B3D15BAB2.2A$
13B5.EBE88.9BDBD6B15.3D42.D.D.D17.9BDBD6B56.D25.9BDBD6B84.7BDBD12B.2B
4A$14B3.BEBE89.8BDBD6B2A12.D.D.D64.8BDBD6B2A54.D26.8BDBD6B2A65.D17.6B
D.D4B.6B2.4B.A$20B90.17BA.A56.D22.18BA.A53.D25.18BA.A64.D17.5B5.2B3.
4B5.2A.A.A$21B89.11B.3B4.A10.D45.D21.13B.3B4.A53.D24.13B.3B4.A64.D2.D
16.2B12.2B7.A2.2A$23B88.8B4.B5.2A9.D45.D2.D17.12B4.B5.2A46.7D23.12B4.
B5.2A63.D2.D29.2B6.A.A$26B87.6B21.D45.D2.D16.4B3.6B87.4B3.6B75.7D25.B
2AB5.2A$26B87.4B23.D45.7D12.4B4.4B61.2D25.4B4.4B110.2A$25B115.7D57.4B
69.D2.D23.4B87.2D$187.2D14.4B70.D2.D22.4B87.D2.D$144.2D40.D2.D12.4B
71.D2.D21.4B88.D2.D$143.D2.D39.D2.D87.7D17.4B89.D2.D$143.D2.D39.D2.D
110.4B90.7D$143.D2.D39.7D$140.7D!

How to get the red Beehive from the yellow Pi ? if there's a way …
Of course avoid to place any cell in the blue area.

Code: Select all

x = 26, y = 23, rule = LifeHistory
3B$4B$5B$5B$6B$8B$9B$10B$6BD4B$5BDBD2B$5BDBDB$6BD2B$11B$12B$12B6.3E$
13B5.EBE$14B3.BEBE$20B$21B$23B$26B$26B$25B!

Thanks.

[wwei47]

It looks like it should be possible to complete this, but no solution yet. (The reaction arriving from the right side can be initiated with a 3G collision. I don't know how to create the reaction arriving from the bottom side. It might be possible by hitting a boat, a tub, or a similar still life previously constructed in the same location.)

Code: Select all

x = 107, y = 47, rule = B3/S23
64bo29bo$64b3o7bo19b3o7bo$67bo5bob2o20bo5bob2o$61b2o3bo6bob2o14b2o3bo
6bob2o$62bo2bo4b2o20bo2bo4b2o$62bobo5bo4bo16bobo5bo4bo$63bo6b2o3bo17bo
6b2o3bo$72b2o22bo5b2o$66b2o28bo$65bo27b2ob2o$62bobo3bo21bo8bo$62b2o4bo
bo21b2o5bo$61bo30bo4bo$62bo17$4bo29bo29bo29bo$4b3o7bo19b3o7bo19b3o7bo
19b3o7bo$7bo5bob2o20bo5bob2o20bo5bobo21bo5bobo$b2o3bo6bob2o14b2o3bo6bo
b2o14b2o3bo6bob2o14b2o3bo6bob2o$2bo2bo4b2o20bo2bo4b2o20bo2bo5b3obo16bo
2bo5b3obo$2bobo5bo4bo16bobo5bo4bo16bobo5b2ob3o16bobo5b2ob3o$3bo6b2o3bo
17bo6b2o3bo13bo3bo7bo2bo18bo7bo2bo$6bo5b2o22bo5b2o14bobo5bo5b2o22bo5b
2o$5bobo27bobo22bo4bobo20b2obo3bobo$2bo3bo29bo22bo4bobobo20bobo3b2o$3b
o5bo24bobobo19b3o3b2o2bo19bo2bo7bo$3o2bo4bo19bo2bobo2bo20b3obo4b2o18b
2o3b7o$3b3obobo20b2o2bo3b2o18bo3b4o4bo18b2o3b3o4bo$3b2o53bo4b2o3b2o2bo
16b2obo2bo2b2ob2o$bo57b2obo2bob2o3b2o17bobo4b3o2bo$58b2obo6bo3bo17bob
3obobo3bobo$60bo3b2o2b2o19bo4bobobo4b2o!

I would go for the python/long python or long long shillelagh route instead; see this predecessor of yours. I currently don't feel motivated to bash this out with JLS, but I can still point out a potentially easier route.

Code: Select all

x = 16, y = 14, rule = B3/S23
3bo$3b3o7bo$6bo5bob2o$2o3bo6bob2o$bo2bo4b2o$bobo5bo4bo$2bo6b2o3bo$11b
2o$5b2o$4bo$bobo3bo$b2o4bobo$o$bo!

[confocaloid]

Is there a more compact H-to-MWSS usable for sending several middleweight spaceships on two different lanes fitting within the same 7-cell-thick band, as shown?

Code: Select all

#C [[ GRID THEME LifeHistory ]]
x = 287, y = 141, rule = B3/S23
58b2o169b2o$58bobo168bobo$60bo4b2o164bo4b2o$56b4ob2o2bo2bo158b4ob2o2bo
2bo$56bo2bobobobob2o158bo2bobobobob2o$59bobobobo164bobobobo$60b2obobo
165b2obobo$64bo170bo2$50b2o169b2o$51bo7b2o161bo7b2o$51bobo5b2o161bobo
5b2o$52b2o169b2o7$62b2o169b2o$62bo170bo$63b3o168b3o$65bo170bo21$90bo
170bo$90bo12b2o156bo12b2o$74b2o3b2o9b3o10bo141b2o3b2o9b3o10bo$74b2o3b
2o11bo11b3o138b2o3b2o11bo11b3o$106bo170bo7$71b2o169b2o$71b2o13b2o154b
2o13b2o$86b2o169b2o3$4bo170bo$4b3o168b3o$7bo170bo$6b2o15b2o152b2o15b2o
$22bobo168bobo$2b2o14b2o2bo150b2o14b2o2bo$bo2bo13bobob2o46b2o100bo2bo
13bobob2o46b2o$bob2o14b2obo2bo44b2o100bob2o14b2obo2bo44b2o$2o22b2o145b
2o22b2o$3b2o169b2o$3o2bo165b3o2bo$o2b2obo15b2o147bo2b2obo15b2o$b2o2bo
5bo10b2o148b2o2bo5bo10b2o$3bo6bobo37b2o122bo6bobo37b2o$b2o7bobo38bo
120b2o7bobo38bo$bo9bo39bobo52b2o64bo9bo39bobo52b2o$2bo18b2o29b2o52bobo
64bo18b2o29b2o52bobo$b2o19bo84bo64b2o19bo84bo$5b2o12b3o154b2o12b3o$5b
2o12bo156b2o12bo$20b2o49b2o118b2o49b2o$21bo50bo119bo50bo$20bo48b3o4b2o
3b2o108bo48b3o4b2o3b2o$20b2o47bo6bo4bo2bo28bo77b2o47bo6bo4bo2bo28bo$
77bo4b3o27bobo133bo4b3o27bobo$76b2o35bo133b2o35bo$82b3o7b2o159b3o7b2o$
74bo6bo2bo8bo151bo6bo2bo8bo$74b3o4b2o10bobo149b3o4b2o10bobo$77bo16b2o
152bo16b2o$76b2o169b2o5$114b2o169b2o$94bo19b2o149bo19b2o$68b2o24bo144b
2o24bo$69bo24b3o143bo24b3o$69bobo24bo143bobo24bo$70b2o39b2o128b2o39b2o
$111b2o169b2o2$64bo170bo$45bo18b3o149bo18b3o$45b3o19bo41b2o105b3o19bo
41b2o$48bo17b2o35b2o4bobo107bo17b2o35b2o4bobo$47b2o55bo6bo106b2o55bo6b
o$101b3o7b2o159b3o7b2o$101bo170bo4$65bo170bo$39b2o24bo144b2o24bo$40bo
24b3o143bo24b3o$40bobo24bo143bobo24bo$41b2o169b2o$74b2o169b2o$75bo170b
o$35bo36b3o131bo36b3o$35b3o34bo133b3o34bo$38bo170bo$37b2o169b2o7$36bo
170bo$36bobo168bobo$36b3o168b3o$38bo170bo2$45b2o169b2o$46bo170bo$43b3o
168b3o$29b2o12bo156b2o12bo$30bo170bo$27b3o168b3o$27bo170bo!

[ElijahKen]

Edit: changed my request. (Sorry, I didn't see the reply yet.)
Is there a way to weld these caterers as shown? The needed sparks are in white.

Code: Select all

x = 12, y = 15, rule = LifeHistory
$6.D$5.CAC$6.2A$5.2A$6.A$2.2A$3.A.2A$4.2A$3.3A2$.C2A2.A.A$3.A.4A$7.2A
!

Edit 2: There is not a way to do it that will work for me (at least according to JLS).

[get_Snacked]

this is almost a blonkic seed for the still life highlighted in red:

Code: Select all

x = 32, y = 25, rule = LifeHistory
27.2A$27.2A8$5.2A$2A3.2A$2A23.2A$25.2A$8.A$8.A$8.A15.2D$24.D2.D2.D$26.
5D2$23.A2.2D.2D$22.2A2.2D.D.D$22.A.A5.D$8.3A$10.A6.3A$9.A!

how can i add more blinkers and blocks to make a clean seed that solely produces the still life?
EDIT: nvm that was easy lol

Code: Select all

x = 32, y = 25, rule = LifeHistory
27.2A$27.2A8$5.2A$2A3.2A$2A23.2A$25.2A$8.A$8.A$8.A15.2D$24.D2.D2.D$26.
5D2$23.A2.2D.2D$22.2A2.2D.D.D$22.A.A5.D$2.3A3.3A$10.A6.3A$9.A!

[Tawal]

I get an annoying Blinker which appears like this :

Code: Select all

x = 15, y = 10, rule = LifeHistory
3.11B$4.3BA2BA3B$4.3BABA2B$4.3B3A$4.6B$2.2AB.3B$.A.AB2.2B$.A$2A!

Is there a catalyst which can eat the Blinker just by interacting with the white marked cell ?

Code: Select all

x = 16, y = 10, rule = LifeHistory
$6.9B$6.7B$6.6B$6.5B$3.2AB.B2AC$2.A.AB2.2B$2.A$.2A!

Edit:
The blue envelops in the patterns come from the previous reaction (which brings this annoying Blinker).
Eidt2:
I know that a p2+2n duoplet sparker will work but I search a stable solution.

Code: Select all

x = 16, y = 10, rule = LifeHistory
$6.9B$6.7B$6.6B$6.5B$3.2AB.B2AC$2.A.AB2.2B2.E$2.A9.E$.2A!

[confocaloid]

The blue envelops in the patterns come from the previous reaction (which brings this annoying Blinker).

At least there should be (big, slow) engineered solution along these lines:

Code: Select all

x = 19, y = 9, rule = LifeHistory
3.11B$4.3BA2BA3B$4.3BABA2B$4.3B3A$4.6B$2.2AB.3B3.2A$.A.AB2.2B2.A2.A2.
2A$.A9.A.A3.2A$2A10.A!

One question is, how exactly the cells change their alive/dead states in the previous reaction? To illustrate the idea, if a tub was placed as shown, would it survive without interactions (before the "annoying blinker" forms), or the tub would interact with earlier reaction due to two other cells becoming alive at once? The envelope by itself doesn't communicate this information, which might be important in general.

Code: Select all

x = 14, y = 9, rule = LifeHistory
3.11B$4.3BA2BA3B$4.3BABA2B$4.3B3A$4.6B$2.2AB.3B$.A.AB2.2B2.A$.A8.A.A$
2A9.A!

[Tawal]

[…]
One question is, how exactly the cells change their alive/dead states in the previous reaction? To illustrate the idea, if a tub was placed as shown, would it survive without interactions (before the "annoying blinker" forms), or the tub would interact with earlier reaction due to two other cells becoming alive at once? The envelope by itself doesn't communicate this information, which might be important in general.

Code: Select all

x = 14, y = 9, rule = LifeHistory
3.11B$4.3BA2BA3B$4.3BABA2B$4.3B3A$4.6B$2.2AB.3B$.A.AB2.2B2.A$.A8.A.A$
2A9.A!

No, the Tub can't survive to the previous reaction because 2 neighbourhood cells are alive at the same time.
Thanks for the possibility of engineered solution, but its for a stable conduit (H to 2G).
And I feel that the engineered solution will be too big and slow as you say.

Do you think it would be a good idea to run a Bellman search ?
Or is it known that there isn't any stable solution ?

Edit:
Here is the previous reaction (Glider+Blinker) :

Code: Select all

x = 15, y = 22, rule = LifeHistory
15B$12BA2B$11BABAB$2B.11BA$4.4B3A2BAB$B5.BAB4A$B6.A2BA2B$8.2ABA$9.BAB
$10.A6$2.2A$.A.A$.A$2A!

[confocaloid]

[...]
Do you think it would be a good idea to run a Bellman search ?
Or is it known that there isn't any stable solution ?

I'm not aware of any existing answer to this, and don't have enough experience with using Bellman to tell if it makes sense. But in general, if an interesting search doesn't need too much efforts to configure and can be expected to complete reasonably quickly (or at least report progress as it goes), it makes sense to try it and see what happens.